Ora-00932 - expected NUMBER got - - oracle

I have been running the below query without issue:
with Nums (NN) as
(
select 0 as NN
from dual
union all
select NN+1 -- (1)
from Nums
where NN < 30
)
select null as errormsg, trunc(sysdate)-NN as the_date, count(id) as the_count
from Nums
left join
(
SELECT c1.id, trunc(c1.c_date) as c_date
FROM table1 c1
where c1.c_date > trunc(sysdate) - 30
UNION
SELECT c2.id, trunc(c2.c_date)
FROM table2 c2
where c2.c_date > trunc(sysdate) -30
) x1
on x1.c_date = trunc(sysdate)-Nums.NN
group by trunc(sysdate)-Nums.NN
However, when I try to pop this in a proc for SSRS use:
procedure pr_do_the_thing (RefCur out sys_refcursor)
is
oops varchar2(100);
begin
open RefCur for
-- see above query --
;
end pr_do_the_thing;
I get
Error(): PL/SQL: ORA-00932: inconsistent datatypes: expected NUMBER got -
Any thoughts? Like I said above, as a query, there is no issue. As a proc, the error appears at note (1) int eh query.

This seems to be bug 18139621 (see MOS Doc ID 2003626.1). There is a patch available, but if this is the only place you encounter this, it might be simpler to switch to a hierarchical query:
with Nums (NN) as
(
select level - 1
from dual
connect by level <= 31
)
...
You could also calculate the dates inside the CTE (which also fails with a recursive CTE):
with Dates (DD) as
(
select trunc(sysdate) - level + 1
from dual
connect by level <= 31
)
select null as errormsg, DD as the_date, count(id) as the_count
from Dates
left join
(
SELECT c1.id, trunc(c1.c_date) as c_date
FROM table1 c1
where c1.c_date > trunc(sysdate) - 30
UNION
SELECT c2.id, trunc(c2.c_date)
FROM table2 c2
where c2.c_date > trunc(sysdate) -30
) x1
on x1.c_date = DD
group by DD;
I'd probably organise it slightly differently, so the subquery doesn't limit the date range directly:
with dates (dd) as
(
select trunc(sysdate) - level + 1
from dual
connect by level <= 31
)
select errormsg, the_date, count(id) as the_count
from (
select null as errormsg, d.dd as the_date, c1.id
from dates d
left join table1 c1 on c1.c_date >= d.dd and c1.c_date < d.dd + 1
union all
select null as errormsg, d.dd as the_date, c2.id
from dates d
left join table2 c2 on c2.c_date >= d.dd and c2.c_date < d.dd + 1
)
group by errormsg, the_date;
but as always with these things, check the performance of each approach...
Also notice that I've switched from union to union all. If an ID could appear more than once on the same day, in the same table or across both tables, then the counts will be different - you need to decide whether you want to count them once or as many times as they appear. That applies to your original query too.

Related

How to generate a start_no and end_no of 1000 split from a table where in it contains numbers from 944900000 to 944999999 using oracle sql

The table contains numbers from 944900000 to 944999999 and i want to split these numbers into ranges of 1000 each like
944900000 to 944900999 -- 1000
944901000 to 944901999 -- 1000
..
..
944999000 to 944999999 -- 1000
is there any way to generate this through oracle SQL not with PL/SQL
You could also use this.
--Your data
CREATE TABLE your_table(your_column) AS
SELECT 944900000 + LEVEL - 1
FROM dual
CONNECT BY 944900000 + LEVEL < 944999999 + 2
;
--from 944900000 to 944999999
WITH cte AS (
SELECT your_column, CASE WHEN MOD(your_column, 1000) = 0 THEN your_column END start_range
FROM your_table
)
SELECT start_range, end_range
FROM (
SELECT start_range, CASE WHEN start_range IS NOT NULL THEN LEAD(your_column, 999)OVER(ORDER BY your_column) END end_range
FROM cte
)T
WHERE end_range IS NOT NULL /*because of the last execution of lead function in the inline view t*/
GROUP BY start_range, end_range
ORDER BY 1, 2
;
You could use ROW_NUMBER to number all records according to increasing number value. Then, compute a DENSE_RANK using the "group" of increments of 1000 to which each record belongs.
WITH cte AS (
SELECT t.*, ROW_NUMBER OVER (ORDER BY col) rn
FROM yourTable t
),
cte2 AS (
SELECT t.*, DENSE_RANK() OVER (ORDER BY FLOOR(rn / 1000)) dr
FROM cte t
)
SELECT *
FROM cte2
WHERE dr = 2; -- e.g. for 2nd partition of 1000 records

Oracle adding a subquery in a CTE

I have the following setup, which works fine and generates output as expected.
I'm trying to add the locations subquery into the CTE so my output will have a random location_id for each row.
The subquery is straight forward and should work but I am getting syntax errors when I try to place it into the 'data's CTE. I was hoping someone could help me out.
CREATE TABLE employees(
employee_id NUMBER(6),
emp_name VARCHAR2(30)
);
INSERT INTO employees(
employee_id,
emp_name
) VALUES
(1, 'John Doe');
INSERT INTO employees(
employee_id,
emp_name
) VALUES
(2, 'Jane Smith');
INSERT INTO employees(
employee_id,
emp_name
) VALUES
(3, 'Mike Jones');
CREATE TABLE locations AS
SELECT level AS location_id,
'Door ' || level AS location_name
FROM dual
CONNECT BY level <=
with rws as (
select level rn from dual connect by level <= 5 ),
data as ( select e.*,round (dbms_random.value(1,5)
) n from employees e)
select employee_id,
emp_name,
trunc (sysdate) + dbms_random.value (0, 5) AS random_date
from rws
join data d on rn <= n
order by employee_id;
-- trying to make this work
with rws as ( select level rn from dual connect by level <= 5 ),
data as ( select e.*, loc.location_id = (
select location_id
from locations order by dbms_random.value()
fetch first 1 row only
),
round (dbms_random.value(1,5)
) n from employees e )
select employee_id,
emp_name,
trunc (sysdate) + dbms_random.value (0, 5) AS random_date
from rws
join data d on rn <= n
order by employee_id;
You need to alias the subquery column expression, rather than trying to assign it to a [variable] name. So instead of this:
with rws as ( select level rn from dual connect by level <= 5 ),
data as ( select e.*, loc.location_id = (
select location_id
from locations order by dbms_random.value()
fetch first 1 row only
),
round (dbms_random.value(1,5)
) n from employees e )
you would do this:
with rws as (
select level rn
from dual
connect by level <= 5
),
data as (
select e.*,
(
select location_id
from locations
order by dbms_random.value()
fetch first 1 row only
) as location_id,
round (dbms_random.value(1,5)) as n
from employees e
)
db<>fiddle
But yes, you'll get the same location_id for each row, which probably isn't what you want.
There are probably better ways to avoid it (or to approach whatever you're actually trying to achieve) but one option is to force the subquery to be correlated by adding something like:
where location_id != -1 * e.employee_id
db<>fiddle
although that might be expensive. It's probably worth asking a new question about that specific aspect.
I am getting the same location_id for every employee_id, which I don't want either.
The subquery is in the wrong place then; move it to the main query, and correlate against both ID and n:
with rws as (
select level rn
from dual
connect by level <= 5
),
data as (
select e.*,
round (dbms_random.value(1,5)) as n
from employees e
)
select d.employee_id,
d.emp_name,
(
select location_id
from locations
where location_id != -1 * d.employee_id * d.n
order by dbms_random.value()
fetch first 1 row only
) as location_id,
trunc (sysdate) + dbms_random.value (0, 5) AS random_date
from rws r
join data d on r.rn <= d.n
order by d.employee_id;
db<>fiddle
Or move the location part to a new CTE, I suppose, with its own row number; and join that on one of your other generated values.

How to convert this code from oracle to redshift?

I am trying to implement the same in redshift and i am finding it little difficult to do that. Since redshift is in top of postgresql engine, if any one can do it in postgresql it would be really helpfull. Basically the code gets the count for previous two month at column level. If there is no count for exact previous month then it gives 0.
This is my code:
with abc(dateval,cnt) as(
select 201908, 100 from dual union
select 201907, 200 from dual union
select 201906, 300 from dual union
select 201904, 600 from dual)
select dateval, cnt,
last_value(cnt) over (order by dateval
range between interval '1' month preceding
and interval '1' month preceding ) m1,
last_value(cnt) over (order by dateval
range between interval '2' month preceding
and interval '2' month preceding ) m2
from (select to_date(dateval, 'yyyymm') dateval, cnt from abc)
I get error in over by clause. I tried to give cast('1 month' as interval) but still its failing. Can someone please help me with this windows function.
expected output:
Regards
This is how I would do it. In Redshift there's no easy way to generate sequences, do I select row_number() from an arbitrary table to create a sequence:
with abc(dateval,cnt) as(
select 201908, 100 union
select 201907, 200 union
select 201906, 300 union
select 201904, 600),
cal(date) as (
select
add_months(
'20190101'::date,
row_number() over () - 1
) as date
from <an arbitrary table to generate a sequence of rows> limit 10
),
with_lag as (
select
dateval,
cnt,
lag(cnt, 1) over (order by date) as m1,
lag(cnt, 2) over (order by date) as m2
from abc right join cal on to_date(dateval, 'YYYYMM') = date
)
select * from with_lag
where dateval is not null
order by dateval

Query with iteration in Oracle pl/sql

I have the following table with a single column
Z_NUM
--------
34545
345
656
32
42
...
I want to build a following dependence
i | SUM(Z_NUM)
----------------
2 | 40934
3 | 51244
4 | 54793
...
based on query
SELECT SUM(z_num) FROM table WHERE z_num < i;
The variable i is a parameter and should be incremented by 1.
How to implement this query in ORACLE?
If I were doing this in MYSQL, I would write something like
SELECT
​#n := #n + 1 n,
SUM(z_num)
FROM table, (SELECT #n := 1) m
WHERE z_num < n;
But unfortunately it does not work in Oracle PL/SQL.
Use two subqueries:
one with connect by to generate numbers i from 2 to N
another dependend subquery to calculate a sum for each i
SELECT i,
( SELECT coalesce( sum(z_num), 0 )
FROM table1 WHERE z_num < i
) as myresult
FROM (
SELECT level+1 As i FROM dual
CONNECT BY LEVEL <= ( SELECT max(Z_NUM) FROM table1 )-1
)
ORDER BY i
Demo: http://sqlfiddle.com/#!4/c460c/5
use ROWNUM,
SELECT SUM(z_num)
FROM (SELECT z_num, rownum rown
FROM table)
WHERE z_num < rown;
OR
SELECT SUM(z_num)
FROM (SELECT z_num, rownum rown
FROM table)
WHERE rown < 10;
Try this:
SELECT i,
( SELECT coalesce( sum(z_num), 0 )
FROM Table_NUM WHERE ROWNUM <= i
) as SUM(Z_NUM)
FROM (
SELECT level+1 As i FROM dual
CONNECT BY LEVEL <= ( SELECT Max(ROWNUM) FROM Table_NUM )-1
)
ORDER BY i;
Result:
I SUM_RESULT
-----------------
2 34890
3 35546
4 35578
5 35620
It may be help you.

How to write a table literal in Oracle?

A table with one column and one row can be created with:
select 'create' as col from dual;
This can be used to build table joins:
with
a as (select 'create' as ac from dual),
b as (select 'delete' as bc from dual)
select * from a left outer join b on (ac = bc);
Now I would like to have two rows. I did it in this way:
select 'create' as col from dual
union
select 'delete' as col from dual;
But is there a more compact notation for this? I tried
select ('create', 'delete') as col from dual;
but it does not work.
You can use collection type and TABLE operator, for example (works in Oracle 10g):
SQL> SELECT column_value FROM TABLE(SYS.ODCIVARCHAR2LIST('abc', 'def', 'ghi'));
COLUMN_VALUE
--------------------------------------------------------------------------------
abc
def
ghi
A couple of ways to generate rows. You could use rownum against a table with a larger number of rows:
SELECT roWnum AS a
FROM user_objects
WHERE rownum <= 3
You could use a hierarchical query:
SELECT level AS a
FROM dual
CONNECT BY LEVEL <= 3
EDIT: change int sequence to alpha sequence:
SELECT CHR( ASCII('a') + level - 1 )
FROM dual
CONNECT BY LEVEL <= 3

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