I have hundreds of images imported into var/import/images folder that have special characters and white spaces in them I need the special characters removed and white spaces replaced with a dash.
I need the following
replace white spaces with a dash
remove (
remove )
remove '
file types are png and jpg
images are on remote server
Create a renamer.php file with the following content:
<?php
foreach (glob('*[_\'\(\)\ ]*.{png,jpg,jpeg}', GLOB_BRACE) as $filename) {
$newName = str_replace(' ', '-', $filename);
$newName = preg_replace('/[\(\)\']/', '', $newName);
echo "mv \"$filename\" " . $newName . PHP_EOL;
// rename($filename, $newName);
}
Save the file in var/import/images and then
Run php -f renamer.php.
It will output the commands to rename the files, like this:
$ php -f renamer.php
mv "d'pool.png" dpool.png
mv "foo(bar).png" foobar.png
mv "hello_.png" hello_.png
mv "hello_world.png" hello_world.png
mv "hi world.png" hi-world.png
If you want it to rename the files for you, just uncomment the last line.
This question already has answers here:
Extract filename and extension in Bash
(38 answers)
Closed 1 year ago.
I'm trying to create a bash script that will move all files recursively from a source folder to a target folder, and simply rename files if they already exist. Similar to the way M$ Windows does, when a file exists it auto-renames it with "<filemame> (X).<ext>", etc. except for ALL files.
I've create the below, which works fine for almost all scenarios except when a folder has a (.) period in its name and a file within that folder has no extension (no period in its name).
eg a folder-path-file such as: "./oldfolder/this.folder/filenamewithoutextension"
I get (incorrectly):
"./newfolder/this (1).folder/filenamewithoutextension"
if "./newfolder/this.folder/filenamewithoutextension" already exist in the target location (./newfolder),
instead of correctly naming the new file: "./oldfolder/this.folder/filenamewithoutextension (1)"
#!/bin/bash
source=$1 ; target=$2 ;
if [ "$source" != "" ] && [ "$target" != "" ] ; then
#recursive file search
find "$source" -type f -exec bash -c '
#setup variables
oldfile="$1" ; osource='"${source}"' ; otarget='"${target}"' ;
#set new target filename with target path
newfile="${oldfile/${osource}/${otarget}}" ;
#check if file already exists at target
[ -f "${newfile}" ] && {
#get the filename and fileextension for numbering - ISSUE HERE?
filename="${newfile%/}" ; newfileext="${newfile##*.}" ;
#compare filename and file extension for missing extension
if [ "$filename" == "$newfileext" ] ; then
#filename has no ext - perhaps fix the folder with a period issue here?
newfileext="" ;
else
newfileext=".$newfileext" ;
fi
#existing files counter
cnt=1 ; while [ -f "${newfile%.*} (${cnt})${newfileext}" ] ; do ((cnt+=1)); done
#set new filename with counter - New Name created here *** Needs re-work, as folder with a period = fail
newfile="${newfile%.*} (${cnt})${newfileext}";
}
#show mv command
echo "mv \"$oldfile\" \"${newfile}\""
' _ {} \;
else
echo "Requires source and target folders";
fi
I suspect the issue is, how to properly identify the filename and extension, found in this line:
filename="${newfile%/}" ; newfileext="${newfile##*.}" which doesn't identify a filename properly (files are always after the last /).
Any suggestion on how to make it work properly?
UPDATED: Just some completion notes - Issues fixes with:
Initially Splitting each full path filename: path - filename - (optional ext)
Reconstructing the full path filename: path - filename - counter - (optional ext)
fixed the file move to ensure directory structure exists with mkdir -p (mv does not create new folders if they do not exist in the target location).
Maybe you could try this instead?
filename="${newfile##*/}" ; newfileext="${filename#*.}"
The first pattern means: remove the longest prefix (in a greedy way) up to the last /.
The second one: remove the prefix up to the first dot (the greedy mode seems unnecessary here) − and as you already noted, in case the filename contains no dot, you will get newfileext == filename…
Example session:
newfile='./oldfolder/this.folder/filenamewithoutextension'
filename="${newfile##*/}"; newfileext="${filename#*.}"
printf "%s\n" "$filename"
#→ filenamewithoutextension
printf "%s\n" "$newfileext"
#→ filenamewithoutextension
newfile='./oldfolder/this.folder/file.tar.gz'
filename="${newfile##*/}"; newfileext="${filename#*.}"
printf "%s\n" "$filename"
#→ file.tar.gz
printf "%s\n" "$newfileext"
#→ tar.gz
I have a FTP folder receiving files from a remote camera. The camera stores the video file name always as ./rec_YYYY-MM-DD_HH-MM.mkv. The video files are stored all in the same folder, the root folder from the FTP server.
I need to move these files to another folder, with this new scheme:
Remove rec_ from the file name.
Change date format to DD-MM-YY.
Remove date from the file name and make it a folder instead, where that same file and all the others in the same date will be stored in.
Final file path would be: ./DD-MM-YYYY/HH-MM.mkv.
The process would continue to all the files, putting them in the folder corresponding to the day it was created.
Summing up: ./rec_YYYY-MM-DD_HH-MM.mkv >> ./DD-MM-YYYY/HH-MM.mkv. The same should apply to all files that are in the same folder.
As I can't make it happen directly from the camera, this needs to be done with Bash on the server that is receiving the files.
So far, what I got is script, which would get the file's creation date and use it to make a folder, and then get creation time to move the file with the new name, based on it's creation time.:
for f in *.mp4
do
mkdir "$f" "$(date -r "$f" +"%d-%m-%Y")"
mv -n "$f" "$(date -r "$f" +"%d-%m-%Y/%H-%M-%S").mp4"
done
I'm getting this output (with testfile 1.mp4):
It creates the folder based on the file's creation date;
it renames the file to it's creation time;
Then, it returns mkdir: cannot create directory ‘1.mp4’: File exists
If two or more files, only one gets renamed and moved as described. The others stay the same and terminal returns:
mkdir: cannot create directory ‘1.mp4’: File exists
mkdir: cannot create directory ‘2.mp4’: File exists
mkdir: cannot create directory ‘12-12-2018’: File exists
Could someone help me out? Better suggestions? Thanks!
Honestly I would just use Perl or Python for this. Here's how to embed either in a shell script.
Here's a perl script that doesn't use any libraries, even ones that ship with Perl (so it'll work without extra packages on distributions like CentOS that don't ship with the entire Perl library). The perl script launches one new process per file in order to perform the copy.
perl -e '
while (<"*.m{p4,kv}">) {
my $path = $_;
my ($prefix, $year, $month, $day, $hour, $minute, $ext) =
split /[.-_]/, $path;
my $sec = q[00];
die "unexpected prefix ($prefix) in $path"
unless $prefix eq q[rec];
die "unexpected extension ($ext) in $path"
unless $ext eq q[mp4] or $ext eq q[mkv];
my $dir = "$day-$month-$year";
my $name = "$hour-$min-$sec" . q[.] . $ext;
my $destpath = $dir . q[/] . $name;
die "$dir . $name is unexpectedly a directory" if (-d $dir);
system("cp", "--", $path, $destpath);
}
'
Here's a Python example, it's compatible with either Python 2 or Python 3 but does use the standard library. The Python script does not spawn any additional processes.
python3 -c '
import os.path as path
import re
from glob import iglob
from itertools import chain
from os import mkdir
from shutil import copyfile
for p in chain(iglob("*.mp4"), iglob("*.mkv")):
fields = re.split("[-]|[._]", p)
prefix = fields[0]
year = fields[1]
month = fields[2]
day = fields[3]
hour = fields[4]
minute = fields[5]
ext = fields[6]
sec = "00"
assert prefix == "rec"
assert ext in ["mp4", "mkv"]
directory = "".join([day, "-", month, "-", year])
name = "".join([hour, "-", minute, "-", sec, ".", ext])
destpath = "".join([directory, "/", name])
assert not path.isdir(destpath)
try:
mkdir(directory)
except FileExistsError:
pass
copyfile(src=p, dst=destpath)
'
Finally, here's a bash solution. It splits paths using -, ., and _ and then extracts various subfields by indexing into $# inside a function. The indexing trick is portable, although regex substitution on variables is a bash extension.
#!/bin/bash
# $1 $2 $3 $4 $5 $6 $7 $8
# path rec YY MM DD HH MM ext
process_file() {
mkdir "$5-$4-$3" &> /dev/null
cp -- "$1" "$5-$4-$3"/"$6-$7-00.$8"
}
for path in *.m{p4,kv}; do
[ -e "$path" ] || continue
# NOTE: two slashes are needed in the substitution to replace everything
# read -a ARRAYVAR <<< ... reads the words of a string into an array
IFS=' ' read -a f <<< "${path//[-_.]/ }"
process_file "$path" "${f[#]}"
done
If you cd /to/some/directory/containing_your_files then you could use the following script
#!/usr/bin/env bash
for f in rec_????-??-??_??-??.m{p4,kv} ; do
dir=${f:4:10} # skip 4 chars ('rec_') take 10 chars ('YYYY_MM_DD')
fnm=${f:15} # skip 15 chars, take the remainder
test -d "$dir" || mkdir "$dir"
mv "$f" "$dir"/"$fnm"
done
note ① that I have not exchanged the years and the days, if you absolutely need to do the swap you can extract the year like this, year=${dir::4} etc and ② that this method of parameter substitution is a Bash-ism, e.g., it doesn't work in dash.
your problem is: mkdir creates folder but you are giving filename for folder creation.
if you want to use fileName for folder creation then use it without extension.
the thing is you are trying to create folder with the already existing fileName
I have a large data file that contains many joint files.
It has an separate index file has that file name, start + end byte of each file within the data file.
I'm needing help in creating a bash script to split the large file into it's 1000's of sub files.
Data File : fileafilebfilec etc
Index File:
filename.png<0>3049
folder\filename2.png<3049>6136.
I guess this needs to loop through each line of the index file, then using dd to extract the relevant bytes into a file. Maybe a fiddly part might be the folder structure bracket being windows style rather than linux style.
Any help much appreciated.
while read p; do
q=${p#*<}
startbyte=${q%>*}
endbyte=${q#*>}
filename=${p%<*}
count=$(($endbyte - $startbyte))
toprint="processing $filename startbyte: $startbyte endbyte: $endbyte count: $c$
echo $toprint
done <indexfile
Worked it out :-) FYI:
while read p; do
#sort out variables
q=${p#*<}
startbyte=${q%>*}
endbyte=${q#*>}
filename=${p%<*}
count=$(($endbyte - $startbyte))
#let it know we're working
toprint="processing $filename startbyte: $startbyte endbyte: $endbyte count: $c$
echo $toprint
if [[ $filename == *"/"* ]]; then
echo "have found /"
directory=${filename%/*}
#if no directory exists, create it
if [ ! -d "$directory" ]; then
# Control will enter here if $directory doesn't exist.
echo "directory not found - creating one"
mkdir ~/etg/$directory
fi
fi
dd skip=$startbyte count=$count if=~/etg/largefile of=~/etg/$filename bs=1
done <indexfile
Trying to get a bash script together, however I'm stuck at this. The rar is splited into x files, within the rar is 1 single file. What I'm doing is as below:
cd $dir
for rarfile in $(find -iname "*.part1.rar")
do
echo "Rar file: " $rarfile >> $dir/execute.log
name = $(unrar lb "$rarfile")
echo "Name of file inside rar container: " $name >> $dir/execute.log
extension ="${name##*.}"
echo "Extension: " $extension >> $dir/execute.log
filename = ${name%.*}
echo "Name: " $filename >> $dir/execute.log
# unrar x -y -o- $rarfile $uprar_dir
done
The excecute.log is as below:
Rar file: ./file.part1.rar
Name of file inside rar container:
Extension:
Name:
Cant seem to get the $name working. The unrar is however working fine as it should. Pls help.
in bash to assign value to a variable you cannot have spaces ie:
name=$(unrar lb "$rarfile")
instead of:
name = $(unrar lb "$rarfile")