I want to split the last string from given path, that string contains some numbers like 1.625.235, but this numbers vary every time. Irrespective of the number that last string should be split.
Ex:
string = "C:/chef/cache/Dynatrace-OneAgent-Windows-1.625.235.msi"
output: Dynatrace-OneAgent-Windows-1.625.235.msi
string = "C:/chef/cache/Dynatrace-OneAgent-Windows-1.181.539.msi"
output: Dynatrace-OneAgent-Windows-1.181.539.msi
This is what we tried
("C:/chef/cache/Dynatrace-OneAgent-Windows-/\d.\d+.\d+/.msi").split('/')[3]
("C:/chef/cache/Dynatrace-OneAgent-Windows-'/\d.\d+.\d+/'.msi").split('/')[3]
("C:/chef/cache/Dynatrace-OneAgent-Windows-'\d.\d+.\d+'.msi").split('/')[3]
("C:/chef/cache/Dynatrace-OneAgent-Windows-'(\d.\d+.\d+').msi").split('/')[3]
("C:/chef/cache/Dynatrace-OneAgent-Windows-('/\d.\d+.\d+/').msi").split('/')[3]
("C:/chef/cache/Dynatrace-OneAgent-Windows-('\d.\d+.\d+').msi").split('/')[3]
If the output you want is always the filename at the end of a path, you could also use File.basename.
string = "C:/chef/cache/Dynatrace-OneAgent-Windows-1.625.235.msi"
output = File.basename(string) # => "Dynatrace-OneAgent-Windows-1.625.235.msi"
string="C:/chef/cache/Dynatrace-OneAgent-Windows-1.625.235.msi"
p string.split("/").last
output
"Dynatrace-OneAgent-Windows-1.625.235.msi"
Related
I am newbie in ruby. In my ruby program, there is a part of code for parsing geocode. The code is like below:
string = "GPS:3;S23.164865;E113.428970;88"
info = string.tr("GPS:",'')
info_array = info.split(";")
puts "GPS: #{info_array[0]},#{info_array[1]},#{info_array[2]}"
The code should split the string into 3 piece: 3, S23.164865 and E113.428970;88 and the expected output is
GPS: 3,S23.164865,E113.428970
but the result is:
GPS: 3,23.164865,E113.428970
Yes, the 'S' letter disappered...
If I use
string = "GPS:3;N23.164865;E113.428970;88"
info = string.tr("GPS:",'')
info_array = info.split(";")
puts "GPS: #{info_array[0]},#{info_array[1]},#{info_array[2]}"
, it prints expected result
GPS: 3,N23.164865,E113.428970
I am very confused why this happens. Can you help?
It looks like you were expecting String#tr to behave like String#gsub.
Calling string.tr("GPS:", '') does not replace the complete string "GPS:" with the empty string. Instead, it replaces any character from within the string "GPS:" with an empty string. Commonly you will find .tr() called with an equal number of input and replacement characters, and in that case the input character is replaced by the output character in the corresponding position. But the way you have called it with only the empty string '' as its translation argument, will delete any of G, P, S, : from anywhere within the string.
>> "String with S and G and a: P".tr("GPS:", '')
=> "tring with and and a "
Instead, use .gsub('GPS:', '') to replace the complete match as a group.
string = "GPS:3;S23.164865;E113.428970;88"
info = string.gsub('GPS:', '')
info_array = info.split(";")
puts "GPS: #{info_array[0]},#{info_array[1]},#{info_array[2]}"
# prints
GPS: 3,S23.164865,E113.428970
Here we've called .gsub() with a string argument. It is probably more often called with a regexp search match argument though.
Given a string like:
abc_1234 xyz def_123aa4a56
I want to replace parts of it so the output is:
abc_*******z def_*******56
The rules are:
abc_ and def_ are kind of delimiters, so anything between the two are part of the previous delimiter string.
The string between the abc_ and def_, and the next delimited string should be replaced by *, except for the last 2 characters of that substring. In the above example, abc_1234 xyz (note trailing space), got turned into abc_*******z
prefixes = %w|abc_ def_|
input = "Hello abc_111def_frg def_333World abc_444"
input.gsub(/(#{Regexp.union(prefixes)})../, "\\1**")
#⇒ "Hello abc_**1def_**g def_**3World abc_**4"
Is this what you are looking for?
str = "Hello abc_111def_frg def_333World abc_444"
str.scan(/(?<=abc_|def_)(?:[[:alpha:]]+|[[:digit:]]+)/)
# => ["111", "frg", "333", "444"]
I've assumed the string following "abc_" or "def_" is either all digits or all letters. It won't work if, for example, you wished to extract "a1b" from "abc_a1b cat". You need to better define the rules for what terminates the strings you want.
The regular expression reads, "Following the string "abc_" or "def_" (a positive lookbehind that is not part of the match), match a string of digits or a string of letters".
Given:
> s
=> "abc_1234 xyz def_123aa4a56"
You can do:
> s.gsub(/(?<=abc_|def_)(.*?)(..)(?=(?:abc_|def_|$))/) { |m| "*" * $1.length<<$2 }
=> "abc_*******z def_*******56"
string = 'xabcdexfghijk'
In the example above, 'x' appears twice. I want to capture everything between the first 'x' and the next 'x'. Thus, the desired result is a new string that equals 'xabcdex'. Any ideas?
You could use a simple regular expression: /x.*?x/. This basically means "match any characters in between two x characters, as few times as possible (non-greedy)".
The matched text can be extracted with String#[regexp]
string = 'xabcdexfghijk'
string[/x.*?x/] # => "xabcdex"
I have the following code which is supposed to be removing a particular email address from a string if it exists. The problem is i get the error "invalid range "y-d" in string transliteration (ArgumentError)" which I assume is because it's treating my input as a regex. I will need to do this delete by a variable in the actual code, not a string literal but this is a simplified version of the problem.
So how do I properly perform this operation?
myvar = "test1#my-domain.com test2#my-domain.com"
myvar = myvar.delete("test1#my-domain.com")
Try
myvar = "test1#my-domain.com test2#my-domain.com"
myvar = myvar.gsub("test1#my-domain.com", '').strip
String#delete(str) does not delete the literal string str but builds a set out of individual characters of str and deletes all occurrences of these characters. try this:
"sets".delete("test")
=> ""
"sets".delete("est")
=> ""
The hyphen has a special meaning, it defines a range of characters. String#delete("a-d") will delete all occurrences of a,b,c and d characters. Range boundary characters should be given in ascending order: you should write "a-d" but not "d-a".
In your original example, ruby tries to build a character range from y-d substring and fails.
Use String#gsub method instead.
You can do it like this
myvar = "test1#my-domain.com test2#my-domain.com"
remove = "test1#my-domain.com"
myvar.gsub!(remove, "")
I have strings like this:
https://www.facebook.com/username_with_number_14/posts/101505775425654414
https://www.facebook.com/username/posts/101505775425654466
I need to extract the number on the end of the string in Ruby. In the first string, it is the second and last number, whereas in the second string it is the first, only and last number.
At the moment I am extracting the number like this:
int1 = Regexp.new('.*?(\\d+)',Regexp::IGNORECASE).match()[1]
But when this is applied to the first string, it extracts the number part of the username, not the desired number.
How can I do it so that it will work on both strings?
text = <<ENDTEXT
https://www.facebook.com/username_with_number_14/posts/101505775425654414
https://www.facebook.com/username/posts/101505775425654466
ENDTEXT
p text.lines.map{|line| line.scan(/\d+/).last}
#=> ["101505775425654414", "101505775425654466"]
for me works regexp like this:
^.*?(\d+)$
look here: http://rubular.com/r/CJzsgjedqJ
Try this
int1 = Regexp.new('.*\\/(\\d+)$',Regexp::IGNORECASE).match()[1]
The $ matches the end of the string. So I put all numbers from the last / to the end of the string into the capturing group 1.