I have an rxjs function using several rxjs operators from which I need to ultimately return an observable. My challenge is detailed below in the sample code with details of what I am trying to do. How can I accomplish this? Do I need a rewrite? Without the change I'm trying to make to access the values from Observable3 everything works as needed. I've tried many things including using withLatestFrom to bring in observable three and also combineLatest but to no luck.
Observable3 = of({obs3Prop1: value1, obs3Prop2: value2})
this.Observable1
.pipe(
switchMap(param1) => {
return this.getCount(param1);
}),
mergeMap((param2: number) =>
this.Observable2
.pipe(
//inside this pipe, return another observable from here using some rxjs operators
//where I need access to param2
//but I also need access to the value from Observable3
)
),
)
It seems like you could use just forkJoin() assuming the all source Observables complete:
mergeMap((param2: number) =>
forkJoin([
Observable3,
this.Observable2,
]).pipe(
mergeMap(([o3params, o2params]) => this.makeCall(o3params.param1, o2params)),
)
),
Related
I use the following code in an angular app. I used the RxJS map call similar to how array map is used. After reading about RxJS switchmap operator, I'm not sure whether I should use map or switchmap. Should I use switchmap so the observable which is returned from the http call is closed so there is no memory leak?
getPeopleForTypeahead(term: string): Observable<IPersonForTypeahead[]> {
var peopleUrl = `https://localhost:5001/api/peoplesearch?name=${term}`;
return this.http.get<any>(peopleUrl)
.pipe(
map(pl => {
return this.peopleAsFlattened(pl.peopleList).reduce((p, c) => p.concat(c));
}),
catchError(this.handleError('getPeopleForTypeahead', []))
);
}
peopleAsFlattened = (pla: IPeopleList[]) => {
return pla.map(pl => pl.people.map(p => {
return {
id: p.id,
fullName: p.fullNames[0].firstName + " " + p.fullNames[0].lastName
};
}));
}
map and switchMap have completely different purposes:
map - transform the shape of an emission
switchMap - subscribe to an observable and emit its emissions into the stream
map
Use map when you want transform the shape of each emission. Ex: emit the user name property, instead of the entire user object:
userName$: Observable<string> = this.service.getUser(123).pipe(
map(user => user.name)
);
switchMap
Use switchMap when you want to map an emission to another observable and emit its emissions. Ex: You have an observable of some id and want to emit the resource after fetching it:
user$: Observable<User> = this.userId$.pipe(
switchMap(id => this.service.getUser(id)),
);
When user$ is subscribed to, the user returned from service.getUser(id) is emitted (not the userId string).
switchMap is not interchangeable with the map operator, nor vise versa. Although both of them has to do with mapping (as their names suggest), they have two separate use-cases.
In your particular case, the map operator is the way to go.
When to use switchMap?
You can only use switchMap(cb) when you check all these requirements:
Your callback function, cb, passed into switchMap returns an observable, observable$.
If your cb (callback function) does not return an observable, you should look into operators that don't handle higher-level observables, such as filter and map (what you actually needed); not operators that handle higher-level observables such as concatMap and well, switchMap.
You want to execute your cb sequentially before the next operation down the pipeline (after switchMap) executes.
Maybe you want to run logic inside of cb, and optionally get the return value of cb after executing, so that you can pass it down the pipeline for further processing, for example.
When you want to "discard" what will happen to cb's execution and re-execute cb every time the source observable (the thing that trickles down to switchMap(cb)) emits a new value/notification.
Applying what we hopefully learned, we know that your cb:
pl => {
return this.peopleAsFlattened(pl.peopleList).reduce((p, c) => p.concat(c));
}
returns a plain JavaScript array; not an observable. This takes using switchMap out of the question since it violates the first requirement I made up above.
Hopefully that makes sense. :)
We use switchMap when the source observable is a hot observable. In which case you prefer the behaviour that cancel the succeeding observable when source emits.
In your code, you source is a one-off http call which means it will not emit multiple times and the follow up action is not executing observable but to mutate an array. There is no need to use switchMap
how can i subscribe for example three observables, and to emit when one of them emit new value depend on the order they are, like forkJoin but emit but the order of them is important so if ob3 emit first, i want the value of obv1 to be null, also obv2
and only obv3 that was emitted will have value
for example
forkJoin(obs1,obs2,ob3)
.subscribe([ob1v,ob2v,ob3v]=>{
if (obv1v){ 'do somthing'}
if (obv2v){ 'do somthing'}
if (obv3v){ 'do somthing'}
})
thanks
Maybe combineLatest with an initial value would work for you. combineLatest will emit the latest value from each source observable whenever any of its sources emit. However, it doesn't emit for the first time until all sources have emitted at least one value.
We can use startWith to overcome this by providing an initial value for each source.
combineLatest([
obs1.pipe(startWith(null)),
obs2.pipe(startWith(null)),
obs3.pipe(startWith(null)),
])
.pipe(
skip(1) // prevent emitting initial [null, null, null] value
)
.subscribe(([v1, v2, v3]) => {
// do something here
});
You can see the output in this StackBlitz.
It seems that you want to do different thing for every observable. Maybe you shouldn't gorup them? If you want to group them and do different side effect for every one of them you can do something similar to BizzyBob anwer but instead of having if statements in subscribe use tap() operator for every stream. Something like this:
combineLatest([
obs1.pipe(tap(() => 'do somthing'),
obs2.pipe(tap(() => 'do somthing')),
obs3.pipe(tap(() => 'do somthing')),
])
.subscribe(([v1, v2, v3]) => {
});
Good practise is not to use subscribe method but instead set this stream to some property in component and than use async pipe in the template.
I was originally searching how to return several actions in a ngrx effect, and found I need to return an array of actions.
Then I noticed that returning a simple array in the switchMap works as fine as returning an observable created from this array.
For example:
timer(1000).pipe(switchMap(val => from([val, val + 1)])).subscribe(val => console.log(val));
timer(1000).pipe(switchMap(val => [val, val + 1])).subscribe(val => console.log(val));
I expect the first to work and think it is the correct syntax.
I don't expect the second to work but it actually does and I would like to understand why.
Thanks,
Because switchMap, among other flattening-operators (mergeMap, exhaustMap, ...), takes an ObservableLike as the return type of its projection function.
An ObservableLike can be Observable, Promise or Array. If you provide an array, it is converted into a stream of its items - basically the same as if you had used from.
TLDR: Working example is in the last codeblock of this question. Check out #bryan60 answer for a working example using concat rather than mergeMap.
I'm trying to run a number of remote requests sequentially, but only the first observable is executed.
The number of request vary, so I can't do a dodgy solution where I nest observables within each other.
I'm using the following code:
const observables = [
observable1,
observable2,
...
];
from(observables).pipe(
mergeMap(ob=> {
return ob.pipe(map(res => res));
}, undefined, 1)
).subscribe(res => {
console.log('Huzzah!');
})
In the past (rxjs 5.5) Ive used the following:
let o = Observable.from(observables).mergeMap((ob) => {
return ob;
}, null, 1);
o.subscribe(res => {
console.log('Huzzah!');
})
I'm not sure what I'm doing wrong, can anybody shed some light?
An additional request would be to only print 'Huzzah!' once on completion of all requests rather than for each individual Observable.
EDIT:
Removing undefined from my original code will make it work, however there was another issue causing only the first observable to be executed.
I'm using Angular's HttpClient for remote requests. My observable code looked like this:
const observables = [];
// Only the first observable would be executed
observables.push(this.http.get(urla));
observables.push(this.http.get(urlb));
observables.push(this.http.get(urlc));
Adding .pipe(take(1)) to each observable results in each observable being executed:
const observables = [];
// All observables will now be executed
observables.push(this.http.get(urla).pipe(take(1));
observables.push(this.http.get(urlb).pipe(take(1));
observables.push(this.http.get(urlc).pipe(take(1));
The code I ended up using, which executes all observables in sequential order and only triggers Huzzah! once is:
const observables = [];
observables.push(this.http.get(urla).pipe(take(1));
observables.push(this.http.get(urlb).pipe(take(1));
observables.push(this.http.get(urlc).pipe(take(1));
from(observables).pipe(
mergeMap(ob=> {
return ob.pipe(map(res => res));
}, 1),
reduce((all: any, res: any) => all.concat(res), [])
).subscribe(res => {
console.log('Huzzah!');
})
Thanks to #bryan60 for helping me wit this issue.
if these are http requests that complete, I think your bug is caused by a change to the mergeMap signature that removed the result selector. it's hard to be sure without knowing exactly which version you're on as it was there, then removed, then added again, and they're removing it once more for good in v7.
if you want to run them sequentially... this is all you need...
// concat runs input observables sequentially
concat(...observables).subscribe(res => console.log(res))
if you want to wait till they're all done to emit, do this:
concat(...observables).pipe(
// this will gather all responses and emit them all when they're done
reduce((all, res) => all.concat([res]), [])
// if you don't care about the responses, just use last()
).subscribe(allRes => console.log(allRes))
In my personal utility rxjs lib, I always include a concatJoin operator that combines concat and reduce like this.
the only trick is that concat requires observables to complete till it moves on to the next one, but the same is true for mergeMap with concurrent subscriptions set to 1.. so that should be fine. things like http requests are fine, as they complete naturally after one emission.. websockets or subjects or event emitters will behave a bit differently and have to be manually completed, either with operators like first or take or at the source.
If you are not concerned about the sequence of execution and just want 'Huzzah!' to be printed once all the observable has been executed forkJoin can also be used.Try this.
forkJoin(...observables).subscribe(res => console.log('Huzzah');
If I have the following code:
const subject = new BehaviorSubject<[]>([]);
const observable = subject.asObservable();
subject.next([{color: 'blue'}])
observable.pipe(first()).subscribe(v => console.log(v))
According to the docs:
If called with no arguments, first emits the first value of the source Observable, then completes....
Does this mean that the source observable(the BehaviorSubject in this case) completes and you can no longer use it? As in you can no longer call .next([...]) on it.
I'm trying to understand how can an observable complete if it doesnt have the .complete() method on it?
I was trying to look at the source code of first() which under the covers uses take() and in turn take() uses lift() so I was curious if somehow first operator returns a copy of the source observable(the subject) and completes that.
The source observable is not completing, what it completes is the subscription. You could have multiple subscriptions on your Observable source, in your case one BehaviorSubject.
subject.next([{color: 'blue'}])
subject.next([{color: 'red'}])
const subs1 = observable.pipe(first()).subscribe(v => console.log(v))
const subs2 = observable.subscribe(v => console.log(v))
In the example above you clearly see that the source is not completing, just the subscription.
I have created a Stackblitz if you want to try it: https://stackblitz.com/edit/rxjs-uv6h6i
Hope I got your point!
Cheers :)