Could not resolve view with name X in servlet with name Y - spring

Question

I am using Spring and AngularJS for a rest web application. Base on this tutorial and based on this tutorial I've created the following folder structure:
-src
|----main
|----webapp
|----static
|----api
|----assets
|----resources
|----sections
|----services
|----index.html
|----WEB-INF
|----web.xml
|----spring
|----dispatcher-servlet.xml
|----applicationContext.xml
I want to serve static HTML files so I declared the resources as following:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd">
<mvc:annotation-driven></mvc:annotation-driven>
<context:component-scan base-package="org.tools.mvc.controllers"></context:component-scan>
<mvc:resources location="/static/" mapping="/**"/>
<mvc:resources location="/static/api/" mapping="/api/**"/>
<mvc:resources location="/static/assets/" mapping="/assets/**"/>
<mvc:resources location="/static/resources/" mapping="/resources/**"/>
<mvc:resources location="/static/services/" mapping="/services/**"/>
<mvc:resources location="/static/sections/home/" mapping="/sections/home/**"/>
<bean name="viewResolver" class="org.springframework.web.servlet.view.BeanNameViewResolver"></bean>
<bean name="jsonTemplate" class="org.springframework.web.servlet.view.json.MappingJackson2JsonView"></bean>
My problem is that when I deploy the application( I am using Glassfish server) the following error occurs( in Eclipse console and also in the browser page):
2016-05-27T04:46:06.640-0700|Warning: StandardWrapperValve[dispatcher]: Servlet.service() for servlet dispatcher threw exception
javax.servlet.ServletException: Could not resolve view with name 'index.html' in servlet with name 'dispatcher'
The functionality of the service is not affected( using Postman to test the rest api results in success). Until now, in order to further develop the application I manually added index.html to the end of the URL(like localhost:8080/status/index.html). The source of the "/" as declared in Web Deployment Assembly is:
Source: /src/main/webapp
Deploy Path: /
Update: The web.xml file is looking like this:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" version="3.1">
<display-name>status</display-name>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/applicationContext.xml</param-value>
</context-param>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/dispatcher-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
How can I resolve this error?
Thank you
P.S The solutions found on SO didn't applied to my scenario.

Answer 1

I discovered that I've declared a view resolver ( BeanNameViewResolver) inside applicationContext.xml. After deleting the view resolver, I didn't receive the error.
The error occurred because Spring was trying to interpret my view( witch was a html static file) to a bean.