Feature Test in Laravel 8 uses withHeader to set Host invalid? - laravel

Since my project has deployed multiple domain names, the API interface that needs to be tested is using the api.example.test domain name as the entrance.
Using $this->get('/v1/ping') in Feature Test will request to www.example.test, I hope to set up $this->withHeader('Host', config('domain.api_domain')) uniformly in setUp in ApiFeatureBaseTestCase to automatically request API related tests to api.example.test Go in.
However, in practice, I found that this is invalid. By tracing the code, I found two codes that may cause the invalid Host setting:
First place (Laravel):
Code in Laravel Framework src/Illuminate/Foundation/Testing/Concerns/MakesHttpRequests.php:503, pass the parameter $uri ='/v1/ping' into $this->prepareUrlForRequest($uri) and get a complete Url with the default Host, the return value is http://www.example.test/v1/ping.
Second place (Symfony):
In the code of Symfony HttpFoundation Component Request.php:355, the parsing in $uri will be used first The coming out host is overwritten in the Header as the default Host.
The above two codes eventually caused the Host I set by withHeader to fail. Obviously, in this code logic, Symfony HttpFoundation Component's choice of Host in conflict cannot be considered wrong, but I submitted this question issue was closed when it was given to Laravel Framework.
I don't know if this issue is a bug or feature?
Finally, I am sorry that my question has interrupted everyone's time, but if there is a conclusion on this question, please tell me what should be more appropriate?
My current approach is $this->get($this->api_base_url . '/v1/ping'), but I don’t think this is elegant
3Q!!1
Code example
// File: config/domain.php
return [
'api_domain' => 'api.example.test',
'web_domain' => 'www.example.test',
];
// File: routes/demo.php
Route::domain(config('domain.api_domain'))
->middleware(['auth:api', 'api.sign.check'])
->namespace($this->namespace)
->group(function () {
Route::get('/v1/ping', function () {
return 'This Api v1';
});
});
Route::domain(config('domain.web_domain'))
->middleware('web')
->namespace($this->namespace)
->group(base_path('routes/web.php'));
// File: tests/ApiFeatureBaseTestCase.php
namespace Tests;
class ApiFeatureBaseTestCase extends TestCase
{
protected function setUp(): void
{
parent::setUp();
$this->withHeader('Host', config('domain.api_domain'));
}
}
// File: tests/Feature/ApiPingTest.php
namespace Tests\Feature;
use Tests\ApiFeatureBaseTestCase;
class ApiPingTest extends ApiFeatureBaseTestCase
{
public function testPing()
{
$this->get('/v1/ping');
}
}

Can you create a wrapper method on your ApiFeatureBaseTestCase class?
public function get($uri, array $headers = [])
{
return parent::get(config('domain.api_domain') . $uri, $headers);
}
Then in your ApiPingTest class:
public function testPing()
{
$this->get('/v1/ping');
}

Related

How can I add extra view component class paths in Laravel?

The problem
The default namespace for view components is App\View\Components with the folder being app/View/Components. I am setting up a DDD file structure and wish to do two things:
Move "shared" view components to a namespace and folder of App\ViewComponents and src/app/ViewComponents respectively
Have view components specific to individual "apps" with their own namespace and folder of App\MyApplication\ViewComponents and /src/app/MyApplication/ViewComponets respectively.
The new App namespace/folder setup is done via composer psr-4 autoload keys and works fine. But Laravel always used the App\View\Components namespace when trying to load components.
My attempt
I have solved the first part of my problem, but I am hoping that there is a better way. For instance when I want to move views, I can just set the view.paths config directive in my AppServiceProvider but I don't see a similar way of, essentially, adding namespaces to where Laravel looks for view components. So what I ended up doing was:
Create a ViewServiceProvider class, extending Illuminate\View\ViewServiceProvider::class and point to it in bootstrap/app.php instead
In there, override the registerBladeEngine method, in there pointing towards my own BladeCompiler class instead of the built-in one
public function registerBladeEngine($resolver)
{
// The Compiler engine requires an instance of the CompilerInterface, which in
// this case will be the Blade compiler, so we'll first create the compiler
// instance to pass into the engine so it can compile the views properly.
$this->app->singleton('blade.compiler', function () {
return new BladeCompiler(
$this->app['files'],
$this->app['config']['view.compiled'],
);
});
$resolver->register('blade', function () {
return new CompilerEngine(
$this->app['blade.compiler']
);
});
}
In my own BladeCompiler class, which extends Illuminate\View\Compilers\BladeCompiler, override the component() and compileComponentTags() methods - basically anywhere that referenced View\\Components - with pretty much a carbon copy but instead using ViewComponents and also made sure that where they return a Illuminate\View\Compilers\ComponentTagCompiler I instead referenced my own ComponentTagCompiler
In my own TagCompiler I override the guessClassName() method, again with essentially a carbon copy, just renaming View\\Components to ViewComponents
As you can see, that's quite a lot of work just to change the path. And I also want to add another path. Multiple "apps" run under the same Laravel codebase, so for instance we might have App\Website\, App\Admin and App\Blog and, depending on which app is currently running, load a different namespace for the running app, i.e. the blog would be App\Blog\ViewComponents pointing to src/app/Blog/ViewComponents.
Is there a way to achieve this without as much overriding as above? If not, can you suggest a way to achieve the second part of the requirement?
Note: I haven't ruled out using sub folders and continuing with everything under the main App\View\Components namespace just yet - I don't want to fight Laravel more than I have to and am willing to concede if there's no better way, but if I can achieve the folder structure I want it would feel a lot tidier.
Update; got a working implementation by using a configuration and php 8 annotations
Follow the steps below to make it possible to add more lookup folders for the blade view components feature, based on your question and details you have provided. It would have helped to have posted that code you already had. But I have added a possible solution to get it to work, using Annotations and using a config with a namespace/path map.
Depending on how you switch between one application and the other, from which the details are not provided in your question, you have to modify the way the configuration is retreived in the MyComponentTagCompiler class.
Blade compiler
In order to change the ComponentTagCompiler we need to change the BladeCompiler class:
namespace App;
class YourBladeCompiler extends \Illuminate\View\Compilers\BladeCompiler
{
protected function compileComponentTags($value)
{
if (! $this->compilesComponentTags) {
return $value;
}
return (new \App\MyComponentTagCompiler( //it is about this line
$this->classComponentAliases, $this->classComponentNamespaces, $this
))->compile($value);
}
}
Service provider
Now register the YourBladeCompiler in YourViewServiceProvider :
class YourViewServiceProvider extends \Illuminate\View\ViewServiceProvider
{
public function registerBladeEngine($resolver)
{
$this->app->singleton('blade.compiler', function () {
return new \App\YourBladeCompiler( //it is about this line
$this->app['files'],
$this->app['config']['view.compiled'],
);
});
$resolver->register('blade', function () {
return new CompilerEngine(
$this->app['blade.compiler']
);
});
}
}
MyComponentTagCompiler
This is an implemention I created that works with PHP 8 Attributes, given below:
namespace App;
#[\Attribute]
class ViewComponentName
{
public string $name;
public string $package;
public function __construct(string $name, string $package)
{
$this->name = $name;
$this->package = $package;
}
}
With this attribute, you can declare the package name and component name on the view component class (see example at the bottom). So during lookup the component can be matched on these parameters.
But you can change it to your own requirements if needed.
What it does:
It first let's Laravel lookup the View Component through it's own mechanisms, in the parent::componentClass method.
If no component is found and an exception (InvalidArgumentException) is thrown, after which my implementation will walk through the given paths and namespaces (from the getLookupPaths method) and see if an attribute matches the component name and package name. If so it returns this class and the view component is loaded accordingly.
namespace App;
use App\View\ViewComponentName;
use Illuminate\View\Compilers\ComponentTagCompiler;
class MyComponentTagCompiler extends ComponentTagCompiler
{
protected function getLookupPaths() : array
{
/*
* add some logic here to get an application specific configuration
* since you have multiple application in one, I cannot know it works in your
* application, since the details are not provided in the question
*/
return config('view_component_paths');
}
private function getFiles(string $dir) : array
{
return scandir($dir);
}
private function isPhpFile(string $file) : bool
{
return strpos($file, ".php");
}
private function getClassNamespace(string $file, string $folderNamespace) : string
{
$class = str_replace(".php", "", $file);
$classNamespace = $folderNamespace . "\\" . $class;
return $classNamespace;
}
private function getComponentName(string $file, string $namespace) : ?ViewComponentName
{
$classNamespace = $this->getClassNamespace($file, $namespace);
$reflection = new \ReflectionClass($classNamespace);
if(method_exists($reflection, 'getAttributes')) {
$attribute = $reflection->getAttributes()[0];
if ($attribute->getName() == ViewComponentName::class) {
return $attribute->newInstance();
}
}
return null;
}
public function componentClass(string $component)
{
try {
parent::componentClass($component);
} catch(\InvalidArgumentException $e) {
list($lookupComponentPackage, $lookupComponentName) = explode("-", $component);
foreach($this->getLookupPaths() as $namespace=>$dir) {
foreach ($this->getFiles($dir) as $file) {
if ($this->isPhpFile($file)) {
if($componentName = $this->getComponentName($file, $namespace)) {
if($componentName->name == $lookupComponentName && $componentName->package == $lookupComponentPackage) {
return $this->getClassNamespace($file, $namespace);
}
}
}
}
}
throw $e;
}
}
}
Where the config contains (config/view_component_paths.php):
return [
"App\\Test"=>__DIR__ . "/Test/"
];
If you wish to replace the default laravel behavior completely or do not like my implementation based on annotations, consider implementing your own version of the method:
public function componentClass(string $component)
{
//return the class name here based the component name
//without calling parent
dd($component);
}
Example view component
namespace App\Test;
use App\View\ViewComponentName;
use Illuminate\View\Component;
#[ViewComponentName('test', 'namespace')]
class MyViewComponent extends Component
{
public function render()
{
return view('components.test');
}
}
In blade:
<x-namespace-test />
It should now be working. I think this is enough information to give you an idea of how to implement this in your own application. There seems to be no other way than to extend some base classes. But looking at this answer, it is possible to create a high level implementation based on a global lookup configuration and php annotations (or some other mechanism you wish, for example converting the class name with namespace to a view component name).
Old answer
Problem 2 as defined in your question
Have view components specific to individual "apps" with their own namespace and folder of App\MyApplication\ViewComponents and /src/app/MyApplication/ViewComponets respectively.
Sadly there seems to be no way of defining multiple class paths for view components in Laravel. But you can however change the application path and namespace prefix. As far as I found out you only have to overwrite the following properties in the Application class.
bootstrap/app.php
Replace the following lines:
$app = new Illuminate\Foundation\Application(
$_ENV['APP_BASE_PATH'] ?? dirname(__DIR__)
);
With:
class YourApplication extends \Illuminate\Foundation\Application
{
protected $namespace = "App\\MyApplication";
protected $appPath = __DIR__ . "/../app/MyApplication";
}
$app = new YourApplication(
$_ENV['APP_BASE_PATH'] ?? dirname(__DIR__)
);
This is enough to change the app folder to another and gives you an idea of how to change it dynamically for having multiple apps in different namespaces. If you now run laravel commands like php artisan make:component Test1234 it is created in your new app folder: app/MyApplication/View/Components/Test1234.php.
Hardcoded paths
Some paths like View/Components are hardcoded in Laravel, and therefor not that easy to change. If you change as defined above, in this case the view components namespace becomes: App\MyApplication\View\Components and the path: app/MyApplication/View/Components.
Problem 1 as defined in your question
Move "shared" view components to a namespace and folder of App\ViewComponents and src/app/ViewComponents respectively
When you change application paths as explained above it is not possible to have a "shared" View Component folder. Laravel, as it seems, has only one default View Components path, which is based on hard coded paths and a dynamic namespace prefix as explained above. But you can of course, create a shared namespace and register the view components manually:
View component (app/ViewComponents/ folder)
namespace App\ViewComponents;
use Illuminate\View\Component;
class Test extends Component
{
public function render()
{
return view('components.test');
}
}
Don't forget the components.test blade view.
ServiceProvider
\Blade::component("shared-test",\App\ViewComponents\Test::class);
Blade
<x-shared-test />

Laravel unit testing automatic dependency injection not working?

With Laravel Framework 5.8.36 I'm trying to run a test that calls a controller where the __construct method uses DI, like this:
class SomeController extends Controller {
public function __construct(XYZRepository $xyz_repository)
{
$this->xyz_repository = $xyz_repository;
}
public function doThisOtherThing(Request $request, $id)
{
try {
return response()->json($this->xyz_repository->doTheRepoThing($id), 200);
} catch (Exception $exception) {
return response($exception->getMessage(), 500);
}
}
}
This works fine if I run the code through the browser or call it like an api call in postman, but when I call the doThisOtherThing method from my test I get the following error:
ArgumentCountError: Too few arguments to function App\Http\Controllers\SomeController::__construct(), 0 passed in /var/www/tests/Unit/Controllers/SomeControllerTest.php on line 28 and exactly 1 expected
This is telling me that DI isn't working for some reason when I run tests. Any ideas? Here's my test:
public function testXYZShouldDoTheThing()
{
$some_controller = new SomeController();
$some_controller->doThisOtherThing(...args...);
...asserts...
}
I've tried things like using the bind and make methods on app in the setUp method but no success:
public function setUp(): void
{
parent::setUp();
$this->app->make('App\Repositories\XYZRepository');
}
That's correct. The whole idea of a unit test is that you mock the dependant services so you can control their in/output consistently.
You can create a mock version of your XYZRepository and inject it into your controller.
$xyzRepositoryMock = $this->createMock(XYZRepository::class);
$some_controller = new SomeController($xyzRepositoryMock);
$some_controller->doThisOtherThing(...args...);
This is not how Laravels service container works, when using the new keyword it never gets resolved through the container so Laravel cannot inject the required classes, you would have to pass them yourself in order to make it work like this.
What you can do is let the controller be resolved through the service container:
public function testXYZShouldDoTheThing()
{
$controller = $this->app->make(SomeController::class);
// Or use the global resolve helper
$controller = resolve(SomeController::class);
$some_controller->doThisOtherThing(...args...);
...asserts...
}
From the docs :
You may use the make method to resolve a class instance out of the
container. The make method accepts the name of the class or interface
you wish to resolve:
$api = $this->app->make('HelpSpot\API');
If you are in a location of your code that does not have access to the
$app variable, you may use the global resolve helper:
$api = resolve('HelpSpot\API');
PS:
I am not really a fan of testing controllers like you are trying to do here, I would rather create a feature test and test the route and verify everything works as expected.
Feature tests may test a larger portion of your code, including how
several objects interact with each other or even a full HTTP request
to a JSON endpoint.
something like this:
use Illuminate\Http\Response;
public function testXYZShouldDoTheThing()
{
$this->get('your/route')
->assertStatus(Response::HTTP_OK);
// assert response content is correct (assertJson etc.)
}

How to swap out dependency in laravel container

I have registered a Paypal service provider:
App\Providers\PaypalHelperServiceProvider::class,
and, when I type hint it in my controller it properly resolves:
public function refund(Request $request, PaypalHelper $paypal) {...
Here is my provider class:
class PaypalHelperServiceProvider extends ServiceProvider
{
protected $defer = true;
public function register()
{
$this->app->bind('App\Helpers\PaypalHelper', function() {
$test = 'test';
return new PaypalHelper();
});
}
public function provides()
{
$test = 'test';
return [App\Helpers\PaypalHelper::class];
}
}
Everything works as expected. Now I wanted to be able to modify controller to take a PayPal interface. I would then update my service provider to conditionally pass in either the real class or a mock one for testing, using the APP_ENV variable to determine which one to use. I put some debuggers into the service provider class and could not get it to ever go in. I thought perhaps that it only loads them on need, so I put a breakpoint inside my controller. The class did resolve, but it still never went into the service provider class! Can someone explain to me why this is the case? Even when I modified the code to pass in a different class type it did not pick up.
EDIT:
Here is the code flow I see when I debug this:
ControllerDispatcher -> resolveClassMethodDependencies -> resolveMethodDependencies -> transformDependency. At this point we have the following laravel code in the RouteDependencyResolveerTrait:
protected function transformDependency(ReflectionParameter $parameter, $parameters, $originalParameters)
{
$class = $parameter->getClass();
// If the parameter has a type-hinted class, we will check to see if it is already in
// the list of parameters. If it is we will just skip it as it is probably a model
// binding and we do not want to mess with those; otherwise, we resolve it here.
if ($class && ! $this->alreadyInParameters($class->name, $parameters)) {
return $this->container->make($class->name);
}
}
Since getClass() always resolves to the interface name, when we call container->make(), it always fails with
Target [App\Helpers\PaypalHelperInterface] is not instantiable.
Change
$this->app->bind('App\Helpers\PaypalHelper', function() {
$test = 'test';
return new PaypalHelper();
});
To
if (app()->environment('testing')) {
$this->app->bind(
PaypalHelperInterface::class,
FakePaypalHelper::class
)
} else {
$this->app->bind(
PaypalHelperInterface::class,
PaypalHelper::class
);
}
I finally found out the issue. My problem was that my provider wasn't being picked up at all. Here was the solution
composer dumpautoload
php artisan cache:clear
https://laravel.io/forum/02-08-2015-laravel-5-service-provider-not-working

How to let a unit test ignore a middleware in Laravel [duplicate]

This question already has answers here:
How to Disable Selected Middleware in Laravel Tests
(6 answers)
Closed 3 years ago.
I'm testing an endpoint in my Laravel app. However, I have a middleware that does complex logic to determine the location of the user (using ip reverse look up etc such as this code:
public function getOpCityByIP()
{
// Get the client's remote ip address
if (isset($_SERVER['HTTP_X_FORWARDED_FOR']) && $_SERVER['HTTP_X_FORWARDED_FOR']) {
$clientIpAddress = explode(',', $_SERVER['HTTP_X_FORWARDED_FOR'])[0];
} else {
$clientIpAddress = $_SERVER['REMOTE_ADDR'];
}
$opCityArray = OpCityIP::get($clientIpAddress);
return $opCityArray;
}
I'm not interested in going inside the guts of such methods in said middleware and having to mock them etc. I'd rather simply skip the entire middleware during the unit testing, or at least mock its entire operations and instead hardcode the result to something predetermined. How do I do that?
I'm using Laravel 5.4
update
i need it to ignore a specific middleware, not all of them
You can use the withoutMiddleware() method on your test object. As of Laravel 5.5, this method accepts a parameter that lets you specify which middleware to disable, instead of just disabling them all.
In your test:
$this->withoutMiddleware([YourGeoIpMiddleware::class]);
To solve my problem of skipping a specific middleware, I simply put this code inside the handle method of said middleware:
public function handle($request, Closure $next)
{
if (config('app.env') === 'testing') {
return $next($request);
}
..
<?php
use Illuminate\Foundation\Testing\WithoutMiddleware;
class ExampleTest extends TestCase
{
use WithoutMiddleware;
// Stuff
}

Why won't this Laravel 5.4 service provider register?

I am trying to do a hello world service provider with the new Laravel 5.4.
I have created the following service provider file:
//File: app/TestProvider/TestServiceProvider.php
namespace App\TestProvider;
use Illuminate\Support\ServiceProvider;
class TestServiceProvider extends ServiceProvider
{
/**
* Register bindings in the container.
*
* #return void
*/
public function register()
{
$this->app->bind('Test', function ($app) {
return new Test();
});
}
}
I have created a simple class under the same namespace:
//File: app/TestProvider/Test.php
namespace App\TestProvider;
class Test
{
/**
* Register bindings in the container.
*
* #return void
*/
public function helloWorld()
{
echo "hello world";
}
}
The problem is, this is not registering. The register method is executing as when I put a breaker before the 'bind' method, it executes:
public function register()
{
dd("BREAKER");
$this->app->bind('Test', function ($app) {
return new Test();
});
}
So this outputs "BREAKER" as expected. However if I put the breaker in the closure, nothing happens which suggests for some reason, that 'bind' method isn't being executed??
Any ideas?
EDIT:
Just some further info: I know that the Test class is registered and in the correct namespace as I can do:
dd(new Test());
in the registration method, and it outputs the resource id as expected.
Explanation
The closure provided only runs when the binding is being resolved. That's why it's a closure, it can be saved in the service container and resolved at any time while the program runs.
Solution
To see the resolved binding, create a controller and resolve the class in that controller:
// File: app/Http/Controllers/TestController.php
namespace App\Http\Controllers;
// This isn't the best way, but it works. See the best way below
class TestController extends Controller {
public function index()
{
return \App::make('Test')->helloWorld();
}
}
Of course, don't forget to register the route:
// File: routes/web.php
Route::get('/', 'TestController#index');
The binding will resolve when you hit the homepage.
However, as I said, it's not the best way, so here I prepared a better way. Change the way you register the binding:
// File: app/Providers/TestProvider.php
namespace App\TestProvider;
use Illuminate\Support\ServiceProvider;
use App\TestProvider\Test;
// Better way
class TestServiceProvider extends ServiceProvider
{
/**
* Register bindings in the container.
*
* #return void
*/
public function register()
{
// Note: we bind the exact complete class name!
$this->app->bind(Test::class, function ($app) {
return new Test();
});
}
}
After this change the controller so that it looks like this:
namespace App\Http\Controllers;
use App\TestProvider\Test;
class TestController extends Controller {
/**
* #var Test $test
*/
private $test;
// Let Laravel resolve the dependency on constructing the class
public function __construct(Test $test)
{
$this->test = $test;
}
public function index()
{
return $this->test->helloWorld();
}
}
You will see that the exact same thing happens, but it looks more elegant and avoids conflicts.
Details
Laravel gives only a high level overview of the service container, which doesn't help to learn how it works on the inside. The best way to see that is to go down the call stack.
When you do that, you find that Laravel registers every class in the project in the service container. That means that whether you create a service provider or not, the class will be in the container. How exactly?
When you run php artisan optimize, Laravel creates files that have array with all the classes of the project. When you run the app, after registering everything from the service providers, Laravel registers the rest of the classes from that file.
That means that in your case, if you don't specifically register the Test class, it will still be resolvable. Basically, you only need to register classes that need some specific instructions to be resolved.
So how does Laravel resolve the dependencies?
When you run \App::make(Test::class) or inject dependency via type hinting in the constructor (the "better way" from my solution), Laravel looks for that dependency among the bindings.
When it finds the dependency, it resolves either the closure associated to it or the constructor of the class directly.
When it resolves the constructor directly, it looks for type hints among the constructor parameters and recursively resolves all of them until there's nothing else to resolve.
After that it returns the resolved class.
Of course, bear in mind that for Laravel to analyze the contructor of a class, it needs to be resolved via the service container in the first place. You can't just call $test = new Test(); and expect Laravel to do all the magic :)
Conclusion
This is a rather quick overview of Laravel's service container. The best way for you to learn it is, of course, studying the sources for yourself. It's truly elegant and it uses PHP's functionality to the fullest.
I really hope this shed some light on the service container for you and can help you in the future :)
The closure passed to the bind() method is not executed until you actually attempt to resolve the alias you are binding.
So, if you dd('breaker') inside the closure, this won't actually get executed until Test is resolved (whatever your preferred resolution method is):
Service provider:
// bind the closure to the 'Test' alias
public function register()
{
$this->app->bind('Test', function ($app) {
dd("BREAKER");
return new Test();
});
}
Code that resolve Test alias:
// different ways of resolving the alias out of the container.
// any of these will execute the bound closure.
$test = resolve('Test');
$test = app('Test');
$test = app()->make('Test');
$test = \App::make('Test');
try:
$this->app->bind(Test::class, function ($app) {
return new Test();
});

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