Spring Boot can't autowire map bean in #configuration class - spring

I have created a map in my #Configuration class which holds all classes that need to be injected.
I'm trying to create a map in there that has to be injected into another class.
The Map creating looks like this in the configuration file:
This is how I inject the map:
The map is always zero so it seems like it doesn't get injected at all.
Any ideas why this might happen?

Learned some new things while looking through stackoverflow.
Turns out spring and spring boot treat #Autowired differently and I'm supposed to use
the #Resource annotation for injecting maps in spring boot.
Besides that I was checking if the map was null inside the constructor of the class it gets injected into. When I checked it outside of the constructor the map did not seem to be null.
I guess this means the injection happens after the constructor, which I was not aware of.

Related

How to make a bean discoverable by Quarkus CDI without using annotations

I have a simple Quarkus resource:
#Path("/rosters")
#Produces(MediaType.APPLICATION_JSON)
#Consumes(MediaType.APPLICATION_JSON)
public class RosterResource {
private final RosterService rosterService;
public RosterResource(RosterService rosterService){
this.rosterService = rosterService;
}
#GET
#Path("/{rosterId}")
public Response getRoster(#PathParam("rosterId")Long rosterId){
return Response.ok(rosterService.getRosterById(rosterId)).build();
}
}
I am trying to inject the RosterServiceinstance in my resource, but I am getting a javax.enterprise.inject.UnsatisfiedResolutionException. However, if I use the #ApplicationScoped annotation on RosterService, then everything works just fine. Is there a way of injecting the RosterService class in my resource without using annotations? In other words, is there a way of making RosterService discoverable by the Quarkus container without directly annotating the class?
Edit: looking into the CDI docs, it seems that you can manually register beans using a method with a #BuildStep annotation. However, it is not clear to me which class should contain the annotated method)
Another option would be to use a Jandex index
To the best of my knowledge, Quarkus only implements so called annotated bean discovery. That means that all CDI beans in Quarkus have to have a bean defining annotation. #ApplicationScoped is one of them.
EDIT: regarding a Jandex index, that allows you to scan for beans in additional JARs. In other words, it will only expand the set of classes that are scanned for a bean defining annotation.
When it comes to a #BuildStep method -- that is only possible in a Quarkus extension. Extensions are powerful (and indeed they can define additional beans) but also complex. You can start at https://quarkus.io/guides/building-my-first-extension, but it may feel overwhelming. It may also feel like this is not the right thing to do if you want to just make your class a bean -- and that would be true. But if your class comes from an external library that you can't change, extension makes sense.
Is there a specific reason why you don't want to annotate your service class with #ApplicationScoped (or any other of the bean discover/scope annotations)?
The only other way that I'm aware of (instead of annotations) is - as you yourself mentioned - the use of Jandex index.

Spring boot getbean vs autowired

I am new to spring boot , I have confusion that
#Autowired
serviceDemo serviceDemo
and getting bean from ApplicationContext is same or different?
and if they are same then which method should I use
It depends on what you’re trying to achieve, but to sum it up;
#Bean registers the instance in the application scope. That way it is accessible for later use.
#Autowired actually asks for an instance of a specific bean already registered in the scope.
Although it’s not exactly the same, you can consider for instance the #Service annotation. It tells spring that the class is a service and registers a bean of it in the scope. If you then have a different class, say a controller (#Controller or #RestController depending on your use case) and simply try to access the service you created you’ll most likely get an error thrown at you. This is because although your IDE might recognize the service location, spring doesn’t. Adding the #Autowired sets a “link” between the bean and the instantiation at the time of booting up your app.

Spring Context Test With Just One Bean

What's the recommended way to run a spring boot test where only the one subject under test is configured in the context.
If I annotate the test with
#RunWith(SpringRunner.class)
#SpringBootTest(properties = "spring.profiles.active=test")
#ContextConfiguration(classes = MyTestBean.class)
Then it seems to work - the test passes, the context starts quickly and seems to only contain the bean that I want. However, this seems like an incorrect use of the #ContextConfiguration(classes = MyTestBean.class) annotation. If I understand correctly the class that I reference is supposed to be a Configuration class, not a regular spring service bean or component for example.
Is that right? Or is this indeed a valid way to achieve this goal? I know there are more complex examples like org.springframework.boot.test.autoconfigure.json.JsonTest which use #TypeExcludeFilters(JsonExcludeFilter.class) to control the context - but this seems overkill for my use case. I just want a context with my one bean.
Clarification
I know that I can just construct the one bean I am testing as a POJO without a spring context test and remove the three annotations above. But in my precise use case I am actually reliant on some of the configuration applied to the context by settings in the application-test.properties file - which is why I've made this a Spring Boot test with a profile set. From my perspective this isn't a plain unit test of a single class in isolation of the spring context configuration - the test is reliant on certain configuration being applied (which is currently provided by the spring boot app properties). I can indeed just test the components as a POJO by creating a new instance outside of a spring context, I'm using constructor injection making the providing of necessary dependencies simple but the test does rely on things like the log level (the test actually makes assertions on certain logs being produced) which requires that the log level is set correctly (which is currently being done via logging.level.com.example=DEBUG in a properties file which sets up the spring context).
For starters, reading the documentation first (e.g., the JavaDoc linked below in this answer) is a recommend best practice since it already answers your question.
If I understand correctly the class that I reference is supposed to be
a Configuration class, not a regular spring service bean or
component for example.
Is that right?
No, that's not completely correct.
Classes provided to #ContextConfiguration are typically #Configuration classes, but that is not required.
Here is an excerpt from the JavaDoc for #ContextConfiguration:
Annotated Classes
The term annotated class can refer to any of the following.
A class annotated with #Configuration
A component (i.e., a class annotated with #Component, #Service, #Repository, etc.)
A JSR-330 compliant class that is annotated with javax.inject annotations
Any other class that contains #Bean-methods
Thus you can pass any "annotated class" to #ContextConfiguration.
Or is this indeed a valid way to achieve this goal?
It is in fact a valid way to achieve that goal; however, it is also a bit unusual to load an ApplicationContext that contains a single user bean.
Regards,
Sam (author of the Spring TestContext Framework)
It is definitely a reasonable and normal thing to only test a single class in a unit test.
There is no problem including just one single bean in your test context. Really, a #Configuration is (typically) just a collection of beans. You could hypothetically create a #Configuration class just with MyTestBean, but that would really be unnecessary, as you can accomplish doing the same thing listing your contextual beans with #ContextConfiguration#classes.
However, I do want to point out that for only testing a single bean in a true unit test, best practice ideally leans towards setting up the bean via the constructor and testing the class that way. This is a key reason why the Spring guys recommend using constructor vs. property injection. See the section entitled Constructor-based or setter-based DI of this article, Oliver Gierke's comment (i.e. head of Spring Data project), and google for more information. This is probably the reason you're getting a weird feeling about setting up the context for the one bean!
You can also use ApplicationContextRunner to create your context using a test configuration of your choice (even with one bean if you like, but as other people have already mentioned for one bean it's more reasonable to use the constructor the classical way without using any spring magic).
What I like this way of testing is the fact that test run very fast since you don't load all the context. This method is best used when the tested bean doesn't have any Autowired dependencies otherwise it's more convenient to use #SpringBootTest.
Below is an example that illustrates the way you can use it to achieve your goal:
class MyTest {
#Test
void test_configuration_should_contains_my_bean() {
new ApplicationContextRunner()
.withUserConfiguration(TestConfiguration.class)
.run(context -> {
assertThat(context.getBean(MyTestBean.class)).isNotNull();
});
}
#Configuraiton
public static class TestConfiguration {
#Bean
public MyTestBean myTestBean(){
new MyTestBean();
}
}
}

Spring injects dependencies in constructor without #Autowired annotation

I'm experimenting with examples from this official Spring tutorials and there is a dependency on this code:
https://github.com/spring-guides/gs-async-method/tree/master/complete
If you look at the code on AppRunner.java class, I have 2 questions:
When server is starting, if I put a breakpoint in this class's constructor, seems like in the constructor, the GitHubLookupService is provided by spring, using the #Service bean that was configured. BUT, there was no #Autowired annotation on the constructor, so how in the world this constructor get called with the right dependency? It was supposed to be null.
Is it an automatic assumption of Spring Boot?
Does Spring see "private field + constructor argument, and it assumes it should look for an appropriate bean?
Is it Spring Framework or Spring boot?
Am I missing something?
As I remember, it was mendatory to provide default constructor to beans / service etc. How come this class (AppRunner) doesn't have a default constructor?
How does Spring knows that it should run the constructor with the argument?
Is it because it is the only constructor?
Starting with Spring 4.3, if a class, which is configured as a Spring bean, has only one constructor, the #Autowired annotation can be omitted and Spring will use that constructor and inject all necessary dependencies.
Regarding the default constructor: You either need the default constructor, a constructor with the #Autowired annotation when you have multiple constructors, or only one constructor in your class with or without the #Autowired annotation.
Read the #Autowired chapter from the official Spring documentation for more information.
Think of it this way... Suppose you have the following component:
#Component
public class FooService {
public FooService(Bar bar) { /*whatever*/ }
}
When Spring is scanning this class, it wants to know how it should go about constructing an instance. It's using reflection so it can get a list of all of the constructors at runtime.
In this case, it is completely unambiguous how Spring must construct this instance. There's only one constructor so there is no decision to be made, and no ambiguity at all.
If you add #Autowired here, you are not narrowing anything down, and you are not giving Spring any extra information to help make its decision - its decision is already made because there is only one candidate.
And so, as a convenience, the Spring team decided #Autowired should be optional. Since its not helping the Spring framework to make a decision, its presence is just noise.
If your component has multiple constructors then you can use #Autowired on one of them to tell Spring "use this one, not that one".

How does spring self injection works with #Resource?

This is a question to understand spring internals. There are a couple of workarounds suggested for self injection of a bean in spring because #Autowired doesn't work. Here are few threads. I would like to know the reason why and how does self injection work technically with #Resource annotation?
#Service(value = "someService")
public class UserService implements Service{
#Resource(name = "someService")
private Service self;
}
Any links to the spring source code would be appreciated. Thanks.
From another thread I got a response which seems fairly ok. Basically it states that spring specially adds defensive checks for handling #Autowired beans but #Resource beans bypass it and hence it works.
I don't know how exactly spring handles it, but here are a few options (the CDI specification uses these for example):
incomplete instances. When beans are instantiated and put in the context, their status is set as 'incomplete' - that is, their instance exists but their dependencies are not injected. Thus, first beans are instantiated, put in the context, and on the next stage their dependencies are injected. This makes the above case trivial - the container first create the instance and then, for each injection point, gets the desired bean from the context - itself, in this case
proxies. A proxy is created for each bean, so that it has beans without actually having instantiated the beans. It creates the proxies (by interface/concrete class), injects them into one another, and passes proxies around when needed. Finally each proxy gets its actual bean. This is perhaps not the case above, because this is used by CDI to handle circular constructor injection.

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