I have relation many to many (posts and tags) in Eloquent. Is it possible to order tags in the pivot table to get 10 most commonly used tags?
Yes it is possible, add some kind of attribute (to the pivot table and update it upon every select from the database. (increment the value)
And when selecting use wherePivot method.
If you want "most recent used", add timestamps to the pivot table in your migration and touch pivot table on every select.
Yes it is actually very simple to do that.
In the table that you store your tags add another column called count_cache(or whatever you want), then every time you add a tag instance to a post instance do a count() of the tag_id in the pivot table and store the value to the count_cache column in the tags table.
Then you can simply get the tags table ordered by the count_cache collumn (descending) with a limit of 10.
If you need further explanation please make a comment :)
Related
Hello I am working with Laravel,
I have to create two simple models, let's say Stores and Books.
Stores can have one or multiple Books and Books can belong to many Stores.
Of course I will use a many to many relationship, with a pivot table.
Books the can have different prices depending the store.
I think a separate table can only complicate things, in my mind the pivot table associating books and stores should have a price column, but pivot tables only contains store_id and book_id.
Should I create a book_prices and associate it with books and to stores? What is the best approach?
You are free and able to set other attributes on your pivot table. You can read more about it in the docs.
https://laravel.com/docs/9.x/eloquent-relationships#retrieving-intermediate-table-columns
You have to define the relationship accordingly, the following should clarify how this works. In this example you use the many-to-many relationship and add the price column to every retrieved pivot model.
public function books()
{
return $this->belongsToMany(Book::class)
->withPivot('price')
}
For example, you are able to access the pivot column in a loop like this
foreach ($shop->books as $book)
{
echo $book->pivot->price;
}
You can define additional columns for your pivot table in the migration for the pivot table, and then when defining the relationship use withPivot to define the additional columns so they come through in the model:
return $this->belongsToMany(Book::class)->withPivot('price');
(Adapted from the Laravel documentation, see https://laravel.com/docs/9.x/eloquent-relationships#retrieving-intermediate-table-columns)
Depends on the complexity of your case, but yes, you have two options for it. Let's say that the pivot table is called as book_store:
Directly adds price column to book_store. This is obviously the simpler option. The drawbacks are:
The history of the price changes isn't logged. You'll have to create another table for logging if you want to keep this history information.
Changes made to price will directly change the price of the related book_store record. Meaning that a price is being updated "live" e.g users cannot update the price now but "publish" it some time later just like this example in the doc.
Create a new, different table to store the price. This may seems relatively more complex, but it may also be more future-proof.
Basically, you get 2 things that you miss in the first option above.
Don't think too much about book_store being a pivot table. One way to see it is like this: book_store IS a pivot table from books and stores tables viewpoints, but it's also just a normal SQL table which could relate to any other tables using any kind of relationships.
If you want to implement this, make sure to create a primary-key in the book_store table.
Alast, it all depends on what you need. Feel free to ask if you need more insight about this. I hope this helps.
I have two tables request and status_tracker. I want to list the row in top which has only one entry in status tracker.
I have the query in $user=DB::table('request')->select('request.*)->get();
I want to add the order based on status_tracker table. If request_id has count '2' in status_tracker table I want to display in top of the table
$user=DB::table('request')->select('request.*)(order may happened here)->get();
if ID 19,11,15 has 2 count in status_tracker it should display first and rest of them will display below as 19,11,15,18,17,16,14,13,12,10.
Is it possible by order the row based on another table field count in laravel?
You could use 'withCount' which will add a column named {relation}_count and orderBy with that, so try something like this:.
$user = App\Request::withCount('status_tracker')
->orderBy('status_tracker_count', 'desc')
->get();
You can read more about this on official Laravel docs
Note: Your model relationship should be well established in order for this to work, so make sure you have specified the relations between both tables :D
I'm trying to figure out if there's some way to get the values of two columns in a pivot table, based on a unique incrementing ID that I gave each row.
I have a Job model, a Location model, and an Application model.
The Job and Location have a many to many relationship with a pivot table "job_location". The two foreign keys it contains are job_id and location_id. However, I also gave every row a unique incrementing ID, jobloc_id.
If I only have the jobloc_id, how can I look up the values of the other two columns?
$jobLoc = $location->jobs->wherePivot('jobloc_id', '=', 1);
return $jobLoc->job_id;
Returns "Method wherePivot does not exist" even though I've seen references of people using it. All I have is the jobloc_id, and am trying to lookup the other two values based on this so that I can fully load the Job and Location to pull attributes from them.
Any pointers would be greatly appreciated. This is in Laravel 5.3.
If you're added ID to pivot table (jobloc_id for example) and you want to get row by ID, just use query builder:
DB::table('job_location')->where('jobloc_id', 1)->first();
That's the fastest and simpliest way to do that when you have unique row ID in the pivot table.
I've two tables user and product, along with their relationship user_product. The relationship table contains an extra field category. Now I want to find
the number of products selected by a user of a particular category.
I've done it in my page through coding. Is there any easier way to do this?
How to use field of pivot table?
you can use withPivot
Ex:
$this->belongsToMany('Role')->withPivot('foo', 'bar');
This is my first post ever and haven't come across any other questions related to this. I am attempting to try and create a hybrid validation type and add it to an existing oracle form. We have a super/subset type of thing going on. When one chooses something from a dropdown, there are 5 options. If 4 of those options are chosen, the data is pulled from one validation table dataset, table A. If the other option is chosen, it comes from a different table's dataset, table B. These (along with others items) are saved in Table C. Table C has a FK constraint regarding these validations. I have added another column to table C to attempt to bypass the FK constraint, but the field still tries to save in the FK column. I can't seem to figure out if I need to add a database trigger, an item level trigger, or a form level trigger to reroute the data to correct columns in the database. Thanks in advance for any help!
If your items are select lists, you would use an item level trigger (when-validate-item) on the superset list item to populate/repopulate the list for the subset item.
Alternatively, you could use a popup LOV on the subset item which has a query which is filtered by the value of the superset item.