How to put a shell parameter in a string inside a string? - bash

Question

There is a parameter $1. It's an email address. I want it to be part of the string within a string of this curl command:
curl 'xy.com' --data-binary '{"email":"variableValueHere!!!"}'
So a command including the parameter $1 should result in this command...
curl 'xy.com' --data-binary '{"email":"xy#z.de"}'
if $1 equals xy#z.de.
How can I put it in there?
What I tried so far:
curl 'xy.com' --data-binary '{"email":"$1"}'
curl 'xy.com' --data-binary '{"email":"`echo $1`"}'

Answer 1

Try this:
curl 'xy.com' --data-binary '{"email":"'"$1"'"}'
It's the concatenation of
'{"email":"'
"$1"
'"}'
and inserts your parameter as a quoted string.

Answer 2

Better use a proper JSON parser like jq:
curl 'xy.com' --data-binary "$(
jq \
--arg email "$1" \
--null-input \
--compact-output \
'.email = $email'
)"
"$(jq ...)": Captures the output of jq as a string.
jq: Is a command-line JSON processor.
--arg email "$1": Pass the shell's argument $1's value as the jq variable $email.
--null-input: Tells jq there is no JSON input stream to parse.
--compact-output: Tells jq to compact its output by putting each JSON object on a single line.
'.email = $email': This is the jq query to assign the value of the $email variable as the JSON string value of the email key from the root JSON object ..
This can also be written more compact:
curl 'xy.com' --data-binary "$(jq -cn --arg e "$1" '.email=$e')"

Answer 3

What do you see when you try this:
curl 'xy.com' --data-binary '{"email":"`$1`"}'

Answer 4

How about
curl xy.com --data-binary "{email:$1}"
?
If you want the 3rd argument to be in JSON Format, write it as:
curl xy.com --data-binary '{"email":"'"$1"'"}'
You can simplify this to
curl xy.com --data-binary '{"email":"'$1'"}'
if you are sure that your email address ($1) does not contain spaces or other troublesome characters.
If you really want to pass additional single quotes to curl (as you stated in your comment), just prepend and append to your argument a
"'"