Ansible playbook to run a command for each subdirectory in a directory - ansible

Question

I have a following directory structure:
parent_dir/
├── subdir_1
├── subdir_2
└── subdir_3
The subdirs don't have a fixed name and there can be an arbitrary number of them.
How to make ansible run a task for each sub directory?
(any task will do, eventually every dir will be a python package to install, but that isn't important for the context of this question)

Answer 1

This is the solution I managed to come up with, perhaps there is a cleaner way with lookups to achieve this in a single task.
Copy pasting the following code will create a directory structure with a minimal ansible playbook that does the required. (tested on Ubuntu/dash)
mkdir action_per_dir
cd action_per_dir
mkdir -p parent_dir/subdir_1 parent_dir/subdir_2 parent_dir/subdir_3
cat > action_per_dir.yml << "EOF"
---
# Gets all the directories and stores all the return values of `find`
# into the results_of_find
# The return value will consist of:
# https://docs.ansible.com/ansible/latest/modules/find_module.html#return-values
- hosts: localhost
tasks:
- name: Get all dirs
find:
paths: parent_dir
file_type: directory
register: result_of_find
# We're interested only in the `files` part of results of find.
# In pseudo code what's happening here is:
# for each item in result_of_find.files:
# print item.path
#
# The output will be very verbose but for debugging purposes it can be filtered
# ansible-playbook action_per_dir.yml | grep msg
- name: Print all the dirs
debug:
msg: "{{ item.path }}"
with_items: "{{ result_of_find.files }}"
EOF
After that it just needs to be run:
ansible-playbook action_per_dir.yml | grep msg