I want to take the max of the progress column that is ordered with a distinct column name.
For example;
progress - journey_id
0 - 90
12 - 90
89 - 90
7 - 90
the code I tried to make but I couldn't do more
$impressions = DB::table('journey_content_impression')
->where('user_id', 11)
->where('journey_id',12)
->select('journey_item_id','progress')->distinct()->get();
Finally, It should give us one row with the max number.
Also, other columns of row should be available like this,
$impressions->first()->user_id; //
Try this:
$impressions = DB::table('journey_content_impression')
->where('user_id',{id})
->where('journey_id',{j_id})
->groupBy('journey_item_id')
->get(['journey_item_id', DB::raw('MAX(progress) as progress')]);
Maybe it helps you try this
$impressions = DB::table('journey_content_impression')
->where([['user_id', 11],['journey_id',12]])
->select('journey_item_id','progress')->distinct()->get();
Related
My data consists of large numbers, I have a column say - 'amount', while using it in charts(sum of amount in Y axis) it shows something like 1.4G, I want to show them as if is billion then e.g. - 2.8B, or in millions then 80M or if it's in thousands (14,000) then simply- 14k.
I have used - if(sum(amount)/1000000000 > 1, Num(sum(amount)/1000000000, '#,###B'), Num(sum(amount)/1000000, '#,###M')) but it does not show the M or B at the end of the figure and also How to include thousand in the same code.
EDIT: Updated to include the dual() function.
This worked for me:
=dual(
if(sum(amount) < 1, Num(sum(amount), '#,##0.00'),
if(sum(amount) < 1000, Num(sum(amount), '#,##0'),
if(sum(amount) < 1000000, Num(sum(amount)/1000, '#,##0k'),
if(sum(amount) < 1000000000, Num(sum(amount)/1000000, '#,##0M'),
Num(sum(amount)/1000000000, '#,##0B')
))))
, sum(amount)
)
Here are some example outputs using this script to format it:
=sum(amount)
Formatted
2,526,163,764
3B
79,342,364
79M
5,589,255
5M
947,470
947k
583
583
0.6434
0.64
To get more decimals for any of those, like 2.53B instead of 3B, you can format them like '#,##0.00B' by adding more zeroes at the end.
Also make sure that the Number Formatting property is set to Auto or Measure expression.
I am trying to plot Num/Den type percentages using OVER. But my thoughts does not appear to translate into spotfire custom expression syntax.
Sample Input:
RecordID CustomerID DOS Age Gender Marker
9621854 854693 09/22/15 37 M D
9732721 676557 09/18/15 65 M D
9732700 676557 11/18/15 65 M N
9777003 5514882 11/25/15 53 M D
9853242 1753256 09/30/15 62 F D
9826842 1260021 09/30/15 61 M D
9897642 3375185 09/10/15 74 M N
9949185 9076035 10/02/15 52 M D
10088610 3512390 09/16/15 33 M D
10120650 41598 10/11/15 67 F N
9949185 9076035 10/02/15 52 M D
10088610 3512390 09/16/15 33 M D
10120650 41598 09/11/15 67 F N
Expected Out:
Row Labels D Cumulative_D N Cumulative_N Percentage
Sep 6 6 2 2 33.33%
Oct 2 8 1 3 37.50%
Nov 1 9 1 4 44.44%
My counts are working.
I want to take the same Cumulative_N & Cumulative_D count and plot Percentage over [Axis.X] as a line chart.
Here's what I am using:
UniqueCount(If([Marker]="N",[CustomerID])) / UniqueCount(If([Marker]="D",[CustomerID])) THEN SUM([Value]) OVER (AllPrevious([Axis.X])) as [CumulativePercent]
I understand SUM([Value]) is not the way to go. But I don't know what to use instead.
Also tried the one below as well, but did not:
UniqueCount(If([Marker]="N",[CustomerID])) OVER (AllPrevious([Axis.X])) / UniqueCount(If([Marker]="D",[CustomerID])) OVER (AllPrevious([Axis.X])) as [CumulativePercent]
Can you have a look ?
I found a way to make it work, but it may not fit your overall solution. I should mention i used Count() versus UniqueCount() so that the results would mirror your desired output.
Add a transformation to your current data table
Insert a calculated column Month([DOS]) as [TheMonth]
Set Row Identifers = [TheMonth]
Set value columns and aggregation methods to Count([CustomerID])
Set column titles to [Marker]
Leave the column name pattern as %M(%V) for %C
That will give you a new data table. Then, you can do your cumulative functions. I did them in a cross table to replicate your expected results. Insert a new cross table and set the values to:
Sum([D]), Sum([N]), Sum([D]) OVER (AllPrevious([Axis.Rows])) as [Cumulative_D],
Sum([N]) OVER (AllPrevious([Axis.Rows])) as [Cumulative_N],
Sum([N]) OVER (AllPrevious([Axis.Rows])) / Sum([D]) OVER (AllPrevious([Axis.Rows])) as [Percentage]
That should do it.
I don't know if Spotfire released a fix or based on everyone's inputs I could get the syntax right. But here is the solution that worked for me.
For Columns D & N,
COUNT([CustomerID])
For columns Cumulative_D & Cumulative_N,
Count([CustomerID]) OVER (AllPrevious([Axis.X])) where [Axis.X] is DOS(Month), Marker
For column Percentage,
Count(If([Marker]="N",[CustomerID])) OVER (AllPrevious([Axis.X])) / Count(If([Marker]="D",[CustomerID])) OVER (AllPrevious([Axis.X]))
where [Axis.X] is DOS(Month)
I am using CDH 5.5, Pig 0.12.0. I have a chararray like this: 25 - 45 and I want to extract 25 and 45 out of this String.
So, I did this:
minValue = (int)SUBSTRING(value,0,2);
maxValue = ((int)SUBSTRING(value,6,2);
I am able to extract minValue but unable to extract the maxValue i.e. last two characters of the given String.
Even I tried but this one is also not working.:
maxValue = ((int)SUBSTRING(value,-2,2);
Please let me know how to make this work.
If delimeter is colon ( - ) always, then we can split and flatten the chararray to extract min and max value.
A = LOAD 'input.csv' USING PigStorage(',') AS (min_max:chararray);
B = FOREACH A GENERATE FLATTEN(STRSPLIT(min_max,' - ',0)) AS (min_val:chararray, max_val:chararray);
DUMP B;
Input :
25 - 45
35 - 65
45 - 85
Output :
(25,45)
(35,65)
(45,85)
You have to use the index of the specific character in the SUBSTRING function.
Here is what you need.
maxValue = (int)SUBSTRING(value,5,7);
I created a toy example of my code below.
In this toy example I would like to create a measure of all higher prices minus lower prices within a self-created reference group. So within each reference group, I would like to take each individual and subtract its price value from all higher price values from other individuals in the same group. I do not want to have negative differences. Then I would like to sum all these differences. In creating this code I found some help here:
http://www.stata.com/support/faqs/data-management/try-all-values-with-foreach/
However, the code didn't work perfectly for me, because my dataset is quite large (several 100K obs) and the examples on the website and my code only work until the numlist maximum of 1600 in Stata. (I am using version 12). The toy example with the auto dataset works, due to small size of the dataset.
I would like to ask if someone has an idea how to code this more efficiently, so that I can get around the numlist restriction. I thought about summing the differences directly without saving them in intermediate variables, but that also blow up the numlist restriction.
clear all
sysuse auto
ren headroom refgroup
bysort refgroup : egen pricerank = rank(price)
qui: su pricerank, meanonly
gen test = `r(max)'
su test
foreach i of num 1/`r(max)' {
qui: bys refgroup: gen intermediate`i' = price[_n+`i'] -price if price[_n+`i'] > price
}
egen price_diff = rowmax(intermediate*)
drop intermediate*
If I understand this correctly, this isn't even a problem that requires explicit loops. The sum of all higher prices is just the difference between two cumulative sums. You might need to think through what you want to do if prices are tied.
. clear
. set obs 10
obs was 0, now 10
. gen group = _n > 5
. set seed 2803
. gen price = ceil(1000 * runiform())
. bysort group (price) : gen sumhigherprices = sum(price)
. by group : replace sumhigherprices = sumhigherprices[_N] - sumhigherprices
(10 real changes made)
. list
+--------------------------+
| group price sumhig~s |
|--------------------------|
1. | 0 218 1448 |
2. | 0 264 1184 |
3. | 0 301 883 |
4. | 0 335 548 |
5. | 0 548 0 |
|--------------------------|
6. | 1 125 3027 |
7. | 1 213 2814 |
8. | 1 828 1986 |
9. | 1 988 998 |
10. | 1 998 0 |
+--------------------------+
Edit: For what the OP needs, there is an extra line
. by group : replace sumhigherprices = sumhigherprices - (_N - _n) * price
If I understand the wording of the problem correctly, maybe this can help. It uses joinby (new observations are created and depending on the size of the original database, you may or not hit the Stata hard-limit on number of observations). The code reproduces the results that would follow from the code of the original post. This is a second attempt. The code before this final edit did not provide the sought-after results. The wording of the problem was somewhat difficult for me to understand.
clear all
set more off
* Load data
sysuse auto
* Delete unnecessary vars
ren headroom refgroup
keep refgroup price
* Generate id´s based on rankings (sort)
bysort refgroup (price): gen id = _n
* Pretty list
order refgroup id
sort refgroup id price
list, sepby(refgroup)
* joinby procedure
tempfile main
save "`main'"
rename (price id) =0
joinby refgroup using "`main'"
list, sepby(refgroup)
* Do not compare with itself and drop duplicates
drop if id0 >= id
* Compute differences and max
gen dif = abs(price0 - price)
collapse (max) dif, by(refgroup id0)
list, sepby(refgroup)
I have written the following function that find if a pixel belongs to an image in matlab.
At the beginning, I wanted to test it as if a number in a set belongs to a vector like the following:
function traverse_pixels(img)
for i:1:length(img)
c(i) = img(i)
end
But, when I run the following commands for example, I get the error shown at the end:
>> A = [ 34 565 456 535 34 54 5 5 4532 434 2345 234 32332434];
>> traverse_pixels(A);
??? Error: File: traverse_pixels.m Line: 2 Column: 6
Unexpected MATLAB operator.
Why is that? How can I fix the problem?
Thanks.
There is a syntax error in the head of your for loop, it's supposed to be:
for i = 1:length(img)
Also, to check if an array contains a specific value you could use:
A = [1 2 3]
if sum(A==2)>0
disp('there is at least one 2 in A')
end
This should be faster since no for loop is included.
for i = 1:length(image)
silly error, not : , it is =