I am trying to get the count of unique batches in gift_code table for each campaign. The gift_code table is joined to campaign table by campaign_id.
Here is some sample data for campaign table.
--------------+--------------
|campaign_id | name |
--------------+--------------
| 1 | abc |
--------------+--------------
| 2 | xyz |
--------------+--------------
Below is some sample data for gift_code table.
--------------+------------------------+--------------+
|gift_code_id | campaign_id | batch | unique_code |
--------------+-------------+----------+---------------
| 1 | 1 | 1 | zxc23 |
--------------+-------------+----------+--------------+
| 2 | 1 | 2 | rtc26 |
--------------+-------------+----------++-------------+
| 3 | 2 | 1 | z8723 |
--------------+-------------+----------+--------------+
| 4 | 2 | 2 | h7c26 |
--------------+-------------+----------++-------------+
| 5 | 2 | 2 | rrcf6 |
--------------+-------------+----------++-------------+
| 6 | 2 | 3 | r7y28 |
--------------+-------------+----------++-------------+
| 7 | 2 | 3 | bnc26 |
--------------+-------------+----------++-------------+
$campaign = DB::table('campaign')
->select('campaign.*', DB::raw('count(gift_code.batch) as batch_count')->groupBy('gift_code.campaign_id')->groupBy('gift_code.batch'))
->leftjoin('gift_code', 'campaign.campaign_id', '=', 'gift_code.campaign_id')
->get();
My expected results are:
--------------+-------------------------+
|campaign_id | name |batch_count|
--------------+-------------+-----------+
| 1 | abc | 2 |
--------------+-------------+-----------+
| 2 | xyz | 3 |
--------------+-------------+-----------+
Try below query
$data = \DB::table('campaign as c')
->leftJoin('gift_code as gc','c.campaign_id','=','gc.campaign_id')
->select('c.*',\DB::raw('COUNT(distinct(gc.batch)) as batch_count'))
->groupBy('c.campaign_id')
->get();
I want to pivot the following table
| ID | Code | date | qty |
| 1 | A | 1/1/19 | 11 |
| 1 | A | 2/1/19 | 12 |
| 2 | B | 1/1/19 | 13 |
| 2 | B | 2/1/19 | 14 |
| 3 | C | 1/1/19 | 15 |
| 3 | C | 3/1/19 | 16 |
into
| ID | Code | mth_1(1/1/19) | mth_2(2/1/19) | mth_3(3/1/19) |
| 1 | A | 11 | 12 | 0 |
| 2 | B | 13 | 14 | 0 |
| 3 | C | 15 | 0 | 16 |
I am new to hive, i am not sure how to implement it.
NOTE: I don't want to do mapping because my month values change over time.
I need a way to avoid duplicate values from oracle join, I have this scenario.
The first table contain general information about a person.
+-----------+-------+-------------+
| ID | Name | Birtday_date|
+-----------+-------+-------------+
| 1 | Byron | 12/10/1998 |
| 2 | Peter | 01/11/1973 |
| 4 | Jose | 05/02/2008 |
+-----------+-------+-------------+
The second table contain information about a telephone of the people in the first table.
+-------+----------+----------+----------+
| ID |ID_Person |CELL_TYPE | NUMBER |
+-------+- --------+----------+----------+
| 1221 | 1 | 3 | 099141021|
| 2221 | 1 | 2 | 099091925|
| 3222 | 1 | 1 | 098041013|
| 4321 | 2 | 1 | 088043153|
| 4561 | 2 | 2 | 090044313|
| 5678 | 4 | 1 | 092049013|
| 8990 | 4 | 2 | 098090233|
+----- -+----------+----------+----------+
The Third table contain information about a email of the people in the first table.
+------+----------+----------+---------------+
| ID |ID_Person |EMAIL_TYPE| Email |
+------+- --------+----------+---------------+
| 221 | 1 | 1 |jdoe#aol.com |
| 222 | 1 | 2 |jdoe1#aol.com |
| 421 | 2 | 1 |xx12#yahoo.com |
| 451 | 2 | 2 |dsdsa#gmail.com|
| 578 | 4 | 1 |sasaw1#sdas.com|
| 899 | 4 | 2 |cvcvsd#wew.es |
| 899 | 4 | 2 |cvsd#www.es |
+------+----------+----------+---------------+
I was able to produce a result like this, you can check in this link http://sqlfiddle.com/#!4/8e326/1
+-----+-------+-------------+----------+----------+----------+----------------+
| ID | Name | Birtday_date| CELL_TYPE| NUMBER |EMAIL_TYPE|EMAIL|
+-----+-------+-------------+----------+----------+----------+----------------+
| 1 | Byron | 12/10/1998 | 3 | 099141021|1 |jdoe#aol.com |
| 1 | Byron | 12/10/1998 | 2 | 099091925|2 |jdoe1#aol.com |
| 1 | Byron | 12/10/1998 | 1 | 099091925| | |
| 2 | Peter | 01/11/1973 | 1 | 088043153|1 |xx12#yahoo.com |
| 2 | Peter | 01/11/1973 | 2 | 090044313|2 |dsdsa#gmail.com |
| 4 | Jose | 05/02/2008 | 1 | 092049013|1 |sasaw1#sdas.com |
| 4 | Jose | 05/02/2008 | 2 | 098090233|2 |cvcvsd#wew.es |
+-----+-------+-------------+----------+----------+----------+----------------+
If you check the data in table Email for user with ID_Person = 4 only present two of the three emails that have, the problem for this case is the person have more emails that cellphone numbers and only will present the same number of the cellphone numbers.
The result i expected is something like this.
+-----+-------+-------------+----------+----------+----------+----------------+
| ID | Name | Birtday_date| CELL_TYPE| NUMBER |EMAIL_TYPE|EMAIL|
+-----+-------+-------------+----------+----------+----------+----------------+
| 1 | Byron | 12/10/1998 | 3 | 099141021|1 |jdoe#aol.com |
| 1 | Byron | 12/10/1998 | 2 | 099091925|2 |jdoe1#aol.com |
| 1 | Byron | 12/10/1998 | 1 | 099091925| | |
| 2 | Peter | 01/11/1973 | 1 | 088043153|1 |xx12#yahoo.com |
| 2 | Peter | 01/11/1973 | 2 | 090044313|2 |dsdsa#gmail.com |
| 4 | Jose | 05/02/2008 | 1 | 092049013|1 |sasaw1#sdas.com |
| 4 | Jose | 05/02/2008 | 2 | 098090233|2 |cvcvsd#wew.es |
| 4 | Jose | 05/02/2008 | | |2 |cvsd#www.es |
+-----+-------+-------------+----------+----------+----------+----------------+
This is the way that i need to present the data.
I could not understand why your query was so complex, thus, added the simple full outer join and it seems to be working:
select distinct p.id, p.name,
case when Lag(CELL) over(partition by p.id order by p.id,pe.id) = CELL then null else cell_type end as cell_type,
case when Lag(CELL) over(partition by p.id order by p.id,pe.id) = CELL then null else CELL end as CELL,
EMAIL_TYPE as EMAIL_TYPE, EMAIL as EMAIL
from person p full outer join phones pe on p.id = pe.id
full outer join emails e
on p.id = e.id and pe.cell_type = e.email_type;
I have dataset like below:
item|location|week1|week2|week3|week4
_____________________________________
1000|10000000|1.2 |2.2 |3.2 |4.5
1001|10000001|1.8 |2.5 |3.5 |4.1
1002|10000002|9.3 |2.9 |3.7 |4.8
I want data to be unpivot like below:
item|location|week_name|week_value
__________________________________
1000|10000000|week1 |1.2
1000|10000000|week2 |2.2
1000|10000000|week3 |3.2
1000|10000000|week4 |4.5
1001|10000001|week1 |1.8
1001|10000001|week2 |2.5
1001|10000001|week3 |3.5
1001|10000001|week4 |4.1
1002|10000002|week1 |9.3
1002|10000002|week2 |2.9
1002|10000002|week3 |3.7
1002|10000002|week4 |4.8
Tell me any efficient way/query to do it ?
*Updated according to the OP reply for my comment (using week_number instead of week_name)
select item
,location
,pe.pos+1 as week_number
,pe.val as week_value
from mytable t
lateral view posexplode(array(week1,week2,week3,week4)) pe
;
+-------+-----------+--------------+-------------+
| item | location | week_number | week_value |
+-------+-----------+--------------+-------------+
| 1000 | 10000000 | 1 | 1.2 |
| 1000 | 10000000 | 2 | 2.2 |
| 1000 | 10000000 | 3 | 3.2 |
| 1000 | 10000000 | 4 | 4.5 |
| 1001 | 10000001 | 1 | 1.8 |
| 1001 | 10000001 | 2 | 2.5 |
| 1001 | 10000001 | 3 | 3.5 |
| 1001 | 10000001 | 4 | 4.1 |
| 1002 | 10000002 | 1 | 9.3 |
| 1002 | 10000002 | 2 | 2.9 |
| 1002 | 10000002 | 3 | 3.7 |
| 1002 | 10000002 | 4 | 4.8 |
+-------+-----------+--------------+-------------+
Oracle has 2 functions - rank() and dense_rank() - which i've found very useful for some applications. I am doing something in mysql now and was wondering if they have something equivalent to those?
Nothing directly equivalent, but you can fake it with some (not terribly efficient) self-joins. Some sample code from a collection of MySQL query howtos:
SELECT v1.name, v1.votes, COUNT(v2.votes) AS Rank
FROM votes v1
JOIN votes v2 ON v1.votes < v2.votes OR (v1.votes=v2.votes and v1.name = v2.name)
GROUP BY v1.name, v1.votes
ORDER BY v1.votes DESC, v1.name DESC;
+-------+-------+------+
| name | votes | Rank |
+-------+-------+------+
| Green | 50 | 1 |
| Black | 40 | 2 |
| White | 20 | 3 |
| Brown | 20 | 3 |
| Jones | 15 | 5 |
| Smith | 10 | 6 |
+-------+-------+------+
how about this "dense_rank implement" in MySQL
CREATE TABLE `person` (
`id` int(11) DEFAULT NULL,
`first_name` varchar(20) DEFAULT NULL,
`age` int(11) DEFAULT NULL,
`gender` char(1) DEFAULT NULL);
INSERT INTO `person` VALUES
(1,'Bob',25,'M'),
(2,'Jane',20,'F'),
(3,'Jack',30,'M'),
(4,'Bill',32,'M'),
(5,'Nick',22,'M'),
(6,'Kathy',18,'F'),
(7,'Steve',36,'M'),
(8,'Anne',25,'F'),
(9,'Mike',25,'M');
the data before dense_rank() like this
mysql> select * from person;
+------+------------+------+--------+
| id | first_name | age | gender |
+------+------------+------+--------+
| 1 | Bob | 25 | M |
| 2 | Jane | 20 | F |
| 3 | Jack | 30 | M |
| 4 | Bill | 32 | M |
| 5 | Nick | 22 | M |
| 6 | Kathy | 18 | F |
| 7 | Steve | 36 | M |
| 8 | Anne | 25 | F |
| 9 | Mike | 25 | M |
+------+------------+------+--------+
9 rows in set (0.00 sec)
the data after dense_rank() like this,including "partition by" function
+------------+--------+------+------+
| first_name | gender | age | rank |
+------------+--------+------+------+
| Anne | F | 25 | 1 |
| Jane | F | 20 | 2 |
| Kathy | F | 18 | 3 |
| Steve | M | 36 | 1 |
| Bill | M | 32 | 2 |
| Jack | M | 30 | 3 |
| Mike | M | 25 | 4 |
| Bob | M | 25 | 4 |
| Nick | M | 22 | 6 |
+------------+--------+------+------+
9 rows in set (0.00 sec)
the query statement is
select first_name,t1.gender,age,FIND_IN_SET(age,t1.age_set) as rank from person t2,
(select gender,group_concat(age order by age desc) as age_set from person group by gender) t1
where t1.gender=t2.gender
order by t1.gender,rank