I need to make a POST request via cURL from the command line. Data for this request is located in a file. I know that via PUT this could be done with the --upload-file option.
curl host:port/post-file -H "Content-Type: text/xml" --data "contents_of_file"
You're looking for the --data-binary argument:
curl -i -X POST host:port/post-file \
-H "Content-Type: text/xml" \
--data-binary "#path/to/file"
In the example above, -i prints out all the headers so that you can see what's going on, and -X POST makes it explicit that this is a post. Both of these can be safely omitted without changing the behaviour on the wire. The path to the file needs to be preceded by an # symbol, so curl knows to read from a file.
I need to make a POST request via Curl from the command line. Data for this request is located in a file...
All you need to do is have the --data argument start with a #:
curl -H "Content-Type: text/xml" --data "#path_of_file" host:port/post-file-path
For example, if you have the data in a file called stuff.xml then you would do something like:
curl -H "Content-Type: text/xml" --data "#stuff.xml" host:port/post-file-path
The stuff.xml filename can be replaced with a relative or full path to the file: #../xml/stuff.xml, #/var/tmp/stuff.xml, ...
If you are using form data to upload file,in which a parameter name must be specified , you can use:
curl -X POST -i -F "parametername=#filename" -F "additional_parm=param2" host:port/xxx
Most of answers are perfect here, but when I landed here for my particular problem, I have to upload binary file (XLSX spread sheet) using POST method, I see one thing missing, i.e. usually its not just file you load, you may have more form data elements, like comment to file or tags to file etc as was my case. Hence, I would like to add it here as it was my use case, so that it could help others.
curl -POST -F comment=mycomment -F file_type=XLSX -F file_data=#/your/path/to/file.XLSX http://yourhost.example.com/api/example_url
I was having a similar issue in passing the file as a param. Using -F allowed the file to be passed as form data, but the content type of the file was application/octet-stream. My endpoint was expecting text/csv.
You are able to set the MIME type of the file with the following syntax:
-F 'file=#path/to/file;type=<MIME_TYPE>
So the full cURL command would look like this for a CSV file:
curl -X POST -F 'file=#path/to/file.csv;type=text/csv' https://test.com
There is good documentation on this and other options here: https://catonmat.net/cookbooks/curl/make-post-request#post-form-data
I had to use a HTTP connection, because on HTTPS there is default file size limit.
https://techcommunity.microsoft.com/t5/IIS-Support-Blog/Solution-for-Request-Entity-Too-Large-error/ba-p/501134
curl -i -X 'POST' -F 'file=#/home/testeincremental.xlsx' 'http://example.com/upload.aspx?user=example&password=example123&type=XLSX'
I'm trying to send a file using curl in windows.
Here's the command i'm using:
C:\curl>curl -X POST -F chat_id=#telegramchannel -F photo=#IMAGE.png https://api.telegram.org/bot812312342:XXXXXXXXXXXXXXXXXXXXXX/sendPhoto
and I keep getting this error:
curl: (26) Failed to open/read local data from file/application
does anybody know how to solve it and how to use the -F properly with files on windows?
Thanks
If telegramchannel is not a file, then you have to escape # with a backslash or use single quotes to encapsulate the content. As # has special meaning in curl context,
either
curl -X POST -F chat_id='#telegramchannel' -F photo=#IMAGE.png https://api.telegram.org/bot812312342:XXXXXXXXXXXXXXXXXXXXXX/sendPhoto
or
curl -X POST -F chat_id=\#telegramchannel -F photo=#IMAGE.png https://api.telegram.org/bot812312342:XXXXXXXXXXXXXXXXXXXXXX/sendPhoto
I want to download specific files in a HDFS directory, with their names starting with "total_conn_data_". Since I've got many files I want to write a bash script.
Here's what I do:
myPatternFile="total_conn_data_*.csv"
for filename in `curl -i -X GET "https://knox.blabla/webhdfs/v1/path/to/the/directory/?OP=LISTSTATUS" -u username`; do
curl -i -X GET "https://knox.blabla/webhdfs/v1/path/to/the/directory/$filename?OP=OPEN" -u username -L -o "./data/$filename" -k;
done
But it does not work since curl -i -X GET "https://knox.blabla/webhdfs/v1/path/to/the/directory/?OP=LISTSTATUS" -u username is sending back a json text and not file names.
How should I do? Thanks
curl provides output in json format only. you will have to use other tools like jquery and sed to format that output and get the list of files.
I need to do a curl upload with a file where I don't know the exact file name.
"curl
-F \"status=2\"
-F \"notify=1\"
-F \"ipa=#${FILE}\"
-F \"teams=${TEAM_ID}\"
-H \"X-HockeyAppToken: ${APITOKEN}\"
https://rink.hockeyapp.net/api/2/apps/${APPVERSION}/app_versions/upload"
This is done in gitlab-ci and the FILE variable is set to build/com.test.app_v*.ipa. The file I want to upload has a version number set and has the path build/com.test.app_v1.0.0.0.ipa. The problem I have now is that the * does not get expanded inside this curl call. I've tried it with an export before:
- export ABSOLUTE_FILENAME=${FILE}
- "curl
-F \"status=2\"
-F \"notify=1\"
-F \"ipa=#${ABSOLUTE_FILENAME}\"
-F \"teams=${TEAM_ID}\"
-H \"X-HockeyAppToken: ${APITOKEN}\"
https://rink.hockeyapp.net/api/2/apps/${APPVERSION}/app_versions/upload"
Still I'm gettin an error curl: (26) couldn't open file "build/com.test.app_v*.ipa" How can I expand the path to an absolute path before my curl upload?
With realpath command:
...
-F \"ipa=#$(realpath $FILE)\"
...
Trying to parse each line of a log file I am tailing to curl as a variable.
Currently I have this:
tail -f log.txt |
buffer |
while read -r LINE; do
curl -s -X POST https://api.com -d id=-123456 -d text="'$LINE'"
done
It's not really working and my goal is to output each line as a variable inside the text field: text=$LINE
How can I accomplish this? Is it an issue with the variable?