Create table temp(col raw(40));
Insert into temp values(0x02900000AB45GH38);
Error: ORA-00917: missing comma
First, your data is not correct hex - "GH" should not be there.
Once you get your data right,
Just pass hex as varchar -
Insert into temp values('0290')
It is same as -
Insert into temp values(hextoraw('0290'))
Related
I'm not able to import data on partitioned table in Hive.
Here is how I create the table
CREATE TABLE IF NOT EXISTS title_ratings
(
tconst STRING,
averageRating DOUBLE,
numVotes INT
)
ROW FORMAT DELIMITED
FIELDS TERMINATED BY '\t'
STORED AS TEXTFILE
TBLPROPERTIES("skip.header.line.count"="1");
And then I load the data into it : LOAD DATA INPATH '/title.ratings.tsv.gz' INTO TABLE eval_hive_db.title_ratings;
It works fine till here. Now I want to create a dynamic partitioned table. First of all, I setup theses params:
SET hive.exec.dynamic.partition=true;
SET hive.exec.dynamic.partition.mode=nonstrict;
I now create my partitioned table:
CREATE TABLE IF NOT EXISTS title_ratings_part
(
tconst STRING,
numVotes INT
)
PARTITIONED BY (averageRating DOUBLE)
ROW FORMAT DELIMITED
FIELDS TERMINATED BY '\n'
STORED AS TEXTFILE;
insert into title_ratings_part partition(title_ratings) select tconst, averageRating, numVotes from title_ratings;
(I also tried with numVotes instead by the way)
And I receive this error: FAILED: ValidationFailureSemanticException eval_hive_db.title_ratings_part: Partition spec {title_ratings=null} contains non-partition columns
Someone can help me please?
Ideally, I want to partition my table by averageRating (less than 2, between 2 and 4, and greater than 4)
You can run this command to check if there are null values or not.
select count(averageRating) from title_ratings group by averageRating;
Now, if there are null values in this column then you will get the count, which you have to fill then apply partitioning again.
Partition column is stored as last column in a table so while inserting you need to maintain correct order in select statement.
Pls change order of columns in select.
insert into title_ratings_part partition(title_ratings)
Select
Tconst,
numVotes,
averageRating --orderwise this should always be last column
from title_ratings
Till today we use to enter numeric value in the Varchar column so Oracle converted that varchar field to Numeric field.
And now when we are trying to insert Character value it is throwing ORA-01722 (invalid number).
Could anyone help me out in order to convert it back to varchar field?
The commenters are correct: the database does not change column types on its own. In general, you must create a new column, copy the old data over to the new column, drop the original column, and rename the new column.
drop table deleteme_table;
-- zippy s/b varchar2(30), not integer
CREATE TABLE deleteme_table
(
adate DATE
, zippy INTEGER
);
-- Add the correct type to the table as a new column
ALTER TABLE deleteme_table
ADD (tempcol VARCHAR2 (30));
-- Copy the old values to the new column
UPDATE deleteme_table
SET tempcol = zippy;
-- Get rid of the original column
ALTER TABLE deleteme_table
DROP COLUMN zippy;
-- Rename to original column name
alter table deleteme_table rename column tempcol to zippy;
I'm completely new to Hive and Stack Overflow. I'm trying to create a table with complex data type "STRUCT" and then populate it using INSERT INTO TABLE in Hive.
I'm using the following code:
CREATE TABLE struct_test
(
address STRUCT<
houseno: STRING
,streetname: STRING
,town: STRING
,postcode: STRING
>
);
INSERT INTO TABLE struct_test
SELECT NAMED_STRUCT('123', 'GoldStreet', London', W1a9JF') AS address
FROM dummy_table
LIMIT 1;
I get the following error:
Error while compiling statement: FAILED: semanticException [Error
10044]: Cannot insert into target because column number type are
different 'struct_test': Cannot convert column 0 from struct to
array>.
I was able to use similar code with success to create and populate a data type Array but am having difficulty with Struct. I've tried lots of code examples I've found online but none of them seem to work for me... I would really appreciate some help on this as I've been stuck on it for quite a while now! Thanks.
your sql error. you should use sql:
INSERT INTO TABLE struct_test
SELECT NAMED_STRUCT('houseno','123','streetname','GoldStreet', 'town','London', 'postcode','W1a9JF') AS address
FROM dummy_table LIMIT 1;
You can not insert complex data type directly in Hive.For inserting structs you have function named_struct. You need to create a dummy table with data that you want to be inserted in Structs column of desired table.
Like in your case create a dummy table
CREATE TABLE DUMMY ( houseno: STRING
,streetname: STRING
,town: STRING
,postcode: STRING);
Then to insert in desired table do
INSERT INTO struct_test SELECT named_struct('houseno',houseno,'streetname'
,streetname,'town',town,'postcode',postcode) from dummy;
No need to create any dummy table : just use command :
insert into struct_test
select named_struct("houseno","house_number","streetname","xxxy","town","town_name","postcode","postcode_name");
is Possible:
you must give the columns names in sentence from dummy or other table.
INSERT INTO TABLE struct_test
SELECT NAMED_STRUCT('houseno','123','streetname','GoldStreet', 'town','London', 'postcode','W1a9JF') AS address
FROM dummy
Or
INSERT INTO TABLE struct_test
SELECT NAMED_STRUCT('houseno',tb.col1,'streetname',tb.col2, 'town',tb.col3, 'postcode',tb.col4) AS address
FROM table1 as tb
CREATE TABLE IF NOT EXISTS sunil_table(
id INT,
name STRING,
address STRUCT<state:STRING,city:STRING,pincode:INT>)
ROW FORMAT DELIMITED
FIELDS TERMINATED BY '.';
INSERT INTO sunil_table 1,"name" SELECT named_struct(
"state","haryana","city","fbd","pincode",4500);???
how to insert both (normal and complex)data into table
I am unable to append data to tables that contain an array column using insert into statements; the data type is array < varchar(200) >
Using jodbc I am unable to insert values into an array column by values like :
INSERT INTO demo.table (codes) VALUES (['a','b']);
does not recognises the "[" or "{" signs.
Using the array function like ...
INSERT INTO demo.table (codes) VALUES (array('a','b'));
I get the following error using array function:
Unable to create temp file for insert values Expression of type TOK_FUNCTION not supported in insert/values
Tried the workaround...
INSERT into demo.table (codes) select array('a','b');
unsuccessfully:
Failed to recognize predicate '<EOF>'. Failed rule: 'regularBody' in statement
How can I load array data into columns using jdbc ?
My Table has two columns: a STRING, b ARRAY<STRING>.
When I use #Kishore Kumar Suthar's method, I got this:
FAILED: ParseException line 1:33 cannot recognize input near '(' 'a' ',' in statement
But I find another way, and it works for me:
INSERT INTO test.table
SELECT "test1", ARRAY("123", "456", "789")
FROM dummy LIMIT 1;
dummy is any table which has atleast one row.
make a dummy table which has atleast one row.
INSERT INTO demo.table (codes) VALUES (array('a','b')) from dummy limit 1;
hive> select codes demo.table;
OK
["a","b"]
Time taken: 0.088 seconds, Fetched: 1 row(s)
Suppose I have a table employee containing the fields ID and Name.
I create another table employee_address with fields ID and Address. Address is a complex data of type array(string).
Here is how I can insert values into it:
insert into table employee_address select 1, 'Mark', 'Evans', ARRAY('NewYork','11th
avenue') from employee limit 1;
Here the table employee just acts as a dummy table. No data is copied from it. Its schema may not match employee_address. It doesn't matter.
I got a column message with data_type = VARCHAR2. It already has some data stored. I want this column to be of type NCLOB. Code-Set for this column should be UTF-8.
I did the following:
added a column tempmessage to my table of type NCLOB
filled tempmessage with message
renamed message to message old (so that i don't use any data (until it works))
renamed tempmessage to message
Then i tried out my integration tests and i got the exception:
java.sql.BatchUpdateException: ORA-01400: Insert of NULL into ("BATCH_LOG"."MESSAGEOLD") not possible.
What have I done wrong?
The original column was defined as NOT NULL, when you renamed that to MESSAGEOLD, this constraint was kept. You need to remove the NOT NULL constraint from the MESSAGEOLD column:
ALTER TABLE foo MODIFY MESSAGEOLD NULL;