Change Swagger UI request URL when I tap to "Execute" button - spring-boot

Question

I deployed my app on AWS. Also, I configured Nginx that /api prefix (https://mywebsitename.com/api) will be automatically redirected to https://127.0.0.1:8080/.
Every HTTP request & response works perfectly.
Also, I added the swagger library to my app, with following configuration:
#Configuration
#EnableSwagger2
class SwaggerConfig {
#Bean
fun api(): Docket {
return Docket(DocumentationType.SWAGGER_2)
.select()
.apis(RequestHandlerSelectors.any())
.paths(PathSelectors.any())
.build()
}
}
I use this two libraries:
implementation("io.springfox:springfox-swagger2:2.9.2")
implementation("io.springfox:springfox-swagger-ui:2.9.2")
Everything works perfectly locally.
The problem is:
The swagger link (https://mywebsitename.com/api/swagger-ui.html) works perfectly, and everything is shown. But, when I tap to the "Try it out" button and make "Execute", it returns me TypeError: Failed to fetch. It happens because the request goes to https://127.0.0.1:8080/some_endpoint.
Question is: How I can configure my spring boot app that when I tap to "Execute" button, the request will go to https://mywebsitename.com/api/some_end_point

Answer 1

Have you tried adding the host call in the Swagger configuration like this:
#Configuration
#EnableSwagger2
class SwaggerConfig {
#Bean
fun api(): Docket {
return Docket(DocumentationType.SWAGGER_2)
.host("https://mywebsitename.com")
.select()
.apis(RequestHandlerSelectors.any())
.paths(PathSelectors.any())
.build()
}
}

Answer 2

you can try adding servers in Swagger Configuration like this:
#Bean
public Docket api() {
Server serverLocal = new Server("local", "http://localhost:8080", "for local usages", Collections.emptyList(), Collections.emptyList());
Server testServer = new Server("test", "https://example.org", "for testing", Collections.emptyList(), Collections.emptyList());
return new Docket(DocumentationType.SWAGGER_2)
.servers(serverLocal, testServer)
.select()
.apis(RequestHandlerSelectors.any())
.paths(PathSelectors.any())
.build();
}