I have a table name "TABLE1" with 4 columns COLUMN1, COLUMN2, FREQ, CNT
I have a result table name "RESULT1" with 4 columns COLUMN1, COLUMN2, FREQ
I have a result table name "RESULT2" with 4 columns COLUMN1, COLUMN2, FREQ
CREATE TABLE TABLE1 ( COLUMN1 VARCHAR2(4), COLUMN2 VARCHAR2(4), FREQ NUMBER, CNT NUMBER);
INSERT INTO TABLE1(COLUMN1, COLUMN2, FREQ) VALUES ('1234', 'ABCD', 1);
INSERT INTO TABLE1(COLUMN1, COLUMN2, FREQ) VALUES ('1234', 'ACBD', 1);
INSERT INTO TABLE1(COLUMN1, COLUMN2, FREQ) VALUES ('1234', 'ABDC', 1);
INSERT INTO TABLE1(COLUMN1, COLUMN2, FREQ) VALUES ('1342', 'DAFY', 1);
INSERT INTO TABLE1(COLUMN1, COLUMN2, FREQ) VALUES ('1423', 'CBAD', 1);
I want to update the CNT column in TABLE1 based on number of times COLUMN1 is repeated.
The result in TABLE1:
COLUMN1 COLUMN2 FREQ CNT
-----------------------------------
1234 ABCD 1 3
1234 ACBD 1 3
1234 ABDC 1 3
1342 DAFY 1 1
1423 CBAD 1 1
Once we get above result,
based on CNT value, if CNT =1 insert in RESULT1 table else CNT > 1 insert those records in RESULT2 table like
RESULT2 table
COLUMN1 COLUMN2 FREQ
-----------------------------------
1234 ABCD 1
1234 ACBD 1
1234 ABDC 1
RESULT1 table
COLUMN1 COLUMN2 FREQ
-----------------------------------
1342 DAFY 1
1423 CBAD 1
I tried using MERGE statement to populate but not able to get answer showing some syntax error.
how about the oracle insert all. lets you insert into multiple tables based on a condition.
insert All
When cnt > 1 THEN
into result1
else
into result2
select column1, column2, freq, count(*) over (partition by column1) as cnt from table1;
here is the sql fiddle. http://sqlfiddle.com/#!4/d6f20/5
From my point of view, a simple way is the best way.
This is the starting point:
SQL> select * from table1;
COLU COLU FREQ CNT
---- ---- ---------- ----------
1234 ABCD 1
1234 ACBD 1
1234 ABDC 1
1342 DAFY 1
1423 CBAD 1
Update TABLE1.CNT:
SQL> update table1 a set
2 a.cnt = (select count(*)
3 from table1 b
4 where b.column1 = a.column1
5 );
5 rows updated.
SQL> select * from table1;
COLU COLU FREQ CNT
---- ---- ---------- ----------
1234 ABCD 1 3
1234 ACBD 1 3
1234 ABDC 1 3
1342 DAFY 1 1
1423 CBAD 1 1
Rows whose cnt = 1 go into result1:
SQL> insert into result1 (column1, column2, freq)
2 select column1, column2, freq
3 from table1
4 where cnt = 1;
2 rows created.
SQL> select * from result1;
COLU COLU FREQ
---- ---- ----------
1342 DAFY 1
1423 CBAD 1
Rows whose cnt > 1 go into result2:
SQL> insert into result2 (column1, column2, freq)
2 select column1, column2, freq
3 from table1
4 where cnt > 1;
3 rows created.
SQL> select * from result2;
COLU COLU FREQ
---- ---- ----------
1234 ABCD 1
1234 ACBD 1
1234 ABDC 1
SQL>
The end.
Related
I have 2 tables - tab1 , tab2 with following data
tab1 data:
OID Label
1 MX1
1 MX2
1 MX3
2 MX4
2 MX5
tab2 data:
OID ID Label
1 5678
1 2347
1 9687
2 4567
2 3455
The join condition between these two tables is oid column.I need to create a process which will update Label column from tab1 to Label column of tab2.It doesn't matter which label gets assigned to which record of tab2 for a particular oid. The only check that needs to happen is that both the tables should have same number of records for an oid.The final outcome should be the following
tab2 data:
OID ID Label
1 5678 MX1
1 2347 MX2
1 9687 MX3
2 4567 MX4
2 3455 MX5
Again, it doesn't matter which label gets assigned to tab2 for a particular oid,but the same label cannot be repeated for a particular oid.What would be the best way to write a code for this requirement?
Here is a sql solution:
merge into tab2
using
(
select t2."id" as ide,t1."label" labela from
(select rownum n,"label","oid" from tab1 order by "oid")t1,
(select rownum n, a2.* from tab2 a2 order by "oid")t2
where t1.n=t2.n and
t1."oid"=t2."oid"
) tb4
on (tab2."id" = tb4.ide)
when matched then
update set tab2."label" = tb4.labela;
Result:
oid| id | label
-----------------
1 5678 mx1
1 2347 mx2
1 9687 mx3
2 4567 mx4
2 3455 mx5
Sample tables:
SQL> select * from tab1 order by oid, label;
OID LAB
---------- ---
1 mx1
1 mx2
1 mx3
2 mx4
2 mx5
SQL> select * from tab2 order by oid, id;
OID ID LAB
---------- ---------- ---
1 2347
1 5678
1 9687
2 3455
2 4567
SQL>
This is query that returns desired result:
SQL> with
2 t1 as (select oid, label, rowid rwid,
3 row_number() over (partition by oid order by label) rn
4 from tab1
5 ),
6 t2 as (select oid, id, rowid rwid,
7 row_number() over (partition by oid order by id) rn
8 from tab2
9 )
10 select b.oid, b.id, a.label
11 from t1 a join t2 b on a.oid = b.oid and a.rn = b.rn;
OID ID LAB
---------- ---------- ---
1 2347 mx1
1 5678 mx2
1 9687 mx3
2 3455 mx4
2 4567 mx5
SQL>
A few options I tried: correlated update won't work because of
ORA-01779: cannot modify a column which maps to a non key-preserved table
SQL> update (
2 with
3 t1 as (select oid, label, rowid rwid,
4 row_number() over (partition by oid order by label) rn
5 from tab1
6 ),
7 t2 as (select oid, id, rowid rwid, label,
8 row_number() over (partition by oid order by id) rn
9 from tab2
10 )
11 select b.oid, b.id, b.label b_label, a.label a_label
12 from t1 a join t2 b on a.oid = b.oid and a.rn = b.rn
13 )
14 set b_label = a_label;
set b_label = a_label
*
ERROR at line 14:
ORA-01779: cannot modify a column which maps to a non key-preserved table
SQL>
MERGE won't work because of
ORA-01732: data manipulation operation not legal on this view
SQL> merge into
2 (select oid, id, label, row_Number() over (partition by oid order by id ) rn from tab2) b
3 using (select oid, label, row_number() over (partition by oid order by label) rn from tab1) a
4 on (a.oid = b.oid and
5 a.rn = b.rn)
6 when matched then update set
7 b.label = a.label;
(select oid, id, label, row_Number() over (partition by oid order by id ) rn from tab2) b
*
ERROR at line 2:
ORA-01732: data manipulation operation not legal on this view
SQL>
Merge would accept a view (created with create view ...), but a view has to be updateable; this one can't be because it contains analytic function.
What's left is a PL/SQL procedure:
SQL> begin
2 for cur_r in (with
3 t1 as (select oid, label, rowid rwid,
4 row_number() over (partition by oid order by label) rn
5 from tab1
6 ),
7 t2 as (select oid, id, rowid rwid,
8 row_number() over (partition by oid order by id) rn
9 from tab2
10 )
11 select b.rwid, a.label
12 from t1 a join t2 b on a.oid = b.oid and a.rn = b.rn
13 )
14 loop
15 update tab2 b set
16 b.label = cur_r.label
17 where b.rowid = cur_r.rwid;
18 end loop;
19 end;
20 /
PL/SQL procedure successfully completed.
SQL> select * from tab2 order by oid, id;
OID ID LAB
---------- ---------- ---
1 2347 mx1
1 5678 mx2
1 9687 mx3
2 3455 mx4
2 4567 mx5
SQL>
Maybe someone has another idea; I'd like to see it & learn something new.
Currently, I have a table MY_TABLE like below:
ID ACCT_TYPE CREDIT_AMT DEBIT_AMT
-- --------- ---------- ---------
1 CDT_01 4 (null)
1 DBT_01 (null) 6
One ID can have multiple ACCT_TYPE like above, and each type has its own amount.
I want to just select the row which has ACCT_TYPE like 'CDT_%' but also the total_amount column which is the total of credit_amt and debit_amt column for the same ID.
My expected output like below:
ID ACCT_TYPE TOTAL_AMT
-- --------- ---------
1 CDT_01 10
I tried with this select statement below but it's no use, I think it's because of different ACCT_TYPE:
Select ID, ACCT_TYPE, SUM(NVL(CREDIT_AMT, 0) + NVL(DEBIT_AMT, 0)) TOTAL_AMT
FROM MY_TABLE WHERE ACCT_TYPE LIKE 'CDT_%' GROUP BY ID, ACCT_TYPE;
Here is the output of the select statement above:
ID ACCT_TYPE TOTAL_AMT
-- --------- ---------
1 CDT_01 4
I just begin to learn some query so I don't know is it really possible to get my expected output.
One way to do it is like below:
with inputs (ID, ACCT_TYPE, CREDIT_AMT, DEBIT_AMT) as
(
select 1, 'CDT_01', 4, null from dual union all
select 1, 'DBT_01', null, 6 from dual
),
prep as
(
select t.*, sum(nvl(credit_amt,0)) over (partition by id) + sum(nvl(debit_amt,0)) over (partition by id) as sum_per_id
from inputs t
)
select id, acct_type, sum_per_id
from prep
where acct_type like 'CDT_%';
Output:
A correlated subquery might be one option; sample data (thank you, #Ranagal) in lines #1 - 5; query that does the job begins at line #6.
SQL> with inputs (ID, ACCT_TYPE, CREDIT_AMT, DEBIT_AMT) as
2 (
3 select 1, 'CDT_01', 4, null from dual union all
4 select 1, 'DBT_01', null, 6 from dual
5 )
6 select a.id,
7 a.acct_type,
8 (select sum(nvl(b.credit_amt, 0)) +
9 sum(nvl(b.debit_amt , 0))
10 from inputs b
11 where b.id = a.id
12 ) total_amt
13 from inputs a
14 where acct_type like 'CDT%';
ID ACCT_T TOTAL_AMT
---------- ------ ----------
1 CDT_01 10
SQL>
I have some fields in table1 to update with random values from some fields in table2.
I have to random into rows of table2 and update each rows of table1 with the same rows values of table2.
Here is my SQL code, but it doesn't work.
update owner.table1 t1
set (t1.adress1, t1.zip_code, t1.town) = (select t2.adress, t2.zip_code, t2.town
from table1 t2
where id = trunc(dbms_random.value(1,20000)))
Result: all rows are updated with the same values, like no random on table 2 rows
How about switching to analytic ROW_NUMBER function? It doesn't really create a random value, but might be good enough.
Here's an example: first, create test tables and insert some data:
SQL> create table t1 (id number,address varchar2(20), town varchar2(10));
Table created.
SQL> create table t2 (id number, address varchar2(20), town varchar2(10));
Table created.
SQL> insert into t1
2 select 1, 'Ilica 20', 'Zagreb' from dual union all
3 select 2, 'Petrinjska 30', 'Sisak' from dual union all
4 select 3, 'Stradun 12', 'Dubrovnik' from dual;
3 rows created.
SQL> insert into t2
2 select 1, 'Pavelinska 15', 'Koprivnica' from dual union all
3 select 2, 'Baščaršija 11', 'Sarajevo' from dual union all
4 select 3, 'Riva 22', 'Split' from dual;
3 rows created.
SQL> select * From t1 order by id;
ID ADDRESS TOWN
---------- -------------------- ----------
1 Ilica 20 Zagreb
2 Petrinjska 30 Sisak
3 Stradun 12 Dubrovnik
SQL> select * From t2 order by id;
ID ADDRESS TOWN
---------- -------------------- ----------
1 Pavelinska 15 Koprivnica
2 Baščaršija 11 Sarajevo
3 Riva 22 Split
Update t1 with rows from t2:
SQL> update t1 set
2 (t1.address, t1.town) =
3 (select x.address, x.town
4 from (select row_number() over (order by address) id, t2.address, t2.town
5 from t2
6 ) x
7 where x.id = t1.id);
3 rows updated.
SQL> select * From t1 order by id;
ID ADDRESS TOWN
---------- -------------------- ----------
1 Baščaršija 11 Sarajevo
2 Pavelinska 15 Koprivnica
3 Riva 22 Split
SQL>
Table contains value 1,2,3 but while display the values needs to show 2,1,3
Example
Table A
column1 column2 column3
1 Rat Animals
2 Parrot Bird
3 Lotus Flower
Need to display parrot first then Rat and Lotus which means 2,1,3
Expected Output:
column1 column2 column3
2 Parrot Bird
1 Rat Animal
3 Lotus Flower
Kindly help me out to fix the issue in order by query.
You could use CASE expression in the ORDER BY clause for the particular conditions, and let other rows retain their order.
Setup
SQL> CREATE TABLE t
2 (column1 int, column2 varchar2(6), column3 varchar2(7));
Table created.
SQL> INSERT ALL
2 INTO t (column1, column2, column3)
3 VALUES (1, 'Rat', 'Animals')
4 INTO t (column1, column2, column3)
5 VALUES (2, 'Parrot', 'Bird')
6 INTO t (column1, column2, column3)
7 VALUES (3, 'Lotus', 'Flower')
8 INTO t (column1, column2, column3)
9 VALUES (7, 'def', 'xyz')
10 INTO t (column1, column2, column3)
11 VALUES (4, 'abc', 'qwe')
12 SELECT * FROM dual;
5 rows created.
SQL> COMMIT;
Commit complete.
Table Data
SQL> SELECT * FROM t;
COLUMN1 COLUMN COLUMN3
---------- ------ -------
1 Rat Animals
2 Parrot Bird
3 Lotus Flower
7 def xyz
4 abc qwe
Required Query
SQL> SELECT * FROM t
2 ORDER BY
3 CASE column1
4 WHEN 1
5 THEN 2
6 WHEN 2
7 THEN 1
8 ELSE 3
9 END,
10 column1;
COLUMN1 COLUMN COLUMN3
---------- ------ -------
2 Parrot Bird
1 Rat Animals
3 Lotus Flower
4 abc qwe
7 def xyz
SQL>
So, you have your desired order as well as the other rows retain their order as specified.
That is a strange order requested, anyways try this -
SELECT Column1,Column2,Column3
FROM TableA
ORDER BY CASE WHEN Column1 = 2 THEN 1
WHEN Column1 = 1 THEN 2
ELSE 3
END
I use following query to insert a new row:
insert into table1 (c1, c2, c3) (select c1, c2, c3 from table2 where some_condition)
This works finely if there is a row in table2 that satisfies some_condition. But if there are no rows, nothing is inserted.
Are there any way to specify default values to insert if select returns empty result set? I want to do that in one sql query.
This isn't very pretty, but it does what you want, You'd need to test with your environment to see if it performs well enough
SQL> drop table so_tgt;
Table dropped.
SQL>
SQL> create table so_src (
2 c1 varchar2(6)
3 ,c2 varchar2(6)
4 ,c3 varchar2(6)
5 );
Table created.
SQL>
SQL> insert into so_src values ( 'foo','bar','moo' );
1 row created.
SQL>
SQL> create table so_tgt as select * from so_src where 1 = 0;
Table created.
SQL>
SQL> /* Test for existing row insert */
SQL> insert into so_tgt
2 with x as ( select s.*, 1 as r
3 from so_src s
4 where c1='foo'
5 union
6 select 'x','y','z',0 as r /* DEFAULT VALUES */
7 from dual )
8 select c1,c2,c3
9 from x
10 where r = ( select max(r) from x ) ;
1 row created.
SQL>
SQL> select * from so_tgt;
C1 C2 C3
------ ------ ------
foo bar moo
SQL> truncate table so_tgt;
Table truncated.
SQL>
SQL> /* Test for default row insert */
SQL> insert into so_tgt
2 with x as ( select s.*, 1 as r
3 from so_src s
4 where c1='far'
5 union
6 select 'x','y','z',0 as r /* DEFAULT VALUES */
7 from dual )
8 select c1,c2,c3
9 from x
10 where r = ( select max(r) from x ) ;
1 row created.
SQL>
SQL> select * from so_tgt;
C1 C2 C3
------ ------ ------
x y z
SQL> truncate table so_tgt ;
Table truncated.
The quick and dirty way, if you don't mind repeating some_condition and where some_condition doesn't depend on the values in table2 is:
insert into table1 (c1,c2,c3)
select c1, c2, c3 from table2 where some_condition
union select defaultvalue1, defaultvalue2, defaultvalue3 from dual where not (some_condition)
If some_condition does depend on values in table2, then you can do (untested):
insert into table1 (c1,c2,c3)
select nvl(t2.c1, defaultvalue1), nvl(t2.c2, defaultvalue2), nvl(t2.c2, defaultvalue3)
from dual left join (select c1,c2,c3 from table2 where some_condition) t2
on 1 = 1
If I'm right, this query will always return at least one row, but if no rows showed up on the right side, then the t2 values will all be returned as null and so the nvl can be used to provide your default values.
Edit: Small caveat. This assumes that the values returned from table2 will not be null or that if they are, you want the default values.