I am using Laravel-5.8 Eloquent to run a query. I want to get the total trucks utilized by a particular client for all their trips without counting a truck twice. I used the query below, but there is repetition of trucks used more than once:
$truckcount = Trip::where('client_id', $userClientId)
->select(\DB::raw("COUNT(truck_no) as count"))
->distinct()
->get();
How do I write the correct Eloquent query to achieve this?
try this:
$truckcount = Trip::where('client_id', $userClientId)
->select(\DB::raw("COUNT(DISTINCT truck_no) as count"))
->get();
Related
I have problem with my eloquent query, i need to use data of my base model into whereRelation.
I tried this query bottom, but results was not what i except. The query return me all users who have one city relation, not only user who have city updated between my last user sync.
$users = People::whereRaw('TIMESTAMPDIFF(SECOND, people.latest_sync, people.updated_at) > 20')
->orWhereRelation('city', 'updated_at', '>', 'people.updated_at')
->get();
I'v tried people.updated_at and latest_sync in value of my Where Relation
Do i need to make pure SQL Raw query with classic join ?
PS: the first whereRaw is ok, and work (i really need)
$konten = Konten::all()->where('kategori','Announcement' AND 'kategori','Activities')->sortByDesc('id');
It's not work what is the right query for using AND Logic in query sir ? im so sorry i don't have much knowledge to find out the way.. the point is i want $konten contains the row from Konten where the kategori is Announcement and Activities.. how to make it happen ? it just showing konten where the kategori is activities the announcement not passed..
You can chain several where to achieve AND:
$konten = Konten::where('kategori', 'Announcement')
->where('kategori', 'Activities')
->orderBy('id', 'desc')
->get();
Or use whereIn like this:
$konten = Konten::whereIn('kategori', ['Announcement', 'Activities'])
->orderBy('id', 'desc')
->get();
To achieve an AND in Laravel, you simply chain ->where() calls:
$konten = Konten::where('kategori','Announcement')->where('kategori','Activities') ...
As a side note, Konten::all() returns a Collection, and is no longer database logic. You shouldn't call ::all() unless you specifically need every record in the database.
Refactor to the following:
$konten = Konten::where('kategori','Announcement')
->where('kategori','Activities')
->orderBy('id', 'desc')
->get();
This will leverage the database to perform the filtering/ordering, instead of offloading every record into a Collection and allowing PHP to perform the same logic, which can be incredibly inefficient depending on the number of records.
try this:
$konten = Konten::whereIn('kategori', ['Announcement', 'Activities'])->orderBy('id', 'desc')->get();
I have a strong feeling that you probably seek for 'orWhere' clause... If you want ALL records when kategori column equals 'Announcement' and all records when kategori equals 'Activities' you sholud use orWhere clause like so:
$konten = Konten::where('kategori', 'Announcement')
->orWhere('kategori', 'Activities')
->orderBy('id', 'desc')
->get();
Or as mentioned in answers below you can use whereIn statement.
I have two tables in my database
My first table
And my second table
I would like to count how many gold members exists and how many silver members exists... I want to do a single count for each category... The rif can be repeated in the column but is the key to join the two tables.. I'm working with Query Builder and I would like to continue work with that. Someone can help me?
I tried with this code but didn't work
$count = DB::table('table1')
->join('table2', 'table1.rif', '=', 'table2.rif')
->select(DB::raw('category')
->count();
Try this:
use Illuminate\Support\Facades\DB;
DB::table('table2')
->join('table1', 'table2.rif', '=', 'table1.rif')
->select(DB::raw('count(*) as count'), 'table1.category as category')
->groupBy('category')
->get();
If you want to count only a specific category:
DB::table('table2')
->join('table1', 'table2.rif', '=', 'table1.rif')
->where('table1.category', 'Silver')
->count()
See Laravel docs for more info.
in a Laravel application, I have a list of companies. Some of those are related to a subscriptions table in a 1 x n relation.
I want to order the companies in a way that the ones which have a subscription appear before the ones which have no subscription using just one db query.
Any idea is much appreciated!
thanks!
Laravel uses separate queries to eager load relationships. So if you want to do this you will need to join the tables and order by...
Something in the form...
$companies = App\Companies::join('subscriptions as sub', 'sub.company_id', '=', 'company.id')
->orderBy('sub.somefield', 'DESC')
->select(what you need)
->with('if you need the relation data');
You know you can also only query those records that have a relationship with
$companies = App\Companies::has('subscription')->get();
Maybe that is all you need... and
$companies = App\Companies::doesntHave('subscription')->get();
... returns the opposite where the company has no subscription...
Hi how can I select limited number of all the item from model and the selection with certain names.
eg:
$product = Product::all()->limit(4)->select('id','name');
Most of example start with Product::find(1) but my case, I don't have id. Thanks
Use the other methods first, then call get at the end:
$products = Product::limit(4)->select('id', 'name')->get();
Limit Query Results
To limit the number of results returned from the query, or to skip a given number of results in the query, you may use the skip() and take() methods:
Example of User model which extends Eloquent:
$users = User::take(5)->skip(10)->get();
Product::all() will be used when get all data without any condition. You need to use get method.
you need to
$products = Product::select('id', 'name')->limit(4)->get();