How to combine POST and UPDATE commands in one action in laravel 8 with ajax?
I have one column "status" in another table that I need to update when I save the data.
In this case basically I have two different tables... thank you for your answer!
Update from the comments:
I have two different database tables, let's say the "Quotation" and "Detail Quotation" tables, where in the "Detail Quotation" table there is a Status column that contains TRUE or FALSE...
Well, I want when I add data to the Quotation table, I also run the command to change the contents of the status column in the "Detail Quotation" table.
you must use observer for this case
https://laravel.com/docs/8.x/eloquent#observers
When you save the POST data in table. Laravel return ID then, with that ID you can call the update function for another table to update the status.
Related
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I want to get Id from students table where i want insert this id in differs table . I don't really know how to explain it but maybe if you see my codes, you would understand. I have already finish making the relationship between this 2 tables already
my student controller
this my differ controller but I do not know any idea about if this code true or no
first: 'app\Differ'? but Differ is in App\Models
you can use hasOne(Differ::class); when Student model and differ in the same folder
the second thing you should know, when using functions of relationship in laravel such as hasOne, a foreign key should be named by student_id in Differ or
you show it in function like hasOne(Differ::class,'id_student','id')
I have two tables Order and OrderItem where OrderItem has the order_id as foreign key from Orders table. I have used laravel relationship in each of their model. Upon deleting a record from Order table which has relation in the OrderItem, I want to update a column name "Cancel" to true in OrderItem table and then soft delete the record.
I only know the manual method where I find the record by id, then update and soft delete it. Can anyone help me with shorter and easier method? Thank you.
I think you're mean is soft delete.
you can see this document.
I have two tables request and status_tracker. I want to list the row in top which has only one entry in status tracker.
I have the query in $user=DB::table('request')->select('request.*)->get();
I want to add the order based on status_tracker table. If request_id has count '2' in status_tracker table I want to display in top of the table
$user=DB::table('request')->select('request.*)(order may happened here)->get();
if ID 19,11,15 has 2 count in status_tracker it should display first and rest of them will display below as 19,11,15,18,17,16,14,13,12,10.
Is it possible by order the row based on another table field count in laravel?
You could use 'withCount' which will add a column named {relation}_count and orderBy with that, so try something like this:.
$user = App\Request::withCount('status_tracker')
->orderBy('status_tracker_count', 'desc')
->get();
You can read more about this on official Laravel docs
Note: Your model relationship should be well established in order for this to work, so make sure you have specified the relations between both tables :D
I have relation many to many (posts and tags) in Eloquent. Is it possible to order tags in the pivot table to get 10 most commonly used tags?
Yes it is possible, add some kind of attribute (to the pivot table and update it upon every select from the database. (increment the value)
And when selecting use wherePivot method.
If you want "most recent used", add timestamps to the pivot table in your migration and touch pivot table on every select.
Yes it is actually very simple to do that.
In the table that you store your tags add another column called count_cache(or whatever you want), then every time you add a tag instance to a post instance do a count() of the tag_id in the pivot table and store the value to the count_cache column in the tags table.
Then you can simply get the tags table ordered by the count_cache collumn (descending) with a limit of 10.
If you need further explanation please make a comment :)
I want to design an online store. For each category of productions, we would have its own fields.
Connections between tables of fields and categories are done and displayed in the part of registration of productions.
At the end, the value of each field should be stored that it should contains the related table between table of fields and productions (in addition to/plus/+) the value of that field.
My problem is in this part and I want that this related table has an additional field that I could value it.
In the following figure, the picture of table and my connections are shown, if there is (any problem/ something wrong with it), I would appreciate you to help me.
View Relationship Images :
http://ir-up.ir/uploads/1416568805731.jpg
You'd simply need to add a withPivot when declaring the relationship:
return $this->belongsToMany('Role')->withPivot('foo', 'bar');
Extra attributes in pivot tables are covered in the docs, here - http://laravel.com/docs/4.2/eloquent#working-with-pivot-tables