What does -Wall flag do when I compile it with the program? - gcc

I am following a tutorial that says how to profile the program using
gprof and the command given is like this
gcc -Wall -pg test_gprof.c test_gprof_new.c -o test_gprof
But it doesn'y give any explanation for this flag (-Wall)

As the name suggests it tells the compiler to enable all warning messages i.e. unused variables. This would help you to write better and clean code.

Related

where to add -g -O0 debug flags for lldb

I've been told that -g, -O0 tell the compiler not to optimize the code, in order to generate the executable the clearest possible. If I need to create explicitly the object file with -c option, do I have to add debug flags in that step or in linking, or both?
-g tells the compiler to generate debug information, -O0 tells it to not optimize the code; those two options can be used independently from each other. In order to generate straightforward code, it suffices to use the -O0 flag in the compiling (-c) step, since that's where the code is generated. Whether -g is needed in the linking step depends on the toolchain - it is not needed with a GNU linker.

Runtime Error with _mm_set1_epi32

I am trying to use SIMD instructions in some projects and everything is working fine, except that I can't use the _mm_set1_epi32(x) command (I can still just use _mm_set_epi32(x,x,x,x) and it works fine) but as soon as I want to use code from another source where the command is used I get a "memory access error" message (please excuse that I don't have the correct english translation for the error, I tried translating it from German where it is Speicherzugriffsfehler)
Some additional information:
I get the error in an empty project where I do nothing except use the command
I got this problem with no other command
For code examples, there is not really something to post here, except this:
int main() {
__m128i test = _mm_set1_epi32(1);
}
The error is at runtime, no problems with compiling.
I solved the problem. The flags I used to compile where wrong, thats also the reason why I didn't put any code, it would be just 1 line where I try to execute the command and the include for it in a main function.
So to the solution, I use now:
-g -std=c++11 -Wall -pedantic -msse4.1 -v
and before I used:
-g -std=c++11 -Wall -pedantic -msse -mmmx -msse2 -msse4.1 -v -mavx2

What is the signification of LDFLAGS

I'm trying to compile AODV for ARM linux. I use a SabreLite as a board with kernel version 3.0.35_4.1.0. It's worth mention that i'm using openembedded to create my Linux Distribution for my board.
The AODV source code (http://sourceforge.net/projects/aodvuu/) has a README file which give some indications on how to install it on ARM as stated a bit here.
(http://w3.antd.nist.gov/wctg/aodv_kernel/kaodv_arm.html).
I was able to upgrade the makefile in order to be used with post 2.6 kernel version ( as stated above, i have the 3.0.35_4.1.0 kernel version).
So, basically, what i am trying to do is that i have to create a module (let's say file.ko) and then load it into the ARM (with insmod file.ko command).
To do that, i am using a cross compiler which some values are stated below:
echo $CC :
arm-oe-linux-gnueabi-gcc -march=armv7-a -mthumb-interwork -mfloat-abi=hard -mfpu=neon -mtune=cortex-a9 --sysroot=/usr/local/oecore-x86_64/sysroots/cortexa9hf-vfp-neon-oe-linux-gnueabi
echo $ARCH=arm
echo $CFLAGS: O2 -pipe -g -feliminate-unused-debug-types
echo $LD :
arm-oe-linux-gnueabi-ld --sysroot=/usr/local/oecore-x86_64/sysroots/cortexa9hf-vfp-neon-oe-linux-gnueabi
echo $LDFLAGS :
-Wl,-O1 -Wl,--hash-style=gnu -Wl,--as-needed -Wl,--as-needed
when i launch "make command", i get the following errors:
LD [M] /home/scof/script_emulation/AODV/aodv-uu/lnx/kaodv.o
arm-oe-linux-gnueabi-ld: unrecognized option '-Wl,-O1'
arm-oe-linux-gnueabi-ld: use the --help option for usage information
It states that there is something wrong with the linker. This linker comes from the cross compilation tools and i normally shouldn't touch it.
Anyway, to get this above errors fixed, i try to withdraw the LDFLAGS like this:
export LDFLAGS='',
and after this, the make command works and i get the module kaodv.ko. But when i insert it into my ARM to check, it does not work. It actually freeze my terminal
So my question is, do i have to specify the LDFLAGS when compiling ? Does withdrawing LDFLAGS can have impact on the generated kernel module.
Actually, i try to understand where might be the problem and the only thing that come to me is that may be i should not change manually the LDFLAGS. But if i don't change de LDFLAGS, i get the unrecognized option error.
My second question related to that is, what are the possibly value of LDFLAGS
in ARM compilation
Thanks !!
echo $LDFLAGS : -Wl,-O1 -Wl,--hash-style=gnu -Wl,--as-needed -Wl,--as-needed
There are two common methods of invoking the linker in a GCC-based toolchain. One is to do it directly, but another is to use GCC as a front end to invoke the linker, rather than invoke it directly. When doing this, options intended for the linker are prefixed with -Wl, so that GCC knows to pass them through rather than interpret them itself.
In your case the error message from LD itself
arm-oe-linux-gnueabi-ld: unrecognized option '-Wl,-O1'
Indicates that your build system is passing LDFLAGS directly to the linker, and not by way of GCC.
Therefore, you should remove the -Wl, prefix and your LDFLAGS would instead be
-O1 --hash-style=gnu --as-needed --as-needed
(the duplication of the last argument is probably pointless but benign)
-O1 is an option that tells the linker to optimize. I believe it something new, and your linker may be slightly out of date. Try removing -Wl,-O1, it should still work.

How to (cross-)compile to both ARM hard- and soft-float (softfp) with a single GCC (cross-)compiler?

I'd like to use a single (cross-)compiler to compile code for different ARM calling conventions: since I always want to use floating point and NEON instructions, I just want to select the hard-float calling convention or the soft-float (softfp) calling convention.
My compiler defaults to hard-float, but it supports both architectures that I need:
$ arm-linux-gnueabihf-gcc -print-multi-lib
.;
arm-linux-gnueabi;#marm#march=armv4t#mfloat-abi=soft
$
When I compile with the default parameters:
$ arm-linux-gnueabihf-g++ -Wall -o hello_world_armhf hello_world.cpp
It succeeds without any errors.
If I compile with the parameters returned by -print-multi-lib:
$ arm-linux-gnueabihf-g++ -marm -march=armv4t -mfloat-abi=soft -Wall -o hello_world hello_world.cpp
It again compiles without error (By the way, how can I test that the resultant code is hard- or soft-float?)
Unfortunately, if I try this:
$ arm-linux-gnueabihf-g++ -march=armv7-a -mthumb-interwork -mfloat-abi=softfp -mfpu=neon -Wall -o hello_world hello_world.cpp
[...]/gcc/bin/../lib/gcc/arm-linux-gnueabihf/4.7.3/../../../../arm-linux-gnueabihf/bin/ld: error: hello_world uses VFP register arguments, /tmp/ccwvfDJo.o does not
[...]/gcc/bin/../lib/gcc/arm-linux-gnueabihf/4.7.3/../../../../arm-linux-gnueabihf/bin/ld: failed to merge target specific data of file /tmp/ccwvfDJo.o
collect2: error: ld returned 1 exit status
$
I've tested some other permutations of the parameters, but it seems that anything other than the combination shown by -print-multi-lib results in an error.
I've read ARM compilation error, VFP registered used by executable, not object file but the problem there was that some parts of the binary were soft- and some were hard-float. I have a single C++ file to compile...
What parameter(s) I miss to be able to compile with -march=armv7-a -mthumb-interwork -mfloat-abi=softfp -mfpu=neon?
How is it possible that the error is about VFP register arguments while I explicitly have -mfloat-abi=softfp in the command line which prohibits VFP register arguments?
Thanks!
For the records, hello_world.cpp contains the following:
#include <iostream>
int main()
{
std::cout << "Hello, world!" << std::endl;
return 0;
}
You need another compiler with corresponding multilib support.
You can check multilib support with next command.
arm-none-eabi-gcc -print-multi-lib
.;
thumb;#mthumb
fpu;#mfloat-abi=hard
armv6-m;#mthumb#march=armv6s-m
armv7-m;#mthumb#march=armv7-m
armv7e-m;#mthumb#march=armv7e-m
armv7-ar/thumb;#mthumb#march=armv7
cortex-m7;#mthumb#mcpu=cortex-m7
armv7e-m/softfp;#mthumb#march=armv7e-m#mfloat-abi=softfp#mfpu=fpv4-sp-d16
armv7e-m/fpu;#mthumb#march=armv7e-m#mfloat-abi=hard#mfpu=fpv4-sp-d16
armv7-ar/thumb/softfp;#mthumb#march=armv7#mfloat-abi=softfp#mfpu=vfpv3-d16
armv7-ar/thumb/fpu;#mthumb#march=armv7#mfloat-abi=hard#mfpu=vfpv3-d16
cortex-m7/softfp/fpv5-sp-d16;#mthumb#mcpu=cortex-m7#mfloat-abi=softfp#mfpu=fpv5-sp-d16
cortex-m7/softfp/fpv5-d16;#mthumb#mcpu=cortex-m7#mfloat-abi=softfp#mfpu=fpv5-d16
cortex-m7/fpu/fpv5-sp-d16;#mthumb#mcpu=cortex-m7#mfloat-abi=hard#mfpu=fpv5-sp-d16
cortex-m7/fpu/fpv5-d16;#mthumb#mcpu=cortex-m7#mfloat-abi=hard#mfpu=fpv5-d16
https://stackoverflow.com/questions/37418986/how-to-interpret-the-output-of-gcc-print-multi-lib
How to interpret the output of gcc -print-multi-lib
With this configuration gcc -mfloat-abi=hard not only will build your files using FPU instructions but also link them with corresponding libs, avoiding "X uses VFP register arguments, Y does not" error.
The above-mentioned -print-multi-lib output produced by gcc with this patch and --with-multilib-list=armv6-m,armv7,armv7-m,armv7e-m,armv7-r,armv7-a,cortex-m7 configuration option.
If you are interested in building your own gcc with Cortex-A series multilib support, just use --with-multilib-list=aprofile configuration option for any arm*-*-* target without any patches (at list with gcc-6.2.0).
As per Linaro FAQ if your compiler prints arm-linux-gnueabi;#marm#march=armv4t#mfloat-abi=soft then you can only use -march=armv4t. If you want to use -march=armv7-a you need to build compiler yourself.
Following link could be helpful in building yourself GCC ARM Builds

Build gcc with -std=c++11 default option

When building gcc itself how do I enable some flags like
-std=c++11 -Wno-unused-local-typedefs etc so they are the default values
unless stated otherwise on the command line.
Thanks in advance

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