Handling a oneToMany relationship in Spring boot JPA - spring

In my database I have a user who can have multiple email addresses. An email address can have only one user. I have following two tables in my database to handle this.
CREATE TABLE IF NOT EXISTS w4a_user (
id INTEGER NOT NULL AUTO_INCREMENT,
login_id VARCHAR(100) NOT NULL UNIQUE,
first_name VARCHAR(100),
last_name VARCHAR(100),
division INTEGER NOT NULL,
created_date TIMESTAMP NOT NULL,
last_active DATE,
PRIMARY KEY (id),
FOREIGN KEY (login_id) REFERENCES w4a_authentication_data (login_id) ON DELETE RESTRICT,
FOREIGN KEY (division) REFERENCES w4a_division (id) ON DELETE RESTRICT
);
CREATE TABLE IF NOT EXISTS w4a_email_address(
email_address VARCHAR(100) NOT NULL,
user_id INTEGER NOT NULL,
is_confirmed BOOLEAN NOT NULL DEFAULT FALSE,
PRIMARY KEY (email_address),
FOREIGN KEY (user_id) REFERENCES w4a_user (id) ON DELETE CASCADE
);
In my Spring boot application, I have following entity classes to handle this.
User.java
#Entity
#Table(name = "w4a_user")
public class User {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private int id;
#Column(name = "first_name")
#Size(max = 100, message = GlobalConstants.ErrorMessageConstants.ERROR_FIRST_NAME_LENGTH_EXCEEDED)
private String firstName;
#Column(name = "last_name")
#Size(max = 100, message = GlobalConstants.ErrorMessageConstants.ERROR_LAST_NAME_LENGTH_EXCEEDED)
private String lastName;
#Column(name = "created_date")
private Date createdDate;
#Column(name = "last_active")
private Date lastActive;
#ManyToOne
#JoinColumn(name = "division", referencedColumnName = "id")
private Division division;
#OneToMany(mappedBy = "userId", cascade = CascadeType.ALL, orphanRemoval = true)
#Size(min = 1)
private List<ContactNumber> contactNumberList;
#OneToMany(mappedBy = "userId", cascade = CascadeType.ALL, orphanRemoval = true)
#Size(min = 1)
private List<EmailAddress> emailAddresses;
.
.
}
EmailAddress.java
#Entity
#Table(name = "w4a_email_address")
public class EmailAddress {
#Id
#Column(name = "email_address")
#Email(message = GlobalConstants.ErrorMessageConstants.ERROR_EMAIL_INCORRECT_FORMAT,
regexp = GlobalConstants.RegexList.EMAIL_REGEX)
#Size(max = 100, message = GlobalConstants.ErrorMessageConstants.ERROR_EMAIL_LENGTH_EXCEEDED)
private String emailAddress;
#ManyToOne
#JoinColumn(name = "user_id", referencedColumnName = "id")
private User userId;
#Column(name = "is_confirmed")
private Boolean isConfirmed;
.
.
}
I use following method to persist entitites to my database.
#PersistenceContext
private EntityManager em;
#Override
public T createEntity(T entity) {
this.em.unwrap(Session.class).save(entity);
return entity;
}
I set email address list in the user entity and perform above method to create a new user.
The issue I have is when adding a user with an email address already used by an existing user. In this case, the database entry for the email address gets updated with the id of the new user. Instead I want to give an error saying the email address is already in use. What is the best way of handling this?

Related

OneToOne JPA issue

I have 2 class
public class User {
#Id
#Column(name = "id")
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String name;
private String age;
#OneToOne
#JoinColumn(name = "address_id", referencedColumnName = "id")
private Address address;
}
and
public class Address {
#Id
#Column(name = "id")
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String building;
private String country;
#OneToOne(mappedBy = "address")
private User user;
}
in my table address, I have a few rows.
When I insert table user with data
{
"id":null,
"name":"Foo",
"age":"18",
"address":{
"id":1,
"building":"Too",
"country":"ABS"
}
}
Table user have 1 row with address_id =1.
I insert same data as above
Table user have 2 row with address_id =1.
My answer is: why 2 table connected by one to one can happen the above case?
You can find your answer here
Why #OneToOne is allowing duplicate associations?
Basically, #JoinColumn(name = "address_id", referencedColumnName = "id") alone doesn't serve the semantics of one-to-one in the database, you need to add unique=true into the #JoinColumn, which makes it #JoinColumn(name = "address_id", referencedColumnName = "id", unique = true).
Side-note: I suggest you drop your tables and then re-creating them before trying this out. If you are using Hibernate, you can set hibernate.hbm2ddl.auto to create-drop

Hibernate: Find entity from one to many table

I have two tables
CREATE TABLE `heroic_quality`
(
`id` INT NOT NULL AUTO_INCREMENT,
`name` VARCHAR(515) NOT NULL UNIQUE,
PRIMARY KEY (`id`)
);
CREATE TABLE `hero`
(
`id` INT NOT NULL AUTO_INCREMENT,
`name` VARCHAR(515) NOT NULL UNIQUE,
`quality_id` INT DEFAULT NULL,
FOREIGN KEY (`quality_id`) REFERENCES heroic_quality (id),
PRIMARY KEY (`id`)
);
And the objects in hibernate are
#Table(name = "heroic_quality")
#Entity(name = "heroic_quality")
public class HeroicQuality
{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id")
protected long id;
#Column(name = "name", nullable = false, unique = true)
private String name;
#OneToMany(fetch = FetchType.EAGER, cascade = CascadeType.ALL)
#JoinColumn(name = "id")
#Fetch(FetchMode.SELECT)
private List<Hero> heroes;
//ommited getters and setters for shortness
}
#Table(name = "hero")
#Entity(name = "hero")
public class Hero
{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id")
protected long id;
#Column(name = "name", nullable = false, unique = true)
private String name;
//ommited getters and setters for shortness
}
As you see my Hero class doesn't have reference to heroic quality, and I would like to keep it that way.
Also I have a repository
#Repository
public interface HeroicQualityDAO
extends PagingAndSortingRepository<HeroicQuality, Long>
{
Optional<HeroicQuality> findByName(String name);
List<HeroicQuality> findByOrderByIdDesc();
}
What I would like to do is have a method such as
Optional<HeroicQuality> findByHeroName(String heroName)
Such that if given a name of hero from Hero table I will be able to get heroic quality object.
How can I make such a method?
Is there any way I can get heroic quality object without having a reference to it in the hero object?
How can I go about doing that?
Add the following method to HeroicQualityDAO.
Optional<HeroicQuality> findByHeroesName(String heroName);
If you are not happy with the method name, you can do
#Query("Select h from HeroicQuality hq join hq.heros h where h.name = :name")
Optional<HeroicQuality> findByHeroName(String name);

Hibernate creates self relation on a table using the primary key

I have an Entity Episode
#Id //The unique id.
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private Long id;
#Column(name= "title", unique = false, nullable = false)
private String title;
#Column(name= "description", unique = false, nullable = false)
private String description;
#Column(name= "price", unique = false, nullable = false)
private BigDecimal price;
#OneToOne(cascade = {CascadeType.ALL}, fetch = FetchType.EAGER)
private Image icon;
#OneToOne(cascade = {CascadeType.ALL}, fetch = FetchType.EAGER)
private Image episodeNexus;
private String repositoryGeneratedId;
#JsonIgnore
#ManyToOne(cascade = {CascadeType.ALL}, fetch = FetchType.LAZY)
#JoinColumn(name="webtoon_id")
Webtoon webtoon;
Webtoon
#Id //The unique id of the webtoon.
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private Long id;
#Column(name= "price", unique = false, nullable = false)
private BigDecimal price;
#OneToOne(cascade = {CascadeType.ALL}, fetch = FetchType.EAGER)
private Image cover;
#OneToOne(cascade = {CascadeType.ALL}, fetch = FetchType.EAGER)
private Image icon;
#Column(name= "title", unique = false, nullable = false)
private String title;
#Column(name= "author_name", unique = false, nullable = false)
private String authorName;
#Column(name= "description", unique = false, nullable = false)
private String description;
#Column(name= "language", unique = false, nullable = false)
private String language;
#Column(name= "company_id", unique = false, nullable = false)
private Long companyId;
#OneToMany(cascade = {CascadeType.ALL}, fetch = FetchType.LAZY, mappedBy="webtoon", orphanRemoval = false)
#Column(name= "user_review", nullable = true)
private List<Review> userReview = new ArrayList<>();
#OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER, mappedBy="webtoon", orphanRemoval = false)
#CollectionTable(name= "list_of_episodes")
#Fetch(value = FetchMode.SUBSELECT)
private List<Episode> listOfEpisodes = new ArrayList<>();
#OneToOne(fetch = FetchType.EAGER)
private Category category;
#OneToOne(fetch = FetchType.EAGER)
private SubCategory subCategory;
#OneToOne(cascade = {CascadeType.ALL}, fetch = FetchType.EAGER)
#JoinColumn(name = "rating", unique=true, nullable=false)
private Rating rating = new Rating();
private String repositoryGeneratedId;
and Image
#Id //The unique id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
private String nexusId;
private String path;
private String name;
private String generatedUniqueId;
private Long size;
When I start my app, I notice that Hibernate create a foreign-key using the id. How is it possible ?
The code generated is the below. This constraint CONSTRAINT fkae0gia7g5anc7p031c00mdf7x FOREIGN KEY (id) must not exist.
CREATE TABLE public.episode
(
id bigint NOT NULL,
description character varying(255) COLLATE pg_catalog."default" NOT NULL,
price numeric(19,2) NOT NULL,
repository_generated_id character varying(255) COLLATE pg_catalog."default",
title character varying(255) COLLATE pg_catalog."default" NOT NULL,
episode_nexus_id bigint,
icon_id bigint,
webtoon_id bigint,
CONSTRAINT episode_pkey PRIMARY KEY (id),
CONSTRAINT fkae0gia7g5anc7p031c00mdf7x FOREIGN KEY (id)
REFERENCES public.episode (id) MATCH SIMPLE
ON UPDATE NO ACTION
ON DELETE NO ACTION,
CONSTRAINT fkeom9w8fbdmqm8j9nkq5hqglia FOREIGN KEY (icon_id)
REFERENCES public.image (id) MATCH SIMPLE
ON UPDATE NO ACTION
ON DELETE NO ACTION,
CONSTRAINT fksd2jfjxp5puq4cnp4renveldi FOREIGN KEY (episode_nexus_id)
REFERENCES public.image (id) MATCH SIMPLE
ON UPDATE NO ACTION
ON DELETE NO ACTION,
CONSTRAINT fkthwbcsb0axcklmd5wfhr650b9 FOREIGN KEY (webtoon_id)
REFERENCES public.webtoon (id) MATCH SIMPLE
ON UPDATE NO ACTION
ON DELETE NO ACTION
)
WITH (
OIDS = FALSE
)
Set hibernate.hbm2ddl.auto value to none in your Hibernate configuration.
See Automatic schema generation in Hibernate User Guide for details.

Spring data JPA join table with extra column

I'm trying to implement a meeting model which contains multiple equipment entity with corresponding quantity.
In the view of meeting, user should be able to CRUD equipment and quantity of this equipment of a meeting
databases:
CREATE TABLE IF NOT EXISTS equipment (
equipment_id SERIAL PRIMARY KEY,
equipment_name VARCHAR(20) NOT NULL
);
CREATE TABLE IF NOT EXISTS meeting (
meeting_id SERIAL PRIMARY KEY,
meeting_time TIMESTAMP NOT NULL,
number_people INTEGER NOT NULL,
setup VARCHAR(255)
);
CREATE TABLE IF NOT EXISTS meeting_equipment (
meeting_equipment_id SERIAL PRIMARY KEY ,
meeting_id INTEGER NOT NULL REFERENCES meeting (meeting_id),
equipment_id INTEGER NOT NULL REFERENCES equipment (equipment_id),
quantity INTEGER NOT NULL DEFAULT 0
);
Entity implementation:
#Entity
#Table(name = "meeting")
#Data
public class Meeting {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "meeting_id", updatable = false)
#JsonIgnore
private int id;
#Column(name = "meeting_time")
#JsonFormat(pattern = "yyyy-MM-dd HH:mm")
#NotNull
private LocalDateTime meetingTime;
#Column(name = "number_people")
#NotNull
#Min(1)
private int numberPeople;
#Column(name = "setup")
#NotNull
private String setup;
#OneToMany(mappedBy = "meeting", cascade = CascadeType.ALL)
#JsonManagedReference
List<MeetingEquipment> equipmentList = new ArrayList<>();
}
#Entity
#Table(name = "equipment")
#Data
public class Equipment {
#Id
#Column(name = "equipment_id", updatable = false)
#JsonIgnore
private int id;
#NotNull
#Column(name = "equipment_name", unique = true)
#Size(min = 1, max = 100)
private String equipmentName;
}
Join table metting_equipment:
#Entity
#Table(name = "meeting_equipment", uniqueConstraints = {
#UniqueConstraint(columnNames = {"meeting_id", "equipment_id"})})
#Data
public class MeetingEquipment {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "meeting_equipment_id", updatable = false)
#JsonIgnore
private int id;
#ManyToOne
#JoinColumn(name = "meeting_id")
#NotNull
#JsonBackReference
private Meeting meeting;
#ManyToOne
#JoinColumn(name = "equipment_id")
#NotNull
private Equipment equipment;
#Column(name = "quantity")
#NotNull
private int quantity;
}
Using the code above, I can successfully create meeting with equipment included (JSON returned from creation method shows correct content). But once I try to remove an element of equipmentList in meeting entity, it does not delete meetingEquipment entity. I tried
meeting.getEquipmentList().clear() and meetingEquipmentDao.delete(meeting.getEquipmentList()), neither works.
Could anyone tell me the cause of this problem, thanks!

Jpa ManytoMany issue with Spring Boot

I have a postgres database and I am trying to make a simple REST service with Spring Boot. I have a problem with jpa ManytoMany relationship.
Person Entity:
#Entity
#Table(name = "person", schema = "persons")
public class Person implements Serializable {
#Id
#GeneratedValue(strategy= GenerationType.IDENTITY)
private Integer id;
#Column(nullable = false)
private String name;
#Column(nullable = false)
private String email;
#Column
private Integer age;
#ManyToOne
#JoinColumn(name = "country_id", referencedColumnName = "id")
private Country countryOfBirth;
#ManyToMany
#JoinTable(
name="persons_countries_residence",
joinColumns=#JoinColumn(name="person_id", referencedColumnName="id"),
inverseJoinColumns=#JoinColumn(name="country_id", referencedColumnName="id"))
private List<Country> countriesOfResidence;
// getters and setters and to String method overriden
}
Country Entity:
#Entity
#Table(name = "country", schema = "persons")
public class Country implements Serializable {
#Id
#GeneratedValue(strategy= GenerationType.IDENTITY)
private Integer id;
#Column(name = "country_name")
private String name;
#Column(name = "country_code")
private String code;
// getters and setters and to String method overriden
}
The postgres schema is the following:
Person Table:
CREATE TABLE persons.person
(
id serial NOT NULL,
name character varying(50) NOT NULL,
email character varying(40) NOT NULL,
age integer,
country_id serial NOT NULL,
CONSTRAINT id PRIMARY KEY (id),
CONSTRAINT country_id FOREIGN KEY (id)
REFERENCES persons.country (id) MATCH SIMPLE
ON UPDATE NO ACTION ON DELETE NO ACTION
)
Country table:
CREATE TABLE persons.country
(
id serial NOT NULL,
country_name character varying(45) NOT NULL,
country_code character varying(10) NOT NULL,
CONSTRAINT country_id PRIMARY KEY (id)
)
Join table:
CREATE TABLE persons.persons_countries_residence
(
person_id integer NOT NULL,
country_id integer NOT NULL,
CONSTRAINT person_country_id PRIMARY KEY (person_id, country_id),
CONSTRAINT persons_countries_residence_country_id_fkey FOREIGN KEY (country_id)
REFERENCES persons.country (id) MATCH SIMPLE
ON UPDATE CASCADE ON DELETE NO ACTION,
CONSTRAINT persons_countries_residence_person_id_fkey FOREIGN KEY (person_id)
REFERENCES persons.person (id) MATCH SIMPLE
ON UPDATE CASCADE ON DELETE CASCADE
)
When i make an HTTP method call, I don't get the Countries of residence.
Service code:
#RequestMapping(method = RequestMethod.GET, produces = {MediaType.APPLICATION_JSON_VALUE, MediaType.APPLICATION_XML_VALUE})
public List<Person> getAllPersons() {
retutn jpaPersonRepository.findAll();
}
Any help appreciated.
Maybe, you need to specify a schema name in the join table name:
#JoinTable(
name="persons_countries_residence", schema="persons",
joinColumns=#JoinColumn(name="person_id", referencedColumnName="id"),
inverseJoinColumns=#JoinColumn(name="country_id", referencedColumnName="id"))
Update your Country class code like :
#Entity
#Table(name = "country", schema = "persons")
public class Country implements Serializable {
#Id
#GeneratedValue(strategy= GenerationType.IDENTITY)
private Integer id;
#Column(name = "country_name")
private String name;
#Column(name = "country_code")
private String code;
#ManyToMany(mappedBy = "countriesOfResidence")
private List<Person> persons;
// getters and setters and to String method overriden
}
Although a ManyToMany relationship is always bi-directional on the
database, the object model can choose if it will be mapped in both
directions, and in which direction it will be mapped in. If you choose
to map the relationship in both directions, then one direction must be
defined as the owner and the other must use the mappedBy attribute to
define its mapping. This also avoids having to duplicate the JoinTable
information in both places.
Do you mean that the country list is null? #ManyToMany associations are lazily loaded by default, you need to enable eager-fetching for it to work straight away.
#ManyToMany(fetch = FetchType.EAGER)
The solution is this:
#ManyToMany
#JoinTable(
name="persons_countries_residence", schema = "persons",
joinColumns=#JoinColumn(name="person_id", referencedColumnName="id"),
inverseJoinColumns=#JoinColumn(name="country_id", referencedColumnName="id"))
private List<Country> countriesOfResidence;
The schema had to be specified at the #JoinTable annotation as well.

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