I have a PHP config file which I retrieved from SSH.
Here is the sample config file in PHP :
<?php
$url_root='https://google.fr';
$document_root='/usr/share/nginx/html';
The command I use to retrieve the url :
grep -oE '\$url_root=.*;' conf.php | tail -1 | sed 's/$url_root=//g;s/;//g'
Output:
'https://google.fr'
But I expect to retrieve only google.fr
Then I need to implement this command line into ssh like :
domain=$(ssh -oStrictHostKeyChecking=no root#127.0.0.1 '
COMMAND HERE;
')
In order to accomodate for unpredictable data (aka you can find complete urls including other routes / files and not only domain names) I would go for:
your_str='https://google.fr/somedir/someotherdir/index.html'
echo $your_str | cut -d'/' -f3
Output:
google.fr
In your ssh command:
'grep -oE '\''\$url_root=.*;'\'' conf.php | tail -1 | sed '\''s/$url_root=//g;s/;//g'\'' | cut -d'\''/'\'' -f3'
Try this:
DOMAIN_NAME=$(grep -oE '\$url_root=.*;' conf.php | tail -1| sed "s/\$url_root='//g;s/^[a-z]*:\/\///g;s/';//")
echo "Domain name is: $DOMAIN_NAME";
# ssh user#$DOMAIN_NAME etc...
The portion of code s/^[a-z]*:\/\///g; looks for one or more occurrences of a-z followed by :// and removes it if it exists.
Related
I've build this command:
arp -a | grep <mac here> | grep -P '\((.*?)\)' -o
This should return an IP address for a specific mac. The problem is that the IP get's returned but with () around them. I need them without the (). Any idea how I can fix this?
Currently: (192.168.187.136)
Should be 192.168.187.136
I believe arp is somewhat deprecated and ip neighbor is the proper replacement. Since ip n output doesn't have those parenthesis, you also avoid this issue
ip n | grep <mac here> | cut -d' ' -f1
You can remove the 1st and last character using sed:
arp -a | grep <mac here> | grep -P '\((.*?)\)' -o | sed 's/^|\(.*\)|$/\1/'
Also, on BASH 4.2 and newer:
ip=$(arp -a | grep <mac here> | grep -P '\((.*?)\)' -o)
echo "${ip:1:-1}"
using sed in one command
arp -a | grep <mac here> | grep -P '\((.*?)\)' -o | sed 's/^|\(.*\)|$/\1/'
Since you're already using grep -P :
arp -a | grep <mac here> | grep -oP '\(\K[^)]*'
\K is a PCRE meta-character meaning "drop the string matched so far", so you will check that there's a bracket before your result without outputting it, and the negated class [^)] will match up to the next bracket excluded.
You can also fuse both greps if the mac address appears before the IP :
arp -a | grep -oP '<mac here>.*\(\K[^)]*'
Using ip neighboor and (posix) awk:
ip n | awk -v mac='<mac here>' 'mac{print $1}'
or using GNU awk and arp:
arp -a | awk -F'[()]' -v mac='<mac here>' '$0 ~ mac{print $2}'
I am trying to use grep to filter out the RDS snapshot identifier from the rds describe-db-snapshots command output below:
"arn:aws:rds:ap-southeast-1:123456789:snapshot:rds:apple-pie-2018-05-06-17-12",
"rds:apple-pie-2018-05-06-17-12",
how to return the exact output as in
rds:apple-pie-2018-05-06-17-12
tried using
grep -Eo ",rds:"
but not able to
Following awk may also help you on same.
awk 'match($0,/^"rds[^"]*/){print substr($0,RSTART+1,RLENGTH-1)}' Input_file
Your grep -Eo ",rds:" is failing for different reasons:
You did not add a " in the string to match
Between the comma and rds you need to match the character.
You are trying to match the comma that can be on the previous line
Your sample input is 2 lines (with a newline in between), perhaps the real input is without the newline.
You want to match until the next double quote.
You can support both input-styles (with/without newline) with
grep -Eo '(,|^)"rds:[^"]*' rdsfile |cut -d'"' -f2
You can do this in one command with
sed -rn 's/.*(,|^)"(rds:[^"]*).*/\2/p' rdsfile
EDIT: Manipulting stdout and not the file is with similar commands:
yourcommand | grep -Eo '(,|^)"rds:[^"]*' |cut -d'"' -f2
# or
yourcommand | sed -rn 's/.*(,|^)"(rds:[^"]*).*/\2/p'
You can also test the original commands with yourcommand > rdsfile.
You might notice that rdsfile is missing data that you have seen on the screen, in that case add 2>&1
yourcommand 2>&1 | grep -Eo '(,|^)"rds:[^"]*' |cut -d'"' -f2
# or
yourcommand 2>&1 | sed -rn 's/.*(,|^)"(rds:[^"]*).*/\2/p'
I have to display net interface and IP's attached to it.
I came up with this code:
if [ -f intf ]; then
rm -I intf
fi &&
if [ -f ipl ]; then
rm -I ipl
fi &&
ip ntable | grep dev | sort | uniq | sed -e 's/^.*dev //;/^lo/d' >> intf &&
ip a | grep -oP "inet\s+\K[\w./]+" | grep -v 127 >> ipl &&
paste <(cat intf) <(cat ipl)
It does the job but I believe it's ugly :), created files, IMHO a total mess :)
any one can suggest the nice way to get exact the same result but short and efficient way ?
If there are a few interfaces, right now I'm thinking about looping, but that will make this code even bigger and probably uglier :) What would you suggest?
As the first thing, you can eliminate the need for temporary files with process substitution:
paste <(ip ntable | grep dev | sort -u | sed -e 's/^.*dev //;/^lo/d') <(ip a | grep -oP "inet\s+\K[\w./]+" | grep -v 127)
sort -u does the same thing as sort | uniq
This oneliner outputs the interface name and its ip address:
ifconfig |\
grep -e 'Link' -A 1 |\
paste -d" " - - - |\
grep ' addr' |\
sed -e 's/ */ /g' -e 's/Link.*addr://' |\
cut -d" " -f1,2
Here an explanation of the commands:
Shows network configuration
Filters lines containing Link and the next line to it.
Joins three lines
Filters lines having an assigned address
Trim whitespaces and remove not relevant information
Splits remaining data and keeps only interface name and ip address.
Example output:
br-2065e5d2fc59 172.18.0.1
docker0 172.17.0.1
lo 127.0.0.1
wlp3s0
Hey so got another predicament that I am stuck in. I wanted to see approximately how many Indian people are using the stampede computer. So I set up an indian txt file in vim that has about 50 of the most common surnames in india and I want to compare those names in the file to the user name list.
So far this is the code I have
getent passwd | cut -f 5 -d: | cut -f -d' '
getent passwd gets the userid list which is going to look like this
tg827313:x:827313:8144474:Brandon Williams
the cut functions will get just the last name so the output of the example will be
Williams
Now can use the grep function to compare files but how do I use it to compare the getent passwd list with the file?
To count how many of the last names of computer users appear in the file namefile, use:
getent passwd | cut -f 5 -d: | cut -f -d' ' | grep -wFf namefile | wc -l
How it works
getent passwd | cut -f 5 -d: | cut -f -d' '
This is your code which I will assume works as intended for you.
grep -wFf namefile
This selects names that match a line in namefile. The -F option tells grep not to use regular expressions for the names. The names are assumed to be fixed strings. The option -f tells grep to read the strings from file. -w tells grep to match whole words only.
wc -l
This returns a count of the lines in the output.
In a shell script I am running nslookup on number of URLs
Sometimes some url returns cannot resolv error. I need to capture those errors in a variable.
here is code for nslookup which gets ip address returned
output=$(nslookup "$URL" | grep Add | grep -v '#' | cut -f 3 -d ' ' | awk 'NR>1' )
Now in same variable output, I want to capture the error
nslookup: can't resolve
Stdout I am capturing in a file.
I have tried different version of re-directions - 2>&1 and others but error does not get assigned to variable. I do not want the error to be re-directed to separate file but want it to be recorded in above output variable.
As long as you are using awk, you can simplify things considerably
nslookup "$URL" 2>&1 |
awk -e '/Add/ && !/#/ && NR > 1 {print $2}'
-e '/resolve|NXDOMAIN/ { print "error" }'
Where one line has been broken into three for clarity. I cannot reproduce the problem you say you have 2&>1 nor do I believe it should fail.
The redirection of stderr works when you use
output=$(nslookup "$URL" 2>&1 | grep Add | grep -v '#' | cut -f 3 -d ' ' | awk 'NR>1')
but it is futile since you filter it out immediately with the grep Add. You need to rethink your logic and what you really want. Maybe a better approach is
output=$(nslookup "$URL" 2>&1)
case $output in
(nslookup:*) ;;
(*) output=$(echo "$output" | grep Add | ...);;
esac