bash to store unique value if array in variable - bash

Question

The bash below goes to a folder and stores all the unique values that are .html file names in f1. It then removes all text after the _ in $p. I added a for loop to get the unique id in $p. The terminal out shows $p is correct, but the last value is only being stored in the new array ($sorted_unique_ids), I am not sure why all three are not.
dir=/path/to
var=$(ls -td "$dir"/*/ | head -1) ## sore newest <run> in var
for f1 in "$var"/qc/*.html ; do
# Grab file prefix
bname=`basename $f1` # strip of path
p="$(echo $bname|cut -d_ -f1)"
typeset -A myarray ## define associative array
myarray[${p}]=yes ## store p in myarray
for i in ${!myarray[#]}; do echo ${!myarray[#]} | tr ' ' '\n' | sort; done
done
output
id1
id1
id1
id2
id1
id2
id1
id2
id3
id1
id2
id3
desired sorted_unique_ids
id1
id2
id3

Answer 1

Maybe something like this:
dir=$(ls -td "$dir"/*/ | head -1)
find "$dir" -maxdepth 1 -type f -name '*_*.html' -printf "%f\n" |
cut -d_ -f1 | sort -u
For input directory structure created like:
dir=dir
mkdir -p dir/dir
touch dir/dir/id{1,2,3}_{a,b,c}.html
So it looks like this:
dir/dir/id2_b.html
dir/dir/id1_c.html
dir/dir/id2_c.html
dir/dir/id1_b.html
dir/dir/id3_b.html
dir/dir/id2_a.html
dir/dir/id3_a.html
dir/dir/id1_a.html
dir/dir/id3_c.html
The script will output:
id1
id2
id3
Tested on repl.

Answer 2

latest=`ls -t "$dir"|head -1` # or …|sed q` if you're really jonesing for keystrokes
for f in "$latest"/qc/*_*.html; do f=${f##*/}; printf %s\\n "${f%_*}"; done | sort -u

Answer 3

Define an associative array:
typeset -A myarray
Use each p value as the index for an array element; assign any value you want to the array element (the value just acts as a placeholder):
myarray[${p}]=yes
If you run across the same p value more than once, each assignment to the array will overwrite the previous assignment; net result is that you'll only ever have a single element in the array with a value of p.
To obtain your unique list of p values, you can loop through the indexes for the array, eg:
for i in ${!myarray[#]}
do
echo ${i}
done
If you need the array indexes generated in sorted order try:
echo ${!myarray[#]} | tr ' ' '\n' | sort
You can then use this sorted result set as needed (eg, dump to stdout, feed to a loop, etc).
So, adding my code to the OPs original code would give us:
typeset -A myarray ## define associative array
dir=/path/to
var=$(ls -td "$dir"/*/ | head -1) ## sore newest <run> in var
for f1 in "$var"/qc/*.html ; do
# Grab file prefix
bname=`basename $f1` # strip of path
p="$(echo $bname|cut -d_ -f1)"
myarray[${p}]=yes ## store p in myarray
done
# display sorted, unique set of p values
for i in ${!myarray[#]}; do echo ${!myarray[#]} | tr ' ' '\n' | sort; done