I am at a loss, i looked around the internet and stackoverflow but every so called solution is giving either errors or plainly don't work.
I have the following setup.
4 fields (setup in date dd-mm-yyyy, hour hh:mm:ss) seconds are not important.
start date : 7-1-2020
start hour : 23:30:00
end date : 8-1-2020
end hour : 03:50:00
What i want to happen is to calculate the diffrence in 'hours, minutes' between the end and the start date, hour. But when I calculate and change the end date to lets say 09-01-2020 it does not count the extra 24h at all.
Use Text format:
=text(A3-A1+A4-A2,"[H]:MM")
You need to format the time difference as a duration using the custom format
[h]:mm
for hours and minutes
or
[h]
for whole hours.
There are some good notes on how it works in Excel here and as far as I can tell from testing it Google Sheets is the same.
Alternatively, if I read your question as wanting to drop the minutes and seconds from the times before doing the calculation, you could use
=(B3-B1)*24+hour(B4)-hour(B2)
and just format the result as a normal number.
After alot of fiddeling and this post i came to the conclusion that the main issue was not laying within the mathematical but within the format of the cell.
By default all time values in sheets are 24h max.
So the basic formula =start - end
The time format needed should be
more date time format
elapsed hours : elapsed minutes
apply
Now you should see the correct elapsed hours and minutes
Related
I am trying to measure how many minutes have elapsed from the time I turn my code from a fixed time, lets say 8:30 am of that day. If I turn my code on at 12am it should see that 210 minutes have elapsed. Any suggestions would help greatly. Thank you
You can import the datetime module, which has a class with the same name, with method datetime.datetime.now().
This returns an object representing the time when it is called.
This object has the method replace(), which can be used to 'change' the time to 8:30, if you call it like so - replace(hour=8, minute=30).
You can then create another similar object but without replacing the time, then you can simply subtract the first from the second to get the elapsed time as a datetime object.
This will then have elapsed_time.seconds to give you the time change in seconds, which can be divided by 60 if you want for the time in minutes.
Example
import datetime
time_A = datetime.datetime.now()
time_A = time_A.replace(hour=8, minute=30)
time_B = datetime.datetime.now()
elapsed_time = time_B - time_A
print(elapsed_time.seconds, "seconds have passed since 8:30 this morning")
If you wanted this for a specific timezone, you can add or subtract the offset from your current timezone. So if you are for example, 5 hours ahead of CST, you can have it get the difference from 3:30 instead.
my issue is that I want to be able to get two time stamps and compare if the second (later taken) one is less than 59 minutes away from the first one.
Following this thread Compare two dates with JavaScript
the date object may do the job.
but first thing i am not happy with is that it takes the time from my system.
is it possible to get the time from some public server or something?
cause there always is a chance that the system clock gets manipulated within the time stamps, so that would be too unreliable.
some outside source would be great.
then i am not too sure how to get the difference between 2 times (using 2 date objects).
many issue that may pop up:
time being something like 3:59 and 6:12
so just comparing minutes would give the wrong idea.
so we consider hours too.
biut there the issue with the modulo 24.
day 3 23:59 and day 4 0:33 wouldnt be viewed proper either.
so including days too.
then the modulo 30 thing, even though that on top changes month for month.
so month and year to be included as well.
so we would need the whole date, everything from current year to second (because second would be nice too, for precision)
and comparing them would require tons of if clauses for year, month, etc.
do the date objects have some predfeined date comparision function that actually keeps all these things in mind (havent even mentioned leap years yet, have I)?
time would be very important cause exactly at the 59 minutes mark (+-max 5 seconds wouldnt matter but getting rmeitely close to 60 is forbidden)
a certain function would have to be used that without fail closes a website.
script opens website at mark 0 min, does some stuff rinse and repeat style and closes page at 59 min mark.
checking the time like every few seconds would be smart.
Any good ideas how to implement such a time comparision that doesnt take too more computer power yet is efficient as in new month starting and stuff doesnt mess it up?
You can compare the two Date times, but when creating a date time there is a parameter of DateTime(value) which you can use.
You can use this API to get the current UTC time which returns a example JSON array like this:
{
"$id":"1",
"currentDateTime":"2019-11-09T21:12Z",
"utcOffset":"00:00:00",
"isDayLightSavingsTime":false,
"dayOfTheWeek":"Saturday",
"timeZoneName":"UTC",
"currentFileTime":132178075626292927,
"ordinalDate":"2019-313",
"serviceResponse":null
}
So you can use either the currentFileTime or the currentDateTime return from that API to construct your date object.
Example:
const date1 = new Date('2019-11-09T21:12Z') // time when I started writing this answer
const date2 = new Date('2019-11-09T21:16Z') // time when I finished writing this answer
const diff = new Date(date2-date1)
console.log(diff.toTimeString()) // time it took me to write this
Please keep in mind that due to network speeds, the time API will be a little bit off (by a few milliseconds)
I used below simple expression for getting duration:
doc['endTime'].date.millisOfDay - doc['startTime'].date.millisOfDay
But the problem starts when, endTime crosses the startTime day.
Example: If startTime is 23:50 and endTime for the same is 00:12, we
crossed by midnight, which changes the date as well.
In that way I am getting absolutely wrong duration, except all the scenarios when both time lies with in the same day result is as expected.
Help on how exactly i can make this.
You should simply subtract the absolute milliseconds value since the epoch (instead of milliseconds since the start of the day):
doc['endTime'].date.millis - doc['startTime'].date.millis
I was wanting to write a program in C that I can simply type in the hours that I worked for each day of the week, including time on break, that will take my input and return the total number of hours I have worked for that week. It's dumb, I know, but I am not sure how to do the math for this regarding time on the clock.
Thank you
At beginning of work: get the current date, make it into seconds.
At end of work: get the current date, make it into seconds.
So working seconds = end seconds - beginning seconds
Then you'll just have to make those into hours.
Here, My timestamps code for Ruby is
#{Time.now.utc.strftime("%B #{ActiveSupport::Inflector.ordinalize(Time.now.day)}%Y%R")}".
Now I want to increase my hour by one. So how it can be possible ?
If I understand correctly you can add one hour and then format them to your previous format:
(Time.now+1.hour).utc.strftime("%B #{ActiveSupport::Inflector.ordinalize(Time.now.day)}%Y%R")