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I want to parse and get url from a string such as hello google.comxxx，the output should be google.com, is there any easy way to do that?
There's a package named xurls which you can use.
import "mvdan.cc/xurls/v2"
func main() {
rxRelaxed := xurls.Relaxed()
rxRelaxed.FindString("Do gophers live in golang.org?") // "golang.org"
rxRelaxed.FindString("This string does not have a URL") // ""
rxStrict := xurls.Strict()
rxStrict.FindAllString("must have scheme: http://example.com/.", -1) // []string{"http://example.com/"}
rxStrict.FindAllString("no scheme, no match: example.com", -1) // []string{}
}
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How to convert "Hello" to string "72101108108111"
[]byte("Hello")=> [72 101 108 108 111]
byteStr := []byte("Hello")
var result string
for _, i := range byteStr {
result += fmt.Sprintf("%d", i)
}
fmt.Println(result)
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I have a raw string which is formed from array of strings like the one defined below
"['a','b','c']"
which i want to convert to proper array of string as below
["a","b","c"]
I am trying this on golang. However, i didn't succeed in getting this done. How this can be accomplished in go
var s = "['a','b','c']"
ss := strings.Split(strings.Trim(s, "[]"), ",")
a := make([]string, len(ss))
for i := range ss {
a[i] = strings.Trim(ss[i], "'")
}
out, err := json.Marshal(a)
if err != nil {
panic(err)
}
fmt.Println(string(out))
// output: ["a","b","c"]
https://go.dev/play/p/kQ0Up06K9zz
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why this program is not throwing any null pointer exception
https://go.dev/play/p/37reql6Pdb5
eventhough m is null, still accessing on m.
Check out this code snippet:
package main
import "fmt"
func main() {
var m map[string]string = nil
fmt.Println(m) // output: "map[]"
}
This is an intended behavior since nil acts as zero value for many types of variables, including (but not limited to) maps and slices.
Also, there's no such thing in Golang as "Exception". You can check if a value exists in your map using this syntax:
value, found := m["key"]
where the found variable indicates if the value exists in the map.
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if i have many option to be filter in IF statement, can i use some function like this?
s1 := "lorem ipsum"
sum := 0
for _, v := range s1 {
if string(v) like ("a","i","u","e","o") {
sum+=1
}
}
You can use switch statement.
Switch supports multiple matches
switch string(v) {
case "a","i","u","e","o":
sum+=1
}
Tried it in the playground - https://play.golang.org/p/QRYhEDA7EUZ
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I'm thinking up about how I find the same characters in one variable looks like this:
var words string = "abab"
and then I want's to eliminate the same characters in that one variable and here's the output to be
Output:
ab
have any solution about this?
One solution can be the use of go map[] to track the taken characters.
sample code:
func main() {
s := "abcdaabcefgahccij"
newS := ""
taken := make(map[rune]int)
for _, value := range s {
if _, ok := taken[value]; !ok {
taken[value] = 1
newS += string(value)
}
}
fmt.Println(newS)
}
Output:
abcdefghij