Removing square brackets from hash array for value - ruby

I am having a following hash array
A = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}
I tried following code to remove the square brackets
A.to_s.gsub("\\[|\\]", "")
also tried with code
p A.map { |hash| hash.each_with_object({}) { |(k, v), hash| hash[k] = v.first } }
but its not working.
How I remove the square brackets to get following output
A = [{"name" => "xx", "status" => "true"}, {"name" => "yy", "status" => "true"}
Kindly assist

Since they're strings inside arrays, the [] is the representation Ruby does of it. Try accessing the first element for each key's value in those hashes:
a = [{"name" => ["xx"], "status" => ["true"]}, {"name" => ["yy"], "status" => ["true"]}]
p a.map { |hash| hash.transform_values(&:first) }
# [{"name"=>"xx", "status"=>"true"}, {"name"=>"yy", "status"=>"true"}]
Depending on your Ruby version, you might not have transform_values available. A simple each_with_object would work similarly in that case:
p a.map { |hash| hash.each_with_object({}) { |(k, v), hash| hash[k] = v.first } }
# [{"name"=>"xx", "status"=>"true"}, {"name"=>"yy", "status"=>"true"}]

Related

Flatten a hash and concatenate the keys

I have a hash like this:
{
"category" => ["sport", "gaming", "other"],
"duration" => 312,
"locations" => {
"688CQQ" => {"country" => "France", "state" => "Rhône-Alpes"},
"aUZCAQ" => {"country" => "France", "state" => "Île de France"}
}
}
I'd like to reduce it to a hash without nesting by flattening a value if the value is a hash. In the final values, I should have only integer, strings or arrays like this:
{
"category" => ["sport", "gaming", "other"],
"duration" => 312,
"locations_688CQQ_country" => "France",
"locations_688CQQ_state" => "Rhône-Alpes",
"locations_aUZCAQ_country" => "France",
"locations_aUZCAQ_state" => "Île de France"
}
I'd like a function that works with any level of nesting. How can I do that in ruby?
Adapted from https://stackoverflow.com/a/9648515/311744
def flat_hash(h, f=nil, g={})
return g.update({ f => h }) unless h.is_a? Hash
h.each { |k, r| flat_hash(r, [f,k].compact.join('_'), g) }
g
end
Here is a recursive approach where h is your hash.
def flat_hash(h)
h.reduce({}) do |a, (k,v)|
tmp = v.is_a?(Hash) ? flat_hash(v).map { |k2,v2| ["#{k}_#{k2}",v2]}.to_h : { k => v }
a.merge(tmp)
end
end
Adapted from https://stackoverflow.com/a/34271380/2066657
pardon me while I pile on, here.
class ::Hash
def flat_hash(j='_', h=self, f=nil, g={})
return g.update({ f => h }) unless h.is_a? Hash
h.each { |k, r| flat_hash(j, r, [f,k].compact.join(j), g) }
g
end
end
And now we can do
irb> {'foo' =>{'bar'=>{'squee'=>'woot'}}}.flat_hash('')
=> {"foobarsquee"=>"woot"}
You owe the Internet Oracle a '!' method.

How to generate direct access keys to nested hash which contains hash and arrays as values?

I want to compare two XML files where one is input and the other is output. I am converting both into a hash.
My idea is to get all the keys from the input XML converted to hash, and search each key in both the input and output hashes for their respective key/value pairs.
I have a hash:
{
"requisition_header" => {
"requested_by" => {"login" => "coupasupport"},
"department" => {"name" => "Marketing"},
"ship_to_address" => {"name" => "Address_1431693296"},
"justification" => nil,
"attachments" => [],
"requisition_lines" => [
{
"description" => "Cleaning Services for Building A",
"line_num" => 1,
"need_by_date" => 2010-09-23 07:00:00 UTC,
"source_part_num" => nil,
"supp_aux_part_num" => nil,
"unit_price" => #<BigDecimal:a60520c,'0.3E4',9(18)>,
"supplier" => {"name" => "amazon.com"},
"account" => {
"code" => "SF-Marketing-Indirect",
"account_type" => {"name" => "Ace Corporate"}
},
"currency" => {"code" => "USD"},
"payment_term" => {"code" => "Net 30"},
"shipping_term" => {"code" => "Standard"},
"commodity" => {"name" => "Marketing-Services"}
}
]
}
}
It is nested and all the values are not directly accessible.
I want a way to generate direct access to each value in the hash.
For example:
requisition_header.requested_by.login
will access "coupasupport".
requisition_header.department.name
will access "Marketing".
requisition_header.requisition_lines[0].description
will access "Cleaning Services for Building A".
requisition_header.requisition_lines[0].line_num
will access "1".
requisition_header.requisition_lines[0].need_by_date
will access "2010-09-23 07:00:00 UTC".
Each key built can be used to search for the value directly inside the hash.
That could be done with the following method, that translates the nested hash into nested OpenStructs:
require 'ostruct'
def deep_structify(hash)
result = {}
hash.each do |key, value|
result[key] = value.is_a?(Hash) ? deep_structify(value) : value
end if hash
OpenStruct.new(result)
end
hash = {"requisition_header"=>{"requested_by"=>{"login"=>"coupasupport"}, "department"=>{"name"=>"Marketing"}, "ship_to_address"=>{"name"=>"Address_1431693296"}, "justification"=>nil, "attachments"=>[], "requisition_lines"=>[{"description"=>"Cleaning Services for Building A", "line_num"=>1, "need_by_date"=>2010-09-23 07:00:00 UTC, "source_part_num"=>nil, "supp_aux_part_num"=>nil, "unit_price"=>#<BigDecimal:a60520c,'0.3E4',9(18)>, "supplier"=>{"name"=>"amazon.com"}, "account"=>{"code"=>"SF-Marketing-Indirect", "account_type"=>{"name"=>"Ace Corporate"}}, "currency"=>{"code"=>"USD"}, "payment_term"=>{"code"=>"Net 30"}, "shipping_term"=>{"code"=>"Standard"}, "commodity"=>{"name"=>"Marketing-Services"}}]}}
struct = deep_structify(hash)
struct.requisition_header.department.name
#=> "Marketing"
You can do it by overriding OpenStruct#new as well,
require 'ostruct'
class DeepStruct < OpenStruct
def initialize(hash=nil)
#table = {}
#hash_table = {}
if hash
hash.each do |k,v|
#table[k.to_sym] = (v.is_a?(Hash) ? self.class.new(v) : v)
#hash_table[k.to_sym] = v
new_ostruct_member(k)
end
end
end
def to_h
#hash_table
end
end
Now you can do:
require 'deep_struct'
hash = {"requisition_header"=>{"requested_by"=>{"login"=>"coupasupport"}, "department"=>{"name"=>"Marketing"}, "ship_to_address"=>{"name"=>"Address_1431693296"}, "justification"=>nil, "attachments"=>[], "requisition_lines"=>[{"description"=>"Cleaning Services for Building A", "line_num"=>1, "need_by_date"=>2010-09-23 07:00:00 UTC, "source_part_num"=>nil, "supp_aux_part_num"=>nil, "unit_price"=>#<BigDecimal:a60520c,'0.3E4',9(18)>, "supplier"=>{"name"=>"amazon.com"}, "account"=>{"code"=>"SF-Marketing-Indirect", "account_type"=>{"name"=>"Ace Corporate"}}, "currency"=>{"code"=>"USD"}, "payment_term"=>{"code"=>"Net 30"}, "shipping_term"=>{"code"=>"Standard"}, "commodity"=>{"name"=>"Marketing-Services"}}]}}
mystruct = DeepStruct.new hash
mystruct.requisition_header.requested_by.login # => coupasupport
mystruct.requisition_header.to_h # => {"requested_by"=>{"login"=>"coupasupport"}
You could use BasicObject#method_missing:
Code
class Hash
def method_missing(key,*args)
(args.empty? && key?(key)) ? self[key] : super
end
end
Example
hash = { animals: {
pets: { dog: "Diva", cat: "Boots", python: "Stretch" },
farm: { pig: "Porky", chicken: "Little", sheep: "Baa" }
},
finishes: {
tinted: { stain: "Millers", paint: "Oxford" },
clear: { lacquer: "Target", varnish: "Topcoat" }
}
}
hash.finishes.tinted.stain
#=> "Millers
hash.animals.pets.cat
#=> "Boots"
hash.animals.pets
#=> {:dog=>"Diva", :cat=>"Boots", :python=>"Stretch"}
hash.animals
#=> {:pets=>{:dog=>"Diva", :cat=>"Boots", :python=>"Stretch"},
# :farm=>{:pig=>"Porky", :chicken=>"Little", :sheep=>"Baa"}}
Reader challenge
There is a potential "gotcha" with this approach. I leave it to the reader to identify it. My example contains a clue. (Mind you, there may be other problems I haven't thought of.)

visiting hash with keys from array

I have a big hash with lots of nested key value pairs.
Eg.
h = {"foo" => {"bar" => {"hello" => {"world" => "result" } } } }
Now I want to access result and I have keys for that in array in proper sequence.
keys_arr = ["foo", "bar", "hello", "world"]
The motive is clear, I want to do following:
h["foo"]["bar"]["hello"]["world"]
# => "result"
But I don't know how to do this. I am currently doing:
key = '["' + keys_arr.join('"]["') + '"]'
eval("h"+key)
# => "result"
Which looks like a hack. Also it greatly reduces my ability to work with hash in real environment.
Please suggest alternate and better ways.
Using Enumerable#inject (or Enumerable#reduce):
h = {"foo" => {"bar" => {"hello" => {"world" => "result" } } } }
keys_arr = ["foo", "bar", "hello", "world"]
keys_arr.inject(h) { |x, k| x[k] }
# => "result"
UPDATE
If you want to do something like: h["foo"]["bar"]["hello"]["world"] = "ruby"
innermost = keys_arr[0...-1].inject(h) { |x, k| x[k] } # the innermost hash
innermost[keys_arr[-1]] = "ruby"
keys_arr.inject(h, :[])
will do
Another way:
h = {"foo" => {"bar" => {"hello" => {"world" => 10 } } } }
keys = ["foo", "bar", "hello", "world"]
result = h
keys.each do |key|
result = result[key]
end
puts result #=>10
If the key may not exist, see here:
Dealing with many [...] in Ruby

ruby db result set to array in a hash in a hash

I have a db query which returns results like:
db_result.each {|row| puts row}
{"IP"=>"1.2.3.4","Field1"=>"abc","Field2"=>"123"}
{"IP"=>"1.2.3.4","Field1"=>"abc","Field2"=>"234"}
{"IP"=>"1.2.3.4","Field1"=>"bcd","Field2"=>"345"}
{"IP"=>"3.4.5.6","Field1"=>"bcd","Field2"=>"456"}
{"IP"=>"3.4.5.6","Field1"=>"bcd","Field2"=>"567"}
And want to put it into a hash like:
{
"1.2.3.4" => {
"abc" => ["123", "234"],
"bcd" => "345"
},
"3.4.5.6" => {
"bcd" => ["456", "567"]
}
}
What I am currently doing is:
result_hash = Hash.new { |h, k| h[k] = {} }
db_result.each do |row|
result_hash[row["IP"]] = Hash.new { |h, k| h[k] = [] } unless result_hash.has_key? row["IP"]
result_hash[row["IP"]][row["Field1"]] << row["Field2"]
end
Which works, however was wondering if there is a neater way.
Consider this a peer-review. As a recommendation for processing and maintenance...
I'd recommend the data structure you want be a little more consistent.
Instead of:
{
"1.2.3.4" => {
"abc" => ["123", "234"],
"bcd" => "345"
},
"3.4.5.6" => {
"bcd" => ["456", "567"]
}
}
I'd recommend:
{
"1.2.3.4" => {
"abc" => ["123", "234"],
"bcd" => ["345"]
},
"3.4.5.6" => {
"abc" => [],
"bcd" => ["456", "567"]
}
}
Keep the same keys in each sub-hash, and make the values all be arrays. The code for processing that overall hash will be more straightforward and easy to follow.
I agree with Michael, there is nothing wrong with your method. The intent behind the code can be easily seen.
If you want to get fancy, here's one (of many) ways to do it:
x = [
{"IP"=>"1.2.3.4","Field1"=>"abc","Field2"=>"123"},
{"IP"=>"1.2.3.4","Field1"=>"abc","Field2"=>"234"},
{"IP"=>"1.2.3.4","Field1"=>"bcd","Field2"=>"345"},
{"IP"=>"3.4.5.6","Field1"=>"bcd","Field2"=>"456"},
{"IP"=>"3.4.5.6","Field1"=>"bcd","Field2"=>"567"}
]
y = x.inject({}) do |result, row|
new_row = result[row["IP"]] ||= {}
(new_row[row["Field1"]] ||= []) << row["Field2"]
result
end
I think this should yield the same time complexity as your method.

How do I convert a Ruby hash so that all of its keys are symbols?

I have a Ruby hash which looks like:
{ "id" => "123", "name" => "test" }
I would like to convert it to:
{ :id => "123", :name => "test" }
hash = {"apple" => "banana", "coconut" => "domino"}
Hash[hash.map{ |k, v| [k.to_sym, v] }]
#=> {:apple=>"banana", :coconut=>"domino"}
#mu is too short: Didn't see word "recursive", but if you insist (along with protection against non-existent to_sym, just want to remind that in Ruby 1.8 1.to_sym == nil, so playing with some key types can be misleading):
hash = {"a" => {"b" => "c"}, "d" => "e", Object.new => "g"}
s2s =
lambda do |h|
Hash === h ?
Hash[
h.map do |k, v|
[k.respond_to?(:to_sym) ? k.to_sym : k, s2s[v]]
end
] : h
end
s2s[hash] #=> {:d=>"e", #<Object:0x100396ee8>=>"g", :a=>{:b=>"c"}}
If you happen to be in Rails then you'll have symbolize_keys:
Return a new hash with all keys converted to symbols, as long as they respond to to_sym.
and symbolize_keys! which does the same but operates in-place. So, if you're in Rails, you could:
hash.symbolize_keys!
If you want to recursively symbolize inner hashes then I think you'd have to do it yourself but with something like this:
def symbolize_keys_deep!(h)
h.keys.each do |k|
ks = k.to_sym
h[ks] = h.delete k
symbolize_keys_deep! h[ks] if h[ks].kind_of? Hash
end
end
You might want to play with the kind_of? Hash to match your specific circumstances; using respond_to? :keys might make more sense. And if you want to allow for keys that don't understand to_sym, then:
def symbolize_keys_deep!(h)
h.keys.each do |k|
ks = k.respond_to?(:to_sym) ? k.to_sym : k
h[ks] = h.delete k # Preserve order even when k == ks
symbolize_keys_deep! h[ks] if h[ks].kind_of? Hash
end
end
Note that h[ks] = h.delete k doesn't change the content of the Hash when k == ks but it will preserve the order when you're using Ruby 1.9+. You could also use the [(key.to_sym rescue key) || key] approach that Rails uses in their symbolize_keys! but I think that's an abuse of the exception handling system.
The second symbolize_keys_deep! turns this:
{ 'a' => 'b', 'c' => { 'd' => { 'e' => 'f' }, 'g' => 'h' }, ['i'] => 'j' }
into this:
{ :a => 'b', :c => { :d => { :e => 'f' }, :g => 'h' }, ['i'] => 'j' }
You could monkey patch either version of symbolize_keys_deep! into Hash if you really wanted to but I generally stay away from monkey patching unless I have very good reasons to do it.
If you are using Rails >= 4 you can use:
hash.deep_symbolize_keys
hash.deep_symbolize_keys!
or
hash.deep_stringify_keys
hash.deep_stringify_keys!
see http://apidock.com/rails/v4.2.1/Hash/deep_symbolize_keys
Just in case you are parsing JSON, from the JSON docs you can add the option to symbolize the keys upon parsing:
hash = JSON.parse(json_data, symbolize_names: true)
Victor Moroz provided a lovely answer for the simple recursive case, but it won't process hashes that are nested within nested arrays:
hash = { "a" => [{ "b" => "c" }] }
s2s[hash] #=> {:a=>[{"b"=>"c"}]}
If you need to support hashes within arrays within hashes, you'll want something more like this:
def recursive_symbolize_keys(h)
case h
when Hash
Hash[
h.map do |k, v|
[ k.respond_to?(:to_sym) ? k.to_sym : k, recursive_symbolize_keys(v) ]
end
]
when Enumerable
h.map { |v| recursive_symbolize_keys(v) }
else
h
end
end
Try this:
hash = {"apple" => "banana", "coconut" => "domino"}
# => {"apple"=>"banana", "coconut"=>"domino"}
hash.tap do |h|
h.keys.each { |k| h[k.to_sym] = h.delete(k) }
end
# => {:apple=>"banana", :coconut=>"domino"}
This iterates over the keys, and for each one, it deletes the stringified key and assigns its value to the symbolized key.
If you're using Rails (or just Active Support):
{ "id" => "123", "name" => "test" }.symbolize_keys
Starting with Ruby 2.5 you can use the transform_key method.
So in your case it would be:
h = { "id" => "123", "name" => "test" }
h.transform_keys!(&:to_sym) #=> {:id=>"123", :name=>"test"}
Note: the same methods are also available on Ruby on Rails.
Here's a Ruby one-liner that is faster than the chosen answer:
hash = {"apple" => "banana", "coconut" => "domino"}
#=> {"apple"=>"banana", "coconut"=>"domino"}
hash.inject({}){|h,(k,v)| h[k.intern] = v; h}
#=> {:apple=>"banana", :coconut=>"domino"}
Benchmark results:
n = 100000
Benchmark.bm do |bm|
bm.report { n.times { hash.inject({}){|h,(k,v)| h[k.intern] = v; h} } }
bm.report { n.times { Hash[hash.map{ |k, v| [k.to_sym, v] }] } }
end
# => user system total real
# => 0.100000 0.000000 0.100000 ( 0.107940)
# => 0.120000 0.010000 0.130000 ( 0.137966)
I'm partial to:
irb
ruby-1.9.2-p290 :001 > hash = {"apple" => "banana", "coconut" => "domino"}
{
"apple" => "banana",
"coconut" => "domino"
}
ruby-1.9.2-p290 :002 > hash.inject({}){ |h, (n,v)| h[n.to_sym] = v; h }
{
:apple => "banana",
:coconut => "domino"
}
This works because we're iterating over the hash and building a new one on the fly. It isn't recursive, but you could figure that out from looking at some of the other answers.
hash.inject({}){ |h, (n,v)| h[n.to_sym] = v; h }
You can also extend core Hash ruby class placing a /lib/hash.rb file :
class Hash
def symbolize_keys_deep!
new_hash = {}
keys.each do |k|
ks = k.respond_to?(:to_sym) ? k.to_sym : k
if values_at(k).first.kind_of? Hash or values_at(k).first.kind_of? Array
new_hash[ks] = values_at(k).first.send(:symbolize_keys_deep!)
else
new_hash[ks] = values_at(k).first
end
end
new_hash
end
end
If you want to make sure keys of any hash wrapped into arrays inside your parent hash are symbolized, you need to extend also array class creating a "array.rb" file with that code :
class Array
def symbolize_keys_deep!
new_ar = []
self.each do |value|
new_value = value
if value.is_a? Hash or value.is_a? Array
new_value = value.symbolize_keys_deep!
end
new_ar << new_value
end
new_ar
end
end
This allows to call "symbolize_keys_deep!" on any hash variable like this :
myhash.symbolize_keys_deep!
def symbolize_keys(hash)
new={}
hash.map do |key,value|
if value.is_a?(Hash)
value = symbolize_keys(value)
end
new[key.to_sym]=value
end
return new
end
puts symbolize_keys("c"=>{"a"=>2,"k"=>{"e"=>9}})
#{:c=>{:a=>2, :k=>{:e=>9}}}
Here's my two cents,
my version of symbolize_keys_deep! uses the original symbolize_keys! provided by rails and just makes a simple recursive call to Symbolize sub hashes.
def symbolize_keys_deep!(h)
h.symbolize_keys!
h.each do |k, v|
symbolize_keys_deep!(v) if v.is_a? Hash
end
end
Facets' Hash#rekey is also a worth mentioning.
Sample:
require 'facets/hash/rekey'
{ "id" => "123", "name" => "test" }.deep_rekey
=> {:id=>"123", :name=>"test"}
There is also a recursive version:
require 'facets/hash/deep_rekey'
{ "id" => "123", "name" => {"first" => "John", "last" => "Doe" } }.deep_rekey
=> {:id=>"123", :name=>{:first=>"John", :last=>"Doe"}}
Here's a little recursive function to do a deep symbolization of the keys:
def symbolize_keys(hash)
Hash[hash.map{|k,v| v.is_a?(Hash) ? [k.to_sym, symbolize_keys(v)] : [k.to_sym, v] }]
end

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