I've tried find all days between 2 dates and I have a query here
with tmp as(
select 1 sno, to_date('20181227', 'YYYYMMDD') curr_date, to_date('20181231', 'YYYYMMDD') curr_date2 from dual
union all
select 2 sno, to_date('20181227', 'YYYYMMDD'), to_date('20181231', 'YYYYMMDD') from dual
)
SELECT sno, curr_date + level - 1 DAY, LEVEL
FROM tmp
CONNECT BY curr_date + level -1 <= curr_date2
But I received duplicate result and I found because of missing START WITH clause here but I don't know START WITH where!!
I still can't find any solution to remove duplicate at result.
Use the prior + sys_guid method.
...
CONNECT BY curr_date + level -1 <= curr_date2
and prior sno = sno
and prior sys_guid() is not null;
DEMO
Related
I have month and year values from select list, concatenated them in a string. If TO_DATE is applied on the string, that returns 'not a valid month' error.
Below is my code snippet,
V_DATE_FROM_STR_TEST := TRIM('01-'||TRIM(TO_CHAR(:P3_FROM_MONTH))||'-'||TRIM(TO_CHAR(:P3_YEAR)));
V_DATE_TO_STR_TEST := TRIM('01-'||TRIM(TO_CHAR(:P3_TO_MONTH))||'-'||TRIM(TO_CHAR(:P3_YEAR)));
Error 'not a valid month' occurs on this line,
TRUNC(TO_DATE(V_DATE_FROM_STR_TEST, 'DD-MON-YYYY'))
I have tried printing by HTP.PRN(V_DATE_FROM_STR_TEST) that shows date 01-JAN-2020.
Adding LOVs
Month LOV
select to_char(add_months(trunc(sysdate, 'yyyy'), level - 1), 'MONTH') d,
to_char(add_months(trunc(sysdate, 'yyyy'), level - 1), 'MON') r
from dual
connect by level <= 12
Year LOV
select YEAR d, YEAR r
from (select to_number(to_char(sysdate,'yyyy')) -8 YEAR
from dual
UNION
select to_number(to_char(sysdate,'yyyy')) -7 YEAR
from dual
UNION
select to_number(to_char(sysdate,'yyyy')) -6 YEAR
from dual
UNION
select to_number(to_char(sysdate,'yyyy')) -5 YEAR
from dual
UNION
select to_number(to_char(sysdate,'yyyy')) -4 YEAR
from dual
UNION
select to_number(to_char(sysdate,'yyyy')) -3 YEAR
from dual
UNION
select to_number(to_char(sysdate,'yyyy')) -2 YEAR
from dual
UNION
select to_number(to_char(sysdate,'yyyy')) -1 YEAR
from dual
UNION
select to_number(to_char(sysdate,'yyyy')) YEAR
from dual
) order by year desc
I am guessing there are some unwanted character is added in the date string from select list value, how can I remove that?
If you switch to digits, things might improve.
Month LoV: display words, but return numbers:
select to_char(add_months(trunc(sysdate, 'yyyy'), level - 1), 'MONTH') d,
level r
from dual
connect by level <= 12;
Then use this for the resulting string:
to_date(lpad(:P3_FROM_MONTH, 2, '0') || :P3_YEAR, 'mmyyyy')
Also, all those TRIMs look unnecessary, but OK - I understand - you tried to fix the problem.
While not directly referenced you can simplify your "Year LOV" query.
select yr d, yr r
from ( select extract(year from sysdate)-level +1 yr
from dual
connect by level <= 9
)
order by yr desc;
I am trying to implement the same in redshift and i am finding it little difficult to do that. Since redshift is in top of postgresql engine, if any one can do it in postgresql it would be really helpfull. Basically the code gets the count for previous two month at column level. If there is no count for exact previous month then it gives 0.
This is my code:
with abc(dateval,cnt) as(
select 201908, 100 from dual union
select 201907, 200 from dual union
select 201906, 300 from dual union
select 201904, 600 from dual)
select dateval, cnt,
last_value(cnt) over (order by dateval
range between interval '1' month preceding
and interval '1' month preceding ) m1,
last_value(cnt) over (order by dateval
range between interval '2' month preceding
and interval '2' month preceding ) m2
from (select to_date(dateval, 'yyyymm') dateval, cnt from abc)
I get error in over by clause. I tried to give cast('1 month' as interval) but still its failing. Can someone please help me with this windows function.
expected output:
Regards
This is how I would do it. In Redshift there's no easy way to generate sequences, do I select row_number() from an arbitrary table to create a sequence:
with abc(dateval,cnt) as(
select 201908, 100 union
select 201907, 200 union
select 201906, 300 union
select 201904, 600),
cal(date) as (
select
add_months(
'20190101'::date,
row_number() over () - 1
) as date
from <an arbitrary table to generate a sequence of rows> limit 10
),
with_lag as (
select
dateval,
cnt,
lag(cnt, 1) over (order by date) as m1,
lag(cnt, 2) over (order by date) as m2
from abc right join cal on to_date(dateval, 'YYYYMM') = date
)
select * from with_lag
where dateval is not null
order by dateval
I have been running the below query without issue:
with Nums (NN) as
(
select 0 as NN
from dual
union all
select NN+1 -- (1)
from Nums
where NN < 30
)
select null as errormsg, trunc(sysdate)-NN as the_date, count(id) as the_count
from Nums
left join
(
SELECT c1.id, trunc(c1.c_date) as c_date
FROM table1 c1
where c1.c_date > trunc(sysdate) - 30
UNION
SELECT c2.id, trunc(c2.c_date)
FROM table2 c2
where c2.c_date > trunc(sysdate) -30
) x1
on x1.c_date = trunc(sysdate)-Nums.NN
group by trunc(sysdate)-Nums.NN
However, when I try to pop this in a proc for SSRS use:
procedure pr_do_the_thing (RefCur out sys_refcursor)
is
oops varchar2(100);
begin
open RefCur for
-- see above query --
;
end pr_do_the_thing;
I get
Error(): PL/SQL: ORA-00932: inconsistent datatypes: expected NUMBER got -
Any thoughts? Like I said above, as a query, there is no issue. As a proc, the error appears at note (1) int eh query.
This seems to be bug 18139621 (see MOS Doc ID 2003626.1). There is a patch available, but if this is the only place you encounter this, it might be simpler to switch to a hierarchical query:
with Nums (NN) as
(
select level - 1
from dual
connect by level <= 31
)
...
You could also calculate the dates inside the CTE (which also fails with a recursive CTE):
with Dates (DD) as
(
select trunc(sysdate) - level + 1
from dual
connect by level <= 31
)
select null as errormsg, DD as the_date, count(id) as the_count
from Dates
left join
(
SELECT c1.id, trunc(c1.c_date) as c_date
FROM table1 c1
where c1.c_date > trunc(sysdate) - 30
UNION
SELECT c2.id, trunc(c2.c_date)
FROM table2 c2
where c2.c_date > trunc(sysdate) -30
) x1
on x1.c_date = DD
group by DD;
I'd probably organise it slightly differently, so the subquery doesn't limit the date range directly:
with dates (dd) as
(
select trunc(sysdate) - level + 1
from dual
connect by level <= 31
)
select errormsg, the_date, count(id) as the_count
from (
select null as errormsg, d.dd as the_date, c1.id
from dates d
left join table1 c1 on c1.c_date >= d.dd and c1.c_date < d.dd + 1
union all
select null as errormsg, d.dd as the_date, c2.id
from dates d
left join table2 c2 on c2.c_date >= d.dd and c2.c_date < d.dd + 1
)
group by errormsg, the_date;
but as always with these things, check the performance of each approach...
Also notice that I've switched from union to union all. If an ID could appear more than once on the same day, in the same table or across both tables, then the counts will be different - you need to decide whether you want to count them once or as many times as they appear. That applies to your original query too.
I have two dates and I have to find out the number of Sundays and holidays fall between those two dates. Can I do this using BETWEEN? If so, how?
SELECT date1, date2, trunc(deposit_date - transaction_date) TOTAL
FROM Table_Name FULL OUTER JOIN Holidays ON date2 = hdate
WHERE hdate IN (date1, date2)
Using this I can definitely check whether there is a holiday on either of the two days, i.e. date1 or date2 but what I am not able to find out that whether there lies a holiday or a Sunday between these two dates. Help!
The solution you've posted is horribly inefficient; you can do all of this in a single SQL statement:
Firstly generate all possible dates between the two you have:
select trunc(:min_date) + level - 1
from dual
connect by level <= trunc(:min_date) - trunc(:max_date)
Then use your HOLIDAY table to restrict to what you want:
with all_dates as (
select trunc(:min_date) + level - 1 as the_date
from dual
connect by level <= trunc(:min_date) - trunc(:max_date)
)
select count(*)
from all_dates a
left outer join holiday b
on a.the_date = b.hdate
where b.hdate is null
and to_char(a.the_date, 'DY') <> 'SUN'
If you want to check if hdate is between the two dates you can query using
where hdate between date1 and date2
If you want to check if hdate is on the same day as date1 or date two you can query like this
where trunc(hdate) in (trunc(date1) ,trunc(date2))
The trunc function removed the time.
You should create a table with the holidays and maintain it on your own.
CREATE TABLE holidays
(
holiday VARCHAR2(100)
, d_date DATE
);
INSERT INTO holidays VALUES ('National Developer Day', DATE'2013-06-01');
SELECT *
FROM holidays;
-- National Developer Day 2013-06-01 00:00:00
The rest is just a matter of a SQL statment
Scenario 1: EXISTS
SELECT COUNT
(
CASE
WHEN TRIM(TO_CHAR(d.start_date_level, 'DAY')) = 'SUNDAY'
OR CASE
WHEN EXISTS (SELECT 1 FROM holidays h WHERE d.start_date_level = h.d_date)
THEN 1
ELSE NULL
END = 1
THEN 1
ELSE NULL
END
) AS holiday_check
FROM
(
SELECT start_date + (LEVEL - 1) AS start_date_level
FROM
(
SELECT start_date, end_date, end_date - start_date AS diff_date
FROM
(
SELECT TRUNC(ADD_MONTHS(SYSDATE, -2)) AS start_date
, TRUNC(SYSDATE) AS end_date
FROM DUAL
)
)
CONNECT BY
LEVEL <= (diff_date + 1)
) d
Scenario 2: LEFT JOIN
SELECT COUNT
(
CASE
WHEN TRIM(TO_CHAR(d.start_date_level, 'DAY')) = 'SUNDAY'
OR h.d_date IS NOT NULL
THEN 1
ELSE NULL
END
) AS holiday_check
FROM
(
SELECT start_date + (LEVEL - 1) AS start_date_level
FROM
(
SELECT start_date, end_date, end_date - start_date AS diff_date
FROM
(
SELECT TRUNC(ADD_MONTHS(SYSDATE, -2)) AS start_date
, TRUNC(SYSDATE) AS end_date
FROM DUAL
)
)
CONNECT BY
LEVEL <= (diff_date + 1)
) d
LEFT JOIN holidays h
ON d.start_date_level = h.d_date
9 Sundays + 1 "National Developer Day" = 10
CREATE OR REPLACE FUNCTION workdays (dt1 DATE, dt2 DATE) RETURN NUMBER IS
weekday_count NUMBER := 0;
date1 DATE := dt1;
date2 DATE := dt2;
cur_dt date;
holiday_count number;
begin
if date1 = date2 then
return 0;
end if;
cur_dt := transaction_date;
while cur_dt <= date2 loop
if cur_dt = date2 then
null;
else
SELECT count(*) INTO holiday_count
FROM holiday
WHERE hdate = cur_dt;
IF holiday_count = 0 THEN
IF to_char(cur_dt,'DY') NOT IN ('SUN') THEN
weekday_count := weekday_count + 1;
END IF;
END IF;
END IF;
cur_dt := cur_dt +1;
END LOOP;
RETURN weekday_count;
END;
And then I queried my database and got the right results. Do post if you have an optimal solution for this.
Here is an even better and efficient solution to the problem,
SELECT A.ID,
COUNT(A.ID) AS COUNTED
FROM tableA A
LEFT JOIN TableB B
ON A.tableB_id=B.id
LEFT JOIN holiday C
ON TRUNC(C.hdate) BETWEEN (TRUNC(a.date1) +1) AND TRUNC(B.date2)
WHERE c.hdate IS NOT NULL
GROUP BY A.ID;
where TableA contains date1 and tableB contains date2. Holiday contains the list of holidays and Sundays. And this query excludes 'date1' from the count.
RESULT LOGIC
trunc(date2) - trunc(date1) = x
x - result of the query
Make a table T$HOLIDAYS with your holidays (HDATE column). These dates will be excluded from calculation of working days within given period (sdate is start date and edate end date of period). Here is the function that calculates working days within given period excluding holidays, saturdays and sundays:
CREATE OR REPLACE FUNCTION WorkingDays(sdate IN DATE,edate IN DATE) RETURN NUMBER IS
days NUMBER;
BEGIN
WITH dates AS (SELECT sdate+LEVEL-1 AS d FROM DUAL CONNECT BY LEVEL<=edate-sdate+1)
SELECT COUNT(*) INTO days
FROM dates
WHERE d NOT IN (SELECT hdate FROM t$holidays) --exclude holidays
AND TO_CHAR(d,'D') NOT IN (6,7); --exclude saturdays + sundays
RETURN days;
END WorkingDays;
/
select sum(qq) from (
select case when to_number(to_char((trunc(sysdate-10) + level - 1),'D'))<=5 then 1 else 0 end as qq
from dual
connect by level <= trunc(sysdate) - trunc(sysdate-10))
The question I need to answer is this "What is the maximum number of page requests we have ever received in a 60 minute period?"
I have a table that looks similar to this:
date_page_requested date;
page varchar(80);
I'm looking for the MAX count of rows in any 60 minute timeslice.
I thought analytic functions might get me there but so far I'm drawing a blank.
I would love a pointer in the right direction.
You have some options in the answer that will work, here is one that uses Oracle's "Windowing Functions with Logical Offset" feature instead of joins or correlated subqueries.
First the test table:
Wrote file afiedt.buf
1 create table t pctfree 0 nologging as
2 select date '2011-09-15' + level / (24 * 4) as date_page_requested
3 from dual
4* connect by level <= (24 * 4)
SQL> /
Table created.
SQL> insert into t values (to_date('2011-09-15 11:11:11', 'YYYY-MM-DD HH24:Mi:SS'));
1 row created.
SQL> commit;
Commit complete.
T now contains a row every quarter hour for a day with one additional row at 11:11:11 AM. The query preceeds in three steps. Step 1 is to, for every row, get the number of rows that come within the next hour after the time of the row:
1 with x as (select date_page_requested
2 , count(*) over (order by date_page_requested
3 range between current row
4 and interval '1' hour following) as hour_count
5 from t)
Then assign the ordering by hour_count:
6 , y as (select date_page_requested
7 , hour_count
8 , row_number() over (order by hour_count desc, date_page_requested asc) as rn
9 from x)
And finally select the earliest row that has the greatest number of following rows.
10 select to_char(date_page_requested, 'YYYY-MM-DD HH24:Mi:SS')
11 , hour_count
12 from y
13* where rn = 1
If multiple 60 minute windows tie in hour count, the above will only give you the first window.
This should give you what you need, the first row returned should have
the hour with the highest number of pages.
select number_of_pages
,hour_requested
from (select to_char(date_page_requested,'dd/mm/yyyy hh') hour_requested
,count(*) number_of_pages
from pages
group by to_char(date_page_requested,'dd/mm/yyyy hh')) p
order by number_of_pages
How about something like this?
SELECT TOP 1
ranges.date_start,
COUNT(data.page) AS Tally
FROM (SELECT DISTINCT
date_page_requested AS date_start,
DATEADD(HOUR,1,date_page_requested) AS date_end
FROM #Table) ranges
JOIN #Table data
ON data.date_page_requested >= ranges.date_start
AND data.date_page_requested < ranges.date_end
GROUP BY ranges.date_start
ORDER BY Tally DESC
For PostgreSQL, I'd first probably write something like this for a "window" aligned on the minute. You don't need OLAP windowing functions for this.
select w.ts,
date_trunc('minute', w.ts) as hour_start,
date_trunc('minute', w.ts) + interval '1' hour as hour_end,
(select count(*)
from weblog
where ts between date_trunc('minute', w.ts) and
(date_trunc('minute', w.ts) + interval '1' hour) ) as num_pages
from weblog w
group by ts, hour_start, hour_end
order by num_pages desc
Oracle also has a trunc() function, but I'm not sure of the format. I'll either look it up in a minute, or leave to see a friend's burlesque show.
WITH ranges AS
( SELECT
date_page_requested AS StartDate,
date_page_requested + (1/24) AS EndDate,
ROWNUMBER() OVER(ORDER BY date_page_requested) AS RowNo
FROM
#Table
)
SELECT
a.StartDate AS StartDate,
MAX(b.RowNo) - a.RowNo + 1 AS Tally
FROM
ranges a
JOIN
ranges b
ON a.StartDate <= b.StartDate
AND b.StartDate < a.EndDate
GROUP BY a.StartDate
, a.RowNo
ORDER BY Tally DESC
or:
WITH ranges AS
( SELECT
date_page_requested AS StartDate,
date_page_requested + (1/24) AS EndDate,
ROWNUMBER() OVER(ORDER BY date_page_requested) AS RowNo
FROM
#Table
)
SELECT
a.StartDate AS StartDate,
( SELECT MIN(b.RowNo) - a.RowNo
FROM ranges b
WHERE b.StartDate > a.EndDate
) AS Tally
FROM
ranges a
ORDER BY Tally DESC