I have some question about my code, i had table like these :
tb teacher
|---------------------------------|
|id | name | id_prodi|
-----------------------------------
|1 | Teacer A | 1 |
|2 | Teacher B | 2 |
|3 | Teacher C | 1 |
tb prodi
|------------------------
|id | prodi |
-------------------------
|1 | Prodi 1 |
|2 | Prodi 2 |
|3 | Prodi 3 |
tb year
|------------------------
|id | year |
-------------------------
|1 | 2018 |
|2 | 2019 |
|3 | 2020 |
tb attendence
|---------------------------------------------------|
|id | teacher_id | year_id | date_in |
-----------------------------------------------------
| 1 | 1 | 3 | 2020-03-20|
| 2 | 1 | 3 | 2020-03-21|
| 3 | 3 | 3 | 2020-03-21|
| 4 | 1 | 3 | 2020-03-22|
thats my tables. what I need to do here, get result like this on my datatable
i have some condition with combobox to select by a year
|----------------------------------------------------------|
|# | name | year | total_attend |
------------------------------------------------------------
| 1 | Teacher A | 2020 | 3 |
| 2 | Teacher C | 2020 | 1 |
some like thats for final result
and this my controller
public function showData(Request $request)
{
$year = $request->year_id;
$prodi_id = $request->prodi_id;
$datas = Teacher::whereHas('attendance', function($query) use ($year) {
$query->where('year_id', $year);
})
->where('prodi_id',$prodi_id)
->get();
return response()->json([
'success' => 'Success',
'data' => $datas
]);
}
my problem is, I cant get total column by count the attendance year. Anyone has clue??
--help
You can achieve this using selectRaw() with a count() function for teacher_name:
DB::table('attendence')->selectRaw('t.name as name,y.year as year,count(t.name) as total_attend')
->join('teacher as t','t.id','=','attendence.teacher_id')
->join('year as y','attendence.year_id','=','y.id')
->where([['attendence.year_id',$year],['t.prodi_id',$prodi_id]])
->groupBy('name','year')->get();
Related
This is my product table.I want to store customer_id from 1000 and save by +1 how much data i stored
id | customer_id | name |
1 | 1000 | ABC |
2 | 1001 | Tripathi |
3 | 1002 | Leaptrig |
4 | 1003 | Falcon |
5 | 1004 | Savillan |
6 | 1005 | Molt |
7 | 1006 | Falt |
My Controller
$lastProduct=Product::pluck('customer_id')->last();
$product=new Product();
$product->name=$request->name;
if($lastProduct){
$product->customer_id=1000+($lastProduct+1);
}
$product->save();
But In this code,Customer id i increment by 1000 2001,3002 like this. so how should i avoid it ?
id | customer_id | name |
1 | 1000 | ABC |
2 | 2001 | Tripathi |
3 | 3002 | Leaptrig |
4 | 4003 | Falcon |
5 | 5004 | Savillan |
6 | 6005 | Molt |
7 | 7006 | Falt |
You can try this :-
$lastProduct=Product::pluck('customer_id')->last();
$product=new Product();
$product->name=$request->name;
if($lastProduct){
$product->customer_id=$lastProduct+1;
}
$product->save();
I am trying to get the count of unique batches in gift_code table for each campaign. The gift_code table is joined to campaign table by campaign_id.
Here is some sample data for campaign table.
--------------+--------------
|campaign_id | name |
--------------+--------------
| 1 | abc |
--------------+--------------
| 2 | xyz |
--------------+--------------
Below is some sample data for gift_code table.
--------------+------------------------+--------------+
|gift_code_id | campaign_id | batch | unique_code |
--------------+-------------+----------+---------------
| 1 | 1 | 1 | zxc23 |
--------------+-------------+----------+--------------+
| 2 | 1 | 2 | rtc26 |
--------------+-------------+----------++-------------+
| 3 | 2 | 1 | z8723 |
--------------+-------------+----------+--------------+
| 4 | 2 | 2 | h7c26 |
--------------+-------------+----------++-------------+
| 5 | 2 | 2 | rrcf6 |
--------------+-------------+----------++-------------+
| 6 | 2 | 3 | r7y28 |
--------------+-------------+----------++-------------+
| 7 | 2 | 3 | bnc26 |
--------------+-------------+----------++-------------+
$campaign = DB::table('campaign')
->select('campaign.*', DB::raw('count(gift_code.batch) as batch_count')->groupBy('gift_code.campaign_id')->groupBy('gift_code.batch'))
->leftjoin('gift_code', 'campaign.campaign_id', '=', 'gift_code.campaign_id')
->get();
My expected results are:
--------------+-------------------------+
|campaign_id | name |batch_count|
--------------+-------------+-----------+
| 1 | abc | 2 |
--------------+-------------+-----------+
| 2 | xyz | 3 |
--------------+-------------+-----------+
Try below query
$data = \DB::table('campaign as c')
->leftJoin('gift_code as gc','c.campaign_id','=','gc.campaign_id')
->select('c.*',\DB::raw('COUNT(distinct(gc.batch)) as batch_count'))
->groupBy('c.campaign_id')
->get();
I need a way to avoid duplicate values from oracle join, I have this scenario.
The first table contain general information about a person.
+-----------+-------+-------------+
| ID | Name | Birtday_date|
+-----------+-------+-------------+
| 1 | Byron | 12/10/1998 |
| 2 | Peter | 01/11/1973 |
| 4 | Jose | 05/02/2008 |
+-----------+-------+-------------+
The second table contain information about a telephone of the people in the first table.
+-------+----------+----------+----------+
| ID |ID_Person |CELL_TYPE | NUMBER |
+-------+- --------+----------+----------+
| 1221 | 1 | 3 | 099141021|
| 2221 | 1 | 2 | 099091925|
| 3222 | 1 | 1 | 098041013|
| 4321 | 2 | 1 | 088043153|
| 4561 | 2 | 2 | 090044313|
| 5678 | 4 | 1 | 092049013|
| 8990 | 4 | 2 | 098090233|
+----- -+----------+----------+----------+
The Third table contain information about a email of the people in the first table.
+------+----------+----------+---------------+
| ID |ID_Person |EMAIL_TYPE| Email |
+------+- --------+----------+---------------+
| 221 | 1 | 1 |jdoe#aol.com |
| 222 | 1 | 2 |jdoe1#aol.com |
| 421 | 2 | 1 |xx12#yahoo.com |
| 451 | 2 | 2 |dsdsa#gmail.com|
| 578 | 4 | 1 |sasaw1#sdas.com|
| 899 | 4 | 2 |cvcvsd#wew.es |
| 899 | 4 | 2 |cvsd#www.es |
+------+----------+----------+---------------+
I was able to produce a result like this, you can check in this link http://sqlfiddle.com/#!4/8e326/1
+-----+-------+-------------+----------+----------+----------+----------------+
| ID | Name | Birtday_date| CELL_TYPE| NUMBER |EMAIL_TYPE|EMAIL|
+-----+-------+-------------+----------+----------+----------+----------------+
| 1 | Byron | 12/10/1998 | 3 | 099141021|1 |jdoe#aol.com |
| 1 | Byron | 12/10/1998 | 2 | 099091925|2 |jdoe1#aol.com |
| 1 | Byron | 12/10/1998 | 1 | 099091925| | |
| 2 | Peter | 01/11/1973 | 1 | 088043153|1 |xx12#yahoo.com |
| 2 | Peter | 01/11/1973 | 2 | 090044313|2 |dsdsa#gmail.com |
| 4 | Jose | 05/02/2008 | 1 | 092049013|1 |sasaw1#sdas.com |
| 4 | Jose | 05/02/2008 | 2 | 098090233|2 |cvcvsd#wew.es |
+-----+-------+-------------+----------+----------+----------+----------------+
If you check the data in table Email for user with ID_Person = 4 only present two of the three emails that have, the problem for this case is the person have more emails that cellphone numbers and only will present the same number of the cellphone numbers.
The result i expected is something like this.
+-----+-------+-------------+----------+----------+----------+----------------+
| ID | Name | Birtday_date| CELL_TYPE| NUMBER |EMAIL_TYPE|EMAIL|
+-----+-------+-------------+----------+----------+----------+----------------+
| 1 | Byron | 12/10/1998 | 3 | 099141021|1 |jdoe#aol.com |
| 1 | Byron | 12/10/1998 | 2 | 099091925|2 |jdoe1#aol.com |
| 1 | Byron | 12/10/1998 | 1 | 099091925| | |
| 2 | Peter | 01/11/1973 | 1 | 088043153|1 |xx12#yahoo.com |
| 2 | Peter | 01/11/1973 | 2 | 090044313|2 |dsdsa#gmail.com |
| 4 | Jose | 05/02/2008 | 1 | 092049013|1 |sasaw1#sdas.com |
| 4 | Jose | 05/02/2008 | 2 | 098090233|2 |cvcvsd#wew.es |
| 4 | Jose | 05/02/2008 | | |2 |cvsd#www.es |
+-----+-------+-------------+----------+----------+----------+----------------+
This is the way that i need to present the data.
I could not understand why your query was so complex, thus, added the simple full outer join and it seems to be working:
select distinct p.id, p.name,
case when Lag(CELL) over(partition by p.id order by p.id,pe.id) = CELL then null else cell_type end as cell_type,
case when Lag(CELL) over(partition by p.id order by p.id,pe.id) = CELL then null else CELL end as CELL,
EMAIL_TYPE as EMAIL_TYPE, EMAIL as EMAIL
from person p full outer join phones pe on p.id = pe.id
full outer join emails e
on p.id = e.id and pe.cell_type = e.email_type;
I have three tables which is connected like.
packages(parent) -> routes(child) -> items(grandchild)
i have to find all items with package id using laravel eloquent i know this can be done by using join but what we do if use eloquent
+---------+ +-----------------------+ +---------------------+
|packages | | routes | | items |
+---------+ +-----------------------+ +---------------------+
|id | name| |id | package_id |name | |id | route_id |name |
| 1 | P1 | | 1 | 1 | R1 | | 1 | 1 | I1 |
| 2 | P2 | -> | 2 | 1 | R2 | -> | 2 | 1 | I2 |
| 3 | P3 | | 3 | 2 | R3 | | 3 | 2 | I3 |
| 4 | P4 | | 4 | 2 | R4 | | 4 | 1 | I4 |
| 5 | P5 | | 5 | 3 | R5 | | 5 | 3 | I5 |
+---------+ +-----------------------+ +---------------------+
Pacakge Model
here where i have to achive this
class Package extends Model
{
public function items(){
return $this->...;
}
}
result (item which is belongs to package_id = 1)
+-----------------------+
|id | route_id | name |
+-----------------------+
| 1 | 1 | I1 |
| 2 | 1 | I2 |
| 3 | 2 | I3 |
| 4 | 1 | I4 |
+-----------------------+
is there any way to do that using eloquent
thanks in advance
you need to do this:
class Package extends Model
{
public function items()
{
return $this->hasManyThrough('App\Item', 'App\Route',
'package_id', 'route_id', 'id');
}
}
Hi I want query from 3 table
user:
+----+-----------+
| id | name |
+----+-----------+
| 1 | Denny |
| 2 | Agus |
| 3 | Dini |
| 4 | Angel |
+----+-----------+
History_Education
+----+-----------+-------------+
| id | userId | educationId |
+----+-----------+-------------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 2 | 1 |
| 4 | 2 | 2 |
+----+-----------+-------------+
Education
+----+-----------+----------+
| id | level | Name |
+----+-----------+----------+
| 1 | 1 | SD |
| 2 | 2 | SMP |
| 3 | 3 | SMA |
| 4 | 4 | S1 |
+----+-----------+----------+
How to query with laravel Eloquent to get the latest user education order by Level DESC
expected:
+----+-----------+----------------------+
| id | Name | Latest_Education |
+----+-----------+----------------------+
| 1 | Denny | SMP |
| 2 | Agus | SMP |
| 3 | Dini | - |
| 4 | Angel | - |
+----+-----------+----------------------+
In normal query:
select id,name ,(select E.name from education E inner join History_eductaion HE on E.id = HE.education_id where HE.userId =U.id limit 1 order by E.level DESC )latest_education from USER U
How to translate to laravel eloquent?
The quick answer is use the query builder - your query needed to be altered slightly to match the table names and columns as listed in your question:
$result = DB::table('user')
->select([
'id',
'name',
DB::raw("(select E.name from Education E inner join History_Education HE on E.id = HE.educationId where HE.userId = user.id order by E.level DESC limit 1) as latest_education")
])
->get();