finaltableA has two columns WORDS, WCOUNTS. The program should insert every word of intitaltableA into finaltableA exactly once. In the column WCOUNTS the program should put how often the word occurs.
intitaltableA
COVID
is
a
disease
COVID
can
be
treated
with
antibodies
COVID
is
a
serious
disease
there
is
a
vaccination
available
for
COVID
finaltableA should look like this -
WORDS
WCOUNTS
a
3
antibodies
1
available
1
be
1
can
1
COVID
4
disease
2
for
1
is
3
serious
1
there
1
treated
1
vaccination
1
with
1
I should use a cursor to insert and update the table. I am new to PL/SQL.
It is quite obvious that you can do this without any cursor in PLSQL, so I guess that means that you are trying to solve a homework problem or a training question. Anyway, here you can see two simple options to get the result you want, with and without PLSQL.
Option 1 - Without PLSQL
with x ( words )
as
(
select 'COVID' from dual union all
select 'is' from dual union all
select 'a' from dual union all
select 'disease' from dual union all
select 'COVID' from dual union all
select 'can' from dual union all
select 'be' from dual union all
select 'treated' from dual union all
select 'with' from dual union all
select 'antibodies' from dual union all
select 'COVID' from dual union all
select 'is' from dual union all
select 'a' from dual union all
select 'serious' from dual union all
select 'disease' from dual union all
select 'there' from dual union all
select 'is' from dual union all
select 'a' from dual union all
select 'vaccination' from dual union all
select 'available' from dual union all
select 'for' from dual union all
select 'COVID' from dual
)
select words, count(words) as counter
from x
group by words
order by 2 desc;
If you execute it, it gives you the output you want
SQL> with x ( words )
2 as
3 (
4 select 'COVID' from dual union all
5 select 'is' from dual union all
6 select 'a' from dual union all
7 select 'disease' from dual union all
8 select 'COVID' from dual union all
9 select 'can' from dual union all
10 select 'be' from dual union all
11 select 'treated' from dual union all
12 select 'with' from dual union all
13 select 'antibodies' from dual union all
14 select 'COVID' from dual union all
15 select 'is' from dual union all
16 select 'a' from dual union all
17 select 'serious' from dual union all
18 select 'disease' from dual union all
19 select 'there' from dual union all
20 select 'is' from dual union all
21 select 'a' from dual union all
22 select 'vaccination' from dual union all
23 select 'available' from dual union all
24 select 'for' from dual union all
25 select 'COVID' from dual
26 )
27 select words, count(words) as counter
28 from x
29 group by words
30* order by 2 desc
SQL> /
WORDS COUNTER
----------- ----------
COVID 4
is 3
a 3
disease 2
there 1
available 1
for 1
serious 1
antibodies 1
can 1
vaccination 1
WORDS COUNTER
----------- ----------
treated 1
be 1
with 1
14 rows selected.
Option 2 - Using PLSQL and a CURSOR
In the below example, I'm going to use dbms_output to show the results. Keep in mind that here there are dozens of ways to do the same, I am just using the simplest one I can think of.
SQL> create table t ( words varchar2(40) ) ;
Table created.
SQL> insert into t
2 with x ( words )
3 as
4 (
5 select 'COVID' from dual union all
6 select 'is' from dual union all
7 select 'a' from dual union all
8 select 'disease' from dual union all
9 select 'COVID' from dual union all
10 select 'can' from dual union all
11 select 'be' from dual union all
12 select 'treated' from dual union all
13 select 'with' from dual union all
14 select 'antibodies' from dual union all
15 select 'COVID' from dual union all
16 select 'is' from dual union all
17 select 'a' from dual union all
18 select 'serious' from dual union all
19 select 'disease' from dual union all
20 select 'there' from dual union all
21 select 'is' from dual union all
22 select 'a' from dual union all
23 select 'vaccination' from dual union all
24 select 'available' from dual union all
25 select 'for' from dual union all
26 select 'COVID' from dual
27* ) select words from x
SQL> /
22 rows created.
SQL> commit ;
Commit complete.
SQL> declare
2 begin
3 for i in ( select words, count(words) as counter from t group by words order by 2 desc )
4 loop
5 dbms_output.put_line( 'Words: '||i.words||' - Wcount is: '||i.counter||' ');
6 end loop;
7* end;
SQL> /
Words: COVID - Wcount is: 4
Words: is - Wcount is: 3
Words: a - Wcount is: 3
Words: disease - Wcount is: 2
Words: antibodies - Wcount is: 1
Words: for - Wcount is: 1
Words: be - Wcount is: 1
Words: vaccination - Wcount is: 1
Words: can - Wcount is: 1
Words: available - Wcount is: 1
Words: treated - Wcount is: 1
Words: there - Wcount is: 1
Words: with - Wcount is: 1
Words: serious - Wcount is: 1
PL/SQL procedure successfully completed.
Related
I need to number the rows so that the row number with the same ID is the same. For example:
Oracle database. Any ideas?
Use the DENSE_RANK analytic function:
SELECT DENSE_RANK() OVER (ORDER BY id) AS row_number,
id
FROM your_table
Which, for the sample data:
CREATE TABLE your_table ( id ) AS
SELECT 86325 FROM DUAL UNION ALL
SELECT 86325 FROM DUAL UNION ALL
SELECT 86326 FROM DUAL UNION ALL
SELECT 86326 FROM DUAL UNION ALL
SELECT 86352 FROM DUAL UNION ALL
SELECT 86353 FROM DUAL UNION ALL
SELECT 86354 FROM DUAL UNION ALL
SELECT 86354 FROM DUAL;
Outputs:
ROW_NUMBER
ID
1
86325
1
86325
2
86326
2
86326
3
86352
4
86353
5
86354
5
86354
db<>fiddle here
I have an interactive report, which using Pivot, but I was trying to custom sort the report by row column of pivot "Age Group", but I couldn't.
I need this report in such this sorting:
How I can do that?
Thanks
Looks like you'd want to sort by the first digit(s), and then by age_group itself (as a string). Something like this (sample data in lines #1 - 10; query you might be interested in begins at line #11):
SQL> with test (age_group) as
2 (select 'wahine 45-64' from dual union all
3 select 'wahine 25-44' from dual union all
4 select 'rangtahi 15-24' from dual union all
5 select 'pepis 0_4' from dual union all
6 select 'pakeke 45-64' from dual union all
7 select 'pakeke 25-44' from dual union all
8 select 'N/A' from dual union all
9 select 'kuia 65+' from dual
10 )
11 select age_group
12 from test
13 order by to_number(regexp_substr(age_group, '\d+')), age_group;
AGE_GROUP
--------------
pepis 0_4
rangtahi 15-24
pakeke 25-44
wahine 25-44
pakeke 45-64
wahine 45-64
kuia 65+
N/A
8 rows selected.
SQL>
I have this data :
1
10
100
101
102
12
120
1a
1b
1c
2
3
4
and I would like to order like this:
1
1a
1b
1c
2
3
4
10
12
100
101
102
120
It's possible in Oracle ?
I tried this but it does not work with alphabetic characters
order by case when replace(translate(trim(COLUMN),'0123456789','0'),'0','') is null then to_number(COLUMN) end asc, COLUMN asc
If you don't mind the minor performance hit, a regexp is an easy solution.
-- sample data
with t as (select '1' as x from dual
union select '10' from dual
union select '100' from dual
union select '101' from dual
union select '102' from dual
union select '12' from dual
union select '120' from dual
union select '1a' from dual
union select '1b' from dual
union select '1c' from dual
union select '2' from dual
union select '3' from dual
union select '4' from dual)
-- query
select x
from t
-- order first by the leading numbers, then alphabetically
order by to_number(regexp_substr(x, '[0-9]*')), x;
How to make a query that will create groups that have a space between them greater than "n"?
Data:
01-01-2000
02-01-2000
03-01-2000
06-01-2000
07-01-2000
19-02-2001
10-01-2002
11-01-2002
I would like to get a result for the interval between records, e.g. 2 days:
DATE GROUP
01-01-2000 1
02-01-2000 1
03-01-2000 1
06-01-2000 2
07-01-2000 2
19-02-2001 3
10-01-2002 4
11-01-2002 4
For 10 days:
01-01-2000 1
02-01-2000 1
03-01-2000 1
06-01-2000 1
07-01-2000 1
19-02-2001 2
10-01-2002 3
11-01-2002 3
Another example with integers:
with x as (
select 1 as A from dual
union all
select 2 as A from dual
union all
select 3 as A from dual
union all
select 10 as A from dual
union all
select 20 as A from dual
union all
select 22 as A from dual
union all
select 33 as A from dual
union all
select 40 as A from dual
union all
select 50 as A from dual
union all
select 100 as A from dual
union all
select 101 as A from dual
union all
select 102 as A from dual
) select A
from x;
I need to create groups for a value increase of more than 3:
Example result:
1 1
2 1
3 1
10 2
20 3
22 3
33 4
40 5
50 6
100 7
101 7
102 7
Here is one way to do it
CREATE TABLE TEST (
DATE_IN DATE
);
INSERT INTO TEST VALUES (TO_DATE('01-01-2000','DD-MM-YYYY'));
INSERT INTO TEST VALUES (TO_DATE('02-01-2000','DD-MM-YYYY'));
INSERT INTO TEST VALUES (TO_DATE('03-01-2000','DD-MM-YYYY'));
INSERT INTO TEST VALUES (TO_DATE('06-01-2000','DD-MM-YYYY'));
INSERT INTO TEST VALUES (TO_DATE('07-01-2000','DD-MM-YYYY'));
INSERT INTO TEST VALUES (TO_DATE('19-02-2001','DD-MM-YYYY'));
INSERT INTO TEST VALUES (TO_DATE('10-01-2002','DD-MM-YYYY'));
INSERT INTO TEST VALUES (TO_DATE('11-01-2002','DD-MM-YYYY'));
--HERE IS AN EXAMPLE FOR 1 DAY. Just change the value in the > 1 TO >10
--if you want to create a group if there is a gap of more than 10days
SELECT DATE_IN, SUM(NEW_GROUP) OVER ( ORDER BY DATE_IN) AS GROUPE FROM (
SELECT
DATE_IN,
CASE WHEN DATE_IN - LAG(DATE_IN,1,TO_DATE('01-01-1900','DD-MM-YYYY')) OVER ( ORDER BY DATE_IN) > 1 THEN 1 ELSE 0 END AS NEW_GROUP
FROM TEST
)
-- Result
DATE_IN GROUPE
2000-01-01T00:00:00Z 1
2000-01-02T00:00:00Z 1
2000-01-03T00:00:00Z 1
2000-01-06T00:00:00Z 2
2000-01-07T00:00:00Z 2
2001-02-19T00:00:00Z 3
2002-01-10T00:00:00Z 4
2002-01-11T00:00:00Z 4
Example with integer:
with x as (
select 1 as A from dual
union all
select 2 as A from dual
union all
select 3 as A from dual
union all
select 10 as A from dual
union all
select 20 as A from dual
union all
select 22 as A from dual
union all
select 33 as A from dual
union all
select 40 as A from dual
union all
select 50 as A from dual
union all
select 100 as A from dual
union all
select 101 as A from dual
union all
select 102 as A from dual
) SELECT A, SUM(NEW_GROUP) OVER ( ORDER BY A) AS GROUPE FROM (
SELECT
A,
CASE WHEN A - LAG(A,1,1) OVER ( ORDER BY A) > 5 THEN 1 ELSE 0 END AS NEW_GROUP
FROM X
)
order by A;
I am using this code to round down the decimal value to the next multiple of 25.
ie if value is 33.60 it should round to 33.50
create or replace
PROCEDURE "TEST1" (PQUERY IN VARCHAR2) as
prNspValue number(14,2) :='';
p_percentage_Value number(4,2) :='';
begin
prNspValue:=33.60;
dbms_output.put_line(prNspValue);
p_percentage_Value:=substr(prNspValue,instr(prNspValue,'.')+1,length(prNspValue));
dbms_output.put_line(p_percentage_value);
p_percentage_Value:=p_percentage_Value-mod(p_percentage_Value,25);
dbms_output.put_line(p_percentage_value);
if(p_percentage_Value!=0)then
prNspValue:=substr(prNspValue,1,instr(prNspValue,'.'))+p_percentage_Value/100;
else
prNspValue:=substr(prNspValue,1,instr(prNspValue,'.'));
end if;
dbms_output.put_line(prNspValue);
end;
but the problem is when the value is 33.60 it is taken as 33.6. so it is rounding it to 33.0.
How can i correct this code?
you can use the round function directly FLOOR(your_number*4)/4:
SQL> WITH my_data AS (
2 SELECT 33.00 num FROM dual
3 UNION ALL SELECT 33.10 FROM dual
4 UNION ALL SELECT 33.20 FROM dual
5 UNION ALL SELECT 33.30 FROM dual
6 UNION ALL SELECT 33.40 FROM dual
7 UNION ALL SELECT 33.50 FROM dual
8 UNION ALL SELECT 33.60 FROM dual
9 UNION ALL SELECT 33.70 FROM dual
10 UNION ALL SELECT 33.80 FROM dual
11 UNION ALL SELECT 33.90 FROM dual
12 ) SELECT num,
13 floor (num * 4) / 4 rounded
14 FROM my_data;
NUM ROUNDED
---------- ----------
33 33
33,1 33
33,2 33
33,3 33,25
33,4 33,25
33,5 33,5
33,6 33,5
33,7 33,5
33,8 33,75
33,9 33,75
10 rows selected