First, I use detach() in laravel with this approach and this is work!
$student = \App\StudentRegistrars::withTrashed()->findOrFail($id);
$student->father_registrars()->detach();
$student->mother_registrars()->detach();
But when I am trying to mass detach in laravel, I can't do that.
$students = \App\StudentRegistrars::whereIn('id', $ids);
$student->father_registrars()->detach();
$student->mother_registrars()->detach();
Any solution about this problem?
There's quite a few issues with your code. You're close, but not quite there.
First, you need to be aware of what your variable is. Currently, this is not working, as $student is not defined. You called your variable $students (with an 's'), so make sure you're using the right variable.
Secondly, at the point you're calling detach(), your $students variable is an instance of the Builder class, not a single StudentRegistrars instance. You need to finalize your query with a closure:
$students = \App\StudentRegistrars::whereIn('id', $ids)->get();
Thirdly, the detach() method only works on a single instance, so if you called $students->father_registrars()->detach(), it would still fail.
You need to iterate your results and call detach() one-by-one:
foreach ($students as $student) {
$student->father_registrars()->detach();
$student->mother_registrars()->detach();
}
You final code would therefore be:
$students = \App\StudentRegistrars::whereIn('id', $ids)->get();
foreach ($students as $student) {
$student->father_registrars()->detach();
$student->mother_registrars()->detach();
}
There are more efficient approaches to mass detachment, such as directly querying and deleting records from the pivot table (or tables):
DB::table('pivot')->whereIn('column', $ids)->delete();
But this answer serves to fix your logic issues.
Related
I have a redirect function that looks like this. For some reason, it looks like it's sometimes missing to increment the item. I'm wondering if it sometimes can be so that it misses this because some caching or something?
public function redirect($key)
{
$item = $this->items->findOrFail($key);
$item->increment('redirects');
$encode = urlencode($item->_url);
return view('item.redirect', ['url' => ($encode)]);
}
I'm not sure about topic of your question. Do you get such method somewhere from Laravel?
I don't know what is $key here but you should make sure this is single id (for example 2) and not array.
For single model:
$item->increment('redirects');
will work
but if $key sometimes is array then
$item = $this->item->findOrFail($key);
will be collection, so increment method would cause error, because there is no increment method on Eloquent collection.
I now spent hours googling and experimenting on trying to get an relation with two intermediate tables working.
My database looks like this:
(apt_id is apartment_id in real, was shorter to write)
I have every relation one away setup correctly with belongsTo and and hasMany:
EXAMPLE FROM House.php
public function user()
{
return $this->belongsTo('App\User');
}
public function apartments()
{
return $this->hasMany('App\Apartment');
}
Isn't there a way to access these relations like:
$house->apartments->tenants->entries
in Blade:
#foreach ( $house->apartments->tenants->entries as $entry )
, since I want to display all house entries on house.show (Blade View)
The only way it's working is by using a bunch of foreach inside each others... :/ and they define the order...
Using my wanted relation calling produces:
Property [tenants] does not exist on this collection instance.
displayed on the page.
Greetings,
Pat
I don't think you can achieve what you want using the code you posted, because when calling, for example, $house->apartments it returns a Collection object. So, it is not dealing with database anymore, that's why you would need to use a bunch of #foreachs.
I don't know if this is the best way to solve this, or if it will help you in your actual problem, but you could think this problem backwards and try something like this:
$entries = \App\Entry::whereHas('tenants', function($q) use ($house) {
$q->whereHas('apartments', function($q1) use ($house) {
$q1->where('apartments.house_id', $house->id);
});
})->get();
And in the view:
#foreach ($entries as $entry)
{{ $entry->tenant->apartment->house->name }}
#endforeach
I am working with laravel 4.2 and have table in db with property is_active.
When I try to access this model property:
$model->is_active
I am getting following error:
Relationship method must return an object of type Illuminate\Database\Eloquent\Relations\Relation
So question is how to access this property?
Please do not recommend to rename this field in the database if possible because this is already existing database in production.
Here is my model class:
class Position extends \Eloquent {
protected $table = "hr_positions";
protected $fillable = ['slug', 'info_small', 'info_full', 'is_active', 'start_date', 'end_date', 'tags', 'user_create_id', 'user_update_id'];
use \MyApp\Core\StartEndDateTrait;
public function postulations(){
return $this->hasMany('Postulation', 'position_id', 'id');
}
}
Latest notice:
All this error ocurrs on a page where I am creating my entity. In the controller before forwarding to the page I am doing:
$position = new \Position();
and then, for example, following code produce error as well:
dd(($position->getAttribute('is_active')));
but if I replace $position = new \Position(); with
$position = \Position::first();
error is gone?
What is going on here?????
Laravel does a lot of magic behind the scenes, as in, calls a lot of php magic methods.
If a called property is not defined, __call is invoked which in Eloquent calls getAttribute().
Steps taken by getAttribute($key) are
Is there a database field by this key? If so, return it.
Is there a loaded relationship by this key? If so, return it.
Is there a camelCase method of this key? If so, return it. (is_active looks for isActive method)
Returns null.
The only time that exception is thrown is in step 3.
When you create a new instance, eloquent has no idea what kind of fields it has, so if you have a method by the same name, it will always throw a relation error, this seems to be the case in both Laravel4 and Laravel5.
How to avoid it? Use the getAttributeValue($key) method. It has no relation checks and returns null by default.
Alternatively you can also add a get mutator for your field.
I have found a hack for this. Still not ideal but at least I have some solution. Better any than none.
So This code produce problem:
$position = new \Position();
if($position->is_active){
//
}
and this one works fine, this is solution even hacky but solution:
$position = new \Position(['is_active' => 0]);
if($position->is_active){
//
}
I will wait if someone give better, cleaner solution. If no one comes in next few days I will accept mine.
Let me explain about my problem.
I am currently using Laravel 5.0. Here is my structure
Table: bgts, Model: Bgt, Controller: BgtController
Table: bgthistories, Model: BgtHistory
Now I want to do these:
Everytimes creating new item into bgts table, I want to make a copy and insert into bgthistories table. Then, everytimes that record is updated, i'll copy one more version, still insert into bgthistories.
Here is store() method.
public function store(Request $request) {
$bgt = new Bgt();
$history = $this->coppy($bgt);
$uploader = new UploadController('/data/uploads/bgt');
$bgt->name = $request['name'];
$bgt->avatar = $uploader->avatar($request);
$bgt->attachments($uploader->attachments($request));
//dd($bgt);
$bgt->save();
$history->save();
return redirect('bgt');
}
And this is the coping:
public function coppy($bgt) {
$array = $this->$bgt->toArray();
$version = new BgtHistory();
foreach($array as $key => $value) {
$version->$key = $value;
}
return $version;
}
I create migration tables already. Everything is ready. But, when I call
$bgt->save();
$history->save();
It did not work. If I remove $history->save();, it create new record ok. I think the save() method that built-in in Model provided by Laravel is problem. Can anyone tell me how to solve this.
I tried to build the raw query then executed it by DB:statement but it did not work too. Every try to execute anything with DB is failing.
Please research before re-inventing the wheel.
(Same stuff different sites in case one is down)
http://packalyst.com/packages/package/mpociot/versionable
https://packagist.org/packages/mpociot/versionable
https://github.com/mpociot/versionable
Cheers and good luck ;)
I want to update all my records where the name is like the one im referencing it.
However im getting an error saying Call to undefined method save()
Here's my code
$section = Section1::where('name', 'like', 'ss123')->get();
$section->name = Input::get('name');
Please help :(
$section = Section1::where('name', 'like', 'ss123')->get() returns a collection (think of an array).
Therefore you should loop through the collection using foreach and apply the save to each object in the collection, as such:
foreach($section as $s)
{
$s->name = Input::get('name');
$s->update();
}
Then again this ain't very DB-friendly.
Therefore, the most appropriate action in your case will be a mass update:
Section1::where('name','like','ss1213')->update(['name'=>Input::get('name')]);
try dd($section) and find the available method to prevent call the undefined method.
I assume you are using $section->save();
if you want to update,
use $section->touch();
or $section->update(array('name' => Input::get'name'));