I am not able order by field_name DESC with null last option. Since the default behaviour on DESC is nulls first, I would like them to be pushed at last.
"$orderby": {"ENAME":"DESC NULLS LAST"}
Thanks in advance
How about such a trick? If ENAME is NULL, use CHR(ASCII(1E4)) - something that is, hopefully, far enough to avoid valid first characters in actual names in your database.
SQL> with test (id, ename) as
2 (select 1, 'Little' from dual union
3 select 2, null from dual union
4 select 3, 'Zoot' from dual
5 )
6 select *
7 from test
8 order by decode(ename, null, chr(ascii(1E4)), ename) desc;
ID ENAME
---------- ------
2
3 Zoot
1 Little
SQL>
Related
I am new to oracle thus this question.
There is a table already existed and I have added a new column to it.
There are 5 rows and I do not want to use update table with where clause to insert the values one by one in the new column. Is there a statement like INSERT ALL to insert the values into the new column in one shot ?
Thanks
You can also use something like below which in-effect I would say is multiple update only, wrapped in single statement.
SQL> select * from test_upd;
ID1 ID2
---------- ----------
1
2
3
4
SQL> update test_upd a set a.id2 =
2 (select
3 case
4 when id1=1 then 100
5 when id1=2 then 200
6 when id1=3 then 300
7 else 5000 end
8 from test_upd b
9 where a.id1=b.id1);
4 rows updated.
SQL> select * from test_upd;
ID1 ID2
---------- ----------
1 100
2 200
3 300
4 5000
Use a MERGE statement:
MERGE INTO your_table dst
USING (
SELECT 1 AS id, 'aaa' AS newvalue FROM DUAL UNION ALL
SELECT 2, 'bbb' FROM DUAL UNION ALL
SELECT 3, 'ccc' FROM DUAL UNION ALL
SELECT 4, 'ddd' FROM DUAL UNION ALL
SELECT 5, 'eee' FROM DUAL
) src
ON (dst.id = src.id)
WHEN MATCHED THEN
UPDATE SET value = src.newvalue;
Which, if you have the table:
CREATE TABLE your_table (id, value) AS
SELECT 1, CAST(NULL AS VARCHAR2(3)) FROM DUAL UNION ALL
SELECT 2, NULL FROM DUAL UNION ALL
SELECT 3, NULL FROM DUAL UNION ALL
SELECT 4, NULL FROM DUAL UNION ALL
SELECT 5, NULL FROM DUAL;
Then, after the MERGE, the table contains:
ID
VALUE
1
aaa
2
bbb
3
ccc
4
ddd
5
eee
db<>fiddle here
I have a table with data in below format
COURSE
[]
["12345"]
["12345","7890"
I want to extract the data between [] but without "
So, my output would be in below format
COURSE
12345
12345, 7890
I tried the below code which works fine for first 3 rows
select REGEXP_SUBSTR (COURSE,
'"([^"]+)"',
1,
1,
NULL,
1) from TEST;
But 4th row only results in 12345.
Why not simple translate?
SQL> with test (course) as
2 (select '[]' from dual union
3 select null from dual union
4 select '["12345"]' from dual union
5 select '["12345","7890"]' from dual
6 )
7 select course,
8 translate(course, 'a[]"', 'a') result
9 from test;
COURSE RESULT
---------------- -----------------------------------------
["12345","7890"] 12345,7890
["12345"] 12345
[]
SQL>
Currently, I have a table MY_TABLE like below:
ID ACCT_TYPE CREDIT_AMT DEBIT_AMT
-- --------- ---------- ---------
1 CDT_01 4 (null)
1 DBT_01 (null) 6
One ID can have multiple ACCT_TYPE like above, and each type has its own amount.
I want to just select the row which has ACCT_TYPE like 'CDT_%' but also the total_amount column which is the total of credit_amt and debit_amt column for the same ID.
My expected output like below:
ID ACCT_TYPE TOTAL_AMT
-- --------- ---------
1 CDT_01 10
I tried with this select statement below but it's no use, I think it's because of different ACCT_TYPE:
Select ID, ACCT_TYPE, SUM(NVL(CREDIT_AMT, 0) + NVL(DEBIT_AMT, 0)) TOTAL_AMT
FROM MY_TABLE WHERE ACCT_TYPE LIKE 'CDT_%' GROUP BY ID, ACCT_TYPE;
Here is the output of the select statement above:
ID ACCT_TYPE TOTAL_AMT
-- --------- ---------
1 CDT_01 4
I just begin to learn some query so I don't know is it really possible to get my expected output.
One way to do it is like below:
with inputs (ID, ACCT_TYPE, CREDIT_AMT, DEBIT_AMT) as
(
select 1, 'CDT_01', 4, null from dual union all
select 1, 'DBT_01', null, 6 from dual
),
prep as
(
select t.*, sum(nvl(credit_amt,0)) over (partition by id) + sum(nvl(debit_amt,0)) over (partition by id) as sum_per_id
from inputs t
)
select id, acct_type, sum_per_id
from prep
where acct_type like 'CDT_%';
Output:
A correlated subquery might be one option; sample data (thank you, #Ranagal) in lines #1 - 5; query that does the job begins at line #6.
SQL> with inputs (ID, ACCT_TYPE, CREDIT_AMT, DEBIT_AMT) as
2 (
3 select 1, 'CDT_01', 4, null from dual union all
4 select 1, 'DBT_01', null, 6 from dual
5 )
6 select a.id,
7 a.acct_type,
8 (select sum(nvl(b.credit_amt, 0)) +
9 sum(nvl(b.debit_amt , 0))
10 from inputs b
11 where b.id = a.id
12 ) total_amt
13 from inputs a
14 where acct_type like 'CDT%';
ID ACCT_T TOTAL_AMT
---------- ------ ----------
1 CDT_01 10
SQL>
I have a table which has data as:
id payor_name
---------------
1 AETNA
2 UMR
3 CIGNA
4 METLIFE
4 AETNAU
5 ktm
6 ktm
Id and payor_name are two columns.So,
My expected output is:
id payor_name
---------------
1 AETNA
2 UMR
3 CIGNA
4 METLIFE
4 AETNAU
6 ktm ...> I want to change the id of this row to be 6 from 5.
6 ktm
I want one to one mapping between id and payor_name.So,this is what I tried:
MERGE INTO offc.payor_collec A
USING (select id from offc.payor_collec where payor_name in(
select payor_name from offc.payor_collec group by payor_name having count(distinct id)>=2)) B
ON (A.id=B.id)
WHEN MATCHED THEN
UPDATE SET A.id=B.id
But when I compiled I got error as:
Error at line 1
ORA-38104: Columns referenced in the ON Clause cannot be updated: "A"."ID"
Id is number where as payor_name is varchar2.
How can I achieve this result?
MERGE works, but slightly different than your code.
SQL> select * from test;
ID PAYOR
---------- -----
1 aetna
2 umr
5 ktm
6 ktm
SQL> merge into test t
2 using (select max(t1.id) id,
3 t1.payor_name
4 from test t1
5 group by t1.payor_name
6 ) x
7 on (x.payor_name = t.payor_name)
8 when matched then update set
9 t.id = x.id;
4 rows merged.
SQL> select * from test;
ID PAYOR
---------- -----
1 aetna
2 umr
6 ktm
6 ktm
SQL>
Use a correlated subquery:
UPDATE PAYOR_COLLEC pc
SET pc.ID = (SELECT MAX(pc2.ID)
FROM PAYOR_COLLEC pc2
WHERE pc2.PAYOR_NAME = pc.PAYOR_NAME)
dbfiddle here
You can use a MERGE statement, as you tried and as Littlefoot has shown.
You can also use a correlated subquery as Bob Jarvis has shown, but that will be quite inefficient.
Many Oracle developers are unaware that you can also update through a join. Worse, there are many who say "there is no such thing in Oracle."
In your problem, you need to join your table to an aggregate query (picking just the max id for each payor_name) and the join is on the group by column in the aggregate. This already guarantees that the join column will be unique in the right-hand table; that is all Oracle needs to allow the update through join.
Here is a complete example, starting with the create table statement, then the update and then showing the table after the update. Note that I don't need any constraints (like primary key, not null, unique, etc.) or indexes on the base table. If they do exist, so much the better, but the solution works in the most general case.
create table t (id, payor_name) as
select 1, 'AETNA' from dual union all
select 2, 'UMR' from dual union all
select 3, 'CIGNA' from dual union all
select 4, 'METLIFE' from dual union all
select 4, 'AETNAU' from dual union all
select 5, 'ktm' from dual union all
select 6, 'ktm' from dual;
Table T created.
update
(
select id, payor_name, max_id
from t inner join
(select max(id) as max_id, payor_name from t group by payor_name)
using (payor_name)
)
set id = max_id where id != max_id
;
1 row updated.
select * from t;
ID PAYOR_NAME
----- ----------
1 AETNA
2 UMR
3 CIGNA
4 METLIFE
4 AETNAU
6 ktm
6 ktm
Notice the where clause at the end of the update statement, too. You don't want to update rows to their pre-existing value; that will still generate undo and redo data (although I understand that Oracle has changed that in more recent versions - it now doesn't generate undo and redo unless a row did indeed change). I assume ID is NOT NULL - otherwise you should rewrite the where clause as
where decode(id, max_id, 0) is null
or equivalent
Good day!
Folks, I have an issue when I want to compare multiple values.
For example I have the Log Data for today, 23rd April. This is related to yesterday's job(22nd April) with specific name.
In my comparison, I should select all logs with their job dates with this specific name. I say that logs' dates must be bigger than our job with this specific name. There are other jobs earlier done with this specific name.
How can I choose only the last nearest one?
Please could you advise?
For example:
Table: Job
id
name
job start date
Table: Log
id
type
Log date
We have 3 different jobs with name "Coding"
and 3 different logs.
Jobs:
1, coding, 21-Apr-10
2, coding, 21-Apr-14
3, coding, 21-Apr-18
Logs:
1. 1, error, 23-Apr-10
2. 2, error, 23-Apr-15
3. 3, error, 20-Apr-18
4. 4, error, 23-Apr-18
And there, when I want to execute logs and jobs, I must look to their dates. For example, error with id 1 is related to job with id 1, because log's date is bigger than job's date.
Or also, log with id 3 should be related to job with id 2.
Generally speaking, something like this might do the job:
select *
from some_table t
where t.date_column = (select max(t1.date_column)
from some_table t1
where t1.id = t.id
)
If it doesn't, please, provide test case (CREATE TABLE and INSERT INTO sample data, which would be the input), and - based on that, tell us what you expect as the output.
[EDIT]
This is somewhat strange data model; jobs and logs aren't related by anything but dates ... anyway, here's code that returns what you described (at least, how I understood it).
SQL> with tjob (id, name, job_start) as
2 (select 1, 'coding', to_date('21.04.2010', 'dd.mm.yyyy') from dual union
3 select 2, 'coding', to_date('21.04.2014', 'dd.mm.yyyy') from dual union
4 select 3, 'coding', to_date('21.04.2018', 'dd.mm.yyyy') from dual
5 ),
6 logs (id, type, log_date) as
7 (select 1, 'error', to_date('23.04.2010', 'dd.mm.yyyy') from dual union
8 select 2, 'error', to_date('23.04.2015', 'dd.mm.yyyy') from dual union
9 select 3, 'error', to_date('20.04.2018', 'dd.mm.yyyy') from dual union
10 select 4, 'error', to_date('23.04.2018', 'dd.mm.yyyy') from dual
11 )
12 select j.id job_id
13 from tjob j
14 where j.job_start = (select max(j1.job_start)
15 from tjob j1
16 where j1.job_start < (select l.log_date
17 from logs l
18 where l.id = &log_id));
Enter value for log_id: 1
JOB_ID
----------
1
SQL> /
Enter value for log_id: 3
JOB_ID
----------
2
SQL>