Method render() is not being called when custom Laravel exception is thrown from view composer - laravel

Edited:
I have a custom exception with render method which is being called when I throw it e.g. from controller, but not being called when I throw it in View composer.
So when I do something like that
public function compose(View $view)
{
throw new CustomException();
}
and put dd() to exception render method
public function render()
{
dd('render is called');
}
I get no result.
If I log my exception directly, finds out that first the CustomException being thrown, then as the result I see ErrorException.
I found a place where it being thrown.
\Illuminate\View\Engines\CompilerEngine::handleViewException
protected function handleViewException(Exception $e, $obLevel)
{
$e = new ErrorException($this->getMessage($e), 0, 1, $e->getFile(), $e->getLine(), $e);
parent::handleViewException($e, $obLevel);
}
I didn't found any mentions in Laravel docs about that case.
I found a tread on github with the same issue: https://github.com/laravel/framework/issues/24658
So the question is, is this expected? Is there any adequate way to avoid this behaviour?

Edit
So, as you know, any exception during view compilation is intercepted and rethrown as ErrorException or as FatalThrowableError.
What you can do is intercept ErrorException and check if ($e->getPrevious() instanceof \CustomException) if so, you do your code, else, let the handler continue.

So I've found working solution for myself.
I've extended CompilerEngine and added additional processing in order to not throw ErrorException when I don't want to.
The important thing is - your resulting Exception must be inherited from ErrorException. Otherwise you will face multiple calls to \App\View\Engines\CompilerEngine::handleViewException which can break your logic and write multiple log entities to your log file.

Related

Handle module not found in laravel 7 routing

let's say I have some
Route::get('/path/{model}', 'Controller#method');
In the case of mysite.com/path/1 & no Model#1, I getting 404 which is default Laravel behavior
I want to handle (basically, redirect to another named route) "NoModelFound" for specific group of routes / specific route
As this route exists, Route::fallback or Route::any will not trigger here.
I know there is a Route()->missing method in Laravel 8, but I have Laravel 7 and can't update.
Also, in the best way, I search for solutions within routes ( web.php )
Is any solution for this? thanks in advance
You can globally handle exception in App\Exceptions\Handler class. If you really and i mean really want to be specific about handling ModelNotFoundException for only certain routes then you can do some thing like
// Exception Handle class
public function render($request, Exception $exception)
{
if(
$request->is('*path/') && // or string match
$exception instanceof ModelNotFoundException
){
redirect()->to('where-ever');
}
}
If you just want to redirect user whenever ModelNotFoundException occurs then you could do this,
// Exception Handle class
public function render($request, Exception $exception)
{
if(
$exception instanceof ModelNotFoundException
){
redirect()->to('where-ever');
}
}
Another way would be to use a middleware and check for certain model, if it doesnt exist, then redirect the user. Depends on what you are trying to do. You can find more information here
https://laravel.com/docs/8.x/middleware
https://laravel.com/docs/8.x/errors#the-exception-handler

Laravel: Way to diagnose "uncaught reflection: class log does not exist" without guessing?

As we all painfully know, this message is generated when an error occurs before Laravel has had a chance to instantiate a "Log" class instance to handle it. And... it therefore seems to completely conceal just what the underlying error is!
In my case the php artisan command won't run either.
Is there any way to find out what's wrong without "blind guessing?"
When you want to handle exceptions, a good way to catch it would be to implement a way to trapping exception out of controllers or services. You can do it in the "render" method of the App\Exceptions\Handler class. In this "render" method, you can write a block of "if" code to show the messages generated by an exception when Laravel throws an exception. For example:
public function render($request, Exception $exception)
{
if($exception) {
// do something
return response()->json(['error' => $exception->getMessage(),
$exception->getTraceAsString()], 500);
}
// Or if you created an exception specialization
if ($exception instanceof MyCustomException) {
return response()->view('errors.custom', [], 500);
}
return parent::render($request, $exception);
}
This was indeed caused by a syntax error, and I'm really surprised that Laravel had even managed to "get started" by that point in time. I literally found it by looking with git at a list of files that had recently changed.

Render from another controller method

I'm using Laravel 5.5 version and I have a question.
Let's say that my controller has 2 methods like this:
public function errorsCheck(){
return view('errors_check');
}
public function index(){
$this->errorsCheck();
// some other important code
}
And when I open my webpage it goes to index() method first. Then it calls errorsCheck(). And errorsCheck() has to render view file and stop script executing.
How can I do it? I can't make something like:
return $this->errorsCheck();
because I need code above to execute if errorsCheck method doesnt found any errors. And this is not validation errors, btw.
Any ideas? Thanks.
SOLUTION:
Well, solution is:
throw new HttpResponseException(
Response::view('account.denied.not_active_account')
);
It will throw exception, but Laravel catch it and will render view.
Well, solution is:
throw new HttpResponseException(
Response::view('account.denied.not_active_account')
);
It will throw exception, but Laravel catch it and will render view.

Laravel: resource not found exception

Say you have a simple resource route like this:
Route::resource('overview', 'OverviewController');
And hit routes which you know don't exist. For example:
/overview/sdflkjdsflkjsd
/overview/sdflkjdsflkjsd/edit
Which in my case throws Trying to get property of non-object error from my view (as no resource is found)
I looked into adding 'Regular Expression Parameter Constraints' from the docs, but it looks like these are not available for resource routes either (plus don't really fix the problem).
I'm looking for a way to throw a single exception for this kind of thing, which I can then handle once, rather than add logic to each action (or at least the show and edit actions).. if possible.
EDIT After looking around github, I found the exception in the Symphony repo here. Is there a way I can hook into it?
Since you're getting a Trying to get property of non-object error, I assume you're fetching the resource via YourModel::find();
I'd suggest you use YourModel::findOrFail() instead. Then, you'd be getting a specific type of exception called ModelNotFoundException. Just register an error handler for this.
For instance,
App::error(function(ModelNotFoundException $e)
{
return Response::make('Not Found', 404);
});
UPDATE: This would actually go into render() method inside the app/Exceptions/Handler.php file in Laravel 5.1, and of course the code would utilize the passed $e parameter instead.
public function render($request, Exception $e)
{
if ($e instanceof ModelNotFoundException)
{
return \Response::make('Not Found', 404);
}
return parent::render($request, $e);
}

Laravel 4: redirect if item doesn't exists, ModelNotFoundException doesn't work anyway I try it

I'm following Dayle Rees' book "Code Bright" tutorial on building a basic app with Laravel (Playstation Game Collection).
So far so good, the app is working but, following his advices at the end of the chapter, I'm doing my homeworks trying to improve it
So, this snippet is working fine for existing models but throws an error if the item doesn't exists:
public function edit(Game $game){
return View::make('/games/edit', compact('game'));
}
In other words, http://laravel/games/edit/1 shows the item with ID = 1, but http://laravel/games/edit/21456 throws an error since there's no item with that ID
Let's improve this behaviour, adapting some scripts found also here on StackOverflow (Laravel 4: using controller to redirect page if post does not exist - tried but failed so far):
use Illuminate\Database\Eloquent\ModelNotFoundException; // top of the page
...
public function edit(Game $game){
try {
$current = Game::findOrFail($game->id);
return View::make('/games/edit', compact('game'));
} catch(ModelNotFoundException $e) {
return Redirect::action('GamesController#index');
}
}
Well... nothing happens! I still have the error with no redirect to the action 'GamesController#index'... and please notice that I have no namespaces in my Controller
I tried almost anything:
Replace catch(ModelNotFoundException $e) with catch(Illuminate\Database\Eloquent\ModelNotFoundException $e): no way
put use Illuminate\Database\Eloquent\ModelNotFoundException; in Model instead of Controller
Return a simple return 'fail'; instead of return Redirect::action('GamesController#index'); to see if the problem lies there
Put almost everywhere this snippet suggested in Laravel documentation
App::error(function(ModelNotFoundException $e)
{
return Response::make('Not Found', 404);
});
Well, simply nothing happened: my error is still there
Wanna see it? Here are the first two items in the errors stack:
http://www.iwstudio.it/laravelerrors/01.png
http://www.iwstudio.it/laravelerrors/02.png
Please, can someone tell me what am I missing? This is driving me mad...
Thanks in advance!
Here are few of my solutions:
First Solution
The most straightforward fix to your problem will be to use ->find() instead of ->findOrFail().
public function edit(Game $game){
// Using find will return NULL if not found instead of throwing exception
$current = Game::find($game->id);
// If NOT NULL, show view, ELSE Redirect away
return $current ? View::make('/games/edit', compact('game')) : Redirect::action('GamesController#index');
}
Second solution
As I notice you may have been using model binding to your route, according to Laravel Route model binding:
Note: If a matching model instance is not found in the database, a 404 error will be thrown.
So somewhere where you define the model binding, you can add your closure to handle the error:
Route::model('game', 'Game', function()
{
return Redirect::action('GamesController#index');
});
Third Solution
In your screenshot, your App::error seems to work as the error says HttpNotFound Exception which is Laravel's way of saying 404 error. So the last solution is to write your redirect there, though this apply globally (so highly discouraged).

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