I have a serialized String like this
$string = '[{"name":"FOO"},{"name":""},{"name":"BAR"}]';
I am trying to process it via Laravel Collection's filter method and eliminate items without a defined "name" property.
$collection = collect(\json_decode($string));
$collection = $collection->filter(function($v){
return !empty($v->name);
});
$string = \json_encode($collection->toArray());
dd($string);
Normally I am expecting something like this:
[{"name":"FOO"},{"name":"BAR"}]
But I'm getting something like this:
{"0":{"name":"FOO"},"2":{"name":"BAR"}}
Funny thing is, if I skip the filtering process or return true every time, I keep getting the string in the desired format. Removing the toArray() call has the same result. I don't want to keep the numeric indices as associative object keys.
Why this anomaly? And what should I do to get the serialized data in desired format?
In PHP arrays the index key must be unique.
In your case you have the key 'name' and collection automatically assigns the index key to all items in the collection.
To overcome that problem just call
$string = \json_encode($collection->values());
Related
I thought the data which is from DB::get() is Array.
However , the console says it is not array.
$fruitList = Food::where('id' => 300)->get(['id']);
shuffle($fruitList);
ErrorException: shuffle() expects parameter 1 to be array, object given in file
The return value of get() is not an array. it's Laravel array collection you can convert it to an array or use shuffle of array collection:
$fruitList = Food::where('id' => 300)->get(['id'])->toArray();
shuffle($fruitList);
with array collection:
$fruitList = Food::where('id' => 300)->get(['id'])->shuffle();
Just like #A.seddighi mentioned, using get() or all() gives you a collection. It may seem like an array when you output it using return or print but it is different.
Collections can be filtered, queried and so on. e.g
$fruitList->has('price')
etc.
To get an array simply called the toArray() method on it, you may also use flatMap(), mapWithKeys() etc. Make sure you follow the documentation that is suitable for your version of laravel.
I want to update a totcosty field in the User table but it is throwing this error everytime and it is not updating the field
this is the function for execution:
public static function cost(){
$user = User::find($user_id);
$total = Helper::totcost();
// dd($tot_amt);
$user->totcosty = $total;
$user->save();
}
array to string means you are sending an array to the database but db will not accept it you have to explode() the array before sending it to db...
Hope it will help!
If you really want to store an array in some table field, then better declare it as a JSON field. For this, your DB should have support for JSON type columns.
See here how to do this.
Once this is done, you can save arrays in that column, you can assign an array value to the model property and laravel will convert it to JSON while saving and also it will be converted to array while retrieving.
Using Laravel 5.3, I have a model with the following function
public function myData() {
return $this->hasMany(MyData::class);
}
and in my collection I have the following
$my_data = MyModel->myData()->get();
All good so far. If I return $my_data I get an eloquent collection with three items.
What I need now though is to create a duplicate of that collection but containing only three of the fields.
I have tried several different things, each of which return an error. The following is the closest I have got, but this returns an empty array - I assume because the fields are located one level deeper than the collection object.
$new_collection = $my_data->only(['field_1', 'field_2', 'field_3']);
What would be the correct way to create a new collection containing all three items, each with only the three selected fields?
Thanks for your help
You could use map:
$slimmed_down = $collection->map(function ($item, $key) {
return [
'field_1' => $item->field_1,
'field_2' => $item->field_2,
'field_3' => $item->field_3
];
});
This will return a new Collection with just the values you want. As far as I know there isn't any other method that does what you want, so iterating over every item and selecting the fields this way is one of the few solutions.
The advantage of using map instead of a standard foreach loop is that when you use map it returns a new instance of Collection.
Edit:
After some thoughts and research about this, the problem you'll have created is that the all the values in the Collection aren't instances of anything anymore. If you don't mind this effect, an even prettier and faster way would be to do this:
$slimmed_down = $collection->toArray()->only(['field_1', 'field_2', 'field_3']);
This basically has the same result.
Using Laravel 9, I just had the same issue :
$my_data->only(['field_1', 'field_2', 'field_3']);
returning an empty array.
I solved it with :
$my_data->map->only(['field_1', 'field_2', 'field_3']);
I have the following code:
$object = Object::with("prototypes.fields")->findOrFail($id)->get();
$object_copied = $object->except(['id', 'prefix', 'prototypes']);
dd($object_copied->all());
Last line returns collection with fields that should be except: 'id', 'prefix', 'prototypes'
The first thing:
$object = Object::with("prototypes.fields")->findOrFail($id)->get();
This is probably wrong.
You should either use:
$object = Object::with("prototypes.fields")->findOrFail($id);
or
$object = Object::with("prototypes.fields")->get();
The second thing is what you really want to achieve. except method might not be what you really want to use here if you want to get only some columns. In this case better option would be using select when getting data from database or maybe using map method.
Assuming in $object you have collection of object using except you will remove only some object from method (those with given keys) and keys in those collection will be numeric 0, 1, ... x so you should pass only numerical keys here if you want to not include first model in collection.
Try $object_copied = collect($object )->except('id', 'prefix', 'prototypes');
I want to get alternative products pictures.
dd($alternativeProduct->pictures);
When die and dump i get this result.
I need to get only the picture which is main. If main equals to 1. It is main picture.
When I write
dd($alternativeProduct->pictures->where('main', 1))
I got an empty array.
Here is my relation with Product and Picture relation
public function pictures(){
return $this->hasMany('App\Models\ProductPicture');
}
What can i do ?
The where method in a collection has three parameters: $key, $value and $strict, the last one defaults to true if not passed when calling the method. When $strict is true the comparison is done via === which does not do type coercion, meaning "1" === 1 is false.
From your dump data, I can see that "main" => "1" which means it's a string and you're passing an integer 1 to the where method, resulting in what I described above as a false condition and returning an empty result set. You can fix that by disabling strict comparison:
$alternativeProduct->pictures->where('main', 1, false);
// or the equivalent helper whereLoose
$alternativeProduct->pictures->whereLoose('main', 1);
Or passing a string as the value:
$alternativeProduct->pictures->where('main', "1");
That being said, if that's the only place you're using that collection in that request's context, I suggest that you filter the results at the database level, not after they are fetched, like so:
$alternativeProduct->pictures()->where('main', 1)->get();
Accessing the relations as a method ->pictures(), instead of as a property ->pictures, will return a Query Builder instance that allows you to add conditions to the database query and only fetch the actual items you need from the database, instead of fetching them all and filtering them out afterwards.
You may want to use whereLoose instead:
dd($alternativeProduct->pictures->whereLoose('main', 1))
From the Laravel docs:
The where method uses strict comparisons when checking item values. Use the whereLoose method to filter using "loose" comparisons.