Plot using Seaborn in for loop with legends - seaborn

I am trying to generate plots using loop, while doing that I am getting multiple/repetative legends in every loop.
Here is the code:
sns.set(rc={'figure.figsize':(11.7,8.27)})
palette = sns.color_palette("Pastel2", 2)
tsne = TSNE(n_components=2)
label_original=[0,1,0.....]
for i in [1,2,3,4,5,6]:
for j in [10,20,30,40,50,60,70,80,90,100]:
data2= some_data_aclculated
X_embedded = tsne.fit_transform(data2)
sns_plot =sns.scatterplot(X_embedded[:,0], X_embedded[:,1], hue=label_original, legend='full')
sns_plot.figure.savefig("%s_%s_plot.png" % (i,j))
In 2nd iteration I get 2 repetative legends, in 3rd iteration I get 3 repetative legends and so on.
How to get rid of repetative legends?
Attached the image:

Related

Seaborn grouped Bar plot

I am trying to create visualizations for recent commonwealth medal tally dataset.
I would like to create a grouped bar chart of top ten countries by total number of medals won.
Y axis = total
x axis = Country name
How can I divide totals into three bars consisting of no of :
gold, Silver,Bronze medals won by each country?
I created one using excel, but don't know how to do it using seaborn
P.S. I have already tried using a list of columns for hue.
df_10 = df.head(10)
sns.barplot(data = df_10, x = 'team' , y = 'total' , hue = df_10[["gold" ,
"silver","bronze"]].apply(tuple , axis = 1) )
Here is the chart that I created using excel:
enter image description here
To plot the graph, you will need to change the dataframe to the format that will allow for easy plotting. One of the ways to do this is using dataframe.melt(). The method used by you may not work... Once the data is in a format that seaborn understands easily, plotting will become simple. As you have not provided the format for df_10, I have assumed the data to have 4 columns - Country, Gold, Silver and Bronze. Below is the code...
## Use melt using Country as ID and G, S, B as the rows for values
df_10 = pd.melt(df_10, id_vars=['Country'], value_vars=['Gold', 'Silver', 'Bronze'])
df_10.rename(columns={'value':'Count', 'variable':'Medals'}, inplace=True) ##Rename so the plot has informative texts
fig, ax=plt.subplots(figsize=(12, 7)) ## Set figure size
ax=sns.barplot(data=df_10, x='Country', y='Count', hue='Medals') ## Plot the graph

Plot does not highlight all the unique values of a column represented by hue

My dataframe has a column 'rideable_type' which has 3 unique values:
1.classic_bike
2.docked_bike
3.electric_bike
While plotting a barplot using the following code:
g = sns.FacetGrid(electric_casual_type_week, col='member_casual', hue='rideable_type', height=7, aspect=0.65)
g.map(sns.barplot, 'day_of_week', 'number_of_rides').add_legend()
I only get a plot showing 2 unique 'rideable_type' values.
Here is the plot:
As you can see only 'electric_bike' and 'classic_bike' are seen and not 'docked_bike'.
The main problem is that all the bars are drawn on top of each other. Seaborn's barplots don't easily support stacked bars. Also, this way of creating the barplot doesn't support the default "dodging" (barplot is called separately for each hue value, while it would be needed to call it in one go for dodging to work).
Therefore, the recommended way is to use catplot, a special version of FacetGrid for categorical plots.
g = sns.catplot(kind='bar', data=electric_casual_type_week, x='day_of_week', y='number_of_rides',
col='member_casual', hue='rideable_type', height=7, aspect=0.65)
Here is an example using Seaborn's 'tips' dataset:
import seaborn as sns
tips = sns.load_dataset('tips')
g = sns.FacetGrid(data=tips, col='time', hue='sex', height=7, aspect=0.65)
g.map_dataframe(sns.barplot, x='day', y='total_bill')
g.add_legend()
When comparing with sns.catplot, the coinciding bars are clear:
g = sns.catplot(kind='bar', data=tips, x='day', y='total_bill', col='time', hue='sex', height=7, aspect=0.65)

Visual Studio - Range chart - Adding background colours per category group

I am using a Range chart to create a Gannt Chart of sorts. I am attempting to do two things:
1) Change the background colour of the range chart based upon one of two Category groups, I have two groups, an outer and an inner, and I would like the background colour to change based on the outer grouping. I have a piece of code that determines a colour but, i'm having trouble applying that to the background. I was hoping interlacing colour would help me, that you aren't able to determine the frequency of the interlacing from what I can tell.
The code I'm using is:
Private colorPalette As String() = { "#C85200", "#FF800E", "#5F9ED1",
"#2CA02C", "#A59D93", "#B8341B", "#352F26", "#F1E7D6", "#E16C56", "#CFBA9B"}
Private count As Integer = 0
Private mapping As New System.Collections.Hashtable()
Public Function GetColor(ByVal groupingValue As String) As String
If mapping.ContainsKey(groupingValue) Then
Return mapping(groupingValue)
End If
Dim c As String = colorPalette(count Mod colorPalette.Length)
count = count + 1
mapping.Add(groupingValue, c)
Return c
End Function
2) Position the X and Y axis labels between the major grid lines. The X axis is a date, and the end user would like the date to be between the two grid lines (representing a day) rather than on each grid line, I've had a look around but can't seem to find anything relevant.
Any help or guidance would be appreciated, thanks!

Keras Image Data Generator show labels

I am using an ImageDataGenerator to augment my images. I need to get the y labels from the generator.
Example : I have 10 training images, 7 are label 0 and 3 are label 1. I want to increase training set size to 100.
total_training_images = 100
total_val_images = 50
model.fit_generator(
train_generator,
steps_per_epoch= total_training_images // batch_size,
epochs=epochs,
validation_data=validation_generator,
validation_steps= total_val_images // batch_size)
By my understanding, this trains a model on 100 training images for each epoch, with each image being augmented in some way or the other according to my data generator, and then validates on 50 images.
If I do train_generator.classes, I get an output [0,0,0,0,0,0,0,1,1,1]. This corresponds to my 7 images of label 0 and 3 images of label 1.
For these new 100 images, how do I get the y-labels?
Does this mean when I am augmenting this to 100 images, my new train_generator labels are the same thing, but repeated 10 times? Essentially np.append(train_generator.classes) 10 times?
I am following this tutorial, if that helps :
https://blog.keras.io/building-powerful-image-classification-models-using-very-little-data.html
The labels generate as one-hot-encoding with the images.Hope this helps !
training_set.class_indices
from keras.preprocessing import image
import matplotlib.pyplot as plt
x,y = train_generator.next()
for i in range(0,3):
image = x[i]
label = y[i]
print (label)
plt.imshow(image)
plt.show()
Based on what you're saying about the generator, yes.
It will replicate the same label for each augmented image. (Otherwise the model would not train properly).
One simple way to check what the generator is outputting is to get what it yields:
X,Y = train_generator.next() #or next(train_generator)
Just remember that this will place the generator in a position to yield the second element, not the first anymore. (This would make the fit method start from the second element).

Error trying to plot 2 images with different size using matlab

I have 2 images that I need to plot in one figure then display the points of interest found with SURF on both images:
Image 1 : size [6113x5693x3]
Image 2 : size [4896x3744x3]
when trying to plot both of images in one figure with this code:
I = zeros([size(I1,1) size(I1,2)*2 size(I1,3)]);
I(:,1:size(I1,2),:)=I1;
I(:,size(I1,2)+1:size(I1,2)+size(I2,2),:)=I2;
figure, imshow(I); hold on;
and to display the points of interest of each one of them with :
plot([Pos1(:,2) Pos2(:,2)+size(I1,2)]',[Pos1(:,1) Pos2(:,1)]','-');
plot([Pos1(:,2) Pos2(:,2)+size(I1,2)]',[Pos1(:,1) Pos2(:,1)]','o');
I get this error and I dont know how to fixed :
Subscripted assignment dimension mismatch.
Any suggestion will be welcome!
Walk through this line by line. The error occurs on line 3. You are trying to assign I2 (with dimension 4896x3744x3) to a select part of I that has an incorrect first dimension (since the first dimension of I is the same as I1, not I2).
size(I(:,size(I1,2)+1:size(I1,2)+size(I2,2),:)) = [ 6113 3744 3 ]
size(I2) = [4896 3744 3]

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