Simple question here. I have an old application that I'm tasked to converting to C#. I hate to ask what seems to be ridiculously simple, but I can't find an answer.
PROCEDURE Calc
PARAMETER apples,bananas
IF TYPE([bananas])#[C]
bananas=[] && What is this right here? Empty string? Empty array? Dynamic?
ENDIF
RETURN
Simple. It is an assignment of an empty string to the variable (or all array elements, if an array). It is the same as
bananas = ""
Related
I have a boolean expression: equals(myStringValue, targetStringValue)
I have an array expression which might or might not be valid, depending on the boolean condition myArrayExpression.
I want to write:
if(
equals(myStringValue, targetStringValue),
myArrayExpression,
?????
)
where ????? is an expression that returns an empty array.
Naturally, this is an XY-problem.
I definitely want to know how to do this directly, because understanding how this language works well is important to me. But if you want to know about the XY problem, it's over here: Azure ADF GetMetadata childItems if folder might not exist
Defining an array variable, with no default value, and then referencing that does work.
But seems very sad - now we've got an extra variable floating around for no reason :(
You can use if (x, Y, skip(createArray(''), 1))
I'm looking for some help understanding why I get an error (no implicit conversion of nil into String) when attempting to use a for-loop to search through an array of letters (and add them to a resulting string, which seems to be the real problem), but not when I use a while-loop or 'each' for the same purposes. I've looked through a lot of documentation, but haven't been able to find an answer as to why this is happening. I understand that I could just use the "each" method and call it a day, but I'd prefer to comprehend the cause as well as the effect (and hopefully avoid this problem in the future).
The following method works as desired: printing "result" which is the original string, only with "!" in place of any vowels.
s="helloHELLO"
result=""
vowels=["a","e","i","o","u","A","E","I","O","U"]
string_array=s.split("")
string_array.each do |i|
if vowels.include?(i)
result+="!"
else
result+=i
end
end
puts result
However, my initial attempt (posted below) raises the error mentioned above: "no implicit conversion of nil into String" citing lines 5 and 9.
s="helloHELLO"
result=""
vowels=["a","e","i","o","u","A","E","I","O","U"]
string_array=s.split("")
for i in 0..string_array.length
if vowels.include?(string_array[i])
result+= "!"
else
result+=string_array[i]
end
end
puts result
Through experimentation, I managed to get it working; and I determined--through printing to screen rather than storing in "result"--that the problem occurs during concatenation of the target letter to the string "result". But why is "string_array[i]" (line #9) seen as NIL rather than as a String? I feel like I'm missing something very obvious.
If it matters: This is just a kata on CodeWars that lead me to a fundamental question about data types and the mechanics of the for..in loop. This seemed very relevant, but not 100% on the mark for my question: "for" vs "each" in Ruby.
Thanks in advance for the help.
EDIT:
Okay, I think I figured it out. I'd still love some answers though, to confirm, clarify, or downright refute.
I realized that if I wanted to use the for-loop, I should use the array itself as the "range" rather than "0..array.length", like so:
s="helloHELLO"
result=""
vowels=["a","e","i","o","u","A","E","I","O","U"]
string_array=s.split("")
for i in string_array
if vowels.include?(i)
result+= "!"
else
result+=i
end
end
puts result
So, is it that since the "each" method variable (in this case, "i") doesn't exist outside the scope of the main block, its datatype become nil after evaluating whether it's included in the 'vowels' array?
You got beaten by the classical error when iterating an array starting with index 0, instead of length as end position it should be length-1.
But it seems like you come from some other programming language, your code is not Rubyesque, a 'For' for example is seldom used.
Ruby is a higher language than most others, it has many solutions build in, we call it 'sugared' because Ruby is meant to make us programmers happy. What you try to achieve can be done in just one line.
"helloHELLO".scan(/[aeoui]/i).count
Some explanation: the literal array "hello HELLO" is a String, meaning an object of the String class and as such has a lot of methods you can use, like scan, which scans the string for the regular expression /[aeoui]/ which means any of the characters enclosed in the [], the i at the end makes it case insentitive so you don't have to add AEOUI. The scan returns an array with the matching characters, an object of the Array class has the method count, which gives us the ... Yeah once you get the drift it's easy, you can string together methods which act upon each other.
Your for loop:
for i in 0..string_array.length
loops from 0 to 10.
But string[10] #=> nil because there is no element at index 10. And then on line 9 you try to add nil to result
result = result + string_array[i] #expanded
You can't add nil to a string like this, you have to convert nil to a string explicitly thus the error. The best way to fix this issue is to change your for loop to:
for i in 0..string_array.length-1
Then your loop will finish at the last element, string[9].
It has been a while since I've used Mathematica, and I looked all throughout the help menu. I think one problem I'm having is that I do not know what exactly to look up. I have a block of code, with things like appending lists and doing basic math, that I want to define as a single variable.
My goal is to loop through a sequence and when needed I wanted to call a block of code that I will be using several times throughout the loop. I am guessing I should just put it all in a loop anyway, but I would like to be able to define it all as one function.
It seems like this should be an easy and straightforward procedure. Am I missing something simple?
This is the basic format for a function definition in Mathematica.
myFunc[par1_,par2_]:=Module[{localVar1,localVar2},
statement1; statement2; returnStatement ]
Your question is not entirely clear, but I interpret that you want something like this:
facRand[] :=
({b, x} = Last#FactorInteger[RandomInteger[1*^12]]; Print[b])
Now every time facRand[] is called a new random integer is factored, global variables b and x are assigned, and the value of b is printed. This could also be done with Function:
Clear[facRand]
facRand =
({b, x} = Last#FactorInteger[RandomInteger[1*^12]]; Print[b]) &
This is also called with facRand[]. This form is standard, and allows addressing or passing the symbol facRand without triggering evaluation.
I used read to get a line from a file. The documentation said read returns any, so is it turning the line to a string? I have problems turning the string "1" to the number 1, or "500.8232" into 500.8232. I am also wondering if Racket can directly read numbers in from a file.
Check out their documentation search, it's complete and accurate. Conversion functions usually have the form of foo->bar (which you can assume takes a foo and returns a bar constructed from it).
You sound like you're looking for a function that takes a string and returns a number, and as it happens, string->number does exist, and does pretty much exactly what you're looking for.
Looks like this was answered in another question:
Convert String to Code in Scheme
NB: that converts any s-expression, not just integers. If you want just integers, try:
string->number
Which is mentioned in
Scheme language: merge two numbers
HTH
In XPath it is possible to convert an object to string using the string() function. Now I want to convert the string back to an object.
I do understand it is not possible in some cases (for example for elements), because some information was lost. But it should be possible for simple types, like int or boolean.
I know, for numbers I can use number() function, but I want general mechanism which will work for any simple type variable.
Going to string is easy, because you've told it that you want a string.
Similarly, going to number is easy, because you've told it that you want a number.
But there is no generic way to say 'turn it back into x', because you haven't told it what x is.
(In other words, string() is like a cast like Java/C/C++/C# have. But there is no uncast.)
string() isn't an object serializer, so you can't deserialize.
Why do you want this? Perhaps there is another way of solving your problem.
If your object $x is the number 1234, then string($x) will be the string "1234".
If your object $x is a nodeset of 1000 XML elements, the first one being
<wibble><wobble>1<ping/>2</wobble>34</wibble>
then string($x) will be the string "1234".
The function is not a bijection, you can't have an inverse as many different values map to the same string.
In no language (that I know of) you can cast A to B and then call a magical function that reverts it back to whatever it was before you casted it.
The process of converting some data type into something else is always an unidirectional one - you lose the information what type it was before. That's because the new data type has no way of storing what it was before.
So, what are you trying to do? I strongly suspect that you ask this question because you are tackling a problem from the wrong end.