I have an array A with size [d1,d2,d3,d4,d5] = size(A).
I have a custom function myFunc that I need to apply to each of the following subarrays of A:
B1 = A(:,1,:,:,:);
B2 = A(:,2,:,:,:);
B3 = A(:,3,:,:,:);
...
The function myFunc has signature:
function [CN1,CN2,CN3,...] = myFunc(BN,varargin)
Here, CN1, CN2, CN3, etc, are a variable number of output arrays whose size depends only on the size of BN.
The goals is to calculate CN1, CN2, CN3, etc, for each BN and then create the arrays
D1 = cat(2,C11,C21,C31,...);
D2 = cat(2,C12,C22,C32,...);
D3 = cat(2,C13,C23,C33,...);
...
I wrote the following function to do this:
function varargout = testFunc(A,funcHdl,varargin)
% Extract the relevant dimensions for array A
sizeA = size(A);
d1 = sizeA(1);
d2 = sizeA(2);
otherDims = sizeA(3:end);
% Extract the number of output arguments of the function handle
numOut = nargout(funcHdl);
Cs = cell(d2,numOut);
% Get the output for all subarrays
for j=1:d2
B = A(:,j,:);
B = reshape(B,[d1,1,otherDims]);
[Cs{j,:}] = funcHdl(B,varargin{:});
end
% Combined the outputs by concatenation
Ds = cell(1,numOut);
for n = 1:numOut
Ds{1,n} = cat(2,Cs{:,n});
end
% Variable number of outputs
varargout = Ds;
end
It's not too inefficient, but I really need this procedure to be efficient. Am I missing a more efficient way of doing this, especially the concatenation?
I use Matlab2020a on Windows 10.
Related
I have a vector with a couple of elements and I want to write a function that returns me all combinations of x items from this vector.
The following code produces the right output for the case x=2 or x=3 or x=4.
However, I can not implement a solution for every possible x following this idea.
values = {'A','B','C','D','E'};
n = length(values);
data2 = {}; % case x=2
for i = 1:n
for j = i+1:n
data2{end+1} = {values{i}, values{j}};
fprintf('%s %s\n',values{i}, values{j})
end
end
data3 = {}; % case x=3
for i = 1:n
for j = i+1:n
for k = j+1:n
data3{end+1} = {values{i}, values{j}, values{k}};
fprintf('%s %s %s\n',values{i}, values{j}, values{k})
end
end
end
data4 = {}; % case x=4
for i = 1:n
for j = i+1:n
for k = j+1:n
for l = k+1:n
data4{end+1} = {values{i}, values{j}, values{k}, values{l}};
fprintf('%s %s %s %s\n',values{i}, values{j}, values{k}, values{l})
end
end
end
end
How would a function look like which would be able to return my data variable?
data = getCombinations(values, x) %values is vector with elements, x is integer value
EDIT
The following code comes pretty close:
data = perms(values)
data = data(:,1:x)
data = unique(data,'rows')
but it still produces output like A,B and B,A
EDIT2
This fixed it somehow but it is not very nice to look at and it does not work for text entries in cells but only for numbers
data = perms(values)
data = data(:,1:x)
data = sort(data,2)
data = unique(data,'rows')
EDIT3
This did it but it is not very nice to look at... Maybe there is a better solution?
function [data] = getCombinations(values,x)
i = 1:length(values);
d = perms(i);
d = d(:,1:x);
d = sort(d,2);
d = unique(d,'rows');
data = v(d);
end
If you don't want repetitions (and your example suggests you don't) then try nchoosek as nchoosek(1:n, x) to give indices:
values = {'A','B','C','D','E'};
n = length(values);
x = 3;
C = nchoosek(1:n, x);
data = values(C)
In the above, each row is a unique combination of 3 of the 5 elements of values.
Alternatively pass in the values directly:
data = nchoosek(values, x);
I write in variable 'O' some values using
for i = 1:size(I,1)
for j = 1:size(1,I)
h = i * j;
O{h} = I(i, j) * theta(h);
end
end
I - double, theta - double.
I need to sum()all 'O' values, but when I do it its give me error: sum: wrong type argument 'cell'.
How can I sum() it?
P.s. when I want to see O(), its give me
O =
{
[1,1] = 0.0079764
[1,2] = 0.0035291
[1,3] = 0.0027539
[1,4] = 0.0034392
[1,5] = 0.017066
[1,6] = 0.0082958
[1,7] = 1.4764e-04
[1,8] = 0.0024597
[1,9] = 1.1155e-04
[1,10] = 0.0010342
[1,11] = 0.0039654
[1,12] = 0.0047713
[1,13] = 0.0054305
[1,14] = 3.3794e-04
[1,15] = 0.014323
[1,16] = 0.0026826
[1,17] = 0.013864
[1,18] = 0.0097778
[1,19] = 0.0058029
[1,20] = 0.0020726
[1,21] = 0.0016430
etc...
The exact answer to your question is to use cell2mat
sum (cell2mat (your_cell_o))
However, this is the very wrong way to solve your problem. The thing is that you should not have created a cell array in first place. You should have created a numeric array:
O = zeros (size (I), class (I));
for i = 1:rows (I)
for j = 1:columns (I)
h = i * j;
O(h) = I(i, j) * theta(h);
endfor
endfor
but even this is just really bad and slow. Octave is a language to vectorize operations. Instead, you should have:
h = (1:rows (I))' .* (1:columns (I)); # automatic broadcasting
O = I .* theta (h);
which assumes your function theta behaves properly and if givena matrix will compute the value for each of the element of h and return something of the same size.
If you get an error about wrong sizes, I will guess you have an old version of Octave that does not perform automatic broadcasting. If so, update Octave. If you really can't, then:
h = bsxfun (#times, (1:rows (I))', 1:columns (I));
A1, B1, C1, A2, B2 and C2 are 6 matrix with the same dimensions 4435X2000.
I have to find the values i, j and k for which A1(k,2000) == A2(i,j) and B1(k,2000) == B2(i,j) and C1(k,2000) == C2(i,j) , with the condition X(k)==1 and Y(i,j)==1
The objective is to find: counter, L, T and D
Is there a way to make this code faster? Can I avoid loops?
counter=0;
L(1)=0;
T(1)=0;
D(1)=0;
for k=1:4435
if X(k)==1 % X is a vector (4435x1)
F(k,:) = [A1(k,2000) B1(k,2000) C1(k,2000)]
for i=1:4435
for j=100:1999
if Y(i,j)==1 % Y is a matrix (4435x1999)
if F(k,:) == [A2(i,j) B2(i,j) C2(i,j)]
counter = counter+1;
L(counter)=k;
T(counter)=i;
D(counter)=j;
end
end
end
end
end
end
I want a solution that will save me at least 80% of the computation time!
and not have the error message: Out of memory
See how this works out for you -
%// Store X-Y data by calling X() and Y() functions
X_data = X(1:4435);
Y_data = Y(1:4435,100:1999);
range1 = 100:1999 %// define range for columns
A2 = A2(:,range1); %// Crop out A2, B2, C2 based on column-range
B2 = B2(:,range1);
C2 = C2(:,range1);
Y_data = Y_data(:,range1)==1;
%// Indices for dim-3
idx_X = find(X_data==1)
%// Map X==1 onto A1, B1, C1
A1Lr = A1(X_data==1,end)
B1Lr = B1(X_data==1,end)
C1Lr = C1(X_data==1,end)
%// Setup output array to store L, T, D as single Nx3 output array
out = zeros(sum(Y_data(:))*numel(A1Lr),3);
%// Try out(sum(Y_data(:)==1)*numel(A1Lr),3)=0; instead for speed!
%// Start collecting output indices
count = 1;
for iter1 = 1:numel(A1Lr)
[R,C] = find(Y_data & A2==A1Lr(iter1) & B2==B1Lr(iter1) & C2==C1Lr(iter1));
nR = numel(R);
out(count:count+nR-1,:) = [R C repmat(iter1,nR,1)];
count = count + nR;
end
out(find(out(:,1)==0,1):end,:)=[];
%// Packup the outputs
T = out(:,1)
D = out(:,2) + range1(1)-1
L = idx_X(out(:,3))
It is very difficult to determine what your code is actually supposed to accomplish, without really working to interpret your code. However, I'll give it a crack:
% Determine where X is true.
XTrue = X == 1;
% Extract values from A1,B1,C1 where X is true.
F ( XTrue , 1 : 3 ) = [ A1(XTrue,2000) B1(XTrue,2000) C1(XTrue,2000) ];
% Determine where Y is true.
YTrueIndex = find ( Y == 1 );
% Determine where the extracted values match
counter = [];
L = [];
T = [];
D = [];
for ( ii = 1 : length(YTrueIndex) )
indexCurrent = YTrueIndex(ii)
FRowsThatMatch = F(:,1)==A2(indexCurrent) & F(:,2)==B2(indexCurrent) & F(:,3)==C2(indexCurrent);
matchCount = length ( find ( FRowsThatMatch ) );
if ( matchCount > 0 )
counter = counter + matchCount;
[ i , j ] = ind2sub ( size ( Y ) , indexCurrent );
L = [ L , find ( FRowsThatMatch ) ];
T = [ T , ones(matchCount,1)*i ];
D = [ D , ones(matchCount,2)*j ];
end
end
:) I'm trying to code a Least Squares algorithm and I've come up with this:
function [y] = ex1_Least_Squares(xValues,yValues,x) % a + b*x + c*x^2 = y
points = size(xValues,1);
A = ones(points,3);
b = zeros(points,1);
for i=1:points
A(i,1) = 1;
A(i,2) = xValues(i);
A(i,3) = xValues(i)^2;
b(i) = yValues(i);
end
constants = (A'*A)\(A'*b);
y = constants(1) + constants(2)*x + constants(3)*x^2;
When I use this matlab script for linear functions, it works fine I think. However, when I'm passing 12 points of the sin(x) function I get really bad results.
These are the points I pass to the function:
xValues = [ -180; -144; -108; -72; -36; 0; 36; 72; 108; 144; 160; 180];
yValues = [sind(-180); sind(-144); sind(-108); sind(-72); sind(-36); sind(0); sind(36); sind(72); sind(108); sind(144); sind(160); sind(180) ];
And the result is sin(165°) = 0.559935259380508, when it should be sin(165°) = 0.258819
There is no reason why fitting a parabola to a full period of a sinusoid should give good results. These two curves are unrelated.
MATLAB already contains a least square polynomial fitting function, polyfit and a complementary function, polyval. Although you are probably supposed to write your own, trying out something like the following will be educational:
xValues = [ -180; -144; -108; -72; -36; 0; 36; 72; 108; 144; 160; 180];
% you may want to experiment with different ranges of xValues
yValues = sind(xValues);
% try this with different values of n, say 2, 3, and 4
p = polyfit(xValues,yValues,n);
x = -180:36:180;
y = polyval(p,x);
plot(xValues,yValues);
hold on
plot(x,y,'r');
Also, more generically, you should avoid using loops as you have in your code. This should be equivalent:
points = size(xValues,1);
A = ones(points,3);
A(:,2) = xValues;
A(:,3) = xValues.^2; % .^ and ^ are different
The part of the loop involving b is equivalent to doing b = yValues; either name the incoming variable b or just use the variable yValues, there's no need to make a copy of it.
I've just started to program and i've had some problems in passing function as arguments using MATLAB. I've to implement Lagrange algorithm for interpolation.
C1 and C2 are vectors that represent points to interpolate coordinates.
My main problem is that I don't know how to explain in my f1 definition that temp1 and temp2 are not variables, but values determined on every iteration of a for loop (for i and j).
I think the code remaining part could be almost correct.
function [ ] = lagrange(C1, C2)
n = length(C1);
f2 = inline('');
g = inline('');
for i = 1:n
temp0 = C2(i);
temp1 = C1(i);
for j = 1:n
if (i~=j)
temp2 = C1(j);
temp3 = C2(j);
f1 = inline('(x-temp2/(temp1-temp2)','x','temp1','temp2');
f2 = f2.*f1
end
g = g+temp0*f2;
end
end
%plot g
end