I have a simple Spring Framework (4.3.16.RELEASE) ear file deployed to TomEE (tomee-plume-8.0.0-M2) using Zulu Java (zulu8.36.0.1-ca-jdk8.0.202-macosx_x64).
I getting errors injecting a data source via JNDI Lookup. My TomEE instance has the following resource in server.xml:
<Resource
auth="Container"
driverClassName="oracle.jdbc.OracleDriver"
name="jdbc/my/DataSource"
password="1234"
type="javax.sql.DataSource"
url="jdbc:oracle:thin:#database.local:1521/db"
username="admin" />
In my application ear I have the following in my web.xml file:
<servlet>
<servlet-name>dispatch</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatch</servlet-name>
<url-pattern>/r/*</url-pattern>
</servlet-mapping>
My applicationContext.xml that lookups the JNDI resource:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:jdbc="http://www.springframework.org/schema/jdbc"
xmlns:jee="http://www.springframework.org/schema/jee"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/jdbc http://www.springframework.org/schema/jdbc/spring-jdbc.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-3.0.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">
<!-- Configures support for #Controllers -->
<context:component-scan base-package="local.gerb" />
<mvc:annotation-driven/>
<jee:jndi-lookup id="writeDataSource" jndi-name="jdbc/my/DataSource" resource-ref="true"/>
<bean id="helloWorld" class="local.gerb.HelloWorldImpl" />
</beans>
However, when I deploy the application I get the following error in the log file:
CreationException: Error creating bean with name 'writeDataSource': Invocation of init method failed; nested exception is javax.naming.NameNotFoundException: Name [jdbc/my/DataSource] is not bound in this Context. Unable to find [jdbc].
04-Mar-2019 12:43:33.610 SEVERE [main] org.springframework.web.servlet.DispatcherServlet.initServletBean Context initialization failed
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'writeDataSource': Invocation of init method failed; nested exception is javax.naming.NameNotFoundException: Name [jdbc/my/DataSource] is not bound in this Context. Unable to find [jdbc].
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1630)
I do see the jdbc/my/DataSource being created in TomEE:
04-Mar-2019 12:43:32.113 INFO [main] org.apache.tomee.catalina.OpenEJBNamingContextListener.bindResource Importing a Tomcat Resource with id 'jdbc/my/DataSource' of type 'javax.sql.DataSource'.
04-Mar-2019 12:43:32.113 INFO [main] org.apache.openejb.assembler.classic.Assembler.createRecipe Creating Resource(id=jdbc/my/DataSource)
So I believe I created the Resource correctly in TomEE but for some reason, spring framework is unable to correctly inject the resource.
I do have the full source pushed to my github repo: https://github.com/jstralko/tomee-poc/tree/master/SpringExamples in case you want to look at everything, I kept it as minimal as possible to help debug this issue.
Any help would be greatly appreciated.
I feel silly, apparently, once I moved the Resource into context.xml from server.xml; I was able to successfully inject a JDBC resource.
Related
I am using Spring and AngularJS for a rest web application. Base on this tutorial and based on this tutorial I've created the following folder structure:
-src
|----main
|----webapp
|----static
|----api
|----assets
|----resources
|----sections
|----services
|----index.html
|----WEB-INF
|----web.xml
|----spring
|----dispatcher-servlet.xml
|----applicationContext.xml
I want to serve static HTML files so I declared the resources as following:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd">
<mvc:annotation-driven></mvc:annotation-driven>
<context:component-scan base-package="org.tools.mvc.controllers"></context:component-scan>
<mvc:resources location="/static/" mapping="/**"/>
<mvc:resources location="/static/api/" mapping="/api/**"/>
<mvc:resources location="/static/assets/" mapping="/assets/**"/>
<mvc:resources location="/static/resources/" mapping="/resources/**"/>
<mvc:resources location="/static/services/" mapping="/services/**"/>
<mvc:resources location="/static/sections/home/" mapping="/sections/home/**"/>
<bean name="viewResolver" class="org.springframework.web.servlet.view.BeanNameViewResolver"></bean>
<bean name="jsonTemplate" class="org.springframework.web.servlet.view.json.MappingJackson2JsonView"></bean>
My problem is that when I deploy the application( I am using Glassfish server) the following error occurs( in Eclipse console and also in the browser page):
2016-05-27T04:46:06.640-0700|Warning: StandardWrapperValve[dispatcher]: Servlet.service() for servlet dispatcher threw exception
javax.servlet.ServletException: Could not resolve view with name 'index.html' in servlet with name 'dispatcher'
The functionality of the service is not affected( using Postman to test the rest api results in success). Until now, in order to further develop the application I manually added index.html to the end of the URL(like localhost:8080/status/index.html). The source of the "/" as declared in Web Deployment Assembly is:
Source: /src/main/webapp
Deploy Path: /
Update: The web.xml file is looking like this:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" version="3.1">
<display-name>status</display-name>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/applicationContext.xml</param-value>
</context-param>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/dispatcher-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
How can I resolve this error?
Thank you
P.S The solutions found on SO didn't applied to my scenario.
I discovered that I've declared a view resolver ( BeanNameViewResolver) inside applicationContext.xml. After deleting the view resolver, I didn't receive the error.
The error occurred because Spring was trying to interpret my view( witch was a html static file) to a bean.
I have got a problem with JNDI configuration on Jetty server. I cannot by any means configure it in a way that afterwards Spring (3.0.5) can retrieve JNDI variables.
I have some credentials which I do not want to store in properties so that it will not exist in git repo. My web application is running on Jetty (most recent version 9.2.3), thus I came up with idea to store this credentials in Jetty web application context. Jetty provides such solution with jetty-env.xml. So I have created jetty-env.xml file in my WEB-INF/ like following:
<?xml version="1.0"?>
<!DOCTYPE Configure PUBLIC "-//Mort Bay Consulting//DTD Configure//EN" "http://jetty.mortbay.org/configure.dtd">
<Configure id="webappCtx" class="org.eclipse.jetty.webapp.WebAppContext">
<New id="username" class="org.eclipse.jetty.plus.jndi.Resource">
<Arg><Ref refid="webappCtx"/></Arg> <!-- scope -->
<Arg>server/username</Arg> <!-- name -->
<Arg type="java.lang.String">myUsername</Arg> <!-- value -->
</New>
<New id="password" class="org.eclipse.jetty.plus.jndi.Resource">
<Arg><Ref refid="webappCtx"/></Arg> <!-- scope -->
<Arg>server/password</Arg> <!-- name -->
<Arg type="java.lang.String">qwerty</Arg> <!-- value -->
</New>
</Configure>
After that I have defined binding in the web.xml as follows:
<?xml version="1.0" encoding="UTF-8"?>
<web-app id="MyWebApp" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>My Web App</display-name>
<!-- INITIALIZE SPRING -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:/spring-context.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- JETTY-ENV JNDI -->
<resource-ref>
<res-ref-name>server/username</res-ref-name>
<res-type>java.lang.String</res-type>
</resource-ref>
<resource-ref>
<res-ref-name>server/password</res-ref-name>
<res-type>java.lang.String</res-type>
</resource-ref>
</web-app>
And configured my Spring context in this way:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:amq="http://activemq.apache.org/schema/core"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:ehcache="http://www.springmodules.org/schema/ehcache"
xmlns:jee="http://www.springframework.org/schema/jee"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd
http://activemq.apache.org/schema/core http://activemq.apache.org/schema/core/activemq-core-5.2.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springmodules.org/schema/ehcache http://www.springmodules.org/schema/cache/springmodules-ehcache.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-3.0.xsd">
<jee:jndi-lookup id="serverUsername" jndi-name="server/username" expected-type="java.lang.String" resource-ref="true" />
<jee:jndi-lookup id="serverPassword" jndi-name="server/password" expected-type="java.lang.String" resource-ref="true"/>
<bean name="abstractServerConnectionFactory" class="my.package.ServerConnectionFactory" abstract="true">
<constructor-arg value="${server.host}"/>
<constructor-arg value="${server.port}"/>
<constructor-arg ref="serverUsername"/>
<constructor-arg ref="serverPassword"/>
</bean>
</beans>
After that I am starting Jetty with --add-to-startd=jndi enabled and I am always getting javax.naming.NameNotFoundException when creating serverUsername and serverPassword. I have tried many modfication, but non have seem to work. I have tried:
Changing org.eclipse.jetty.plus.jndi.Resource to org.eclipse.jetty.plus.jndi.EnvEntry and then refering to it via resource-env-ref in web.xml
Setting resource scope to JVM instead of webapp so changing <Arg><Ref refid="webappCtx"/></Arg> to <Arg></Arg> as mentioned here
Adding automatic binding without using web.xml as mentioned here
<Call name="bindToENC">
<Arg>server/username</Arg> <!-- binds server/username to java:comp/env/server/username for this webapp -->
</Call>
And many other, but it just does not work. Please give me a working example how I can get it to work. Thank you!
Ok so I have managed to get this working. The problem was the configuration. I am using Jetty 9 so according to the official documentation (http://www.eclipse.org/jetty/documentation/current/jndi.html#jndi-quick-setup) the only thing that needs to be done prior to using JNDI in Jetty is adding jndi module to start.d by doing --add-to-startd=jndi. And well, that's not exactly true, because this will enable JNDI, BUT WILL NOT INCLUDE jetty-env.xml contents (Jetty do not even touch it). I've been reading about the container lifecycle and noticed that in order to use JNDI one need to include following classes in the web application context configuration classes set:
org.eclipse.jetty.plus.webapp.EnvConfiguration
org.eclipse.jetty.plus.webapp.PlusConfiguration
This is done by default in $JETTY_HOME/etc/jetty-plus.xml, which is config file for plus module. So in order to add this classes into the Jetty container lifecycle, and by this include and parse jetty-env.xml, one need to enable plus module in addition to jndi module (jndi does not depend upon plus)! Thus I have changed my start.d config by invoking --add-to-startd=jndi,plus (no space between modules) and everything started working like a charm.
Deploying war to Apache Tomcat 8 the following way.
Placing myApp.xml under $CATALINA_HOME/conf/[enginename]/[hostname]/
with the following contents:
<Context>
<Parameter name="myApp_configs" value="file:/the/path/to/configs/folder"
type="java.lang.String" override="false"/>
</Context>
B.t.w. I do not place any kind of Context.xml into war.
Then copying myApp.war to $CATALINA_HOME/webapps
This is my web.xml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
<display-name>service</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>WEB-INF/beans.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<servlet>
<servlet-name>CXFServlet</servlet-name>
<display-name>CXF Servlet</display-name>
<servlet-class>
org.apache.cxf.transport.servlet.CXFServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>CXFServlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>
And this way I try loading properties-file in beans.xml (referenced in web.xml above).
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:jaxrs="http://cxf.apache.org/jaxrs"
xmlns:context="http://www.springframework.org/schema/context" xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://cxf.apache.org/jaxrs http://cxf.apache.org/schemas/jaxrs.xsd">
<!-- Imported resources for cxf -->
<import resource="classpath:META-INF/cxf/cxf.xml" />
<import resource="classpath:META-INF/cxf/cxf-extension-jaxrs-binding.xml" />
<import resource="classpath:META-INF/cxf/cxf-servlet.xml" />
<bean class="org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor"/>
<!--context:property-placeholder
location="#{contextParameters['myApp_configs']}/myApp.properties"/-->
<bean id="configurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location"
value="#{contextParameters['myApp_configs']}/myApp.properties"/>
</bean>
...other lines follow here...
</beans>
However I am getting following error upon beans loading:
Field or property 'contextParameters' cannot be found on object of type 'org.springframework.beans.factory.config.BeanExpressionContext'
Could you help me understand the error and propose a fix so that I can access Context-defined parameters?
P.S. I have not put here, but I also have some <Environment>-nodes in Context, and they are successfully accessible via JNDI in other places.
So as we were not able to solve the root cause - why contextParameters bean is not available, the following workaround (using ol' syntax) took place:
<bean id="myConfigsLocation"
class="org.springframework.web.context.support.ServletContextParameterFactoryBean">
<property name="initParamName" value="myApp_configs" />
</bean>
<context:property-placeholder
location="#{myConfigsLocation}/myApp.properties" />
And it worked successfully.
I am developing a web application using JSF 2.0 ,Spring 3.1.
When I am deploying my application I am getting following error
ERROR [ContextLoader] Context initialization failed
org.springframework.beans.factory.BeanDefinitionStoreException: Invalid bean definition with name 'AllProjectDetailsBean' defined in ServletContext resource [/WEB-INF/springApp-spring.xml]: Could not resolve placeholder 'OutputFilePath'
Application Context file
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-3.0.xsd ">
<aop:aspectj-autoproxy />
<bean id="placeholderConfig"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
</bean>
<bean id="AllProjectDetailsBean"
class="com.tcs.srl.expertFinder.sections.ProjectDetailsBeanFactory"
factory-method="createInstance">
<constructor-arg index="0" value="${OutputFilePath}" />
</bean>
What I understand from error is when I deploy application the context loads very first time but it fails because it dose not find any property with name OutputFilePath.
That means I have to set system property with the name OutputFilePath before context loads.
Can some tell me how to set system property while deploying jsf application or before context loads.
Or is there any option to remove this error.
Please Help
Thanks
I am trying to define a JNDI DB connection in a test project with Spring. I've bootstrapped the project with Spring Roo and thus is Mavenized. Here is the Roo script for reference (Roo 1.2.1)
project --topLevelPackage org.obliquid.cpool
jpa setup --database MYSQL --provider HIBERNATE --jndiDataSource /jdbc/cpool
web mvc setup
entity jpa --class org.obliquid.cpool.entity.Person
field string --fieldName name
web mvc scaffold --class ~.entity.Person
web mvc all --package ~.web
In src/main/resources/META-INF/spring/applicationContext.xml I've the following (created by Roo):
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:jee="http://www.springframework.org/schema/jee"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-3.1.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.1.xsd
http://www.springframework.org/schema/jee
http://www.springframework.org/schema/jee/spring-jee-3.1.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.1.xsd">
...
<jee:jndi-lookup id="dataSource" jndi-name="/jdbc/cpool" resource-ref="true"/>
...
I've created src/main/resources/META-INF/context.xml with the following content:
<?xml version="1.0" encoding="UTF-8"?>
<Context path="/myapp" docBase="cpool" reloadable="true" debug="1">
<Resource name = "jdbc/cpool"
auth = "Container"
type = "javax.sql.DataSource"
username = "dbusername"
password = "dbpassword"
driverClassName = "com.mysql.jdbc.Driver"
url = "jdbc:mysql://localhost:3306/dbname?DateTimeBehavior=convertToNull&characterEncoding=UTF-8"
maxActive = "100"
maxIdle = "4"
maxWait = "20000"
removeAbandoned = "true"
removeAbandonedTimeout="600"
logAbandoned="true"/>
</Context>
However, when I try to run the application in Tomcat 7.0, I get the following error:
ERROR org.springframework.web.context.ContextLoader - Context initialization failed
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'dataSource': Invocation of init method failed; nested exception is javax.naming.NameNotFoundException: Name jdbc is not bound in this Context
What should I do to properly define the datasource?
The context.xml file must be in the META-INF directory of the war file. It must not be in the classes directory or in a jar file.
Put the META-INF directory with the context.xml in the directory containing the root of the webapp in your source folder tree.