Oracle - creating a group based on group spacing - oracle

Question

How to make a query that will create groups that have a space between them greater than "n"?
Data:
01-01-2000
02-01-2000
03-01-2000
06-01-2000
07-01-2000
19-02-2001
10-01-2002
11-01-2002
I would like to get a result for the interval between records, e.g. 2 days:
DATE GROUP
01-01-2000 1
02-01-2000 1
03-01-2000 1
06-01-2000 2
07-01-2000 2
19-02-2001 3
10-01-2002 4
11-01-2002 4
For 10 days:
01-01-2000 1
02-01-2000 1
03-01-2000 1
06-01-2000 1
07-01-2000 1
19-02-2001 2
10-01-2002 3
11-01-2002 3
Another example with integers:
with x as (
select 1 as A from dual
union all
select 2 as A from dual
union all
select 3 as A from dual
union all
select 10 as A from dual
union all
select 20 as A from dual
union all
select 22 as A from dual
union all
select 33 as A from dual
union all
select 40 as A from dual
union all
select 50 as A from dual
union all
select 100 as A from dual
union all
select 101 as A from dual
union all
select 102 as A from dual
) select A
from x;
I need to create groups for a value increase of more than 3:
Example result:
1 1
2 1
3 1
10 2
20 3
22 3
33 4
40 5
50 6
100 7
101 7
102 7

Answer 1

Here is one way to do it
CREATE TABLE TEST (
DATE_IN DATE
);
INSERT INTO TEST VALUES (TO_DATE('01-01-2000','DD-MM-YYYY'));
INSERT INTO TEST VALUES (TO_DATE('02-01-2000','DD-MM-YYYY'));
INSERT INTO TEST VALUES (TO_DATE('03-01-2000','DD-MM-YYYY'));
INSERT INTO TEST VALUES (TO_DATE('06-01-2000','DD-MM-YYYY'));
INSERT INTO TEST VALUES (TO_DATE('07-01-2000','DD-MM-YYYY'));
INSERT INTO TEST VALUES (TO_DATE('19-02-2001','DD-MM-YYYY'));
INSERT INTO TEST VALUES (TO_DATE('10-01-2002','DD-MM-YYYY'));
INSERT INTO TEST VALUES (TO_DATE('11-01-2002','DD-MM-YYYY'));
--HERE IS AN EXAMPLE FOR 1 DAY. Just change the value in the > 1 TO >10
--if you want to create a group if there is a gap of more than 10days
SELECT DATE_IN, SUM(NEW_GROUP) OVER ( ORDER BY DATE_IN) AS GROUPE FROM (
SELECT
DATE_IN,
CASE WHEN DATE_IN - LAG(DATE_IN,1,TO_DATE('01-01-1900','DD-MM-YYYY')) OVER ( ORDER BY DATE_IN) > 1 THEN 1 ELSE 0 END AS NEW_GROUP
FROM TEST
)
-- Result
DATE_IN GROUPE
2000-01-01T00:00:00Z 1
2000-01-02T00:00:00Z 1
2000-01-03T00:00:00Z 1
2000-01-06T00:00:00Z 2
2000-01-07T00:00:00Z 2
2001-02-19T00:00:00Z 3
2002-01-10T00:00:00Z 4
2002-01-11T00:00:00Z 4

Answer 2

Example with integer:
with x as (
select 1 as A from dual
union all
select 2 as A from dual
union all
select 3 as A from dual
union all
select 10 as A from dual
union all
select 20 as A from dual
union all
select 22 as A from dual
union all
select 33 as A from dual
union all
select 40 as A from dual
union all
select 50 as A from dual
union all
select 100 as A from dual
union all
select 101 as A from dual
union all
select 102 as A from dual
) SELECT A, SUM(NEW_GROUP) OVER ( ORDER BY A) AS GROUPE FROM (
SELECT
A,
CASE WHEN A - LAG(A,1,1) OVER ( ORDER BY A) > 5 THEN 1 ELSE 0 END AS NEW_GROUP
FROM X
)
order by A;