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How to convert "Hello" to string "72101108108111"
[]byte("Hello")=> [72 101 108 108 111]
byteStr := []byte("Hello")
var result string
for _, i := range byteStr {
result += fmt.Sprintf("%d", i)
}
fmt.Println(result)
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I have a raw string which is formed from array of strings like the one defined below
"['a','b','c']"
which i want to convert to proper array of string as below
["a","b","c"]
I am trying this on golang. However, i didn't succeed in getting this done. How this can be accomplished in go
var s = "['a','b','c']"
ss := strings.Split(strings.Trim(s, "[]"), ",")
a := make([]string, len(ss))
for i := range ss {
a[i] = strings.Trim(ss[i], "'")
}
out, err := json.Marshal(a)
if err != nil {
panic(err)
}
fmt.Println(string(out))
// output: ["a","b","c"]
https://go.dev/play/p/kQ0Up06K9zz
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if i have many option to be filter in IF statement, can i use some function like this?
s1 := "lorem ipsum"
sum := 0
for _, v := range s1 {
if string(v) like ("a","i","u","e","o") {
sum+=1
}
}
You can use switch statement.
Switch supports multiple matches
switch string(v) {
case "a","i","u","e","o":
sum+=1
}
Tried it in the playground - https://play.golang.org/p/QRYhEDA7EUZ
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I want to parse and get url from a string such as hello google.comxxx，the output should be google.com, is there any easy way to do that?
There's a package named xurls which you can use.
import "mvdan.cc/xurls/v2"
func main() {
rxRelaxed := xurls.Relaxed()
rxRelaxed.FindString("Do gophers live in golang.org?") // "golang.org"
rxRelaxed.FindString("This string does not have a URL") // ""
rxStrict := xurls.Strict()
rxStrict.FindAllString("must have scheme: http://example.com/.", -1) // []string{"http://example.com/"}
rxStrict.FindAllString("no scheme, no match: example.com", -1) // []string{}
}
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How can I convert an integer 3 to byte '3'?
package main
import (
"fmt"
)
func main() {
num := 3
b := byte(num)
if b == '3' { fmt.Println("how to make this line true") }
fmt.Printf("%v, %T\n", b, b) // 3, uint8
fmt.Printf("%v, %T\n", '3', '3') // 51, int32
}
To do what you say you want to do, you could do this:
strconv.Itoa(3)[0] == '3'
https://play.golang.com/p/LFDDf1JfWDQ
However, as pointed out by others, this is probably not what you actually want to do.
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I'm thinking up about how I find the same characters in one variable looks like this:
var words string = "abab"
and then I want's to eliminate the same characters in that one variable and here's the output to be
Output:
ab
have any solution about this?
One solution can be the use of go map[] to track the taken characters.
sample code:
func main() {
s := "abcdaabcefgahccij"
newS := ""
taken := make(map[rune]int)
for _, value := range s {
if _, ok := taken[value]; !ok {
taken[value] = 1
newS += string(value)
}
}
fmt.Println(newS)
}
Output:
abcdefghij