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Why JMeter failures marks as KO?
(3 answers)
Closed 2 years ago.
When you generate jmeter dashboard, you get a table called statistics. It shows similar stats like one of the GIU views provide when you run JMeter in GUI mode.
There is a column called "KO" under "executions" section of the table.
What does the "KO" stands for?
In this case, KO means "not OK" or "Failure". It is possible to rename it if needed.
Just found the answer here.
KO: Total Number of samples failed to execute.
However I still don't know why it's called "KO"
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Force retesting or disable test caching
(5 answers)
Closed 4 years ago.
Golang 1.10 introduced caching for test, but there is no obvious way to disable test caching.
So the question is, how to temporal dislable it and how to force rebuild it.
I did read the documentation: https://golang.org/cmd/go/#hdr-Build_and_test_caching but did not found any obvious answer to that question.
The idiomatic way to bypass test caching is to use -count=1. This is the recommended way for doing that in release note as well
The go test command now caches test results: if the test executable
and command line match a previous run and the files and environment
variables consulted by that run have not changed either, go test will
print the previous test output, replacing the elapsed time with the
string “(cached).” Test caching applies only to successful test
results; only to go test commands with an explicit list of packages;
and only to command lines using a subset of the -cpu, -list,
-parallel, -run, -short, and -v test flags. The idiomatic way to bypass test caching is to use -count=1.
Refer : https://golang.org/doc/go1.10#test
This question already has an answer here:
Spring Batch. How to get the number of the element being processed
(1 answer)
Closed 7 years ago.
Is there any way to get the current row number of the file that is being processed inside item processor without implementing listeners?
Thanks
if your item implements the ItemCountAware Interface, spring batch will fill the current row number for you
ps: i am almost 100% sure that a similar question and answer already exists here at stackoverflow, but i did not found it
This question already has answers here:
How to get file creation date/time in Bash/Debian?
(13 answers)
Closed 7 years ago.
I know you can't for files, but is there by any chance a way to check this for folders?
It is not possible to get creation time of any files in linux, since
Each file has three distinct associated timestamps: the time of last
data access, the time of last data modification, and the time the file
status last changed.
Also you as you wrote in your question "I know you can't for files, but is there by any chance a way to check this for folders?", in linux, all files and directories are considered as files, so you have your own answer in your question.
Source
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How copy data from one database to another on different server?
(1 answer)
Closed 8 years ago.
Actually I want to copy 50 GB of database from one one server to another server, I just want to know that which one of three options is best.
Thanks
Assuming you don't have to transform the data, can't see any gain by using Hadoop (or parallel processing, for that matter) in this scenario.
See this question on copying Oracle data between servers
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Closed 9 years ago.
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I have a file (for example system.log). I need to scan this file to find a specific string that must appear several times during a period of 5 minutes.
I imagine that I can make a script with 4 parameters:
the location of the file
the string to search
the number of times that the string appears
the period of time
If this script finds the string in the specified period of time it writes, for example, the message 'success'
Here's the begin of the script
#!/bin/ksh
#set -x
#############
# VARIABLES #
#############
location="/moteurs/websphere/7.0/esb/managed01/logs/"
file="SystemOut.log"
pattern="WSV0605W: Thread \"SIBFAPInboundThreadPool"
string=$(grep -ic "${pattern}" ${location}/${file})
Now that I've defined my variables, I don't know how can I make a function that scans SystemOut.log every 5 minutes.
Do you kown how can I create this shell?
Yes. Use your favorite editor, write the shell script, execute it. You are done.
Just a half answer, but maybe it gets you somewhere:
To run something repeatedly every five minutes, you can make a loop with a sleep:
while true
do
echo "I'm doing something!" # replace this by the actual code
sleep $[5*60]
done
This will run the code (here just an echo) every five minutes. — Okay, plus the time the code needs, so do not rely on the time being accurate; to get it accurate, you can use
while sleep $[ 5*60 - $(date +%s) % (5*60) ]
do
echo "I'm doing something!" # replace this by the actual code
done
This will always wait for a full 5-minute point on the clock before executing the code.