How to render SCSS while keeping nesting? - sass

I am creating a SCSS -> HTML plugin and need to first render SCSS -> CSS while keeping the nesting so I can then parse with PostCSS to then create an HTML tree with.
I would like to render SCSS like this
// myMixin.scss
#mixin myMixin {
.myMixin {
padding: 1rem;
background: yellow;
}
}
// main.scss
#import 'myMixin.scss';
$blue: #004AAD;
.button {
.text {
color: $blue;
}
#include myMixin;
}
And the output would look like this:
.button {
.text {
color: #004AAD;
}
.myMixin {
padding: 1rem;
background: yellow;
}
}
Basically, I'd like a way to render everything in SCSS while keeping the original nesting. Is it possible? Thanks.

Nesting is specific to SCSS. Also I don't think #import is best practice, use #use instead.
https://sass-lang.com/documentation/at-rules/use

Here is the thing our client(browsers) only support raw CSS and not SCSS, When you use SCSS it compiles down to raw CSS, And CSS doesn't have inbuilt Nesting feature.

Related

Using irregular CSS in a .scss file

I have some funky formatting which I am using to override a Polymer component. It's the custom variables mixin. Scss does not like it to compile with. Is it possible to set a chunk that doesn't get compiled the sass way? Similar to jekyll raw html tag.
For example
// tag do not compile with sass //
--my-component-custom-mixin: {
background-color: #000;
color: #fff;
};
// tag finish do not compile with sass //
You could use Sass string interpolation (#{'...'}) to escape the CSS mixin:
SELECTOR {
--CSS-VARIABLE-NAME: #{'CSS-VARIABLE-VALUE'};
}
Example:
my-view1 {
--my-component-custom-mixin: #{'{
background-color: #000;
color: #fff;
}'};
}
demo

Iterate over theme-variable files in SCSS

I want to create different css-themes for a WordPress theme by using theme setup files. The setup (simplified) would be as following:
/themes/_theme1.scss
/themes/_theme2.scss
/components/_file1.scss
/components/_file2.scss
/theme.scss
The idea is to enable easy theming by adding a class to the body of the document like .theme-theme1 or .theme-theme2. In the files _theme#.scss I want to define variables like text colour, font sizes and so on. In _file#.scss the actual styles are defined.
My question now is, how to iterate over the theme setup files while filling up the files.scss.
Sample idea, Background colour:
body {
###foreach themefile###
&.theme# {
background-color: $background-color;
}
###/foreach###
}
I know how to do this with only one theme available in the resulting CSS file, but I want to make ALL themes available in the resulting CSS. Feel free to ask more details as I am not sure if I explain me right.
Is there a way to create this stylesheet via some kind of foreach loops through variables in theme files or does it have to be done with extra scss-rules per theme file?
This is somewhat possible using a combo of #import with a #mixin to generate the styles. This method should produce minimal repeated code.
Here's how we'll setup the files.
- scss
- themes
- _theme1.scss
- _theme2.scss
- _theme.scss
- styles.scss
The _ prefix on some of the files prevent them from being compiled into CSS to keep our build nice and clean. Now let's go through the contents of the files:
_theme1.scss
$theme-name: 'theme1';
$primary-color: red;
$primary-font-size: 24px;
_theme2.scss
$theme-name: 'theme2';
$primary-color: blue;
$primary-font-size: 12px;
This is an oversimplified example but should give the basic idea. Each theme file will contain only variables.
_theme.scss
#mixin themestyle() {
body.#{$theme-name} {
p {
color: $primary-color;
font-size: $primary-font-size;
}
.bordered {
border: 3px solid $primary-color;
}
}
}
The themestyle mixin will contain all the styles for each theme, using the variables from the /themes/_theme*.scss files. The body.#{$theme-name} will create a selector like body.theme1 or body.theme2, depending on the current value of the $theme-name variable.
In this demo I'm styling on a p tag but this could easily be extended to all elements/selectors for your site. The important thing to remember is all styles need to be inside the body.#{$theme-name} selector.
Now the final, and least DRY part. The styles.scss file will import each theme file then call the themestyle mixin to generate the styles for each theme.
styles.scss
#import 'themes/theme';
/* Theme 1 Styles */
#import 'themes/theme1';
#include themestyles();
/* Theme 2 Styles */
#import 'themes/theme2';
#include themestyles();
The repeated #import/#include is required because it's not possible to #import within a loop or mixin, or this could be optimized a bit more.
Once styles.scss is compiled the output will be:
/* Theme 1 Styles */
body.theme1 p {
color: red;
font-size: 24px; }
body.theme1 .bordered {
border: 3px solid red; }
/* Theme 2 Styles */
body.theme2 p {
color: blue;
font-size: 12px; }
body.theme2 .bordered {
border: 3px solid blue; }
These themes can now be implemented by adding a class to the body tag, like <body class="theme1"> or <body class="theme1">.
Here's a Cloud9 project showing the setup.

What is the equivalent of LESS's "import (reference) 'style'" in SASS

In addition to application.css.scss, I have multiple partials like homepage.css.scss. At the moment I have to add #import 'bootstrap' to each one of them in order to use bootstrap variables and mixins.
Let's say I want to change my default links colour to red, I'd add that to application.css.scss. But the links in homepage.css.scss will not be red because the bootstrap import will override it with blue.
In LESS, I can do #import (reference) "bootstrap", how can I do that in SASS?
The closest you will get is a silent class / placeholder. These work a little different to how LESS and reference work, you can read more on them here: http://blog.teamtreehouse.com/extending-placeholder-selectors-with-sass
LESS
lib.less
.class {
background: red;
}
main.less
#import (reference) "lib";
.anotherClass {
&:extend(.class);
}
SASS
lib.sass
%class {
background: red;
}
main.sass
#import "lib";
.anotherClass {
#extend %class;
}
CSS Output
.anotherClass {
background: red;
}

Possible to make SASS #extend styles !important?

Is there a way to give SASS styles applied using the #extend feature the status of being !important? I tried this:
.somestyles {
width: 1000px;
}
.importantstyle {
#extend .somestyles !important;
}
Didn't work, but how might this be done? Or is it just not possible?
What you're asking for is not possible. You could increase the specificity of the selector that's doing the extending.
body .importantstyle {
#extend .somestyles;
}

Is it possible to merge properties of same selectors from different partial files in sass?

Let's assume you have a style.scss file as well as two partials called _base.scss and _typo.scss.
style.scss only contains:
#import 'compass', 'x1', 'x2';
_base.scss contains:
p{
width:80%;
}
_typo.scss contains:
p{
color:red;
}
when the style.scss is compiled style.css looks like:
p {
width: 80%;
}
p {
color: red;
}
instead of merging the properties of the same selector into one in the final css that it would look like that:
p {
width: 80%;
color: red;
}
is it possible to get the latter result somehow? or is there anything not recommendable about it? best regards ralf

Resources