I have a .csv where each row corresponds to a person (first column) and attributes with values that are available for that person. I want to extract the names and values a particular attribute for persons where the attribute is available. The doc is structured as follows:
name,attribute1,value1,attribute2,value2,attribute3,value3
joe,height,5.2,weight,178,hair,
james,,,,,,
jesse,weight,165,height,5.3,hair,brown
jerome,hair,black,breakfast,donuts,height,6.8
I want a file that looks like this:
name,attribute,value
joe,height,5.2
jesse,height,5.3
jerome,height,6.8
Using this earlier post, I've tried a few different awk methods but am still having trouble getting both the first column and then whatever column has the desired value for the attribute (say height). For example the following returns everything.
awk -F "height," '{print $1 "," FS$2}' file.csv
I could grep only the rows with height in them, but I'd prefer to do everything in a single line if I can.
You may use this awk:
cat attrib.awk
BEGIN {
FS=OFS=","
print "name,attribute,value"
}
NR > 1 && match($0, k "[^,]+") {
print $1, substr($0, RSTART+1, RLENGTH-1)
}
# then run it as
awk -v k=',height,' -f attrib.awk file
name,attribute,value
joe,height,5.2
jesse,height,5.3
jerome,height,6.8
# or this one
awk -v k=',weight,' -f attrib.awk file
name,attribute,value
joe,weight,178
jesse,weight,165
With your shown samples please try following awk code. Written and tested in GNU awk. Simple explanation would be, using GNU awk and setting RS(record separator) to ^[^,]*,height,[^,]* and then printing RT as per requirement to get expected output.
awk -v RS='^[^,]*,height,[^,]*' 'RT{print RT}' Input_file
I'd suggest a sed one-liner:
sed -n 's/^\([^,]*\).*\(,height,[^,]*\).*/\1\2/p' file.csv
One awk idea:
awk -v attr="height" '
BEGIN { FS=OFS="," }
FNR==1 { print "name", "attribute", "value"; next }
{ for (i=2;i<=NF;i+=2) # loop through even-numbered fields
if ($i == attr) { # if field value is an exact match to the "attr" variable then ...
print $1,$i,$(i+1) # print current name, current field and next field to stdout
next # no need to check rest of current line; skip to next input line
}
}
' file.csv
NOTE: this assumes the input value (height in this example) will match exactly (including same capitalization) with a field in the file
This generates:
name,attribute,value
joe,height,5.2
jesse,height,5.3
jerome,height,6.8
With a perl one-liner:
$ perl -lne '
print "name,attribute,value" if $.==1;
print "$1,$2" if /^(\w+).*(height,\d+\.\d+)/
' file
output
name,attribute,value
joe,height,5.2
jesse,height,5.3
jerome,height,6.8
awk accepts variable-value arguments following a -v flag before the script. Thus, the name of the required attribute can be passed into an awk script using the general pattern:
awk -v attr=attribute1 ' {} ' file.csv
Inside the script, the value of the passed variable is reference by the variable name, in this case attr.
Your criteria are to print column 1, the first column containing the name, the column corresponding to the required header value, and the column immediately after that column (holding the matched values).
Thus, the following script allows you to fish out the column headed "attribute1" and it's next neighbour:
awk -v attr=attribute1 ' BEGIN {FS=","} /attr/{for (i=1;i<=NF;i++) if($i == attr) col=i;} {print $1","$col","$(col+1)} ' data.txt
result:
name,attribute1,value1
joe,height,5.2
james,,
jesse,weight,165
jerome,hair,black
another column (attribute 3):
awk -v attr=attribute3 ' BEGIN {FS=","} /attr/{for (i=1;i<=NF;i++) if($i == attr) col=i;} {print $1","$col","$(col+1)} ' awkNames.txt
result:
name,attribute3,value3
joe,hair,
james,,
jesse,hair,brown
jerome,height,6.8
Just change the value of the -v attr= argument for the required column.
I'm looking to replace the numerical values in a file with a new value provided by me. Can be present in any part of the text, in some cases, it comes across as the third position but is not always necessarily the case. Also to try and save a new version of the file.
original format
A:fdg:user#server:r
A:g:1234:xtcy
A:d:1111:xtcy
modified format
A:fdg:user#server:rxtTncC
A:g:replaced_value:xtcy
A:d:replaced_value:xtcy
bash line command with awk:
awk -v newValue="newVALUE" 'BEGIN{FS=OFS=":"} /:.:.*:/ && ~/^[0-9]+$/{~=newValue} 1' original_file.txt > replaced_file.txt
You can simply use sed instead of awk:
sed -E 's/\b[0-9]+\b/replaced_value/g' /path/to/infile > /path/to/outfile
Here is an awk that asks you for replacement values for each numerical value it meets:
$ awk '
BEGIN {
FS=OFS=":" # delimiters
}
{
for(i=1;i<=NF;i++) # loop all fields
if($i~/^[0-9]+$/) { # if numerical value found
printf "Provide replacement value for %d: ",$i > "/dev/stderr"
getline $i < "/dev/stdin" # ask for a replacement
}
}1' file_in > file_out # write output to a new file
I would use GNU AWK for this task following way, let file.txt content be
A:fdg:user#server:rxtTncC
A:g:1234:xtcy
A:d:1111:xtcy
then
awk 'BEGIN{newvalue="replacement"}{gsub(/[[:digit:]]+/,newvalue);print}' file.txt
output
A:fdg:user#server:rxtTncC
A:g:replacement:xtcy
A:d:replacement:xtcy
Explanation: replace one or more digits using newvalue. Disclaimer: I assumed numeric is something consisting solely from digits.
(tested in gawk 4.2.1)
How about
awk -F : '$3 ~ /^[0-9]+$/ { $3 = "new value"} {print}' original_file >replaced_file
?
I'm trying to modify a groups.tsv file (I'm on repl.it so path to file is fine).
Each line in the file looks like this:
groupname \t amountofpeople \t lastadded
and I'm trying to count the occurences of both groupname($nomgrp) and a login($login), and change lastadded to login.
varcol2=$(grep "$nomgrp" groups | cut "-d " -f2- | awk -F"\t" '{print $2}' )
((varcol21=varcol2+1));
varcol3=$(awk -F"\t" '{print $3}' groups)
sed -i "s|${nomgrp}\t${varcol2}\t$varcol3|${nomgrp}\t${varcol21}\t${login}|" groups
However, I'm getting the error message:
sed : -e expression #1, char 27: unterminated 's' command
The groups file has lines such as " sudo 2 user1" (delimited with a tab): a user inputs "user" which is stored in $login, then "sudo" which is stored in $nomgrp.
What am I doing wrong?
Sorry if this has been answered/super easy to fix, I'm quite the newbie here...
If I understand what you are trying to do correctly and if you have GNU awk, you could do
gawk -i inplace -F '\t' -v group="$nomgrp" -v login="$login" -v OFS='\t' '$1 == group { $2 = $2 + 1; $3 = login; } { print }' groups.tsv
Example:
$ cat groups.tsv
wheel 1000 2019-12-10
staff 1234 2019-12-11
users 9001 2019-12-12
$ gawk -i inplace -F '\t' -v group=wheel -v login=2019-12-12 -v OFS='\t' '$1 == group { $2 = $2 + 1; $3 = login; } 1' groups.tsv
$ cat groups.tsv
wheel 1001 2019-12-12
staff 1234 2019-12-11
users 9001 2019-12-12
This works as follows:
-i inplace is a GNU awk extension that allows you to change a file in place,
-F '\t' sets the input field separator to a tab so that the input is interpreted as TSV and fields with spaces in them are not split apart,
-v variable=name sets an awk variable for use in awk's code,
specifically, -v OFS='\t' sets the output field separator variable to a tab, so that the output is again a TSV
So we set variables group, login to your shell variables and ensure that awk outputs a TSV. The code then works as follows:
$1 == group { # If the first field in a line is equal to the group variable
$2 = $2 + 1; # add 1 to the second field
$3 = login; # and overwrite the third with the login variable
}
{ # in all lines:
print # print
}
{ print } could also be abbreviated as 1, I'm sure people someone will point out, but I find this way easier to explain.
If you do not have GNU awk, you could achieve the same with a temporary file, e.g.
awk -F '\t' -v group="$nomgrp" -v login="$login" -v OFS='\t' '$1 == group { $2 = $2 + 1; $3 = login; } { print }' groups.tsv > groups.tsv.new
mv groups.tsv.new groups.tsv
I have semicolon-separated columns, and I would like to add some characters to a specific column.
aaa;111;bbb
ccc;222;ddd
eee;333;fff
to the second column I want to add '#', so the output should be;
aaa;#111;bbb
ccc;#222;ddd
eee;#333;fff
I tried
awk -F';' -OFS=';' '{ $2 = "#" $2}1' file
It adds the character but removes all semicolons with space.
You could use sed to do your job:
# replaces just the first occurrence of ';', note the absence of `g` that
# would have made it a global replacement
sed 's/;/;#/' file > file.out
or, to do it in place:
sed -i 's/;/;#/' file
Or, use awk:
awk -F';' '{$2 = "#"$2}1' OFS=';' file
All the above commands result in the same output for your example file:
aaa;#111;bbb
ccc;#222;ddd
eee;#333;fff
#atb: Try:
1st:
awk -F";" '{print $1 FS "#" $2 FS $3}' Input_file
Above will work only when your Input_file has 3 fields only.
2nd:
awk -F";" -vfield=2 '{$field="#"$field} 1' OFS=";" Input_file
Above code you could put any field number and could make it as per your request.
Here I am making field separator as ";" and then taking a variable named field which will have the field number in it and then that concatenating "#" in it's value and 1 is for making condition TRUE and not making and action so by default print action will happen of current line.
You just misunderstood how to set variables. Change -OFS to -v OFS:
awk -F';' -v OFS=';' '{ $2 = "#" $2 }1' file
but in reality you should set them both to the same value at one time:
awk 'BEGIN{FS=OFS=";"} { $2 = "#" $2 }1' file
I have following lines
380:<CHECKSUM_VALIDATION>
393:</CHECKSUM_VALIDATION>
437:<CHECKSUM_VALIDATION>
441:</CHECKSUM_VALIDATION>
I need to format it as below
CHECKSUM_VALIDATION:380:393
CHECKSUM_VALIDATION:437:441
Is it possible to achieve above output using "awk"? [I'm using bash]
Thanks you!
Here you go:
awk -F '[:<>/]+' '{ n = $1; getline; print $2 ":" n ":" $1 }'
Explanation:
Set the field separator with -F to be a sequence of a mix of :<>/ characters, this way the first field will be the number, and the second will be CHECKSUM_VALIDATION
Save the first field in variable n and read the next line (which would overwrite $1)
Print the line: a combination of the number from the previous line, and the fields on the current line
Another approach without using getline:
awk -F '[:<>/]+' 'NR % 2 { n = $1 } NR % 2 == 0 { print $2 ":" n ":" $1 }'
This one uses the record counter NR to determine whether it's time to print: if NR is odd, save the first field in n, if NR is even, then print.
You can try this sed,
sed 'N; s/\([0-9]\+\):<\(.*\)>\n\([0-9]\+\):<\(.*\)>/\2:\1:\3/' file.txt
Test:
sat:~$ sed 'N; s/\([0-9]\+\):<\(.*\)>\n\([0-9]\+\):<\(.*\)>/\2:\1:\3/' file.txt
CHECKSUM_VALIDATION:380:393
CHECKSUM_VALIDATION:437:441
Another way:
awk -F: '/<C/ {printf "CHECKSUM_VALIDATION:%d:",$1; next} {print $1}'
Here is one gnu awk
awk -F"[:\n<>]" 'NR==1{print $3,$1,$5;f=$3;next} $3{print f,$3,$7}' OFS=":" RS="</CH" file
CHECKSUM_VALIDATION:380:393
CHECKSUM_VALIDATION:437:441
Based on Jonas post and avoiding getline, this awk should do:
awk -F '[:<>/]+' '/<C/ {f=$1;next} { print $2,f,$1}' OFS=\: file
CHECKSUM_VALIDATION:380:393
CHECKSUM_VALIDATION:437:441