Why this websocket server does not broadcast to connected client? - go

Below code is a websocket broadcast server that read from a specific connection then broadcasting it to connected clients.
But this server does not broadcast despite there is no error and warnings.
Why this server does not broadcast?
In this code self.KabucomConn is origin socket so read from this socket, then broadcast to client which stored in Hub.RClients.
When new connection established, passing connection object with register channel to Hub, then Hub adds a client to RClient that stored client object.
package main
import (
"log"
"net/http"
"net/url"
"github.com/gorilla/websocket"
)
var upgrader = websocket.Upgrader{
CheckOrigin: func(r *http.Request) bool {
return true
},
}
type Client struct {
hub *Hub
Conn *websocket.Conn
Send chan []byte
}
func (self *Client) writepump() {
for {
select {
case message := <-self.Send:
w, err := self.Conn.NextWriter(websocket.TextMessage)
if err != nil {
log.Print("writepump: nextwriter error")
}
w.Write(message)
w.Close()
}
}
}
type Hub struct {
RClients map[*Client]bool
KabucomConn *websocket.Conn
register chan *Client
unregister chan *Client
kabucomchan chan []byte
url url.URL
}
func (self *Hub) KabucomRun() {
for {
_, b, err := self.KabucomConn.ReadMessage() // read data from origin data connection
log.Println("read message")
if err != nil {
log.Println(err)
self.KabucomConn.Close()
for i := 1; i <= 5; i++ { //retry re-connect up to 5 times
self.KabucomConn, _, err = websocket.DefaultDialer.Dial(self.url.String(), nil)
if i >= 5 && err != nil {
log.Fatal(err)
} else if err != nil {
log.Println(err, "try", i)
continue
} else {
break
}
}
log.Println("conti")
continue
}
log.Println(b)
self.kabucomchan <- b
}
}
func (self *Hub) Run() {
defer func() {
for c, _ := range self.RClients {
close(c.Send)
c.Conn.Close()
}
}()
for {
select {
case message := <-self.kabucomchan:
log.Println("kabucomchan")
log.Println(message)
for c, _ := range self.RClients {
c.Send <- message
}
case c := <-self.register:
log.Println("reg")
self.RClients[c] = true
case c := <-self.unregister:
log.Println("unreg")
delete(self.RClients, c)
close(c.Send)
}
}
}
func newHub() *Hub {
u := url.URL{Scheme: "ws", Host: "192.168.1.8:20063", Path: "/ws"}
var conn *websocket.Conn
for i := 1; i <= 5; i++ {
d, _, err := websocket.DefaultDialer.Dial(u.String(), nil)
if err != nil && i < 5 {
log.Println(err)
continue
} else if i >= 5 {
log.Println("Hub: Kabucom connection error")
}
conn = d
break
}
return &Hub{RClients: make(map[*Client]bool), register: make(chan *Client), KabucomConn: conn}
}
func handler(w http.ResponseWriter, r *http.Request, hub *Hub) {
conn, err := upgrader.Upgrade(w, r, nil)
if err != nil {
return
}
client := &Client{Conn: conn, hub: hub, Send: make(chan []byte, 256)}
go client.writepump()
hub.register <- client
}
func main() {
hub := newHub()
go hub.Run()
go hub.KabucomRun()
http.HandleFunc("/ws", func(w http.ResponseWriter, r *http.Request) {
handler(w, r, hub)
})
log.Println(":20021/ws")
http.ListenAndServe(":20021", nil)
}

Because you are not initializing Hub.kabucomchan.
func newHub() *Hub {
//...
return &Hub{RClients: make(map[*Client]bool), register: make(chan *Client), KabucomConn: conn, /* kabucomchan ??? */}
}
Send and receive operations on channels assume that both sender c<- and receiver <-c hold a reference to the same channel, but when the channel is nil this reference doesn't exist, and the send and receive just block forever.
Properly initialize the channel in the Hub constructor:
return &Hub{
RClients: make(map[*Client]bool),
register: make(chan *Client),
KabucomConn: conn,
kabucomchan: make(chan []byte, /* buffered? */), // <--- !
}

Related

Gorilla websocket is not closing

I want to open websocket server whenever i want to and close but server does not close after writing "exit" when i go back to my main() and i try to start again it fails saying "httpHandleFunc multiple registration '/' " how do i close websocket server permanently and go back to main and start server again like switch on/off.
Another issue i am facing is client side errors with Bad Handshake when using gorilla mux as a handler.
#Server-Side Code
https://go.dev/play/p/n_I4xzOomWz
package main
import (
"bufio"
"flag"
"fmt"
"net/http"
"os"
"strings"
"time"
"github.com/gorilla/mux"
"github.com/gorilla/websocket"
log "github.com/sirupsen/logrus"
)
const (
// Time allowed to write a message to the peer.
writeWait = 10 * time.Second
// Maximum message size allowed from peer.
maxMessageSize = 8192
// Time allowed to read the next pong message from the peer.
pongWait = 60 * time.Second
// Send pings to peer with this period. Must be less than pongWait.
pingPeriod = (pongWait * 9) / 10
// Time to wait before force close on connection.
closeGracePeriod = 2 * time.Second
)
var (
server http.Server
addr = "0.0.0.0:443"
upgrader = websocket.Upgrader{
CheckOrigin: func(r *http.Request) bool {
return true
},
}
)
func ping(ws *websocket.Conn, done chan struct{}) {
ticker := time.NewTicker(pingPeriod)
defer ticker.Stop()
for {
select {
case <-ticker.C:
if err := ws.WriteControl(websocket.PingMessage, []byte{}, time.Now().Add(writeWait)); err != nil {
log.Println("ping:", err)
}
case <-done:
return
}
}
}
// write message
func pumpStdout(ws *websocket.Conn, done chan struct{}) {
defer func() {
}()
for {
text := ReadInput("User220 > ")
if text == "exit" {
break
}
ws.SetWriteDeadline(time.Now().Add(writeWait))
if err := ws.WriteMessage(websocket.TextMessage, []byte(text)); err != nil {
ws.Close()
log.Errorln(err)
break
}
}
close(done)
ws.SetWriteDeadline(time.Now().Add(writeWait))
ws.WriteMessage(websocket.CloseMessage, websocket.FormatCloseMessage(websocket.CloseNormalClosure, ""))
time.Sleep(closeGracePeriod)
ws.Close()
}
// receive message
func pumpStdin(ws *websocket.Conn, done chan struct{}) {
defer ws.Close()
ws.SetReadLimit(maxMessageSize)
ws.SetReadDeadline(time.Now().Add(pongWait))
ws.SetPongHandler(func(string) error { ws.SetReadDeadline(time.Now().Add(pongWait)); return nil })
ticker := time.NewTicker(time.Second)
defer ticker.Stop()
for {
select {
case <-done:
break
case <-ticker.C:
_, message, err := ws.ReadMessage()
if err != nil {
ws.CloseHandler()
err := ws.UnderlyingConn().Close()
fmt.Println(err)
main()
}
if len(message) > 0 {
fmt.Printf("\r\n%sUser220 > ", message)
}
}
}
}
func WebsocketHandle(w http.ResponseWriter, r *http.Request) {
c, err := upgrader.Upgrade(w, r, nil)
if err != nil {
log.Fatalln(err)
}
defer c.Close()
stdoutDone := make(chan struct{})
go pumpStdout(c, stdoutDone)
go ping(c, stdoutDone)
pumpStdin(c, stdoutDone)
}
func start_socket() {
flag.Parse()
log.Printf("listen at %s", addr)
// ----------------------
mux := mux.NewRouter()
mux.HandleFunc("/", WebsocketHandle)
//-----------------------
http.HandleFunc("/", WebsocketHandle)
server = http.Server{Addr: addr}
log.Fatalln(server.ListenAndServe())
}
func stop_server() {
err := server.Close()
if err != nil {
log.Fatalln(err)
}
}
func ReadInput(promt string) string {
fmt.Printf("\n%s", promt)
reader := bufio.NewReader(os.Stdin)
input, _ := reader.ReadString('\n')
return strings.TrimSpace(input)
}
func main() {
for {
read := ReadInput("Main : ")
switch read {
case "start":
start_socket()
case "stop":
stop_server()
default:
fmt.Println("Not Sure")
}
}
}
Client side i am just polling and writing back the same message right now.
#Client-Side Code
https://go.dev/play/p/y4nUkvMFYec
package main
import (
"fmt"
"net/url"
"github.com/gorilla/websocket"
log "github.com/sirupsen/logrus"
)
var addr = "localhost:443"
func main() {
dial := websocket.Dialer{}
u := url.URL{Scheme: "ws", Host: addr, Path: "/"}
log.Printf("connecting to %s", u.String())
c, _, err := dial.Dial(u.String(), nil)
if err != nil {
log.Fatalln(err)
}
defer c.Close()
for {
_, message, err := c.ReadMessage()
if err != nil {
log.Fatalln(err)
}
fmt.Println("Recevied : " + string(message))
err = c.WriteMessage(websocket.TextMessage, message)
if err != nil {
log.Fatalln(err)
}
}
}

Could not `chan` pass through RPC in Go?

For the following code, get Message via RPC, why its Done field is nil?
Could not chan pass through RPC?
type Message struct {
Text string
Done chan bool
}
type (
GetArgs struct {
Key string
}
GetReply struct {
Message *Message
}
)
// Client
func connect() *rpc.Client {
client, err := rpc.Dial("tcp", ":1234")
if err != nil {
log.Fatal("dialing:", err)
}
return client
}
func get(key string) *Message {
client := connect()
args := GetArgs{key}
reply := GetReply{}
err := client.Call("KV.Get", &args, &reply)
if err != nil {
log.Fatal("error:", err)
}
client.Close()
return reply.Message
}
// Server
type KV struct {
mu sync.Mutex
messages map[string]*Message
}
func server() {
kv := new(KV)
kv.messages = map[string]*Message{}
done := make(chan bool)
kv.messages["Jan"] = &Message{Text: "hello", Done: done}
rpcs := rpc.NewServer()
rpcs.Register(kv)
l, err := net.Listen("tcp", ":1234")
if err != nil {
log.Fatal("error:", err)
}
go func() {
for {
conn, err := l.Accept()
if err == nil {
go rpcs.ServeConn(conn)
} else {
break
}
}
l.Close()
}()
}
func (kv *KV) Get(args *GetArgs, reply *GetReply) error {
kv.mu.Lock()
defer kv.mu.Unlock()
val, ok := kv.messages[args.Key]
if ok {
reply.Message = val
}
return nil
}
func main() {
server()
fmt.Printf("get() -> %v\n", get("Jan"))
// Output:
// get() -> &{hello <nil>}
}
No. RPC arguments can only be those that are serializable by encoding/gob, and chans are not one of them
Functions and channels will not be sent in a gob. Attempting to encode such a value at the top level will fail. A struct field of chan or func type is treated exactly like an unexported field and is ignored.

WebSocket Server that feeds messages to clients in a round robin fashion

I have a websocket server in Go using the Gorilla websocket package. At this stage, I will have only one server serving 5 clients. I am getting some messages from upstream into the WebSocket server. My intention is to NOT BROADCAST all the messages to the connected clients. I would like to send only one copy of the message to the connected clients in a round robin fashion. It doesn't matter which client gets it as long as there is only one that gets it.
My attempted solution
I have a simple Go server, created a Pool of clients (websocket connections) that I am receiving. However, I do not see any options to round robin the messages as I mentioned above. All my clients are getting the message. How can I send only one copy of the message to the connected clients instead of broadcasting to all.
Discalimer
The code I have is taken from online sources and modified to my requirement. I am relatively new to Go and Websockets. Is this something even possible using Websockets?
main.go
package main
import (
"fmt"
"net/http"
"github.com/realtime-chat-go-react/backend/pkg/websocket"
)
func serveWs(pool *websocket.Pool, w http.ResponseWriter, r *http.Request) {
fmt.Println("WebSocket Endpoint Hit")
conn, err := websocket.Upgrade(w, r)
if err != nil {
fmt.Fprintf(w, "%+v\n", err)
}
client := &websocket.Client{
Conn: conn,
Pool: pool,
}
pool.Register <- client
client.Read()
}
func setupRoutes() {
pool := websocket.NewPool()
go pool.Start()
http.HandleFunc("/ws", func(w http.ResponseWriter, r *http.Request) {
serveWs(pool, w, r)
})
}
func main() {
setupRoutes()
err := http.ListenAndServe(":8080",nil)
if err != nil {
fmt.Println(err)
}
}
websocket.go
package websocket
import (
"log"
"net/http"
"github.com/gorilla/websocket"
)
var upgrader = websocket.Upgrader{
ReadBufferSize: 1024,
WriteBufferSize: 1024,
}
var wsList []*websocket.Conn
func Upgrade(w http.ResponseWriter, r *http.Request) (*websocket.Conn, error) {
upgrader.CheckOrigin = func(r *http.Request) bool { return true }
conn, err := upgrader.Upgrade(w, r, nil)
wsList = append(wsList, conn) //Creating a list here to store all websocket clients.
if err != nil {
log.Println(err)
return nil, err
}
return conn, nil
}
pool.go
package websocket
import "fmt"
type Pool struct {
Register chan *Client
Unregister chan *Client
Clients map[*Client]bool
Broadcast chan Message
}
func NewPool() *Pool {
return &Pool{
Register: make(chan *Client),
Unregister: make(chan *Client),
Clients: make(map[*Client]bool),
Broadcast: make(chan Message),
}
}
func (pool *Pool) Start() {
for {
select {
case client := <-pool.Register:
pool.Clients[client] = true
fmt.Println("Size of Connection Pool: ", len(pool.Clients))
for client, _ := range pool.Clients {
fmt.Println(client)
client.Conn.WriteJSON(Message{Type: 1, Body: "New User Joined..."})
}
break
case client := <-pool.Unregister:
delete(pool.Clients, client)
fmt.Println("Size of Connection Pool: ", len(pool.Clients))
for client, _ := range pool.Clients {
client.Conn.WriteJSON(Message{Type: 1, Body: "User Disconnected..."})
}
break
case message := <-pool.Broadcast: //This is where I need to modify the code but not sure how
fmt.Println("Sending message to all clients in Pool")
for client, _ := range pool.Clients {
if err := client.Conn.WriteJSON(message); err != nil {
fmt.Println(err)
return
}
}
}
}
}
client.go
package websocket
import (
"fmt"
"log"
"sync"
"github.com/gorilla/websocket"
)
type Client struct {
ID string
Conn *websocket.Conn
Pool *Pool
mu sync.Mutex
}
type Message struct {
Type int `json:"type"`
Body string `json:"body"`
}
func (c *Client) Read() {
defer func() {
c.Pool.Unregister <- c
c.Conn.Close()
}()
for {
messageType, p, err := c.Conn.ReadMessage()
if err != nil {
log.Println(err)
return
}
message := Message{Type: messageType, Body: string(p)}
c.Pool.Broadcast <- message
fmt.Printf("Message Received: %+v\n", message)
}
}
Modify the pool to store clients in a slice instead of a map. Add field to record index of the previous client used.
type Pool struct {
Register chan *Client
Unregister chan *Client
Clients []*Client
Broadcast chan Message
PrevClientIndex int
}
Round robin instead of broadcasting:
case message := <-pool.Broadcast:
if len(pool.Clients) == 0 {
continue
}
pool.PrevClientIndex++
if pool.PrevClientIndex >= len(pool.Clients) {
pool.PrevClientIndex = 0
}
client := pool.Clients[pool.PrevClientIndex]
if err := client.Conn.WriteJSON(message); err != nil {
// handle error
...
Register appends to the slice:
case client := <-pool.Register:
pool.Clients = append(pool.Clients, client)
...
Unregister removes the client from the slice:
case client := <-pool.Unregister:
j := 0
for _, c := range pool.Clients {
if c != client {
c.Clients[j] = c
j++
}
}
pool.Clients = pool.Clients[:j]
...

TCP connection returns 'broken pipe' error when used multiple times

This question relates to go and its net package.
I wrote a simple tcp server handles some RPC. the client is using a chan net.Conn to manage all tcp connection on the client side. Server is running with a tcp listener.
here's the code:
client:
package server
import (
"errors"
"log"
"net"
)
var tcpPool chan net.Conn
func NewClient(connections int, address string) {
tcpPool = make(chan net.Conn, connections)
for i := 0; i < connections; i++ {
conn, err := net.Dial("tcp4", address)
if err != nil {
log.Panic(err)
}
tcpPool <- conn
}
}
func SendMessage(msg []byte) ([]byte, error) {
conn := getConn()
log.Println("check conn: ", conn)
log.Println("msg: ", msg)
defer releaseConn(conn)
// send message
n, err := conn.Write(msg)
if err != nil {
log.Panic(err)
} else if n < len(msg) {
log.Panic(errors.New("Message did not send in full"))
}
// receiving a message
inBytes := make([]byte, 0)
for {
// bufsize 1024, read bufsize bytes each time
b := make([]byte, bufSize)
res, err := conn.Read(b)
log.Println("server sends >>>>>>>>>>>>: ", res)
if err != nil {
b[0] = ReError
break
}
inBytes = append(inBytes, b[:res]...)
// message finished.
if res < bufSize {
break
}
}
// check replied message
if len(inBytes) == 0 {
return []byte{}, errors.New("empty buffer error")
}
log.Println("SendMessage gets: ", inBytes)
return inBytes, nil
}
func releaseConn(conn net.Conn) error {
log.Println("return conn to pool")
select {
case tcpPool <- conn:
return nil
}
}
func getConn() (conn net.Conn) {
log.Println("Take one from pool")
select {
case conn := <-tcpPool:
return conn
}
}
server
func StartTCPServer(network, addr string) error {
listener, err := net.Listen(network, addr)
if err != nil {
return errors.Wrapf(err, "Unable to listen on address %s\n", addr)
}
log.Println("Listen on", listener.Addr().String())
defer listener.Close()
for {
log.Println("Accept a connection request.")
conn, err := listener.Accept()
if err != nil {
log.Println("Failed accepting a connection request:", err)
continue
}
log.Println("Handle incoming messages.")
go onConn(conn)
}
}
//onConn recieves a tcp connection and waiting for incoming messages
func onConn(conn net.Conn) {
inBytes := make([]byte, 0)
defer func() {
if e := recover(); e != nil {
//later log
if err, ok := e.(error); ok {
println("recover", err.Error())
}
}
conn.Close()
}()
// load msg
for {
buf := make([]byte, bufSize)
res, err := conn.Read(buf)
log.Println("server reading: ", res)
inBytes = append(inBytes, buf[:res]...)
if err != nil || res < bufSize {
break
}
}
var req RPCRequest
err := json.Unmarshal(inBytes, &req)
if err != nil {
log.Panic(err)
}
log.Println("rpc request: ", req)
var query UserRequest
err = json.Unmarshal(req.Query, &query)
if err != nil {
log.Panic(err)
}
log.Println("rpc request query: ", query)
// call method to process request
// good now we can proceed to function call
// some actual function calls gets a output
// outBytes, err := json.Marshal(out)
conn.Write(outBytes)
}
I think this is very standard. but for some reason, I can only send message on the client side one, and then the follow 2nd and 3rd start to show some irregularity.
1st ---> success, gets response
2nd ---> client can send but nothing gets back, logs on server side shows no in coming message
3rd ---> if I send from client side one more time, it shows broken pipe error..
There are some bad handling way.
First, the flag to insure the msg from server finished is depending on io.EOF,not length
// message finished.
if res < 512 {
break
}
instead of this, reader returns an io.EOF is the only symbol that shows message finished.
Second, chan type has its property to block and not need to use select.by the way, you really need to start a goroutine to release. The same requirement for getConn
func releaseConn(conn net.Conn) {
go func(){
tcpPool <- conn
}()
}
func getConn() net.Conn {
con := <-tcpPool
return con
}
Third, listener should not be close, code below is bad
defer listener.Close()
The most important reason is
on the client side,
res, err := conn.Read(b) this receive the reply from the server.
when nothing reply ,it block rather than io.EOF, nor some error else.
It means ,you cann't box a lasting communicating part into a function send().
You can do a single thing to use sendmsg() to send, but never use sendmsg() to handle the reply.
you can handle reply like this
var receive chan string
func init() {
receive = make(chan string, 10)
}
func ReceiveMessage(con net.Conn) {
// receiving a message
inBytes := make([]byte, 0, 1000)
var b = make([]byte, 512)
for {
// bufsize 1024, read bufsize bytes each time
res, err := con.Read(b)
if err != nil {
if err == io.EOF {
break
}
fmt.Println(err.Error())
break
}
inBytes = append(inBytes, b[:res]...)
msg := string(inBytes)
fmt.Println("receive msg from server:" + msg)
receive <- msg
}
}
I found several problem in your code, but I can't tell which one leads your failure.
This is my code according to what you write and did some fixing.
client.go:
package main
import (
"fmt"
"io"
"log"
"net"
)
var tcpPool chan net.Conn
var receive chan string
func init() {
receive = make(chan string, 10)
}
func NewClient(connections int, address string) {
tcpPool = make(chan net.Conn, connections)
for i := 0; i < connections; i++ {
conn, err := net.Dial("tcp", address)
if err != nil {
log.Panic(err)
}
tcpPool <- conn
}
}
func SendMessage(con net.Conn, msg []byte) error {
// send message
_, err := con.Write(msg)
if err != nil {
log.Panic(err)
}
return nil
}
func ReceiveMessage(con net.Conn) {
// receiving a message
inBytes := make([]byte, 0, 1000)
var b = make([]byte, 512)
for {
// bufsize 1024, read bufsize bytes each time
res, err := con.Read(b)
if err != nil {
if err == io.EOF {
break
}
fmt.Println(err.Error())
break
}
inBytes = append(inBytes, b[:res]...)
msg := string(inBytes)
fmt.Println("receive msg from server:" + msg)
receive <- msg
}
}
func getConn() net.Conn {
con := <-tcpPool
return con
}
func main() {
NewClient(20, "localhost:8101")
con := <-tcpPool
e := SendMessage(con, []byte("hello, i am client"))
if e != nil {
fmt.Println(e.Error())
return
}
go ReceiveMessage(con)
var msg string
for {
select {
case msg = <-receive:
fmt.Println(msg)
}
}
}
server.go
package main
import (
"fmt"
"io"
"net"
)
func StartTCPServer(network, addr string) error {
listener, err := net.Listen(network, addr)
if err != nil {
return err
}
for {
conn, err := listener.Accept()
if err != nil {
fmt.Println(err.Error())
continue
}
onConn(conn)
}
}
//onConn recieves a tcp connection and waiting for incoming messages
func onConn(conn net.Conn) {
inBytes := make([]byte, 0)
// load msg
for {
buf := make([]byte, 512)
res, err := conn.Read(buf)
if err != nil {
if err == io.EOF {
return
}
fmt.Println(err.Error())
return
}
inBytes = append(inBytes, buf[:res]...)
fmt.Println("receive from client:" + string(inBytes))
conn.Write([]byte("hello"))
}
}
func main() {
if e := StartTCPServer("tcp", ":8101"); e != nil {
fmt.Println(e.Error())
return
}
}
this works and no error.
By the way, I can't see where either on the client side or the server side you do con.Close(). It's nessasary to close it.This means a connection once got from the pool, you don't put it back. When you think a connection is over, then close it and build a new connection to fill the pool rather than put it back,beause it's a fatal operation to put a closed con back to the pool.

Multiple connections to a TCP server

I've developed a small Go TCP server to make a chat application. But when I try to connect clients to it, the server works fine with two clients, but whenever I tried to connect the third client it is not connected to the server. I am running on Windows. What could be the issue?
package main
import (
"bufio"
"fmt"
"net"
)
var allClients map[*Client]int
type Client struct {
// incoming chan string
outgoing chan string
reader *bufio.Reader
writer *bufio.Writer
conn net.Conn
connection *Client
}
func (client *Client) Read() {
for {
line, err := client.reader.ReadString('\n')
if err == nil {
if client.connection != nil {
client.connection.outgoing <- line
}
fmt.Println(line)
} else {
break
}
}
client.conn.Close()
delete(allClients, client)
if client.connection != nil {
client.connection.connection = nil
}
client = nil
}
func (client *Client) Write() {
for data := range client.outgoing {
client.writer.WriteString(data)
client.writer.Flush()
}
}
func (client *Client) Listen() {
go client.Read()
go client.Write()
}
func NewClient(connection net.Conn) *Client {
writer := bufio.NewWriter(connection)
reader := bufio.NewReader(connection)
client := &Client{
// incoming: make(chan string),
outgoing: make(chan string),
conn: connection,
reader: reader,
writer: writer,
}
client.Listen()
return client
}
func main() {
allClients = make(map[*Client]int)
listener, _ := net.Listen("tcp", ":8080")
for {
conn, err := listener.Accept()
if err != nil {
fmt.Println(err.Error())
}
client := NewClient(conn)
for clientList, _ := range allClients {
if clientList.connection == nil {
client.connection = clientList
clientList.connection = client
fmt.Println("Connected")
}
}
allClients[client] = 1
fmt.Println(len(allClients))
}
}
Your code is fine. I compiled in on Linux, tried with 4 connections. Everything worked as expected.

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