Elegantly return value(s) matching criteria from an array of nested hashes - in one line - ruby

Question

I have been searching for a solution to this issue for a couple of days now, and I'm hoping someone can help out. Given this data structure:
'foo' => {
'bar' => [
{
'baz' => {'faz' => '1.2.3'},
'name' => 'name1'
},
{
'baz' => {'faz' => '4.5.6'},
'name' => 'name2'
},
{
'baz' => {'faz' => '7.8.9'},
'name' => 'name3'
}
]
}
I need to find the value of 'faz' that begins with a '4.', without using each. I have to use the '4.' value as a key for a hash I will create while looping over 'bar' (which obviously I can't do if I don't yet know the value of '4.'), and I don't want to loop twice.
Ideally, there would be an elegant one-line solution to return the value '4.5.6' to me.
I found this article, but it doesn't address the full complexity of this data structure, and the only answer given for it is too verbose; the looping-twice solution is more readable. I'm using Ruby 2.3 on Rails 4 and don't have the ability to upgrade. Are there any Ruby gurus out there who can guide me?

Answer 1

You can use select to filter results.
data = {'foo' => {'bar' => [{'baz' => {'faz' => '1.2.3'}, 'name' => 'name1'}, {'baz' => {'faz' => '4.5.6'}, 'name' => 'name2'}, {'baz' => {'faz' => '7.8.9'}, 'name' => 'name3'}]}}
data.dig('foo', 'bar').select { |obj| obj.dig('baz', 'faz').slice(0) == '4' }
#=> [{"baz"=>{"faz"=>"4.5.6"}, "name"=>"name2"}]
# or if you prefer the square bracket style
data['foo']['bar'].select { |obj| obj['baz']['faz'][0] == '4' }
The answer assumes that every element inside the bar array has the nested attributes baz -> faz.
If you only expect one result you can use find instead.