I would like to order result of eloquent by field on the other related table.
I have users table. Every user has one profile. Profile has sponsored (which is boolean) field. So when I would like to get all users, I want to display first sponsored users, then non sponsored.
public function profile(){
return $this->hasOne('App\Doctor');
}
There are two ways:
1)You have to join tables,
User::join('profiles','users.id','=','profile.user_id')->orderBy('sponsored','DESC')->get()
2)Order by eager loading
User::with(array('profile' => function($query) {
$query->orderBy('sponsored', 'DESC');
}))
->get();
Try this one
User::leftJoin('profile', 'user.id', '=', 'profile.user_id')
->orderBy('profile.sponsored', 'ASC')
->get();
I highly recommend not using table joins as it would fail you on the scale.
A better solution is to get users, get their profiles and then sort them using laravel collection methods.
You can use this sample to achieve this solution.
//get all users
$users = User::all();
//extract your users Ids
$userIds = $users->pluck('id')->toArray();
//get all profiles of your user Ids
$profiles = Profile::whereIn('user_id', $userIds)->get()->keyBy('user_id');
//now sort users based on being sponsored or not
$users = $users->sort(function($item1, $item2) use ($profiles) {
if($profiles[$item1->id]->sponsored == 1 && $profiles[$item2->id]->sponsored == 1){
return 0;
}
if($profiles[$item1->id]->sponsored == 1) return 1;
return -1;
});
You can check this link which explains on laravel collection sorts.
$order = 'desc';
$users = User::join('profile', 'users.id', '=', 'profile.id')
->orderBy('profile.id', $order)->select('users.*')->get();
Related
I have comics and categories related many to many through pivot tables. I use join and groupBy caterories.id but it doesn't group categories same comics id.
If I do not use the group
$result = DB::table('comics')
->select('comics.name','categories.title')
->join('category_comic', 'comics.id', '=', 'category_comic.comic_id')
->join('categories', 'category_comic.category_id', '=', 'categories.id')
->get();
I want each comic group category
(source: uphinh.org)
First of all
try tou use Laravel Eloquent Relationship and its really cool and very easy to use
In Eloquent Method
In Comics Model
add relationship function
public function cat(){
return $this->hasOne(ComicCategory::class,'id','comic_id'); //ComicCategory::class is your category_comic model
}
Then you just need you Comic Model to get a group of your category com
$result = Comic::with('cat')->get(); //Commic is your model
In query Builder, you need to group manual using foreach
$result = DB::table('comics')
->select('comics.name','categories.title')
->join('category_comic', 'comics.id', '=', 'category_comic.comic_id')
->join('categories', 'category_comic.category_id', '=', 'categories.id')
->get();
$result = json_decode(json_encode($result), TRUE);
$new_result = [];
foreach($result as $row){
$arr[$row['id']]['name'] = $row['name'];
$arr[$row['id']]['cat'][] = $row['title'];
}
and finally rearange the key
$new_result = array_values($new_result );
PS : thats array method, i never group using object method
Trying to get this query to work in eloquent
A user can be in multiple teams however I want to generate a list of users NOT in a specific team. The following SQL query works if executed directly but would like to make it cleaner by converting it to eloquent
SELECT * FROM users LEFT JOIN team_members ON team_members.member_id = users.id WHERE NOT EXISTS ( SELECT * FROM team_members WHERE team_members.member_id = users.id AND team_members.team_id = $team_id )
This should provide a list of all the users that are not members of team $team_id
This is a guess ad you do not give much info on your Eloqent models but here is a hint of where to go:
User::doesnthave('teamMembers', function($builder) use($team_id){
return $builder->where('team_members.team_id');
});
That is assuming you have a "User" model with a "teamMembers" relationship setup on it
You may have a closer look in the Laravel docs for doesntHave
Laravel 5.8
Let's assume you have model name "User.php"
& there is method name "teamMembers" in it.
Basic
$users = User::doesntHave('teamMembers')->get();
Advance
use Illuminate\Database\Eloquent\Builder;
$users = User::whereDoesntHave('teamMembers', function (Builder $query) {
$query->where('id', '=', {your_value});
})->get();
You can find details description in this link >>
https://laravel.com/docs/5.8/eloquent-relationships#querying-relationship-absence
Laravel 5.2
Example:
DB::table('users')
->whereExists(function ($query) {
$query->select(DB::raw(1))
->from('orders')
->whereRaw('orders.user_id = users.id');
})
->get();
Check this link for advance where clause:
https://laravel.com/docs/5.2/queries#advanced-where-clauses
You can use below example
$list = User::leftJoin('users', 'users.id', '=', 'team_members.member_id')
->whereNotExists(function ($query) use ($team_id) {
$query->from('team_members')
->whereRaw('team_members.member_id = users.id')
->where('team_members.team_id', '=', $team_id);
})
->get();
I have products table that each of the product has many orders,product.php
public function orders()
{
return $this->hasMany(Order::class,'product_id');
}
I can get products that order by order_count with this code:
$products = Product::withCount('orders')->orderBy('orders_count', 'desc')->get();
Now I want to get products in controller that their orders count is bigger than 5,
How I can do it?
One way to do this would to use whereHas():
$products = Product::withCount('orders')
->whereHas('orders', null, '>', 5)
->orderBy('orders_count', 'desc')
->get();
I don't think it's mentioned in the docs but you don't have to pass a closure as the 2nd param, and the 3rd and 4th can be used to pass the operator and the count.
Alternatively, you could use having() instead:
$products = Product::withCount('orders')
->having('orders_count', '>', 5)
->orderBy('orders_count', 'desc')
->get();
You can use mapping on your collection to filter out records e.g. :`
$collection = collect($products)->map(function ($product) {
return $product->orders->count() > 5;
})
->reject(function ($name) {
return $product->orders->count() < 5;
});`
This is just an example, you can put more conditions if required.
Hope this helps.
The below code should give you just the orders with a count greater than 5
$products = Product::withCount('orders')->where('orders_count', '>', 5)->orderBy('orders_count', 'desc')->get();
Adding ->where() should do it.
Hope that helps.
Update
Try
->whereRaw('count("orders.id") > 5')
This should work to get products with more than 5 orders.
i have three table in mysql:
1-users
table of users
2-projects
table of project
3-project_user
there is id and project_id and user_id for relation
there is two model : user and project
the relation between these table are belongsToMany
when a project create maybe one project define for two person
NOW how can i show the project of each person?
Assuming you properly defined your relationships, do
$users = User::with('projects')->get();
//show each user projects
foreach($users as $user) {
echo $user->projects;
}
//Getting project users
$projects = Project::with('users')->get();
This will give you projects list, in each list you can see which user has access or not.
Updates
Taking project with specified user_id
$projects = Project::with(['users' => function ($query) use ($user_id) {
$query->where('user_id', '=', $user_id);
}])->get();
New code
Or try to to get the user
$user = User::with('projects')->where('id', $user_id)->first();
Or via projects, constraining by user_id
$projects = Project::with('users')->whereHas('users', function ($query) use ($user_id) {
$query->where($user_id);
})->get();
the way i solve it:
//save user_id
$user_id = $request->id;
//select in project_user where user_id = $user_id
$project_user = DB::table('project_user')->where('user_id', '=', $user_id)->get();
//create an empty array
$p_id = array();
//fill empty array with project_id
foreach($project_user as $pro) {
$p_id[] = $pro->project_id;
}
//select code and id in project table where id = one of that [$p_id] array
$data = Project::select('code','id')->whereIn('id', $p_id)->get();
//return your data in json
return response()->json($data);
As far as I understood your question, you want to query Project as per user_id. Here is how you do it.
Project::with('users')->whereHas('users', function ($query) use ($user_id_array) {
$query->whereIn('id',$user_id_array);
})->get();
This will give you projects whose user_id are from $user_id_array. Let me know if you need any further help.
I have a query like:
$users = User::with('role')
->get();
How can I order the results by the related table, so it's something like:
$users = User::with('role')
->orderBy('role.id', 'DESC')
->get();
Is there a way to do it without joining the role table (since we're already doing with('role')?
what are you trying to order. the list of users or the roles.
if you are trying to sort the users base on role do.
$users = User::with('role')->orderBy('role_id', 'DESC')
->get();
if you are trying to sort the roles of the user then pocho's answer is correct.
$users = User::with(array('role' => function($query)
{
$query->orderBy('id', 'DESC');
}))->get();
From the documentation:
$users = User::with(array('role' => function($query)
{
$query->orderBy('id', 'DESC');
}))->get();
You can also do a raw query using DB::raw like in the examples here.
You can always sort the returned collection quite easily...
$users = User::with('role')
->get()
->sortBy(function($user, $key)
{
return $user->role->id;
});
This is assuming a user hasOne or belongsTo a role. If your relationship is something that can return multiple roles, then it becomes a bit more complex because you need to decide which of the user's roles to sort by.