What should be the route for the search page in laravel 8? My routes are...
List of routes :
Redirect that I use in the search method in the controller:
enter image description here
please can someone help me I'm blocked?
with get method, you've called two times /search URL.
The first is for personnel and the second is for material. While running route:list personnel route override by material. Hence, It show only last route.
You should have one URL for any route.
Route('/search/{type}',MaterialController#search)->name('type.search');
Now you can use it in a dynamic way.
{{ url('search/material')}}
{{ url('search/personnel')}}
{{ route('type.search','material')}}
{{ route('type.search','personnel')}}
In the controller, you can make it as dynamic as below.
public function invoicestorecentiga($type) {
if($type == 'material'){
}
if($type == 'personnel'){
}
}
You have two same search routes in your web.php file. Even if you named them differently, your second search route is overwriting the first one, and the first route basically doesn't exist anymore. My suggestion would be to rename one of those routes to something else, example:
Route::get('materials/search', ....)
Route::get('personnel/search', ....)
Related
here is the URL i want to access an articel in Laravel.
http://mysite.test/art-entertainment-articles/poetry-articles/guide-praising-comments-1.html
now article_slug is "/art-entertainment-articles/poetry-articles/guide-praising-comments-1.html".
i made a route like this.
Route::get('/{any:.*}', 'ArticlesController#article');
but it is showing error 404 not found. now i want to get article by matching slug like this.
$article = Article::where('article_slug', '=', $article_slug)->first();
what should i write in route? it breaks at slashes and count not read the method.
You are probably better off using the fallback function like so
Route::fallback(function () {
//
});
This will catch all routes that are not defined above it. Then you can add the logic to hit your controller and figure out the article you require from the url.
To display the blog list i have using the following route
// Blog List
Route::name('blog')->get('blog', 'Front\BlogController#index');
Ex: http://www.mypropstore.com/blog/
To display the blog category,
Route::name('category')->get('blog/{category}', 'Front\PostController#category');
Ex: http://www.mypropstore.com/blog/buy-sell
To display the blog details, comments and tag details, we have using "posts" middleware
// Posts and comments
Route::prefix('posts')->namespace('Front')->group(function () {
Route::name('posts.display')->get('{slug}', 'PostController#show');
Route::name('posts.tag')->get('tag/{tag}', 'PostController#tag');
Route::name('posts.search')->get('', 'PostController#search');
Route::name('posts.comments.store')->post('{post}/comments', 'CommentController#store');
Route::name('posts.comments.comments.store')->post('{post}/comments/{comment}/comments', 'CommentController#store');
Route::name('posts.comments')->get('{post}/comments/{page}', 'CommentController#comments');
});
Ex: http://www.mypropstore.com/posts/apartment-vs-villa-which-is-the-right-choice-for-you
Now i want to change the blog details url page to
http://www.mypropstore.com/blog/apartment-vs-villa-which-is-the-right-choice-for-you-{{blogid}}
Ex: http://www.mypropstore.com/blog/apartment-vs-villa-which-is-the-right-choice-for-you-54
If i change that above format, it conflict category page. Any body knows how to set the routing for blog details page(middleware "posts")
Assuming the blogid part, at the end of your suggested route...
http://www.mypropstore.com/blog/apartment-vs-villa-which-is-the-right-choice-for-you-{{blogid}}
...is numeric, you could do something like this:
For your route definition for your post details page, use the following:
Route::name('posts.display')
->get('blog/{slug}-{id}', 'PostController#show')
->where('id', '[0-9]+');
What this does is ensures that this route is only matched by paths that follow the pattern blog/{slug}-{id} but constrains that the id part of your route must be numeric i.e. consist only of one or more numbers.
You will need to ensure that this route appears before the one matching your category route or else the category route will take precedence.
Your controller should have a show method like this:
class PostController extends Controller
{
public function show($slug, $id)
{
// $id will contain the number at the end of the route
// $slug will contain the slug before the number (without the hyphen)
// You should be able to do this to get your post.
$post = Post::findOrFail($id);
dd($post);
}
}
Since your categories aren't numbers you could solve the conflict specifying that id will always be a number like this:
Route::get('/blog/{id}', 'BlogController#show')->where('id', '[0-9]+');
I have a function that I'm trying to pass some data to a view. I can't get the Route to recognize the data, it just keeps saying my variables are undefined. Here's what I'm trying to do:
return redirect('confirm')->with([
'name'=>$name,
'service'=>$service,
'$email_address'=>$email_address
]);
Then in my web.php file, I have:
Route::get ('confirm', function($name,$service,$email_address){
return view('confirm',compact('name','service','email_address'));
})->name('confirm');
Laravel just throws an error "Missing argument 1 for Illuminate\Routing\Router::{closure}()"
I'm at a complete loss, I've tried this a bunch of different ways. If I call the view right from my controller, it works fine, but then URL isn't what I want it to be, so it seems like I have to return the redirect and reference the data in my route definition. Can anyone enlighten me?
If it's ok to show the email in the route then you can correct the problem like this :
Route::get ('confirm/{name}/{service}/{email_address}', function($name,$service,$email_address){
return view('confirm',compact('name','service','email_address'));
})->name('confirm');
And in the controller :
return \Redirect::route('confirm', [
'name'=>$name,
'service'=>$service,
'email_address'=>$email_address
]);
Ps : this is not recommended i just answer you problem but there is a better way to do it, passing just an id for exsample then find the user by id then take his email and other stuff.
How to get the last part of the current URL without the / sign, dynamically?
For example:
In www.news.com/foo/bar get bar.
In www.news.com/foo/bar/fun get fun.
Where to put the function or how to implement this in the current view?
Of course there is always the Laravel way:
request()->segment(count(request()->segments()))
You can use Laravel's helper function last. Like so:
last(request()->segments())
This is how I did it:
{{ collect(request()->segments())->last() }}
Use basename() along with Request::path().
basename(request()->path())
You should be able to call that from anywhere in your code since request() is a global helper function in Laravel and basename() is a standard PHP function which is also available globally.
The Route object is the source of the information you want. There are a few ways that you can get the information and most of them involve passing something to your view. I strongly suggest not doing the work within the blade as this is what controller actions are for.
Passing a value to the blade
The easiest way is to make the last part of the route a parameter and pass that value to the view.
// app/Http/routes.php
Route::get('/test/{uri_tail}', function ($uri_tail) {
return view('example')->with('uri_tail', $uri_tail);
});
// resources/views/example.blade.php
The last part of the route URI is <b>{{ $uri_tail }}</b>.
Avoiding route parameters requires a little more work.
// app/Http/routes.php
Route::get('/test/uri-tail', function (Illuminate\Http\Request $request) {
$route = $request->route();
$uri_path = $route->getPath();
$uri_parts = explode('/', $uri_path);
$uri_tail = end($uri_parts);
return view('example2')->with('uri_tail', $uri_tail);
});
// resources/views/example2.blade.php
The last part of the route URI is <b>{{ $uri_tail }}</b>.
Doing it all in the blade using the request helper.
// app/Http/routes.php
Route::get('/test/uri-tail', function () {
return view('example3');
});
// resources/views/example3.blade.php
The last part of the route URI is <b>{{ array_slice(explode('/', request()->route()->getPath()), -1, 1) }}</b>.
Try request()->segment($number) it should give you a segment of the URL.
In your example, it should probably be request()->segment(2) or request()->segment(3) based on the number of segments the URL has.
YourControllor:
use Illuminate\Support\Facades\URL;
file.blade.php:
echo basename(URL::current());
It was useful for me:
request()->path()
from www.test.site/news
get -> news
I just had the same question. In the meantime Laravel 8. I have summarised all the possibilities I know.
You can test it in your web route:
http(s)://127.0.0.1:8000/bar/foo || baz
http(s)://127.0.0.1:8000/bar/bar1/foo || baz
Route::get('/foo/{lastPart}', function(\Illuminate\Http\Request $request, $lastPart) {
dd(
[
'q' => request()->segment(count(request()->segments())),
'b' => collect(request()->segments())->last(),
'c' => basename(request()->path()),
'd' => substr( strrchr(request()->path(), '/'), 1),
'e' => $lastPart,
]
)->where('lastPart', 'foo,baz'); // the condition is only to limit
I prefer the variant e).
As #Qevo had already written in his answer. You simply make the last part part of the request. To narrow it down you can put the WHERE condition at the route.
Try with:
{{ array_pop(explode('/',$_SERVER['REQUEST_URI'])) }}
It should work well.
I am using Laravel 4.
I have an old url that needs to be routable. It doesn't really matter what it's purpose is but it exists within the paypal systems and will be called regularly but cannot be changed (which is ridiculous I know).
I realise that this isn't the format url's are supposed to take in Laravel, but this is the url that will be called and I need to find a way to route it:
http://domain.com/forum/index.php?app=subscriptions&r_f_g=xxx-paypal
(xxx will be different on every request)
I can't figure out how to route this with laravel, i'd like to route it to the method PaypalController#ipbIpn so i've tried something like this:
Route::post('forum/index.php?app=subscriptions&r_f_g={id}-paypal', 'PaypalController#ipbIpn');
But this doesn't work, infact I can't even get this to work:
Route::post('forum/index.php', 'PaypalController#ipbIpn');
But this will:
Route::post('forum/index', 'PaypalController#ipbIpn');
So the question is how can I route the url, as it is at the top of this question, using Laravel?
For completeness I should say that this will always be a post not a get, but that shouldn't really make any difference to the solution.
Use this:
Route::post('forum/{file}', 'PaypalController#ipbIpn');
And then in the controller, use
public function forum($file) {
$request = Route::getRequest();
$q = (array) $request->query; // GET
$parameters = array();
foreach($q as $key => $pararr) {
$parameters = array_merge($parameters, $pararr);
}
}
You can then access the get parameters via e.g.
echo $parameters['app'];
you can use route redirection to mask and ending .php route ex:
Route::get('forum/index', ['uses'=> 'PaypalController#ipbIpn']);
Route::redirect('forum/index.php', 'forum/index');