I have products table that each of the product has many orders,product.php
public function orders()
{
return $this->hasMany(Order::class,'product_id');
}
I can get products that order by order_count with this code:
$products = Product::withCount('orders')->orderBy('orders_count', 'desc')->get();
Now I want to get products in controller that their orders count is bigger than 5,
How I can do it?
One way to do this would to use whereHas():
$products = Product::withCount('orders')
->whereHas('orders', null, '>', 5)
->orderBy('orders_count', 'desc')
->get();
I don't think it's mentioned in the docs but you don't have to pass a closure as the 2nd param, and the 3rd and 4th can be used to pass the operator and the count.
Alternatively, you could use having() instead:
$products = Product::withCount('orders')
->having('orders_count', '>', 5)
->orderBy('orders_count', 'desc')
->get();
You can use mapping on your collection to filter out records e.g. :`
$collection = collect($products)->map(function ($product) {
return $product->orders->count() > 5;
})
->reject(function ($name) {
return $product->orders->count() < 5;
});`
This is just an example, you can put more conditions if required.
Hope this helps.
The below code should give you just the orders with a count greater than 5
$products = Product::withCount('orders')->where('orders_count', '>', 5)->orderBy('orders_count', 'desc')->get();
Adding ->where() should do it.
Hope that helps.
Update
Try
->whereRaw('count("orders.id") > 5')
This should work to get products with more than 5 orders.
Related
I have have 3 tables in my projects they are:
products(can have Multiple Variants)
variants (belongsto product)
product_attributes (this have product_id,attribute_id,value_id)
I want to filter variants from a product by value ids thats comes from form request as example (1,2,6)
I have tried like this:
$poruduct_id = $request->product_id;
$value_ids = $request->value_ids;
$searched_variants = Variant::whereHas('product.attributeValues', function ($query) use ($value_ids, $product_id) {
$query->whereIn('value_id', [$value_ids]);
})->where('product_id', $product_id)->get();
dd($searched_variants);
But the problem is the query returns all records from the product. What is the solution to filter exactly the values that the product Variants have?
Thank you.
-UPDATED-
I have tried like this but nothing changed
$searched_variants = Variant::select('product_id')->whereHas('product.attributeValues', function ($query) use ($value_ids, $product_id) {
$query->whereIn('value_id', [$value_ids]);
})->groupBy('product_id')
->havingRaw('COUNT(*) = ?', [count((array) $value_ids)])
->get();
-**FİNALLY SOLUTİON**-
I made it like this : I get the value code that is in for example Large the code is L
get all the codes to controller and executed this query ı hope this helps someone
1.$value_codes=$request->value_codes;
2.$value_codes_array=explode(',',$value_codes);
3.$product_id=$request->product_id;
4.$searchValues = preg_split('/,/', $value_codes_array, -1, PREG_SPLIT_NO_EMPTY);
$searchValues = preg_split('/,/', $value_idss, -1, PREG_SPLIT_NO_EMPTY);
$variants= Variant::where(function ($q) use ($searchValues) {
foreach ($searchValues as $value) {
$q->orWhere('sku', 'like', "%-{$value}")
->orWhere('sku', 'like', "%-{$value}-%")
->orWhere('sku', 'like', "{$value}-%");
}
})->where('product_id',$product_id)->get();
dd($variants);
If you have n variants to one product, you query should be like:
Product Model
public function variants: HasMany relationships
//usage
$produtc->variants->and here the query function
You need to use it in this way, it should work:
$productId = $request->product_id;
$valueIds = $request->value_ids;
$searchedVariants = Variant::whereHas('product.attributeValues', function ($query) use ($valueIds) {
$query->distinct()->whereIn('value_id', $valueIds);
}, '=', count($valueIds))->where('product_id', $productId)->get();
I have products , orders and third pivot table product_order(product_id , order_id), I need to count the orders of the product based on created_at
my shut:
public function product_chart(Product $product)
{
$orders = $product->whereHas('orders', function ($query) {
$query->whereMonth('created_at', '04');
})->count();
dd($orders);
}
The output gives the number of products :(
of course, I have a relation in a product called (orders) and in Order called (products)
So I need to count the orders of the product based on the created_at of order!
That's because you are counting the products.
You can simply do this:
$ordersCount = $product->orders()->count();
But since you are applying some conditions, you need to append the where clause:
$ordersCount = $product->orders()->whereMonth('created_at', '04')->count();
Also there's a simpler way doing it according to Laravel Documentation:
use Illuminate\Database\Eloquent\Builder;
$posts = App\Post::withCount(['votes', 'comments' => function (Builder $query) {
$query->where('content', 'like', 'foo%');
}])->get();
echo $posts[0]->votes_count;
echo $posts[0]->comments_count;
I would like to order result of eloquent by field on the other related table.
I have users table. Every user has one profile. Profile has sponsored (which is boolean) field. So when I would like to get all users, I want to display first sponsored users, then non sponsored.
public function profile(){
return $this->hasOne('App\Doctor');
}
There are two ways:
1)You have to join tables,
User::join('profiles','users.id','=','profile.user_id')->orderBy('sponsored','DESC')->get()
2)Order by eager loading
User::with(array('profile' => function($query) {
$query->orderBy('sponsored', 'DESC');
}))
->get();
Try this one
User::leftJoin('profile', 'user.id', '=', 'profile.user_id')
->orderBy('profile.sponsored', 'ASC')
->get();
I highly recommend not using table joins as it would fail you on the scale.
A better solution is to get users, get their profiles and then sort them using laravel collection methods.
You can use this sample to achieve this solution.
//get all users
$users = User::all();
//extract your users Ids
$userIds = $users->pluck('id')->toArray();
//get all profiles of your user Ids
$profiles = Profile::whereIn('user_id', $userIds)->get()->keyBy('user_id');
//now sort users based on being sponsored or not
$users = $users->sort(function($item1, $item2) use ($profiles) {
if($profiles[$item1->id]->sponsored == 1 && $profiles[$item2->id]->sponsored == 1){
return 0;
}
if($profiles[$item1->id]->sponsored == 1) return 1;
return -1;
});
You can check this link which explains on laravel collection sorts.
$order = 'desc';
$users = User::join('profile', 'users.id', '=', 'profile.id')
->orderBy('profile.id', $order)->select('users.*')->get();
I have 2 models in my app:
1. Customer.php
2. Car.php
Now I would like to run a query that returns all customers that have less than 2 cars. Where 2 is a number that can be changed by the user.
I have tried this but it didn't work, it just returns all customer records:
$customers = Customer::whereHas("cars", function($query) {
$query->selectRaw("count(*) < ?", [2]);
})
->get();
Edit:
The two models are linked in a pivot table, meaning A customer can have more than 1 car and a Car can belong to more than 1 customer.
Use this:
$customers = Customer::withCount('cars')
->having('cars_count', '<', 2)
->get();
So , here is the result.
Relation in model Customer.php
public function cars()
{
return $this->belongsToMany('App\Car','car_customer','car_id','customer_id');
}
Query to get all customers with N cars:
$userInput = 2;
$data = Customer::with('cars')
->withCount('cars')
->has('cars', '<', $userInput)
->orderBy('cars_count', 'desc')
->get();
Where the $userInput is your 'N'.
This is the best way:
$customers = Customer::has('cars','<', 2)->get();
Have you tried this approach?
$input = 2;
$customers = Customer::whereHas("cars", function($query) use ($input) {
$query->where(DB::raw("count(cars.id)"), "<", DB::raw($input))
})->get();
I have this controller which grabs posts from a post table.
Every post in the posts table have the relation "hasMany" with another table likes.
Controller:
public function getDashboard(){
$posts = Post::orderBy('created_at', 'desc')->get();
return view('dashboard', ['posts' => $posts]);
}
I'd like to replace 'created at' with something like:
$post->likes->sum(like)
Don't know how to write the right syntax though.
EDIT:
Here are the tables.
Posts
--id
--body
Likes
--id
--post_id
--like
The column like can have the value 1 or -1.
I'd like to order on the summation of that column for each post.
So a post with one dislike(-1) and one like(1) will have the aggregated value of 0, hence will be placed after a post with one like(1).
You can use withCount() for this as:
Post::withCount('likes')->orderBy('likes_count')->get()
withCount() will place a {relation}_count column on your resulting
models
Update
Post::withCount(['likes' => function($q) {
$q->where('like', 1)
}])
->orderBy('likes_count')
->get()
Update2
You can use sortByDesc() to sort your collection as:
$posts = Post::get();
$posts = $posts->sortByDesc(function ($post) {
return $post->likes->sum('like');
});
If you want to sum column value from relationship and then sort records.
$users = User::addSelect(['likes' => Post::selectRaw('sum(likes) as total_likes')
->whereColumn('user_id', 'useres.id')
->groupBy('user_id')
])
->orderBy('likes', 'DESC')
->get()
->toArray();
Or
use below
$users = User::select("*",
\DB::raw('(SELECT SUM(likes) FROM likes_table WHERE likes_table.user_id = users.id) as tolal_likes'))
->orderBy('likes', 'DESC')
->get()
->toArray();