I see a below syntax in one of the ruby files written by an user. Can someone help me in understanding what the below code means?
if fieldWidth==nil
fW = regStr.length
else
fW = fieldWidth
regStr.rjust(fW,'0') # Left pad with 0s if fW > regStr.length
end
if fW >= fWOld: fWMax = fW end
fWOld = fW
regStrIx = 0
In the context of the if conditional, a footnote in The Ruby Programming Language on page 119 : "Ruby 1.8 also allows a colon, but this syntax is no longer legal in 1.9."
A newline or semicolon or the keyword then is correct.
Related
In Ruby, I'm reading an .ifc file to get some information, but I can't decode it. For example, the file content:
"'S\X2\00E9\X0\jour/Cuisine'"
should be:
"'Séjour/Cuisine'"
I'm trying to encode it with:
puts ifcFileLine.encode("Windows-1252")
puts ifcFileLine.encode("ISO-8859-1")
puts ifcFileLine.encode("ISO-8859-5")
puts ifcFileLine.encode("iso-8859-1").force_encoding("utf-8")'
But nothing gives me what I need.
I don't know anything about IFC, but based solely on the page Denis linked to and your example input, this works:
ESCAPE_SEQUENCE_EXPR = /\\X2\\(.*?)\\X0\\/
def decode_ifc(str)
str.gsub(ESCAPE_SEQUENCE_EXPR) do
$1.gsub(/..../) { $&.to_i(16).chr(Encoding::UTF_8) }
end
end
str = 'S\X2\00E9\X0\jour/Cuisine'
puts "Input:", str
puts "Output:", decode_ifc(str)
All this code does is replace every sequence of four characters (/..../) between the delimiters, which will each be a Unicode code point in hexadecimal, with the corresponding Unicode character.
Note that this code handles only this specific encoding. A quick glance at the implementation guide shows other encodings, including an \X4 directive for Unicode characters outside the Basic Multilingual Plane. This ought to get you started, though.
See it on eval.in: https://eval.in/776980
If someone is interested, I wrote here a Python Code that decode 3 of the IFC encodings : \X, \X2\ and \S\
import re
def decodeIfc(txt):
# In regex "\" is hard to manage in Python... I use this workaround
txt = txt.replace('\\', 'µµµ')
txt = re.sub('µµµX2µµµ([0-9A-F]{4,})+µµµX0µµµ', decodeIfcX2, txt)
txt = re.sub('µµµSµµµ(.)', decodeIfcS, txt)
txt = re.sub('µµµXµµµ([0-9A-F]{2})', decodeIfcX, txt)
txt = txt.replace('µµµ','\\')
return txt
def decodeIfcX2(match):
# X2 encodes characters with multiple of 4 hexadecimal numbers.
return ''.join(list(map(lambda x : chr(int(x,16)), re.findall('([0-9A-F]{4})',match.group(1)))))
def decodeIfcS(match):
return chr(ord(match.group(1))+128)
def decodeIfcX(match):
# Sometimes, IFC files were made with old Mac... wich use MacRoman encoding.
num = int(match.group(1), 16)
if (num <= 127) | (num >= 160):
return chr(num)
else:
return bytes.fromhex(match.group(1)).decode("macroman")
I have a ruby string array value and i want to get it as string value. I am using ruby with chef recipe. Running in windows platform. Code-
version_string = Mixlib::ShellOut.new('some.exe -version').run_command
Log.info(version.stdout.to_s)
extract_var = version_string.stdout.to_s.lines.grep(/ver/)
Log.info('version:'+ extract_var.to_s)
output is coming-
version 530
[2016-06-08T07:03:49+00:00] INFO: version ["version 530\r\n"]
I want to extract 530 string only.
long time no see since Rot :)
You can use some Chef helper methods and regular expressions to make this a little easier.
output = shell_out!('saphostexec.exe -version', cwd: 'C:\\Program Files\\hostctrl\\exe').stdout
if output =~ /kernel release\s+(\d+)/
kernel_version = $1
else
raise "unable to parse kernel version"
end
Chef::Log.info(kernel_version)
As you want val = 720 and not val = "720" you can write
val = strvar.first.to_i
#=> 720
You can return the first series of digits found as an integer from the current_kernel string with String#[regexp] :
current_kernel[/\d+/].to_i
#=> 720
In File.open, there seems to be two systems, one set uses "r", "w", "wb", and the other uses "RDONLY", "RDWR". For the second set, I haven't found the flag for "b". Thanks for the help.
"File::BINARY"
uninitialized constant File::BINARY (NameError)
Those flags are called mode flags. The mode flag for binary is BINARY.
See http://www.ruby-doc.org/core-2.1.2/File/Constants.html
File::BINARY, listed in File constants.
EDIT: On my system, it works:
$ ruby -e "puts File::BINARY"
0
(it doesn't do much, but it's there). Note this:
If the underlying platform doesn't define a constant the corresponding Ruby constant is not defined.
So you might be getting interference from your OS? Or maybe you misspelled it?
Try this in any ruby program:
p File::RDONLY
p File::CREAT
p File::BINARY
I get:
--output:--
0
512
1.rb:3: uninitialized constant File::BINARY (NameError)
Or, to see which constants File::Constants actually defines on your system, you can do this:
File::Constants.constants.sort.each do |const|
puts "#{const} = #{File::Constants.const_get(const)}"
end
I get this:
APPEND = 8
CREAT = 512
EXCL = 2048
FNM_CASEFOLD = 8
FNM_DOTMATCH = 4
FNM_NOESCAPE = 1
FNM_PATHNAME = 2
FNM_SYSCASE = 0
LOCK_EX = 2
LOCK_NB = 4
LOCK_SH = 1
LOCK_UN = 8
NOCTTY = 131072
NONBLOCK = 4
RDONLY = 0
RDWR = 2
SYNC = 128
TRUNC = 1024
WRONLY = 1
No BINARY for me(OSX 10.6.8).
I have recently learned how to work with basic files in Fortran
and I assumed it was as simple as:
open(unit=10,file="data.dat")
read(10,*) some_variable, somevar2
close(10)
So I can't understand why this function I wrote is not working.
It compiles fine but when I run it it prints:
fortran runtime error:end of file
Code:
Function Load_Names()
character(len=30) :: Staff_Name(65)
integer :: i = 1
open(unit=10, file="Staff_Names.txt")
do while(i < 65)
read(10,*) Staff_Name(i)
print*, Staff_Name(i)
i = i + 1
end do
close(10)
end Function Load_Names
I am using Fortran 2008 with gfortran.
A common reason for the error you report is that the program doesn't find the file it is trying to open. Sometimes your assumptions about the directory in which the program looks for files at run-time will be wrong.
Try:
using the err= option in the open statement to write code to deal gracefully with a missing file; without this the program crashes, as you have observed;
or
using the inquire statement to figure out whether the file exists where your program is looking for it.
You can check when a file has ended. It is done with the option IOSTAT for read statement.
Try:
Function Load_Names()
character(len=30) :: Staff_Name(65)
integer :: i = 1
integer :: iostat
open(unit=10, file="Staff_Names.txt")
do while(i < 65)
read(10,*, IOSTAT=iostat) Staff_Name(i)
if( iostat < 0 )then
write(6,'(A)') 'Warning: File containts less than 65 entries'
exit
else if( iostat > 0 )then
write(6,'(A)') 'Error: error reading file'
stop
end if
print*, Staff_Name(i)
i = i + 1
end do
close(10)
end Function Load_Names
Using Fortran 2003 standard, one can do the following to check if the end of file is reached:
use :: iso_fortran_env
character(len=1024) :: line
integer :: u1,stat
open (newunit=u1,action='read',file='input.dat',status='old')
ef: do
read(u1,'A',iostat=stat) line
if (stat == iostat_end) exit ef ! end of file
...
end do ef
close(u1)
Thanks for all your help i did fix the code:
Function Load_Names(Staff_Name(65))!Loads Staff Names
character(len=30) :: Staff_Name(65)
integer :: i = 1
open(unit=10, file="Staff_Names.txt", status='old', action='read')!opens file for reading
do while(i < 66)!Sets Set_Name() equal to the file one string at a time
read(10,*,end=100) Staff_Name(i)
i = i + 1
end do
100 close(10)!closes file
return!returns Value
end Function Load_Names
I needed to change read(10,*) to read(10,*,END=100)
so it knew what to do when it came to the end the file
as it was in a loop I assume.
Then your problem was that your file was a row vector, and it was likely
giving you this error immediately after reading the first element, as #M.S.B. was suggesting.
If you have a file with a NxM matrix and you read it in this way (F77):
DO i=1,N
DO j=1,M
READ(UNIT,*) Matrix(i,j)
ENDDO
ENDDO
it will load the first column of your file in the first row of your matrix and will give you an error as soon as it reaches the end of the file's first column, because the loop enforces it to read further lines and there are no more lines (if N<M when j=N+1 for example). To read the different columns you should use an implicit loop, which is why your solution worked:
DO i=1,N
READ(UNIT,*) (Matrix(i,j), j=1,M)
ENDDO
I am using GNU Fortran 5.4.0 on the Ubuntu system 16.04. Please check your file if it is the right one you are looking for, because sometimes files of the same name are confusing, and maybe one of them is blank. As you may check the file path if it is in the same working directory.
I have a ruby multi-line string (called efixes) that looks like:
ID STATE LABEL INSTALL TIME UPDATED BY ABSTRACT
=== ===== ========== ================= ========== ======================================
1 S hayo32.02 xxxxxxx xxxxxxxx xxxxxxxxxxxxxxx
2 S 23434.23 xxxxxxx xxxxxxxx xxxxxxxxxxxxxxx
STATE codes:
S = STABLE
M = MOUNTED
U = UNMOUNTED
Q = REBOOT REQUIRED
B = BROKEN
I = INSTALLING
R = REMOVING
T = TESTED
P = PATCHED
N = NOT PATCHED
SP = STABLE + PATCHED
SN = STABLE + NOT PATCHED
QP = BOOT IMAGE MODIFIED + PATCHED
QN = BOOT IMAGE MODIFIED + NOT PATCHED
RQ = REMOVING + REBOOT REQUIRED
I only want to display the lines that start with a number. I am having trouble, it doesn't seem to be matching. I found this solution here, (that I don't truly understand right now):
efixes_array = efixes.split("\n").select{|x| /\A[0-9]/.match(x)}
io.puts efixes_array.collect{|x| x.scan(/\A[0-9]/)}.flatten
It is only matching the numbers. I want to display the entire line. The end result, I want to display what is under the "LABELS" column.
This line from your example code
efixes.split("\n").select{|x| /\A[0-9]/.match(x)}
returns an array with all lines that start with a number.