I have a file like below format:
$ cat file_in.csv
1308123;28/01/2019;28/01/2019;22/01/2019
1308456;20/11/2018;27/11/2018;09/11/2018;15/11/2018;10/11/2018;02/12/2018
1308789;06/12/2018;04/12/2018
1308012;unknown
How can i transpose as below, starting from second column:
1308123;28/01/2019
1308123;28/01/2019
1308123;22/01/2019
1308456;20/11/2018
1308456;27/11/2018
1308456;09/11/2018
1308456;15/11/2018
1308456;10/11/2018
1308456;02/12/2018
1308789;06/12/2018
1308789;04/12/2018
1308012;unknown
I'm testing my script, but obtain a wrong result
echo "123;23/05/2018;24/05/2018" | awk -F";" 'NR==3{a=$1";";next}{a=a$1";"}END{print a}'
Thanks in advance
1st Solution: Eaisest solution will be, loop through all fields(off course have set field separator as ;) and then print $1 along with all fields in new line. Also note that loop is running from i=2 to till value of NF leaving first field since we need to print in new line from column 2nd onwards.
awk 'BEGIN{FS=OFS=";"} {for(i=2;i<=NF;i++){print $1,$i}}' Input_file
2nd Solution: Using 1 time substitution(sub) and global substitutions(gsub) functionality of awk. Here I am changing very first occurence of ; with ###(assumed that your Input_file will NOT have this characters together, in case it is there choose any unique character(s) which are NOT in one's Input_file on place of ###), then globally subsituting ;(all occurences) with ORS val(a variable which has value of $1) and ; so make values in new column. Now finally remove ### from first field. Why we have done this approch if we DO NOT substitute very first occurence of ; with any other character then it will place a NEW LINE before substituion which we DO NOT want to have. (Also as per Ed sir's comment this solution was tested in 1 Input_file and may have issues while reading multiple Input_files)
awk 'BEGIN{FS=OFS=";"} {val=$1;sub(";","###");gsub(";",ORS val ";");sub("###",";",$1)} 1' Input_file
Another awk
awk -F";" '{ OFS="\n" $1 ";"; $1=$1;$1=""; printf("%s",$0) } ' file
Related
I have a line containing this string:
$DLOAD , 123 , Loadcase name=SUBCASE_1
I am trying to only print SUBCASE_1. Here is my code, but I get a syntax error.
awk -F, '{n=split($3,a,"="); a[n]} {printf(a[1]}' myfile
How can I fix this?
1st solution: In case you want only to get last field(which contains = in it) then with your shown samples please try following
awk -F',[[:space:]]+|=' '{print $NF}' Input_file
2nd solution: OR in case you want to get specifically 3rd field's value after = then try following awk code please. Simply making comma followed by space(s) as field separator and in main program splitting 3rd field storing values into arr array, then printing 2nd item value of arr array.
awk -F',[[:space:]]+' '{split($3,arr,"=");print arr[2]}' Input_file
Possibly the shortest solution would be:
awk -F= '{print $NF}' file
Where you simply use '=' as the field-separator and then print the last field.
Example Use/Output
Using your sample into in a heredoc with the sigil quoted to prevent expansion of $DLOAD, you would have:
$ awk -F= '{print $NF}' << 'eof'
> $DLOAD , 123 , Loadcase name=SUBCASE_1
> eof
SUBCASE_1
(of course in this case it probably doesn't matter whether $DLOAD was expanded or not, but for completeness, in case $DLOAD included another '=' ...)
I have two sorted files in question
1)one is a control file(ctrl.txt) which is external process generated
2)and other is line count file(count.txt) that I generate using `wc -l`
$more ctrl.txt
Thunderbird|1000
Mustang|2000
Hurricane|3000
$more count.txt
Thunder_bird|1000
MUSTANG|2000
Hurricane|3001
I want to compare these two files ignoring wrinkles in column1(filenames) such as "_" (for Thunder_bird) or "upper case" (for MUSTANG) so that my output only shows below file as the only real different file for which counts dont match.
Hurricane|3000
I have this idea to only compare second column from both the files and output whole line if they are different
I have seen other examples in AWK but I could not get anything to work.
Could you please try following awk and let me know if this helps you.
awk -F"|" 'FNR==NR{gsub(/_/,"");a[tolower($1)]=$2;next} {gsub(/_/,"")} ((tolower($1) in a) && $2!=a[tolower($1)])' cntrl.txt count.txt
Adding a non-one liner form of solution too now.
awk -F"|" '
FNR==NR{
gsub(/_/,"");
a[tolower($1)]=$2;
next}
{ gsub(/_/,"") }
((tolower($1) in a) && $2!=a[tolower($1)])
' cntrl.txt count.txt
Explanation: Adding explanation too here for above code.
awk -F"|" ' ##Setting field seprator as |(pipe) here for all lines in Input_file(s).
FNR==NR{ ##Checking condition FNR==NR which will be TRUE when first Input_file(cntrl.txt) in this case is being read. Following instructions will be executed once this condition is TRUE.
gsub(/_/,""); ##Using gsub utility of awk to globally subtitute _ with NULL in current line.
a[tolower($1)]=$2; ##Creating an array named a whose index is first field in LOWER CASE to avoid confusions and value is $2 of current line.
next} ##next is awk out of the box keyword which will skip all further instructions now.(to make sure they are read when 2nd Input-file named count.txt is being read).
{ gsub(/_/,"") } ##Statements from here will be executed when 2nd Input_file is being read, using gsub to remove _ all occurrences from line.
((tolower($1) in a) && $2!=a[tolower($1)]) ##Checking condition here if lower form of $1 is present in array a and value of current line $2 is NOT equal to array a value. If this condition is TRUE then print the current line, since I have NOT given any action so by default printing of current line will happen from count.txt file.
' cntrl.txt count.txt ##Mentioning the Input_file names here which we have to pass to awk.
I have a .txt file like this:
ENST00000000442 64073050 64074640 64073208 64074651 ESRRA
ENST00000000233 127228399 127228552 ARF5
ENST00000003100 91763679 91763844 CYP51A1
I want to get only the last 3 columns of each line.
as you see some times there are some empty lines between 2 lines which must be ignored. here is the output that I want to make:
64073208 64074651 ESRRA
127228399 127228552 ARF5
91763679 91763844 CYP51A1
awk '/a/ {print $1- "\t" $-2 "\t" $-3}' file.txt.
it does not return what I want. do you know how to correct the command?
Following awk may help you in same.
awk 'NF{print $(NF-2),$(NF-1),$NF}' OFS="\t" Input_file
Output will be as follows.
64073208 64074651 ESRRA
127228399 127228552 ARF5
91763679 91763844 CYP51A1
EDIT: Adding explanation of command too now.(NOTE this following command is for only explanation purposes one should run above command only to get the results)
awk 'NF ###Checking here condition NF(where NF is a out of the box variable for awk which tells number of fields in a line of a Input_file which is being read).
###So checking here if a line is NOT NULL or having number of fields value, if yes then do following.
{
print $(NF-2),$(NF-1),$NF###Printing values of $(NF-2) which means 3rd last field from current line then $(NF-1) 2nd last field from line and $NF means last field of current line.
}
' OFS="\t" Input_file ###Setting OFS(output field separator) as TAB here and mentioning the Input_file here.
You can use sed too
sed -E '/^$/d;s/.*\t(([^\t]*[\t|$]){2})/\1/' infile
With some piping:
$ cat file | tr -s '\n' | rev | cut -f 1-3 | rev
64073208 64074651 ESRRA
127228399 127228552 ARF5
91763679 91763844 CYP51A1
First, cat the file to tr to squeeze out repeted \ns to get rid of empty lines. Then reverse the lines, cut the first three fields and reverse again. You could replace the useless cat with the first rev.
IE:
File:
1234:abcd
1234:930
1234:999999
194:keee
194:284
194:222222
Result:
1234:abcd:930:999999
194:kee:284:222222
I have exhausted my brain to the best of my knowledge and can't come up with a way. Sorry to bother you guys!
$ awk -F: '$1==last {printf ":%s",$2; next} NR>1 {print "";} {last=$1; printf "%s",$0;} END{print "";}' file
1234:abcd:930:999999
194:keee:284:222222
How it works
-F:
This tells awk to use a : as the field separator.
$1==last {printf ":%s",$2; next}
If the first field of this line is the same as the first field of the last line, print a colon followed by field 2. Then, skip the rest of the commands and start over with the next line.
NR>1 {print "";}
If we get here, that means that this line has a new not-seen-before value of the first field. If this not the first line, we finish the last line by printing a newline character.
{last=$1; printf "%s",$0;}
Update the variable last with the new value of field 1. Then, print this line.
END{print "";}
After we reach the end of the file, print one last newline character.
Combining non-consecutive lines
Consider this test file:
$ cat testfile2
3:abcd
4:abcd
10:123
3:999
4:999
10:123
Apply this awk script:
$ awk -F: '{a[$1]=a[$1]":"$2;} END{for (x in a) print x ":" substr(a[x],2);}' testfile2
3:abcd:999
4:abcd:999
10:123:123
In this approach, the lines will not necessarily come out in any particular order. If order is important, you may want to pipe this output to sort.
I have to process a file with data organized like this
AAAAA:BB:CCC:EEEE:DDDD
FF:III:JJJ:KK:LLL
MMMM:NN:OOO:PP
etc
Columns can have different length but lines always have the same number of columns.
I want to be able to cut a specific column of a given line and change it to the value I want.
For example I'd apply my command and change the file to
AAAAA:BB:XXXX:EEEE:DDDD
FF:III:JJJ:KK:LLL
MMMM:NN:OOO:PP
I know how to select a specific line with sed and then cut the field but I have no idea on how to replace the field with the value I have.
Thanks
Here's a way to do it with awk:
Going with your example, if you wanted to replace the 3rd field of the 1st line:
awk 'BEGIN{FS=OFS=":"} {if (NR==1) {$3 = "XXXX"}; print}' input_file
Input:
AAAAA:BB:CCC:EEEE:DDDD
FF:III:JJJ:KK:LLL
MMMM:NN:OOO:PP
Output:
AAAAA:BB:XXXX:EEEE:DDDD
FF:III:JJJ:KK:LLL
MMMM:NN:OOO:PP
Explanation:
awk: invoke the awk command
'...': everything enclosed by single-quotes are instructions to awk
BEGIN{FS=OFS=":"}: Use : as delimiters for both input and output. FS stands for Field Separator. OFS stands for Output Field Separator.
if (NR==1) {$3 = "XXXX"};: If Number of Records (NR) read so far is 1, then set the 3rd field ($3) to "XXXX".
print: print the current line
input_file: name of your input file.
If instead what you are trying to accomplish is simply replace all occurrences of CCC with XXXX in your file, simply do:
sed -i 's/CCC/XXXX/g` input_file
Note that this will also replace partial matches, such as ABCCCDD -> ABXXXXDD
This might work for you (GNU sed):
sed -r 's/^(([^:]*:?){2})CCC/\1XXXX/' file
or
awk -F: -vOFS=: '$3=="CCC"{$3="XXXX"};1' file