Laravel pagination with problems - laravel

Question

i have a simple question as i do not know which line i should add into to get laravel pagination. (->paginate(5).
public function index(Request $request)
{
$codeSearch = $request->get('code');
$descriptionSearch = $request->get('description');
//$tmp = Category::all()->toArray();
$tmp = Category::where('code','like','%' .$codeSearch. '%')->where('description','like','%' .$codeSearch. '%')->get()->toArray();
$category = array();
foreach ($tmp as $key => $row) {
$policy = Category::find($row['parent_id']);
$tmpResult = new Category();
$tmpResult->id = $row['id'];
$tmpResult->code = $row['code'];
$tmpResult->description = $row['description'];
$tmpResult->parent_id = $policy['description'];
$tmpResult->status = $row['status'];
array_push($category, $tmpResult);
}
return view('category.index', compact('category'));
}

Answer 1

Paginate can't be called on the collection, so you have to run it on the query, by simply replace ->get() with ->paginate(5) like this
$tmp = Category::where('code','like','%' .$codeSearch. '%')
->where('description','like','%' .$codeSearch. '%')
->paginate(5)
->toArray();

Answer 2

Try
$tmp = Category::where('code','like','%' .$codeSearch. '%')->where('description','like','%' .$codeSearch. '%')->paginate(5);
In view
#foreach($tmp as $tm)
//whatever operation you like to do
#endforeach
{{$tmp->links()}}

Answer 3

The following ->get(), ->first(), all() get the results from the database and so does ->paginate(5), so I would suggest that you replace ->get() with paginate(5) an you can get rid of toArray() because the result will be a collection with which you can use foreach() or get a value by index.

Answer 4

As you need an array in your condition, then you can simply convert the final array into a collection object and use the pagination concept.
$items = [
'item1',
'item2',
'item3',
'item4',
'item5',
'item6',
'item7',
'item8',
'item9',
'item10'
];
// Get current page form url e.x. &page=1
$currentPage = LengthAwarePaginator::resolveCurrentPage();
// Create a new Laravel collection from the array data
$itemCollection = collect($items);
// Define how many items we want to be visible in each page
$perPage = 1;
// Slice the collection to get the items to display in current page
$currentPageItems = $itemCollection->slice(($currentPage * $perPage) - $perPage, $perPage)->all();
// Create our paginator and pass it to the view
$paginatedItems= new LengthAwarePaginator($currentPageItems , count($itemCollection), $perPage);
// set url path for generted links
$paginatedItems->setPath($request->url());
return view('items_view', ['items' => $paginatedItems]);

Answer 5

It would probably be easier to have a relationship setup for a Category's parent. Then you can load the parent when you retrieve the categories.
class Category extends Model
{
...
public function parent()
{
return $this->belongsTo(self::class);
}
}
I feel like your search is probably trying to do an OR WHERE, search the code field for this value or the description:
$categories = Category::with('parent')
->where('code', 'like', '%' .$codeSearch. '%')
->orWhere('description', 'like', '%' .$codeSearch. '%')
->paginate(5);
Then in your view if you want the parent category's description you can get it through the relationship:
#foreach ($categories as $category)
parent description: {{ $category->parent->description }}
#endforeach