I have 3 tables that I want to join
table users table comments table posts
| id | name | | id | user_id | post_id | comment | | id| text |
|----|------| | -- | ------- | ------- | ------- | |---| ---- |
| 1 | a | | 1 | 1 | 2 | b | | 1 | a |
| 2 | b | | 2 | 1 | 1 | c | | 2 | b |
i want to display it like this
| id | user_id | name | post_id | comment |
i only know joining tables between comments and posts using hasMany relationship
how to join more table (in this case users table) with eloquent relationship?
You can join using following code. But I dont think you can display the record as | id | user_id | name | post_id | comment | because you will have - a user can have many comments and a comment can have many posts. So you will not be able to show on same row. But you can make use of arrays.
An example
$user=User::with(['comments','comments.post'])->get();
Related
First, I've checked other topics on the subject like this one How to transpose/pivot data in hive? but that doesn't match with what I want.
So this is the table I have
| ID | Day | Status |
| 1 | 1 | A |
| 2 | 10 | B |
| 3 | 101 | A |
| 3 | 322 | B |
| 3 | 102 | C |
| 3 | 354 | D |
And i'd like to concat the different Status for each IDs ordering by the Day, in order to have this :
| ID | Status |
| 1 | A |
| 2 | B |
| 3 | A,C,B,D |
The thing is that I don't know how many status I can have, so i can't create as many columns I want for the days since I don't know how many day/status I'll have, so the answers from other topics with group_map or others, I don't know how to adapt it for my problem.
Thank's for helping me ^^
use collect_set (for distinct values) or collect_list to aggregate array and concatenate it using concat_ws:
select ID, concat_ws(',',collect_list(Status)) as Status
from table
group by ID;
I need a way to avoid duplicate values from oracle join, I have this scenario.
The first table contain general information about a person.
+-----------+-------+-------------+
| ID | Name | Birtday_date|
+-----------+-------+-------------+
| 1 | Byron | 12/10/1998 |
| 2 | Peter | 01/11/1973 |
| 4 | Jose | 05/02/2008 |
+-----------+-------+-------------+
The second table contain information about a telephone of the people in the first table.
+-------+----------+----------+----------+
| ID |ID_Person |CELL_TYPE | NUMBER |
+-------+- --------+----------+----------+
| 1221 | 1 | 3 | 099141021|
| 2221 | 1 | 2 | 099091925|
| 3222 | 1 | 1 | 098041013|
| 4321 | 2 | 1 | 088043153|
| 4561 | 2 | 2 | 090044313|
| 5678 | 4 | 1 | 092049013|
| 8990 | 4 | 2 | 098090233|
+----- -+----------+----------+----------+
The Third table contain information about a email of the people in the first table.
+------+----------+----------+---------------+
| ID |ID_Person |EMAIL_TYPE| Email |
+------+- --------+----------+---------------+
| 221 | 1 | 1 |jdoe#aol.com |
| 222 | 1 | 2 |jdoe1#aol.com |
| 421 | 2 | 1 |xx12#yahoo.com |
| 451 | 2 | 2 |dsdsa#gmail.com|
| 578 | 4 | 1 |sasaw1#sdas.com|
| 899 | 4 | 2 |cvcvsd#wew.es |
| 899 | 4 | 2 |cvsd#www.es |
+------+----------+----------+---------------+
I was able to produce a result like this, you can check in this link http://sqlfiddle.com/#!4/8e326/1
+-----+-------+-------------+----------+----------+----------+----------------+
| ID | Name | Birtday_date| CELL_TYPE| NUMBER |EMAIL_TYPE|EMAIL|
+-----+-------+-------------+----------+----------+----------+----------------+
| 1 | Byron | 12/10/1998 | 3 | 099141021|1 |jdoe#aol.com |
| 1 | Byron | 12/10/1998 | 2 | 099091925|2 |jdoe1#aol.com |
| 1 | Byron | 12/10/1998 | 1 | 099091925| | |
| 2 | Peter | 01/11/1973 | 1 | 088043153|1 |xx12#yahoo.com |
| 2 | Peter | 01/11/1973 | 2 | 090044313|2 |dsdsa#gmail.com |
| 4 | Jose | 05/02/2008 | 1 | 092049013|1 |sasaw1#sdas.com |
| 4 | Jose | 05/02/2008 | 2 | 098090233|2 |cvcvsd#wew.es |
+-----+-------+-------------+----------+----------+----------+----------------+
If you check the data in table Email for user with ID_Person = 4 only present two of the three emails that have, the problem for this case is the person have more emails that cellphone numbers and only will present the same number of the cellphone numbers.
The result i expected is something like this.
+-----+-------+-------------+----------+----------+----------+----------------+
| ID | Name | Birtday_date| CELL_TYPE| NUMBER |EMAIL_TYPE|EMAIL|
+-----+-------+-------------+----------+----------+----------+----------------+
| 1 | Byron | 12/10/1998 | 3 | 099141021|1 |jdoe#aol.com |
| 1 | Byron | 12/10/1998 | 2 | 099091925|2 |jdoe1#aol.com |
| 1 | Byron | 12/10/1998 | 1 | 099091925| | |
| 2 | Peter | 01/11/1973 | 1 | 088043153|1 |xx12#yahoo.com |
| 2 | Peter | 01/11/1973 | 2 | 090044313|2 |dsdsa#gmail.com |
| 4 | Jose | 05/02/2008 | 1 | 092049013|1 |sasaw1#sdas.com |
| 4 | Jose | 05/02/2008 | 2 | 098090233|2 |cvcvsd#wew.es |
| 4 | Jose | 05/02/2008 | | |2 |cvsd#www.es |
+-----+-------+-------------+----------+----------+----------+----------------+
This is the way that i need to present the data.
I could not understand why your query was so complex, thus, added the simple full outer join and it seems to be working:
select distinct p.id, p.name,
case when Lag(CELL) over(partition by p.id order by p.id,pe.id) = CELL then null else cell_type end as cell_type,
case when Lag(CELL) over(partition by p.id order by p.id,pe.id) = CELL then null else CELL end as CELL,
EMAIL_TYPE as EMAIL_TYPE, EMAIL as EMAIL
from person p full outer join phones pe on p.id = pe.id
full outer join emails e
on p.id = e.id and pe.cell_type = e.email_type;
I have models Book and BookCategory
How do I select the cheapest book in every category?
Book table:
| id | name | price | book_category_id |
| 1 | test | 10 | 1
| 2 | test | 15 | 3
| 3 | test | 75 | 1
| 4 | test | 25 | 2
| 5 | test | 19 | 1
| 6 | test | 11 | 2
| 7 | test | 10 | 1
The selection should be :
| id | name | price | book_category_id |
| 1 | test | 10 | 1
| 2 | test | 15 | 3
| 6 | test | 11 | 2
I've tried:
$books = Book::groupBy("book_category_id")->orderBy("price")->get()
But the output is not the minimum price row.
any idea?
EDIT:
I found this page:
https://www.xaprb.com/blog/2006/12/07/how-to-select-the-firstleastmax-row-per-group-in-sql/
it has 90% of the solution in SQL
SELECT *
FROM books
WHERE price = (SELECT MIN(price) FROM books AS u WHERE u.book_category_id= books.book_category_id)
GROUP BY books.book_category_id
how to convert this to laravel query builder?
You need to perform a subquery like this post. Try this:
$books = Book::from(DB::raw("SELECT * FROM books order by price asc"))
->groupBy("book_category_id")->get();
Please note that this is a mysql only solution because in mysql you're allowed to not aggregate non-group-by columns. If you need to do this for another DB, you need to perform an inner join on the subquery
Hi I want query from 3 table
user:
+----+-----------+
| id | name |
+----+-----------+
| 1 | Denny |
| 2 | Agus |
| 3 | Dini |
| 4 | Angel |
+----+-----------+
History_Education
+----+-----------+-------------+
| id | userId | educationId |
+----+-----------+-------------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 2 | 1 |
| 4 | 2 | 2 |
+----+-----------+-------------+
Education
+----+-----------+----------+
| id | level | Name |
+----+-----------+----------+
| 1 | 1 | SD |
| 2 | 2 | SMP |
| 3 | 3 | SMA |
| 4 | 4 | S1 |
+----+-----------+----------+
How to query with laravel Eloquent to get the latest user education order by Level DESC
expected:
+----+-----------+----------------------+
| id | Name | Latest_Education |
+----+-----------+----------------------+
| 1 | Denny | SMP |
| 2 | Agus | SMP |
| 3 | Dini | - |
| 4 | Angel | - |
+----+-----------+----------------------+
In normal query:
select id,name ,(select E.name from education E inner join History_eductaion HE on E.id = HE.education_id where HE.userId =U.id limit 1 order by E.level DESC )latest_education from USER U
How to translate to laravel eloquent?
The quick answer is use the query builder - your query needed to be altered slightly to match the table names and columns as listed in your question:
$result = DB::table('user')
->select([
'id',
'name',
DB::raw("(select E.name from Education E inner join History_Education HE on E.id = HE.educationId where HE.userId = user.id order by E.level DESC limit 1) as latest_education")
])
->get();
so I'm a BIRT beginner, and I just tried to get a real simple report from one of my tables of a postgres DB.
So I defined a flat table as datasource which looks like:
+----------------+--------+----------+-------+--------+
| date | store | product | value | color |
+----------------+--------+----------+-------+--------+
| 20160101000000 | store1 | productA | 5231 | red |
| 20160101000000 | store1 | productB | 3213 | green |
| 20160101000000 | store2 | productX | 4231 | red |
| 20160101000000 | store3 | productY | 3213 | green |
| 20160101000000 | store4 | productZ | 1223 | green |
| 20160101000000 | store4 | productK | 3113 | yellow |
| 20160101000000 | store4 | productE | 213 | green |
| .... | | | | |
| 20160109000000 | store1 | productA | 512 | green |
+----------------+--------+----------+-------+--------+
So I would like to add a table / crosstab to my birt report which creates a table (and after that a page break) for EVERY store which looks like:
**Store 1**
+----------------+----------+----------+----------+-----+
| | productA | productB | productC | ... |
+----------------+----------+----------+----------+-----+
| 20160101000000 | 3120 | 1231 | 6433 | ... |
| 20160102000000 | 6120 | 1341 | 2121 | ... |
| 20160103000000 | 1120 | 5331 | 1231 | ... |
+----------------+----------+----------+----------+-----+
--- PAGE BREAK ---
....
So what I tried in first was: Getting to work the standard CrossTab tutorial-template of BIRT.
I defined the DataSource, and created a datacube with dimension-group of 'store' and 'product' , and as SUM / detail -data the 'value' and for this example I just selected ONE day.
But the result looks like this:
+--------+----------+----------+----------+----------+-----+----------+
| | productA | productC | productD | productE | ... | productZ |
+--------+----------+----------+----------+----------+-----+----------+
| Store1 | 213 | | 3234 | 897 | ... | 6767 |
| Store2 | 513 | 2213 | 1233 | | ... | 845 |
| Store3 | 21 | | | 32 | ... | |
| Store4 | 123 | 222 | 142 | | ... | |
+--------+----------+----------+----------+----------+-----+----------+
It's because not every product is selled in every store, but the crosstab creates the columns by selecting ALL products available.
So, I just have no idea how to generate dynamicly different tables with different (but also dynamic) amount of columns.
The second step then would be to get the dates (days) to work.
But thanks in advance for every hint ot tutorial link to question one ;-)
You can just add a table with the complete datasource. Select the table and a group. Group by StoreID. You can set the pagebreak options for each grouping. Set the property for after to "always exluding last".
BIRT will add a group header. You can add multiple groupheader rows get the layout you're after.
For crosstabs it works in a similar way. After you added the crosstab to your page and set the info for the groups on rows and columns and added summaries. You can view the data. Select the crosstab and View the Row Area properties, select the pagegroup settings and add a new pagebreak. You can select on which group you want to break, choose your storeID group and select after: "always excluding last"